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Swing Angle Calculation

1) This document contains calculations for the swing angle of jumper insulators on a 400 Kv transmission line tower type 4D25 under peak wind conditions and light industrial wind conditions. 2) Key inputs include the conductor and insulator properties, wind speeds, and formulas to calculate the wind pressure and insulator swing angles. 3) The results show the insulator swing angle would be 32.6 degrees under peak wind conditions and 13.54 degrees under light industrial wind conditions.

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Rajas Alshi
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1K views4 pages

Swing Angle Calculation

1) This document contains calculations for the swing angle of jumper insulators on a 400 Kv transmission line tower type 4D25 under peak wind conditions and light industrial wind conditions. 2) Key inputs include the conductor and insulator properties, wind speeds, and formulas to calculate the wind pressure and insulator swing angles. 3) The results show the insulator swing angle would be 32.6 degrees under peak wind conditions and 13.54 degrees under light industrial wind conditions.

Uploaded by

Rajas Alshi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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400 Kv Megnaghat and Madunaghat Transmission Line

Jumper Insulator
Swing Angle Calculation Tower Type "4D25"

DESIGN INPUT
S.NO DSECRIPTION UNIT VALUE
1 CONDUCTOR DIAMETER(D) M 0.03015
2 NO OF CONDUCTOR(N) 4
3 JUMPER DEPTH(H) M 3.5
4 WIND SPAN(S) M 12
5 WEIGHT SPAN(aw) M 14.7
UNIT WEIGHT OF CONDUCTOR WITHOUT SPACER KG/M 2.02
DAMPER(WUC)
6
UNIT WEIGHT OF BUNDLE WITHOUT SPACER KG/M 8.08
DAMPER(WUC')
7
8 WEIGHT OF ONE SPACER (WS) KG 50
9 UNIT WEIGHT OF SPACER (WUS) KG/M 3.40
10 NO OF SPACERS N' 4
11 WEIGHT OF CONDUCTOR WC KG 132.54
12 FL FOR 3 SECOND GUST M/S 80

PFC VELOCITY (50% FL) (V1) M/S 27.972028


13
14 LIC Velocity(15.6 M/S) M/S 15.6
14 Air Density (ℓ/2) Kg/M 3
0.613
15 Drag Factor(Cc) 1
16 Span Factor(GL) 1
17 PFC WIND PRESSURE(P1) N/M2 479.632256
18 LIC WIND PRESSURE(P2) N/M2 149.17968
19 WIND ON JUMPER INSULATOR(PFC)QWINS N 0
20 WIND ON JUMPER INSULATOR(LIC)QWINS N 0
21 WEIGHT OF INSULATOR SET WINS KG 0
Swing angle Calculation For Jumper Insulator As per above Formula
22 INSULATOR SWING IN PFC(φ1) DEG 28.1036711
23 INSULATOR SWING IN LIC(φ2) DEG 9.43071725

23 σφ1 2.24910815
24 σφ2 2.05316807
25 TOTAL INSULATOR SWING ANGLE FOR PFC(Ø1) 32.6
26 TOTAL INSULATOR SWING ANGLE FOR LIC(Ø1) 13.54
CALCULATION

LC=(awX(1+8/3X(H/aw)^2))

WUC'=WUCXN

WUS=(WS/LC)

WC=((N'XWUS)+(WUC'XLC))
Refer Annex 9-1 tech specification

1.43 factor taken from Annex D ASCE 74

Refer Cl 8.2.4 tech specification

P1=V1^2X((ℓ/2)XCcXGL)
P2=V2^2X((ℓ/2)XCcXGL)
NO JUMPER INSULATOR PROVIDED
NO JUMPER INSULATOR PROVIDED
NO JUMPER INSULATOR PROVIDED
ulator As per above Formula
EQUATION 2.6.3
EQUATION 2.6.3

EQUATION 2.6.5
EQUATION 2.6.5
(Ø1)=(φ1)+2Xσφ1
(Ø2)=(φ2)+2Xσφ2

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