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Design of Combind Footing

The document provides the design of combined footings for a project. Key inputs and outputs are given, including the resultant load, footing dimensions, shear and moment checks, reinforcement details, and a sketch. The footing is designed to support two load cases of 200t and 100t located 1.67m apart. The minimum footing dimensions are found to be 460cm by 545cm thickened to 11.97cm. Reinforcement ratios are calculated and bar arrangements are shown on the provided sketch.

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3ces
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0% found this document useful (0 votes)
154 views10 pages

Design of Combind Footing

The document provides the design of combined footings for a project. Key inputs and outputs are given, including the resultant load, footing dimensions, shear and moment checks, reinforcement details, and a sketch. The footing is designed to support two load cases of 200t and 100t located 1.67m apart. The minimum footing dimensions are found to be 460cm by 545cm thickened to 11.97cm. Reinforcement ratios are calculated and bar arrangements are shown on the provided sketch.

Uploaded by

3ces
Copyright
© Attribution Non-Commercial (BY-NC)
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLS, PDF, TXT or read online on Scribd
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* Design of Combined footings

* Project :

INPUT
40 cm
Fcu
Fy

qall

t (R.C) =

250
3600

kg/cm

1.2
60

kg/cm

40

cm

kg/cm2
2

cm

40

40

cm

cm

200 t

2.5

100 t

(C.G) OF "R"

OUT PUT
R=P1+P2

300.00

L=2*A+a+2*C=

543.33

cm

1.67 m

Resultant of 2 loads is at:

P.C

Dims. of P.C :

INPUT
qn(Stress on Soil)=Rt/(L*B)=

R.C

GET

A=

qall=R/(L*B)

GET

B= 458.72

from center of small load col

B (cm)

L (cm)

t (cm)

minimum

460

545

25

CHOSEN

DIM design

460

545

11.97

t/m2

Dims. of R.C :

INPUT

1.67

R*A=P2*S

B (cm)

L (cm)

t (cm)

minimum
CHOSEN

410

495

60

DIM design

410

495
210

SKETCH

145cm

210cm

60cm
25cm

65cm
143.333
83.3333

500cm
550cm

143
83.3

(CHECK SHEAR & MOMENT )

fn=(Rt/(A*B)=

14.78

t/m2

Q0=fn*x0*B=

39.39

Q1=P1-fn*x1*B=

36.36

Q2=P2-fn*x2*B=

87.88

Q3=fn*x3*B=

87.88

Qmax=

87.88

(Qmax-fn*B*d)/(0.87*B*d)

27.80

t/m2

q(sh)=

27.80

t/m2

q(allw) =

63.26

t/m2

get

36.36 t

87.88 t

39.39 t
105 cm
65 cm

185 cm
145 cm

t/m2

87.88 t

from eq:
fn*B*X-P2=0.0
X (at Zero Shear)=
3.30
from eq:

100

14.78

SAFE SHEAR

fn*B*X /2-P2*(X-b/2)

M(0,1) (POSITSVE MOM.)=


M(2,3) (POSITSVE MOM.)=

21.89
82.50

t.m
t.m

M(NEGAT) (at Zero Shear)=

0.00

t.m

M(max)=
d = C1 (Mu/(Fcu*b))

82.50
get C1 =

t.m
5.01

330
cm

0.00 m.t

82.50 m.t

SAFE MOMENT

(CHECK PUNNCHING )

200 t

21.89 m.t

dp1=(p1-Ac*fn/10)/(*qallp)=

0.51

m
p1= 200

2.78 FALSE
were

4
Ac=
1

dp2=(p2-Ac*fn/10)/(*qallp)=

0.24

m
p2= 100

Ac=

SAFE PUNCHING UNDER P1


SAFE PUNCHING UNDER P2

4
1

qallp=
fn=

9
14.78

kg/cm2
t/m2

qallp=
fn=

9
14.78

kg/cm2
t/m2

(A)

Top Rft. :

M(NEGAT) (at Zero Shear)=

from table

0.00

SH(401)

t.m

get J =

As=Mu*1.5/(Fy*j*d)

#####

Asmin=0.15*b*d

33.21

Asmin=11*b*d/Fy

67.65

0.826
#DIV/0!

33.21
Asmin=

0.00

33.21

0.00

33.21 cm2

TAKE As/(B)=

Top Rft. :

(B)

J<0.826

get C1 = ####

#DIV/0!

Asmin=1.33*Asreq

( Longitudinal direction )

d = C1 (Mu/(Fcu*b))

no.

12

total no/(B)

/m

34

7.17

Bottom Rft. :

1- COLUMN C1 WERE P1= 200 t


M(2,3) (POSITSVE MOM.)=

from table

82.50

SH(401)

t.m

get J =

As=Mu*1.5/(Fy*j*d)

0.826

J<0.826

get C1 = 5.01
0.826
0.829

77.1

Asmin=0.15*b*d

33.21

Asmin=11*b*d/Fy
Asmin=1.33*Asreq

33.21

67.65

Asmin=

102.50

67.65

67.65

77.07 cm2

TAKE As/(B)=

no.

10

16

Bottom Rft. :

( DESIGN)

d = C1 (Mu/(Fcu*b))

total no/(B)

/m

43

9.35

2- COLUMN C2 WERE P2= 100 t

M(0,1) (POSITSVE MOM.)=

from table

SH(401)

21.89

t.m

d = C1 (Mu/(Fcu*b))

get J =

0.826

J<0.826

get C1 = 9.72

0.826
0.860

As=Mu*1.5/(Fy*j*d)

20.5

Asmin=0.15*b*d

33.21

Asmin=11*b*d/Fy

67.65

Asmin=1.33*Asreq

33.21
Asmin=

27.20

33.21

27.20

33.21 cm2

TAKE As/(B)=

Bottom Rft. :

no.

16

/m

total no/(B)
22

4.03

(A)

Top Rft. :
Top Rft. :

(B)

no.

12

total no/(B)

/m

26

Bottom Rft. :

1- COLUMN C1 WERE P1= 200 t


BEAM WIDTH = (a+2d)=
TAKE (B.W)=

83.48

M (working)=WL2/2 =

t.m
were

W=P/B=

48.78 t/m

&

L=

d = C1 (Mu/(Fcu*b))

from table

SH(401)

get J =

( Transverse direction)

As=Mu*1.5/(Fy*j*d)

( DESIGN)

148 cm
145 cm
1.85 m
get C1 = 2.85

J<0.826

0.727

0.826
0.727

90.30

Asmin=0.15*b*d
Asmin=11*b*d/Fy
Asmin=1.33*Asreq

11.53
6.60

11.53

120.09

6.60

Asmin=

11.53

90.30 cm2

TAKE As/(B)=

Bottom Rft. :

T.no

80

12

total no/(B.W)

145

cm

79.88

2- COLUMN C2 WERE P2= 100 t


BEAM WIDTH = (a+2d)=
TAKE (B.W)=
M (working)=WL2/2 =

41.74

t.m
were

W=P/B=

24.39 t/m

&

L=

d = C1 (Mu/(Fcu*b))

from table

SH(401)

148 cm
145 cm

get J =

As=Mu*1.5/(Fy*j*d)

J<0.826

0.805

1.85 m
get C1 = 4.03
0.826
0.805

40.74

Asmin=0.15*b*d
Asmin=11*b*d/Fy
Asmin=1.33*Asreq

11.53
23.48

11.53

54.19

23.48

Asmin=

23.48

40.74 cm2

TAKE As/(B)=

Bottom Rft. :

T.no

37

12

total no/(B.W)
145 cm
36.04

/M

DRAWING

5f12/M

8f12/M

5f12/M

10f16/M
80f12/145

145cm

5f12/M

5f16/M
145cm

37f12/145

* Design of Combined footings


* Project :

INPUT
40 cm
Fcu
Fy

=
=

qall
=
t (R.C) =

60

cm

250
3600

kg/cm

1.5
60

kg/cm2

40

60

cm

cm

cm

kg/cm2

100 t

2.5

200 t

P.C

(C.G) OF "R"

OUT PUT
R=P1+P2

300.00

L=2*A+a+2*C=
Lmin=

373.33
385.00

cm
cm

Resultant of 2 loads is at:

1.67 m

GET

A=

1.67

qall=R/(L*B)

GET

B=

512.82

from center of small load col

Dims. of P.C :

B (cm)

L (cm)

t (cm)

minimum

515

390

25

0
515

0
390

INPUT

chosen
DIM design

qn(Stress on Soil)=Rt/(L*B)=

14.94

Dims. of R.C :

R.C

R*A=P2*S

INPUT

chosen
DIM design

INPUT LOGIC.DIM WERE B<L

t/m2
B (cm)

L (cm)

t (cm)

465

365

60

0
465

0
365

(CHECK SHEAR & MOMENT )

fn(Stress on R.C)=Rt/(L*B)=

17.68

t/m2

Q0=fn*x0*B=

53.42

Q1=P1-fn*x1*B=

97.26

Q2=P2-fn*x2*B=

67.12

Qmax=

97.26

(Qmax-fn*B*d)/(0.87*B*d)

23.40

t/m2

q(sh)=

23.40

t/m2

q(allw) =

63.26

t/m2

100 t

17.68

t/m2

67.12 t

from eq:
fn*B*X-P2=0.0
X (at Zero Shear)=
1.22

97.26 t

SAFE SHEAR

get

200

53.42 t
125 cm
65 cm

40 cm
m
40.83 m.t

from eq:

fn*B*X /2-P2*(X-b/2)

M(0) (POSITSVE MOM.)=


M(max) (at Zero Shear)=

17.36
40.83

t.m
t.m

d = C1 (Mu/(Fcu*b))

get C1 =

7.58

17.36 m.t

1.22 m

(CHECK PUNNCHING )

SAFE MOMENT

dp1=(p1-Ac*fn/10)/(*qallp)=

0.41

m
p1= 100

2.78 FALSE
were

2.4
Ac=
0.7

dp2=(p2-Ac*fn/10)/(*qallp)=

0.40

m
p2= 200

Ac=

SAFE PUNCHING UNDER P1


SAFE PUNCHING UNDER P2

4.8
1.44

qallp=
fn=

9
17.68

kg/cm2
t/m2

qallp=
fn=

9
17.68

kg/cm2
t/m2

(A)

Top Rft. :

M(max) (working)=

from table

SH(401)

40.83

t.m

d = C1 (Mu/(Fcu*b))

get J =

As=Mu*1.5/(Fy*j*d)

0.826

76.73
50.73

( Longitudinal direction )

Asmin=11*b*d/Fy
Asmin=1.33*Asreq

( DESIGN)

37.67

Asmin=0.15*b*d

37.67

Asmin=11*b*d/Fy
Asmin=1.33*Asreq

76.73

37.67
Asmin=

50.73

50.73

50.73 cm2

TAKE As/(B)=

Top Rft. :

no.

16

total no/(B)

/m

29

5.43

Bottom Rft. :

M(POSITIVE) (working)=

from table

0.826
0.853

38.14

Asmin=0.15*b*d

(B)

J<0.826

get C1 = 7.58

SH(401)

17.36

t.m

d = C1 (Mu/(Fcu*b))

get J =

As=Mu*1.5/(Fy*j*d)

0.826

J<0.826

get C1 = 11.62
0.826
0.863

16.2
37.67
Asmin=

21.57

37.67

21.57

37.67 cm2

TAKE As/(B)=

Bottom Rft. :

no.

16

total no/(B)

/m

4.03

(A)

Top Rft. :
Top Rft. :

(B)

no.

12

total no/(B)

/m

20

Bottom Rft. :
1-INTERIOR COLUMN

M (working)=WL2/2 =

88.19
were

BEAM WIDTH = (a+2d)=


TAKE (B.W)=

t.m
W=P/B= 43.01 t/m

&

L=

d = C1 (Mu/(Fcu*b))

from table

SH(401)

get J =

( DESIGN)

( Transverse direction)

As=Mu*1.5/(Fy*j*d)

get C1 = 2.96

J<0.826

0.739

0.826
0.739

13.12
5.22

13.12

124.72

5.22

Asmin=

Bottom Rft. :

T.no

83

12

2-EXTIRIOR COLUMN

48.56
were

total no/(B.W)

165

cm

BEAM WIDTH = (a+d)=


TAKE (B.W)=

W=P/B= 21.51 t/m

get J =

As=Mu*1.5/(Fy*j*d)

82.96

94 cm
90 cm

t.m
&

L=

d = C1 (Mu/(Fcu*b))

SH(401)

13.12

93.78 cm2

TAKE As/(B)=

from table

2.025 m

93.8

Asmin=0.15*b*d
Asmin=11*b*d/Fy
Asmin=1.33*Asreq

M (working)=WL2/2 =

168 cm
165 cm

J<0.826

0.738

2.125 m
get C1 = 2.95
0.826
0.738

51.7

Asmin=0.15*b*d
Asmin=11*b*d/Fy
Asmin=1.33*Asreq

7.16
14.58

7.16

68.81

14.58

Asmin=

14.58

51.74 cm2

TAKE As/(B)=

Bottom Rft. :

T.no

46

12

total no/(B.W)
90
cm

45.77

DRAWING

/M
5f12/M

6f16/M

5f16/M
46f12/90

90cm

165cm
5f12/M

83f12/165

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