Statistical Tests For Pairwise Comparisons of Signal-to-Noise Ratios: The Nominal The Best Case
Statistical Tests For Pairwise Comparisons of Signal-to-Noise Ratios: The Nominal The Best Case
Abstract— We propose statistical tests for pairwise comparisons of            the asymptotic distribution of the estimate of the signal-to-
signal-to-noise ratios when the response variable is “the nominal the         noise ratio. Statistical tests for pairwise comparisons of signal-
best” case. A Monte Carlo study and an illustrative example on real           to-noise ratios are presented. A Monte Carlo study and an
data are provided.                                                            illustrative example on real data are provided.
Keywords— Asymptotic distribution, multivariate delta theorem,                  II.    SIGNAL-TO-NOISE RATIO FOR THE NOMINAL THE BEST
pairwise comparisons, signal-to-noise ratio, statistical test..                                         CASE
                         I.   INTRODUCTION                                        Let y1 , y2 ,…, yn be a realization of iid random variables
Robust parameter design is one of the most creative and                       Y1 , Y2 ,…, Yn        normally distributed           with    mean     µ    and
effective tools in quality engineering. This tool works by
identifying factor settings to reduce the variation in products               variance σ . In many cases, it is of interest to achieve a target
                                                                                            2
or processes. Robust parameter design had been practised in                   value for the response, say y = T , while the variation is
Japan for many years before it was introduced to the United                   minimum [7]. Deviations in either direction are undesirable. In
States of America by its originator Genichi Taguchi in the                    this case, Taguchi recommends the following signal-to-noise
mid-1980’s [1].                                                               ratio:
    One of the central ideas in the Taguchi approach to                                              µ2 
parameter design is the use of the performance criterion that                  SNRT = 10 log 10  2  .                                     (1)
                                                                                                    σ 
he called Signal-to-noise ratio (SNR) for variation reduction
                                                                              Its estimate is obtained as
and parameter optimization. The signal-to-noise ratio is a
performance measure that combines the mean response and                                               y2 
variance [2]. The extend to which maximization of such
                                                                                SNR T = 10 log10  2  ,
                                                                                                     s 
                                                                                                                                           (2)
                                                                                                          
criterion can be linked with minimization of quadratic loss
                                                                                                 1 n
was considered in [3].                                                        where        y = ∑ yi              is the sample    mean     and
    The signal-to-noise ratio that is used depends on the goal                                   n i =1
                                                                                                (           )
of the experiment. Different goals of the designed experiment                          1 n               2
are as follows:                                                                s2 =       ∑
                                                                                     n − 1 i =1
                                                                                                 yi − y is the sample variance.
1. The nominal the best: The experimenter wishes for the
                                                                                  Note          that         (2)    can   be    written      as
                                                                                                     ( ) − 10 log
    response to attain a specific target value.
                                                                                                                         ( s ).
                                                                                                        2
2. The smaller the better: The experimenter is interested in                  SNR T = 10 log10 y                    10
                                                                                                                           2
                                                                                                                                  Kacker [8] pointed out
    minimizing the response.
                                                                              that in cases where the response variance and mean are
3. The larger the better: The experimenter is interested in
                                                                              independent, one or more factors (tuning or adjustment
    maximizing the response.
                                                                              factors) can be used in order to eliminate the response bias,
    The signal-to-noise ratio has generated many controversies
as seen by the discussions on Box’s paper [4] and the panel                   that is, the adjustments result in E ( y ) = T . If one assumes an
                                                                                                                                          E ( y − T ) reduces
                                                                                                                                                   2
discussions edited by Nair [5]. Different studies have proposed               additional model, the loss function
statistical improvements to the signal-to-noise ratio, for
example [6].                                                                  to Var ( y ) . As a result, the estimate of the signal-to-noise ratio
    Multiple comparisons of treatments is one of the most                     reduces to SNR T = −10 log10 ( s 2 ) . If the mean y is set at a
important topics in designed experiments. In the literature, the
concept of multiple comparisons of treatments based on                        target value, then maximizing SNRT is equivalent to
signal-to-noise ratios is not studied. The objective of this                  minimizing log10 ( s 2 ) [2]. When the variation in the
paper is to propose statistical tests based on signal-to-noise
ratios for pairwise comparisons of treatments when the                        log10 ( s 2 ) component is larger than the variation in the
                                                                                      ( ) component, SNR
response variable is the nominal the best case. We initially                            2
define the signal-to-noise ratio for the nominal the best case.               log10 y                           T        is dominated by the variation in
In addition, for performing statistical inference, we determine
148
  A. Bizimana, J. D. Domínguez, and H. Vaquera, “Statistical tests for pairwise comparisons of signal-to-noise ratios: The nominal the best
  case,” International Research Journal of Advanced Engineering and Science, Volume 2, Issue 1, pp. 148-152, 2017.
                       International Research Journal of Advanced Engineering and Science
                                                                                                                                       ISSN (Online): 2455-9024
149
  A. Bizimana, J. D. Domínguez, and H. Vaquera, “Statistical tests for pairwise comparisons of signal-to-noise ratios: The nominal the best
  case,” International Research Journal of Advanced Engineering and Science, Volume 2, Issue 1, pp. 148-152, 2017.
                                    International Research Journal of Advanced Engineering and Science
                                                                                                                                                                                                                                                                 ISSN (Online): 2455-9024
Sample 2: y2 = y21 , y22 ,… , y2 n2 .                                                                                                                                  The statistical test in case µ1 , µ2 , σ 1 and σ 2 are known is given
Let SNRT1 and SNRT2 represent the corresponding signal-to-                                                                                                             by
noise ratios. The corresponding estimates of signal-to-noise
                                                                                                                                                                       z=
                                                                                                                                                                              ( SNR         T1                       ) (
                                                                                                                                                                                                     − SNR T2 − SNRT1 − SNRT2                                )
                                                                                                                                                                                                                                                                     ,                    (18 )
ratios are SNRT1 and SNRT2 respectively. It is desired to test                                                                                                                                              σ SNR     T1   − SNR T2
the hypothesis
H 0 : SNRT1 = SNRT2 against H 1 : SNRT1 ≠ SNRT2 ,                                                                                                      (14 )           and the statistical test when µ1 , µ2 , σ 1 and σ 2 are unknown is
or equivalently,                                                                                                                                                            ( SNR       T1                           ) (
                                                                                                                                                                                                 − SNR T2 − SNRT1 − SNRT2                                    )
                                                                                                                                                                                                                                                                                              (19 )
H 0 : SNRT1 − SNRT2 = 0 against H 1 : SNRT1 − SNRT2 ≠ 0 . (1 5 )                                                                                                       t=                                                                                        .
                                                                                                                                                                                                        σ SNR         T1   − SNR T2
Result 2. Mean and standard deviation of SNRT1 − SNRT2                                                                                                                 Under H 0 , SNRT1 − SNRT2 = 0 , and the statistics in (18) and
Let y1 = y11 , y12 ,… , y1n and y 2 = y 21 , y 22 ,… , y 2 n
                                                  1
                                                             be                                                                       2
                                                                                                                                                           two         (19) reduce to the following expressions.
independent samples of sizes n1 and n2 , respectively, drawn                                                                                                           The statistical test in case µ1 , µ2 , σ 1 and σ 2 are known is given
from two independent normal populations with mean µ i and                                                                                                              by
variance σ i2 , i = 1, 2. Under H0, the mean and standard                                                                                                                   SNR T1 − SNR T2
                                                                                                                                                                        z=
deviation of SNRT − SNRT                                                      are asymptotically zero and                                                                     σ SNRT − SNRT
                                          1                      2                                                                                                                               1      2
 10  4σ 1        4σ 22                                                                                                                                                     10   y1   10   y 2 
             2                                                                                                                                                                            2                 2
               2         2
        2 2 + 2 + 2 2 + 2,                                      respectively [10].
 ln10  n1 µ1 n1 n2 µ 2 n2                                                                                                                                                        ln 2 −          ln 2
                                                                                                                                                                             ln10   s1   ln10   s2 
                                                                                                                                                                          =
                                                                                                                                                                             10  4σ 1             4σ 22
                                                                                                                                                                                          2
Proof                                                                                                                                                                                          2            2
                                                                                                                                                                                           +    +       + 2
                                                                                                                                                                             ln10  n1 µ1 n1 n2 µ 2 n2
                                                                                                                                                                                       2 2      2    2 2
In fact,
                                             10   µ1   10   µ 2 
                                                           2                  2
µ SNR                   = µ SNRT − µ SNRT =          ln  2  −       ln  2                                                                                                           y2        y2 
                                                                                                                                                                                    ln  12  − ln  22 
        T1   − SNRT2            1        2
                                             ln 10   σ 1   ln 10   σ 2                                                                                                            s1       s 
                                                                                                                                                                                                    2 
                                           = SNRT1 − SNRT2 = 0.             (16 )                                                                                         =                                   .                                                                          ( 20 )
                                                                                                                                                                                   4σ 12      2     4σ 22   2
                                                                                                                                                                                           +     +        +
                                                                                                                                                                                   n12 µ12 n12 n22 µ 22 n22
    The standard deviation of the difference of SNRT and                                                                                               1
                                                                                                                                                                       The statistical test in case µ1 , µ2 , σ 1 and σ 2 are unknown is
SNRT2 , say              σ SNR     T1 − SNRT2
                                                  , is determined as follows:
                                                                                                                                                                       given by
  σ SNR                          = σ SNR   + σ SNR                                                                                                                                            10   y1   10   y 2 
                                     2         2                                                                                                                                                           2                   2
              T1   − SNRT2               T    1    T                     2
                                                                                                                                                                                                    ln        −       ln
                                                                                                                                                                                              ln10   s1   ln10   s2 
                                                                                                                                                                                                          2                    2
                                                                                                                                                                           SNR T − SNR T
                                    10   4σ                                          10   4σ                                                
                                                  2                                                           2
                                                                                                                                                                       t=                  =
                                                                 2                                                            2
                                                                                 2                                                            2                                         1                    2
                             =                                        +            +                                               +
                                                                 1                                                            2
                                                                                                                                                                           σ SNR − SNR       10  4 s1
                                                                                                                                                                                                           2
                                                                                                                                                                                                                       4 s22
                                    ln 10   n µ         2         2            2
                                                                                 n1     ln 10   n µ
                                                                                                                          2       2            2
                                                                                                                                              n2                                           T1         T2          2
                                                                                                                                                                                                               + 2 +         +
                                                                                                                                                                                                                               2
                                                           1     1                                                        2   2
                                                                                                                                                                                                           2
                                                                                                                                                                                              ln10  n 2 y       n1 n 2 y 2 n22
                                  10                4σ 1                            4σ 2
                                                           2                                2
                                                                                                                                                       (17 )
                                                                         2                               2                                                                                                                                       1   1                   2   2
                             =                                 +               +               +                •
                                  ln 10             n1 µ1
                                                       2     2
                                                                         n1
                                                                             2
                                                                                      n2 µ 2
                                                                                       2     2            2
                                                                                                         n2                                                                                                                        y   2
                                                                                                                                                                                                                                              y                2
                                                                                                                                                                                                                               ln  21  − ln  22 
                                                                                                                                                                                                                                    s1       s2 
                                                                                                                                                                                                                                                
Result 3. Statistical tests for comparing SNRT and SNRT                                                           1                                2                                                             =
                                                                                                                                                                                                                                 2              2
                                                                                                                                                                                                                                                                             •                ( 21)
The statistical test for comparing SNRT and SNRT in the case                                                                                                                                                                 4 s1       2    4 s2    2
                                                                                                     1                                2                                                                                              + 2 +         + 2
                                                                                                                                                                                                                              2 2      n      2 2    n
                                                                                                  y2        y2                                                                                                          n y
                                                                                                                                                                                                                             1       1  1   n y        2 2       2
                                                                                              ln  21  − ln  22 
                                                                                                  s1        s2 
µ1 , µ 2 , σ 1 and σ 2 are known is                                                                               , and                                                                                                      a                                                 a
150
  A. Bizimana, J. D. Domínguez, and H. Vaquera, “Statistical tests for pairwise comparisons of signal-to-noise ratios: The nominal the best
  case,” International Research Journal of Advanced Engineering and Science, Volume 2, Issue 1, pp. 148-152, 2017.
                   International Research Journal of Advanced Engineering and Science
                                                                                                                                         ISSN (Online): 2455-9024
    V.     MONTE CARLO STUDY OF THE PROPERTIES OF THE                                    ∆ = 0.001, 0.01, 0.1, 1. The increment ∆ = 0 implies equal
                    PROPOSED TESTS                                                       parameters.
    Monte Carlo simulations are performed to evaluate the
                                                                                         B. Results
performance of the proposed statistical tests in terms of test
sizes and powers. Sample means and sample variances are                                      Table I shows the estimated sizes of the test statistic. The
used to determine the estimates of signal-to-noise ratios.                               population parameters used are µ X = µY = 35 and σ X = σ Y = 2.
Simulation under H 0 , this is, simulation with equal population                         The row entries represent the proportion of times H 0 was
parameters ( µ X = µY and σ X = σ Y ) permits estimating the                             rejected at α = 0.05 under H 0 , this is, the proportion of
test size. Under H1 , simulations are conducted after applying                           times H 0 is wrongly rejected. The test size is very close to the
an increment ∆ to the population parameters. Simulations with                            significance level. Moreover, it seems that the sample size
different values of population parameters give the estimates of                          does not affect the value of the test size.
power tests.
                                                                                           TABLE I. Estimated Type I error rates of t test for various sample sizes.
A. Procedure for Monte Carlo simulation                                                                      Sample size       Type I error
The simulation process has been conducted according to the                                                       10                 0.0499
following procedure:                                                                                             20                 0.0500
                                                                                                                 30                 0.0498
1. From two independent normal populations, X and Y ,                                                            60                 0.0496
   such that X ∼ N ( µ X , σ X2 ) and Y ∼ N ( µY , σ Y2 ) , simulate
                                                                                            Table II contains the estimated powers obtained in
   two independent samples of sizes n X = nY = 10.
                                                                                         changing the population means and population variances
2. Calculate the sample means and sample variances;                                      simultaneously. In this case, the population parameters used in
    X , Y , s X2 and sY2 .                                                               simulations are: µY = µ X + ∆ µ and σ Y = σ X + ∆σ . The row
3. Calculate the estimates of the signal-to-noise ratios; SNR X                          entries represent the proportion of times H 0 is rejected at
   and SNR Y .                                                                           α = 0.05 under H1 , this is, the proportion of times H 0 is
4. Based on asymptotic normality of the estimates of the                                 correctly rejected.
   signal-to-noise ratios, simulate MC = 10000 replicates of
                   (                             )                                        TABLE II. Estimated powers of t test for various sample sizes and various
             a
    SNR X ∼ N µ SNR X , σ µ2                                                 and            increments, changing the population means and population variances
                                        SNR X
                                                                                                                      simultaneously.
                 N (µ                           ). Four configurations of sample
            a
    SNRY ∼              SNRY
                               , σ µ2                                                         Sample       ∆ µ = 0.001      ∆ µ = 0.01     ∆ µ = 0.1     ∆µ = 1
                                    SNRY
    sizes are used: n = 10, 20, 30, 60.                                                         size       ∆σ = 0.001       ∆σ = 0.01       ∆σ = 0.1     ∆σ = 1
                                                                                                 10          0.0503          0.0799         0.9990          1
5. For each replicate, conduct a t test for the null hypothesis                                  20          0.0589          0.8642            1            1
     H 0 : SNR X − SNRY = 0, and count the number of rejections                                  30          0.1365             1              1            1
    (# Rejections).                                                                              60          0.9981            1               1            1
                                     # Rejections
6. Determine the rejection rate:                  .                                          Table III contains the estimated powers, obtained in
                                          MC                                             changing the population means and maintaining population
    The parameters used in Step 1 are determined by applying                             variances        at       constant         values.     In      this
an increment ∆ according to the following scheme:                                        case, µY = µ X + ∆ µ and σ Y = σ X . The row entries represent the
1. Simultaneous change of population means and population
    variances. The population parameters are determined as                               proportion of times H 0 is rejected at α = 0.05 under H 1 .
    follows:
                                                                                         TABLE III. Estimated powers of t test for various sample sizes and various
µY = µ X + ∆ µ     and σ Y = σ X + ∆σ ; where ∆ µ and ∆σ are
                                                                                         increments, obtained in changing the population means and maintaining the
   increments in population mean and population variance,                                                  population variances at constant values.
   respectively.                                                                             Sample size     ∆ µ = 0.001     ∆ µ = 0.01     ∆ µ = 0.1   ∆µ = 1
2. Changing the population means and maintaining the                                             10            0.0499          0.0504        0.0622        1
   population variances at constant values. In this scheme, the                                  20            0.0497          0.0549        0.4549        1
   population parameters are determined as follows:                                              30            0.0503          0.0800         0.9996       1
                                                                                                 60            0.0596         0.08449            1         1
    µY = µ X + ∆ µ and σ Y = σ X .
3. Changing the population variances and maintaining the                                    Table IV contains the estimated powers, obtained in
   population means at constant values. In this case, the                                changing the population variances and maintaining population
   population parameters are determined as follows:                                      means         at    a        constant     value.      In     this
   µY = µ X and σ Y = σ X + ∆σ .                                                         case, µY = µ X and σ Y = σ X + ∆σ . The row entries represent the
Four configurations of increments are used:                                              proportion of times H 0 was rejected at α = 0.05 under H 1 .
151
 A. Bizimana, J. D. Domínguez, and H. Vaquera, “Statistical tests for pairwise comparisons of signal-to-noise ratios: The nominal the best
 case,” International Research Journal of Advanced Engineering and Science, Volume 2, Issue 1, pp. 148-152, 2017.
                       International Research Journal of Advanced Engineering and Science
                                                                                                                                                        ISSN (Online): 2455-9024
152
   A. Bizimana, J. D. Domínguez, and H. Vaquera, “Statistical tests for pairwise comparisons of signal-to-noise ratios: The nominal the best
   case,” International Research Journal of Advanced Engineering and Science, Volume 2, Issue 1, pp. 148-152, 2017.