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Exp # 11

This document describes an experiment to determine the acid value of an oil sample. The experiment involves titrating a sample of oil dissolved in neutralized alcohol with N/10 NaOH solution using phenolphthalein as an indicator. The volume of base added is recorded and used to calculate the acid value of the oil sample based on the reaction of fatty acids with the base. The acid value provides a measure of how acidic the oil is.

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0% found this document useful (0 votes)
67 views2 pages

Exp # 11

This document describes an experiment to determine the acid value of an oil sample. The experiment involves titrating a sample of oil dissolved in neutralized alcohol with N/10 NaOH solution using phenolphthalein as an indicator. The volume of base added is recorded and used to calculate the acid value of the oil sample based on the reaction of fatty acids with the base. The acid value provides a measure of how acidic the oil is.

Uploaded by

Aasia Farrukh
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Chemical Process Industries (lab)

Department of Chemical Engineering Course No. Ch.E-201


Wah Engineering College wahcantt.

EXPERIMENT# 11

Experiment Title: Oil analysis

Objectives: To determine acid value in the given sample of oil.

Apparatus required: Oil sample, titration flask, burette, pipette, beaker, weighing balance.

Chemicals required: N/10 NaOH, 1% alcoholic solution of phenolphthalein, neutralized alcohol.


Procedure:

Take 4-5 grams of given sample of oil in a titration flask. Add 50 ml of neutralized
alcohol in the titration flask , thoroughly mix it. Heat the contents of titration flask on water bath to boiling
temperature followed by the addition of 1% alcoholic solution of phenolphthalein. Titrate it against N/10
NaOH till pink colour which persist for about 10 seconds arises. . The boiling should be carried out very
slowly on oxidizing flame and titration is carried out at boiling point. The volume of N/10 NaOH is
noted down and take three readings.

Observations and Calculations:


1. Weight of oil sample taken = 4.1 g
2. Volume of neutralized alcohol added = 50 mlIndicator = erichrome Black-T
3. Standard solution = N/10 NaOH
4. Indicator used = phenolphthalein
5. Initial colour = colourless
6. End point colour of the solution = pink (which persist only for about 10 seconds)
7. Solution taken in the burette = N/10 NaOH

Reactions:
RCOOH + NaOH → RCOONa + H2O

[Type text] Page 1


Chemical Process Industries (lab)
Department of Chemical Engineering Course No. Ch.E-201
Wah Engineering College wahcantt.

Sr.No. Initial Burette Reading Final Burette Reading Volume of N/10 NaOH used
(ml) (ml) (ml)

Mean Reading = ________

Volume of N/10 NaOH solution used = (x) ________________________ml

x ml of N/10 NaOH solution = x ml of N/10 KOH solution

1000 ml of 1 N KOH = 56 g = 56000mg

x ml of 1/10 N KOH = (56*1000/10*1000) * (x) * mg of KOH = y mg of KOH

Acid Value = y/weight of oil sample taken =

[Type text] Page 2

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