MTug Reveena
MTug Reveena
Introduction
The name Tug Boats gives a fair idea about the size and task of the vessel being
discussed. These are relatively smaller but very powerful for their size. These are primarily
used to tug or pull vessels that cannot move by themselves like disabled ships, oil
platforms and barges or those that should not move like a big or loaded ship in a narrow
canal or a crowded harbor. In addition to these, tug boats are also used as ice breakers
or salvage boats and as they are built with firefighting guns and monitors, they assist in
the firefighting duties especially at harbors and when required even at sea.
Tugboats are mainly divided according to their application and utility. The three
main categories in which the tugboats can be divided are: Seagoing Tugs, Escort Tugs
Seagoing tugs have a wide range of applications as they are not constrained by
any port duties. Seagoing tugs perform the following tasks: (1) Seagoing tugs are
manufactured to stay away at the sea for a longer duration of time and yet retain power to
pull a vessel that is much larger in size than its own. (2) Used by environmentalist and
researchers for surveying a particular area, and for pulling offshore drilling platforms and
also for handling anchors in the offshore industry. (3) Used extensively in pulling structures
that needs to be relocated. For e.g. Partly completed ships that has to be shifted from one
port to another, pulling and erecting drilling rigs, moving ship wrecks away from the
waterways etc. and, (4) Used for averting a major disaster in case a ship has developed a
crack in the cargo hold or an accidental leakage. These tugboats are never used for
transporting purposes.
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Escort Tugs, this type of tugboats are used to escort huge vessels along narrow
or dangerous passages. This facilities are provided only to massive ships whose own
propulsion system is not capable of doing maneuverability in dangerous. This facility has
been introduces as a result of series of accidents in the past that had lead adverse effects
on both marine and human life. Escort tugs are small and sturdy vessels that generally
operate in the confined water. They have high maneuverability power and often
Harbor Tugs are multiple-utility boats that are used in ports and inland water
ways for assisting and towing vessels in and out of the ports. They are also used for
pulling barges used for carrying goods in inland water ways or along the ports. Harbor tugs
assist seagoing tugs when the later are pulling a very heavy object. The harbor tugs have
the highest maneuverability as they have to pull and tow huge ships within small area.
Apart from that, harbor tugs are used in firefighting and keeping ports free from ice in
winter season. They have a capacity to generate a towing force at zero velocity. They are
also equipped with firefighting arrangements and equipment for fighting marine pollution.
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History
Tugboat, small, powerful watercraft designed to perform a variety of functions,
especially to tow or push barges and large ships. In 1736 Jonathan Hulls of
move large vessels in and out of harbours. The first tugboat actually built was
the Charlotte Dundas, powered by a Watt engine and paddle wheel and used on the Forth
and Clyde Canal in Scotland. Screw propulsion for tugboats was introduced in the United
States about 1850, the diesel engine about 50 years later. Tugs are still indispensable in
berthing large ships. Oceangoing tugs are used for salvage missions.
Mission
To assists the merchant vessel in entering the port of Davao and to accompany
the dredger from port of Davao to port of Zamboanga vice versa. It has a fire fighting to
used in assisting large vessel. The tug is required to have 70 tons bollard pull and have
good maneuverability. Also, this tug must maximize its usefulness and earning power.
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ASIAN INSTITUTE OF MARITIME STUDIES
OWNER’S REQUIREMENTS
OWNER'S REQUIREMENT
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 1
PARENTSHIP
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CHAPTER 1 : PARENTSHIP
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CHAPTER 2
DETERMINATION
OF PARTICULARS
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CUBEROOT METHOD
•BLOCK COEFFICIENT
Reference: Elements of Ship Design by R. Munro - Smith, p 14
Cb=
where:
Δ- Displacement of the ship
L- Length (LBP)
B- Breadth molded
838 d- draft
1398.10 ρ- density, 1.025 tonnes/m 3
Cb= 0.599
•DEADWEIGHT COEFFICIENT
Reference: Elements of Ship Design by R. Munro - Smith, p 14
Cd= DEADWEIGHT
DISPLACEMENT
320 tonnes
838 tonnes
Cd= 0.382
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•CUBEROOT METHOD
Reference: Ship Design and Performance for Masters and Mates by Dr C.B. Barras, p. 5
From the information on ships already built and in service, the Naval archihtect
can decide upon the relations of L/B and B/d for the new ship. Knowing these
values he can have a good first attempt at the Main Dimensions for the new
vessel. He can used the following formula:
(DEADWEIGHT)(L/B)²(B/D)
LBP= ( (ρ)(Cb) (Cd) )
where: L: Length (LBP)
L/B: Length -Breadth Ratio
B/d: Breadth-draft Ratio
ρ: Density of seawater (1.025 tonnes/m3)
Cb: Block Coefficient
Cd: Deadweight Coefficient
2
320 x 2.77 x 2.85
( 0.599 x 1.025 x 0.382 )
6997.6848
( 0.2346 )
LBP= 31 meters
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31.01 / 2.77
B= 11.195 , 11 meters
• DEPTH MOULDED
L/D= 6.25
where:
D= L / 6.25 L= LBP, 31.01
31.01 / 6.25
D= 4.9616 , 5 meters
• DRAFT
L/d= 7.92
where:
D= L / 7.92 L= LBP, 31.01
31.01 / 7.92
D= 3.9154 , 4 meters
Note: Derived from the design ratios of the averaged particulars of the vessel to be designed.
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To check the gathered particulars, I will use the proportions of tugboats from Table 1 of
Modern Tug Design:
• BREADTH MOULDED
L/B= 2.7 to 3.7
= L / B
= 31.00 / 11.195
L/B = 2.8
• DEPTH MOULDED
B/d = 2.3 to 3.6
where:
= B / d L= LBP, 0.00
= 11.195 / 4.96
B/d = 2.3
• DRAFT
L/D = 5 to 30
where:
= L / D L= LBP, 0.00
31.00 / 3.915
D= 8
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SPEED COMPUTATION
• SERVICE SPEED (Vs)
Vs where:
= 0.60 TO 0.70
√L 0.60 to 0.70 adopt to 0.65
L - LBP in feet 101.744
Vs
= 0.65
√101.74
Vs = 0.65 x 10.0868
= 6.55643
Vs = 7 Knots
Vk = 1.2 x 10.0868
= 12.1042
Vk = 12 Knots
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Vk
Cb = 1.08 -
2 √L
= 1.08 - 0.595
Cb = 0.49
• VOLUME OF DISPLACEMENT (s )
s= 668.36 m 3
• DISPLACEMENT (Δ )
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 3
LINES DRAWING
PLAN
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A ship’s hull is three dimensional and, as is usually the case, it is assumed here to
The shape is defined by its intersections with three mutually orthogonal planes.
The intersections with horizontal planes, known as waterplanes whether below or above
water, are known as water lines. Those with the athwartships planes define the transverse
sections of the hull and planes parallel to the middle line plane lead to what are termed
The external hull shape can be defined by the distances of the hull from the
centerline plane at each transverse section and waterplane. In tabular form these are
A set of lines consists essentially of three plans of view namely the elevation or the
profile of vessel, generally known as half breadth plan and the set of transverse section
Known as body plan and Naval architects use different methods for hull construction
The form of a ship’s hull drawn to scale is called the lines drawing. Lines’ drawing
is the first step the ship design and is the foundation on which other ship design parameters
For an instance, the general arrangement plan, the lines drawing will provide the
amount of space that the naval architect can use to determine the arrangements of
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The first step of the lines drawing is to draw a rectangular box with the length of
your vessel. This will be your size of your propose vessel and the existence of the lines
drawing. This body plans show the shape of the vessel from your lines drawing Project
lines from half Breadth plan to body plan then project body plan to Buttock line. The body
plan of ship design is to guide the designers for the desired displacement and Position of
LCB can be derived from the basic form by lifting sections for the new ship Design from
the basis at a revised spacing from the end. To visualize the projection of body plan, we
must imagine the ship’s hull is obtained at each cut when resulting curve or projected to
To visualize the projection knows as body plan, we must imagine the ship’s hull at
transverse in several place. The shape of transverse plane intersection of the full is
obtained at each cut; when the resulting curves are project in to the body plan they show
To visualize the half-breadth plan, we must imagine the ship cut horizontally in
sever; place. The cuts are designated as “waterlines”, although the ship could not possibly
float at many of these lines. The base plane which serves as the point of origin for waterline
is usually horizontal plane that the coincides which the top of the keel.
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CHAPTER 4
SECTIONAL AREA
COMPUTATION
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PARTICULARS:
V ALUE
LENGTH OV ERALL 32.52 METERS
L.B.P. 31 METERS
BREADTH MOULDED 11 METERS
DEPTH MOULDED 5 METERS
DRAFT 4 METERS
DISPLACEMENT 685.0 TONNES
V OL. OF DISPLACEMENT 668.0 TONNES
STATION SPACING 3.1 METERS
WATERLINE SPACING 0.5 METERS
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4 1 0 0 4 1 2.458 2.458
3.5 4 0 0 3.5 4 2.234 8.936
3 2 0 0 3 2 1.689 3.378
2.5 4 0 0 2.5 4 0.972 3.888
2 2 0 0 2 2 0.209 0.418
1.5 4 0 0 1.5 4 0 0
1 2 0 0 1 2 0 0
0.5 4 0 0 0.5 4 0 0
0 1 0 0 0 1 0 0
∑ f(A) 0 ∑ f(A) 19.078
79
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STATION 2 STATION 3
WATERLINE SM ORDINATES f(A) WATERLINE SM ORDINATES f(A)
STATION 4 STATION 5
WATERLINE SM ORDINATES f(A) WATERLINE SM ORDINATES f(A)
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STATION 6 STATION 7
WATERLINE SM ORDINATES f(A) WATERLINE SM ORDINATES f(A)
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STATION AP
WATERLINE SM ORDINATES f(A)
4 1 4.228 4.228
3.5 4 0 0
3 2 0 0
2.5 4 0 0
2 2 0 0
1.5 4 0 0
1 2 0 0
0.5 4 0 0
0 1 0 0
∑ f(A) 4.228
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320.644 x 3.1 x 2 / 3
s= 662.7 m3
662.7 x 1.025
Δ= 679.2 TONNES
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 5
HYDROSTATIC
COMPUTATION
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hydrostatics in ship design and ship performance, taking you from first principles through
modeling and analysis. Real life examples of the practical application of hydrostatics are
Hydrostatics is the branch of fluid mechanics that studies fluids at rest. It embraces the
conditions to which the vessel is subjected to while at rest in water and its ability to remain
afloat. This involves computing buoyancy and other hydrostatic properties, such as trim
and stability.
of vessel in the water. It is very useful as a guide to chief-mate during loading and
Using hydrostatic calculations, you will get the values needed for plotting the
sectional area and bonjean curves. This part will also determine if block coefficient is
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ASIAN INSTITUTE OF MARITIME STUDIES
PARTICULARS:
VALUE
LBP 31 Meters
BREADTH 11 Meters
DEPTH 5 Meters
DRAFT 4 Meters
WATERLINE SPACING 0.5 Meter
STATION SPACING 3.1 Meters
DIVISOR 180
TABLE OF OFFSETS
STATION WL 0 WL 0.5 WL 1 WL 1.5 WL 2 WL 2.5 WL 3 WL 3.5 WL 4
0.5 0.000 0.000 0.000 0.000 0.209 0.972 1.689 2.234 2.458
1.0 0.000 0.000 0.000 0.838 1.576 2.212 2.736 3.087 3.214
1.5 0.000 0.000 0.924 1.812 2.544 3.094 3.439 3.657 3.780
8.5 0.000 0.000 0.000 0.000 0.000 0.551 4.401 4.795 4.959
9.5 0.000 0.000 0.000 0.000 0.000 0.000 0.000 3.358 4.477
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STA SMs W.L. 0.00 W.L. 0.5 W.L. 1 F(A)s F(V)s LA F(LM)
SM 1 SM 4 SM 1 Area
0.000 0.000 0.000
FP 0.50 0.000 0.000 0.000 0.000 0.000 5 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
0.50 2.0 0.000 0.000 0.000 0.000 0.000 4.5 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
1.00 1.0 0.000 0.000 0.000 0.000 0.000 4 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.924
1.50 2.00 0.000 0.000 1.848 0.924 1.848 3.5 6.468 0.308
0.000 0.000 0.924
0.000 0.597 1.662
2 1.50 0.000 0.896 2.493 4.050 6.075 3 18.225 1.350
0.000 2.388 1.662
0.000 1.485 2.814
3 4.00 0.000 5.940 11.256 8.754 35.016 2 70.032 2.918
0.000 5.940 2.814
0.000 2.099 3.562
4 2.0 0.000 4.198 7.124 11.958 23.916 1 23.916 3.986
0.000 8.396 3.562
0.000 2.355 3.919
5 4.0 0.000 9.420 15.676 13.339 53.356 0 0.000 4.446
0.000 9.420 3.919
0.000 1.410 3.302
6 2.0 0.000 2.820 6.604 8.942 17.884 -1 -17.884 2.981
0.000 5.640 3.302
0.000 0.000 0.000
7 4.0 0.000 0.000 0.000 0.000 0.000 -2 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
8 1.5 0.000 0.000 0.000 0.000 0.000 -3 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
8.5 2.0 0.000 0.000 0.000 0.000 0.000 -3.5 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
9 1.0 0.000 0.000 0.000 0.000 0.000 -4 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
9.5 2 0.000 0.000 0.000 0.000 0.000 -4.50 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
AP 0.50 0.000 0.000 0.000 0.000 0.000 -5.00 0.000 0.000
0.000 0.000 0.000
Sum of
F(A)
0.0 23.3 45.001 F(V) 138.095 118.641 FWD
SM 1 4 1 -17.884 AFT
Sum of
TOTAL F (V)
1/2F(VM) 0 46.547 45.001 276.190 624.6934 PROD.
DIVISOR
(3N3)/WL 0 C.FWD
SPA 180
1/2F(VM)x2 183.096 MEAN F(V) 1.534 624.6934 TOTAL F(LM)
C.FWD. 0
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STA SMs W.L. 1.0 W.L. 1.5 W.L. 2 F(A)s F(V)s LA F(LM)
SM 1 SM 4 SM 1 Area
0.000 0.000 0.000
FP 0.50 0.000 0.000 0.000 0.000 0.000 5 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.209
0.50 2.0 0.000 0.000 0.418 0.209 0.418 4.5 1.881 0.070
0.000 0.000 0.209
0.000 0.838 1.576
1.00 1.0 0.000 0.838 1.576 4.928 4.928 4 19.712 1.643
0.000 3.352 1.576
0.924 1.812 2.544
1.50 2.00 1.848 3.624 5.088 10.716 21.432 3.5 75.012 3.880
0.924 7.248 2.544
1.662 2.643 3.308
2 1.50 2.493 3.965 4.962 15.542 23.313 3 69.939 6.531
1.662 10.572 3.308
2.814 3.944 4.291
3 4.00 11.256 15.776 17.164 22.881 91.524 2 183.048 10.545
2.814 15.776 4.291
3.562 4.482 4.796
4 2.0 7.124 8.964 9.592 26.286 52.572 1 52.572 12.748
3.562 17.928 4.796
3.919 4.637 4.940
5 4.0 15.676 18.548 19.760 27.407 109.628 0 0.000 13.582
3.919 18.548 4.940
3.302 4.558 4.864
6 2.0 6.604 9.116 9.728 26.398 52.796 -1 -52.796 11.780
3.302 18.232 4.864
0.000 2.011 4.436
7 4.0 0.000 8.044 17.744 12.480 49.920 -2 -99.840 4.160
0.000 8.044 4.436
0.000 0.000 0.000
8 1.5 0.000 0.000 0.000 0.000 0.000 -3 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
8.5 2.0 0.000 0.000 0.000 0.000 0.000 -3.5 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
9 1.0 0.000 0.000 0.000 0.000 0.000 -4 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
9.5 2 0.000 0.000 0.000 0.000 0.000 -4.50 0.000 0.000
0.000 0.000 0.000
0.000 0.000 0.000
AP 0.50 0.000 0.000 0.000 0.000 0.000 -5.00 0.000 0.000
0.000 0.000 0.000
Sum of
F(A)
45.00 68.87 86.03 F(V) 406.531 402.164 FWD
SM 1 4 1 -152.636 AFT
Sum of
F(V) 45.001 275.5 86.032 F(V) 406.531 249.528 DIFF
LA 1.00 1.5 2 CFwd 276.190 6.2 2xS
TOTAL F
1/2F(VM) 45.001 413.25 172.06 (V) 1089.252 1547.074 PROD.
DIVISOR
(3N3)/WL 624.6934 C.FWD
SPA 180
TOTAL F(LM)
MEAN F(V)
1/2F(VM)x2 1260.624 6.051 2171.767
C.FWD. 183.096
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STA SMs W.L. 3.0 W.L. 3.5 W.L. 4 F(A)s F(V)s LA F(LM)
SM 1 SM 4 SM 1 Area
0.000 0.000 0.000
FP 0.50 0.000 0.000 0.000 0.000 0.000 5 0.000 0.000
0.000 0.000 0.000
1.689 2.234 2.458
0.50 2.0 3.378 4.468 4.916 13.083 26.166 4.5 117.747 6.359
1.689 8.936 2.458
2.736 3.087 3.214
1.00 1.0 2.736 3.087 3.214 18.298 18.298 4 73.192 12.129
2.736 12.348 3.214
3.439 3.657 3.780
1.50 2.00 6.878 7.314 7.560 21.847 43.694 3.5 152.929 17.282
3.439 14.628 3.780
4.061 4.160 4.269
2 1.50 6.092 6.240 6.404 24.970 37.455 3 112.365 22.236
4.061 16.640 4.269
4.796 4.881 4.976
3 4.00 19.184 19.524 19.904 29.296 117.184 2 234.368 29.494
4.796 19.524 4.976
5.178 5.257 5.337
4 2.0 10.356 10.514 10.674 31.543 63.086 1 63.086 33.384
5.178 21.028 5.337
5.287 5.366 5.446
5 4.0 21.148 21.464 21.784 32.197 128.788 0 0.000 34.675
5.287 21.464 5.446
5.239 5.307 5.376
6 2.0 10.478 10.614 10.752 31.843 63.686 -1 -63.686 32.655
5.239 21.228 5.376
5.116 5.192 5.282
7 4.0 20.464 20.768 21.128 31.166 124.664 -2 -249.328 24.222
5.116 20.768 5.282
4.740 4.990 5.120
8 1.5 7.110 7.485 7.680 29.820 44.730 -3 -134.190 15.900
4.740 19.960 5.120
4.401 4.795 4.959
8.5 2.0 8.802 9.590 9.918 28.540 57.080 -3.5 -199.780 11.715
4.401 19.180 4.959
2.206 4.456 4.729
9 1.0 2.206 4.456 4.729 24.759 24.759 -4 -99.036 8.988
2.206 17.824 4.729
0.000 3.358 4.477
9.5 2 0.000 6.716 8.954 17.909 35.818 -4.50 -161.181 5.970
0.000 13.432 4.477
0.000 0.000 4.228
AP 0.50 0.000 0.000 2.114 4.228 2.114 -5.00 -10.570 1.409
0.000 0.000 4.228
Sum of
F(A)
118.832 132.240 139.731 F(V) 787.522 753.687 FWD
SM 1 4 1 -917.771 AFT
Sum of
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0.50 2.0 0.000 0.000 4.5 0.000 4.5 0.000 2.00 0.000 0.000
1.50 2.00 0.924 1.848 3.5 6.468 3.5 22.638 2.00 0.789 1.578
8.5 2.0 0.000 0.000 -3.5 0.000 -3.5 0.000 2.00 0.000 0.000
9.5 2 0.000 0.000 -4.50 0.000 -4.5 0.000 2.00 0.000 0.000
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0.50 2.0 0.209 0.418 4.5 1.881 4.5 8.465 2.00 0.009 0.018
1.50 2.00 2.544 5.088 3.5 17.808 3.5 62.328 2.00 16.465 32.929
8.5 2.0 0.000 0.000 -3.5 0.000 -3.5 0.000 2.00 0.000 0.000
9.5 2 0.000 0.000 -4.50 0.000 -4.5 0.000 2.00 0.000 0.000
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0.50 2.0 1.689 3.378 4.5 15.201 4.5 68.405 2.00 4.818 9.636
1.50 2.00 3.439 6.878 3.5 24.073 3.5 84.256 2.00 40.672 81.344
8.5 2.0 4.401 8.802 -3.5 -30.807 -3.5 107.825 2.00 85.242 170.484
9.5 2 0.000 0.000 -4.50 0.000 -4.5 0.000 2.00 0.000 0.000
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0.50 2.0 2.458 4.916 4.5 22.122 4.5 99.549 2.00 14.851 29.701
1.50 2.00 3.780 7.560 3.5 26.460 3.5 92.610 2.00 54.010 108.020
8.5 2.0 4.959 9.918 -3.5 -34.713 -3.5 121.496 2.00 121.950 243.900
9.5 2 4.477 8.954 -4.50 -40.293 -4.5 181.319 2.00 89.735 179.470
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COMPUTATION SHEET
Up to Waterline 0 - 1
1 LCB = F(LM) / F(V) = 624.69 / 276.19 = 2.26 M
2 VCB = F(VM) / F(V) = 183.10 / 276.19 = 0.66 M
3 VOL. OF DISPLACEMENT = MEAN F(V) x L = 1.53 x 31.00 = 47.57 M3
4 DISPLACEMENT OF S. W. = V x 1.025 = 47.57 x 1.025 = 48.76 tons
5 DISPLACEMENT OF F. W. = V x 1.000 = 47.57 1.000 = 47.57 tons
6 MIDSHIP AREA = 1/3WLS x F(A) x 2 + C.FWD = 0.17 x 13.3390 x 2.00 + 0.00 = 4.45 M2
7 AWP NO. ______
0.5 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 23.27 x 2.00 = 48.10 M2
8 AWP NO. ______
1.00 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 45.00 x 2.00 = 93.00 M2
9 T.P.C. NO. W.L. 0.5 = AWP / 97.5 = 48.10 / 97.50 = 0.49 ton
10 T.P.C. NO. W.L. 1 = AWP / 97.5 = 93.00 / 97.50 = 0.95 ton
11 BLOCK COEFFICIENT = V / (L x B x H) = 47.57 /( 31.00 x 11.00 x 1.00 )= 0.14
12 PRISMATIC COEFFICIENT = V / (L x MIDSHIP AREA) = 47.57 /( 31.00 x 4.45 )= 0.35
13 MIDSHIP COEFFICIENT = MIDSHIP AREA / (B x H) = 4.45 /( 11.00 x 1.00 = 0.40
14 WATERPLANE COEFFICIENT = AWP / (L x B) = 93.00 /( 31.00 x 11.00 = 0.27
15 C.F. about STA. 5 = NET F(LMs) / F(As) x S = ( 36.98 / 45.00 )x 3.10 = 2.55 M
3
16 IL about STA. 5 = 1/3 x S x 2 x F(LI's) = 0.33 x 29.79 x 2.00 x 103.83 = 2062.07 M4
17 IL CORRECTION = AWP x C.F. from STA 5 = 93.00 x 2.55 = 236.91 M4
18 IL OF C.F. = IL - IL CORRECTION = 2062.1 - 236.91 = 1825.16 M4
19 BML = IL of CF/ V = 1825.2 / 47.57 = 38.37 M
ASIAN INSTITUTE OF MARITIME STUDIES
20 M Tcm = S.W. DISPL. x BML / (100 x L) = 48.76 x 38.37 /( 100.00 x 31.00 )= 0.60 T
21 IT = 2/3 x S/3 x F(TI's) = 0.67 x 1.03 x 500.75 = 344.96 M4
22 BMT = IT / V = 344.96 / 47.57 = 7.25 M
23 KMT = VCB + BMT = 0.66 + 7.25 = 7.92 M
24 KML = VCB + BML = 0.66 38.37 = 39.03 M
Page | 36
25 FRESHWATER ALLOWANCE = DISPLACEMENT/4TPC = 48.76 /( 4.00 x 0.95 )= 12.78 mm
COMPUTATION SHEET
Up to Waterline 1 - 2
1 LCB = F(LM) / F(V) = 2171.77 / 1089.25 = 1.99 M
2 VCB = F(VM) / F(V) = 1443.72 / 1089.25 = 1.33 M
3 VOL. OF DISPLACEMENT = MEAN F(V) x L = 6.05 x 31.00 = 187.59 M3
4 DISPLACEMENT OF S. W. = V x 1.025 = 187.59 x 1.025 = 192.28 tons
5 DISPLACEMENT OF F. W. = V x 1.000 = 187.59 1.000 = 187.59 tons
6 MIDSHIP AREA = 1/3WLS x F(A) x 2 + C.FWD = 0.17 x 27.4 x 2.00 + 4.446 = 13.58 M2
7 AWP NO. ______
1.5 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 68.87 x 2.00 = 142.34 M2
8 AWP NO. ______
2.00 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 86.03 x 2.00 = 177.80 M2
9 T.P.C. NO. W.L. 1.5 = AWP / 97.5 = 142.34 / 97.50 = 1.46 ton
10 T.P.C. NO. W.L. 2 = AWP / 97.5 = 177.80 / 97.50 = 1.82 ton
11 BLOCK COEFFICIENT = V / (L x B x H) = 187.59 /( 31.00 x 11.00 x 2.00 )= 0.28
12 PRISMATIC COEFFICIENT = V / (L x MIDSHIP AREA) = 187.59 /( 31.00 x 13.58 )= 0.45
13 MIDSHIP COEFFICIENT = MIDSHIP AREA / (B x H) = 13.58 /( 11.00 x 2.00 = 0.62
14 WATERPLANE COEFFICIENT = AWP / (L x B) = 177.80 /( 31.00 x 11.00 = 0.52
15 C.F. about STA. 5 = NET F(LMs) / F(As) x S = ( 39.58 / 86.03 )x 3.10 = 1.43 M
3
16 IL about STA. 5 = 1/3 x S x 2 x F(LI's) = 0.33 x 29.79 x 2.00 x 299.62 = 5950.62 M4
17 IL CORRECTION = AWP x C.F. from STA 5 = 177.80 x 1.43 = 253.60 M4
18 IL OF C.F. = IL - IL CORRECTION = 5950.62 - 253.60 = 5697.03 M4
19 BML = IL of CF/ V = 5697.03 / 187.59 = 30.37 M
20 M Tcm = S.W. DISPL. x BML / (100 x L) = 192.28 x 30.37 /( 100.00 x 31.00 )= 1.88 T
ASIAN INSTITUTE OF MARITIME STUDIES
Page | 37
25 FRESHWATER ALLOWANCE = DISPLACEMENT/4TPC = 192.28 /( 4.00 x 1.82 )= 26.36 mm
COMPUTATION SHEET
Up to Waterline 2 - 3
1 LCB = F(LM) / F(V) = 3317.37 / 2308.89 = 1.44 M
2 VCB = F(VM) / F(V) = 4525.61 / 2308.89 = 1.96 M
3 VOL. OF DISPLACEMENT = MEAN F(V) x L = 12.83 x 31.00 = 397.64 M3
4 DISPLACEMENT OF S. W. = V x 1.025 = 397.64 x 1.025 = 407.58 tons
5 DISPLACEMENT OF F. W. = V x 1.000 = 397.64 1.000 = 397.64 tons
6 MIDSHIP AREA = 1/3WLS x F(A) x 2 + C.FWD = 0.17 x 31.1 x 2.00 + 13.58 = 23.94 M2
7 AWP NO. ______
2.50 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 101.24 x 2.00 = 209.23 M2
8 AWP NO. ______
3.00 = 1/3 S x F(A) x 2 = 0.33 X 3.10 x 118.83 x 2.00 = 245.59 M2
9 T.P.C. NO. W.L. 2.5 = AWP / 97.5 = 209.23 / 97.50 = 2.15 ton
10 T.P.C. NO. W.L. 3 = AWP / 97.5 = 245.59 / 97.50 = 2.52 ton
11 BLOCK COEFFICIENT = V / (L x B x H) = 397.64 /( 31.00 x 11.00 x 3.00 )= 0.39
12 PRISMATIC COEFFICIENT = V / (L x MIDSHIP AREA) = 397.64 /( 31.00 x 23.94 )= 0.54
13 MIDSHIP COEFFICIENT = MIDSHIP AREA / (B x H) = 23.94 /( 11.00 x 3.00 = 0.73
14 WATERPLANE COEFFICIENT = AWP / (L x B) = 245.59 /( 31.00 x 11.00 = 0.72
15 C.F. about STA. 5 = NET F(LMs) / F(As) x S = ( 4.85 / 118.83 )x 3.10 = 0.13 M
3
16 IL about STA. 5 = 1/3 x S x 2 x F(LI's) = 0.33 x 29.79 x 2.00 x 637.80 = 12667.05 M4
17 IL CORRECTION = AWP x C.F. from STA 5 = 245.59 x 0.13 = 31.07 M4
18 IL OF C.F. = IL - IL CORRECTION = 12667.05 - 31.07 = 12635.98 M4
19 BML = IL of CF/ V = 12635.98 / 397.64 = 31.78 M
20 M Tcm = S.W. DISPL. x BML / (100 x L) = 407.58 x 31.78 /( 100.00 x 31.00 )= 4.18 T
ASIAN INSTITUTE OF MARITIME STUDIES
Page | 38
COMPUTATION SHEET
Up to Waterline 3 - 4
1 LCB = F(LM) / F(V) = 2300.05 / 3883.93 = 0.59 M
2 VCB = F(VM) / F(V) = 10059.16 / 3883.93 = 2.59 M
3 VOL. OF DISPLACEMENT = MEAN F(V) x L = 21.58 x 31.00 = 668.90 M3
4 DISPLACEMENT OF S. W. = V x 1.025 = 668.90 x 1.025 = 685.62 tons
5 DISPLACEMENT OF F. W. = V x 1.000 = 668.90 1.000 = 668.90 tons
6 MIDSHIP AREA = 1/3WLS x F(A) x 2 + C.FWD = 0.17 x 32.2 x 2.00 + 23.94 = 34.68 M2
7 AWP NO. ______
3.50 = 1/3 S x F(A) x 2 = 0.33 x 3.10 x 132.24 x 2.00 = 273.30 M2
8 AWP NO. ______
4.00 = 1/3 S x F(A) x 2 = 0.33 x 3.10 x 139.73 x 2.00 = 288.78 M2
9 T.P.C. NO. W.L. 3.5 = AWP / 97.5 = 273.30 / 97.50 = 2.80 ton
10 T.P.C. NO. W.L. 4 = AWP / 97.5 = 288.78 / 97.50 = 2.96 ton
11 BLOCK COEFFICIENT = V / (L x B x H) = 668.90 /( 31.00 x 11.00 x 4.00 )= 0.490
12 PRISMATIC COEFFICIENT = V / (L x MIDSHIP AREA) = 668.90 /( 31.00 x 34.68 )= 0.622
13 MIDSHIP COEFFICIENT = MIDSHIP AREA / (B x H) = 34.68 /( 11.00 x 4.00 = 0.788
14 WATERPLANE COEFFICIENT = AWP / (L x B) = 288.78 /( 31.00 x 11.00 = 0.847
15 C.F. about STA. 5 = NET F(LMs) / F(As) x S = ( -49.41 / 139.73 )x 3.10 = -1.10 M
3
16 IL about STA. 5 = 1/3 x S x 2 x F(LI's) = 0.33 x 29.79 x 2.00 x 987.22 = 19606.78 M4
17 IL CORRECTION = AWP x C.F. from STA 5 = 288.78 x -1.10 = -316.55 M4
18 IL OF C.F. = IL - IL CORRECTION = 19606.78 - -316.55 = 19923.33 M4
19 BML = IL of CF/ V = 19923.33 / 668.90 = 29.79 M
20 M Tcm = S.W. DISPL. x BML / (100 x L) = 685.62 x 29.79 /( 100.00 x 31.00 )= 6.59 T
ASIAN INSTITUTE OF MARITIME STUDIES
Page | 39
SUMMARY
ITEM DRAFTS IN METER
HYDROSTATIC PARTICULARS
NO 1 2 3 4
1 FRESHWATER DISPLACEMENT in MT 47.57 187.59 397.64 668.90
2 SALTWATER DISPLACEMENT in MT 48.76 192.28 407.58 685.62
3 BLOCK COEFFICIENT, Cb 0.14 0.28 0.39 0.49
4 MIDSHIP COEFFICIENT, Cm 0.40 0.62 0.73 0.79
5 WATERPLANE COEFFICIENT, Cwp 0.27 0.52 0.72 0.85
6 PRISMATIC COEFFICIENT, Cp 0.35 0.45 0.54 0.62
7 TONNES PER CENTIMETER IMMERSION, TP cm 0.95 1.82 2.52 2.96
8 MOMENT TRIM BY 1 CENTIMETER, MT cm 0.60 1.88 4.18 6.59
9 TRANSVERSE METACENTER FROM CENTER OF BOUYANCY, BMT in M 7.25 6.20 4.65 3.50
10 TRANSVERSE METACENTRIC HEIGHT ABOVE KEEL, KMT in M 7.92 7.53 6.61 6.09
11 LONGITUDINAL METACENTER FROM CENTER OF BOUYANCY, BML in M 38.37 30.37 31.78 29.79
12 LONGITUDINAL METACENTRIC HEIGHT ABOVE KEEL, KML in M 39.03 31.69 33.74 32.38
ASIAN INSTITUTE OF MARITIME STUDIES
Page | 40
ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 6
BONJEAN
CURVES OFFSET
AND PLAN
Page | 41
ASIAN INSTITUTE OF MARITIME STUDIES
PARTICULARS:
VALUE
LBP 31 Meters
BREADTH 11 Meters
DEPTH 5 Meters
DRAFT 4 Meters
WATERLINE SPACING 0.5 Meter
STATION SPACING 3.1 Meters
DIVISOR 180
STA WL 1 WL 2 WL 3 WL 4
FP
0.000 0.000 0.000 0.000
0.5
0.000 0.070 1.998 6.359
1
0.000 1.643 6.029 12.129
1.5
0.308 3.880 10.000 17.282
2
1.350 6.531 13.912 22.236
3
2.918 10.545 19.729 29.494
4
3.986 12.748 22.870 33.384
5
4.446 13.582 23.943 34.675
6
2.981 11.780 22.041 32.655
7
0.000 4.160 13.833 24.222
8
0.000 0.000 5.960 15.900
8.5
0.000 0.000 2.202 11.715
9
0.000 0.000 0.735 8.988
9.5
0.000 0.000 0.000 5.970
AP
0.000 0.000 0.000 1.409
DIVISOR = /15
Page | 42
ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 7
STABILITY
Page | 43
ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 7: STABILITY
FORMULA 1:
VCB = d x (0.9 - (0.36 x Cm))
where: d - draft, 4m
= 4 x (0.9 - (0.36 x 0.79)) Cm - 0.79
VCB = 1.8468 m
FORMULA 2:
VCB = d x (0.9 - 0.36 x Cm - 0.1 x Cb)
where: d - draft, 4m
= 4 x (0.9 - 0.36 x 0.79 - 0.1 x 0.49) Cm - 0.79
Cb - 0.49
VCB = 1.9938 m
FORMULA 3:
VCB = d x (0.78 - 0.285 x Cm / Cw)
where: d - draft, 4m
= 4 x (0.78 - 0.285 x 0.79/0.85) Cm - 0.79
Cw - 0.85
VCB = 1.545 m
FORMULA 4:
VCB = 0.52 x d
VCB = 2.08 m
FORMULA 5:
VCB = 0.535 x d
VCB = 2.14 m
VCB AVERAGE
VCB AVE. = 1.847 + 1.994 + 1.545 + 2.08 + 2.14
5
Page | 44
ASIAN INSTITUTE OF MARITIME STUDIES
FORMULA 1:
VCG = 0.01D x ((46.6 + 0.135 x 0.81 - Cb) x (L/D)2)
where: D - depth, 5m
2
= 0.01(5) x ((46.6+0.135x0.81-0.49)x(31/5) ) Cb - 0.49
L - LBP, 31 m
= 0.01(5) x (46.6 + 0.135 x 0.32 x 38.44 )
VCG = 2.41 m
FORMULA 2:
VCG = 0.75 x D
VCG = 3.75 m
VCG AVERAGE
VCG AVE. = 2.42 + 3.75
2
FORMULA :
BMT= k x B2
h x Cb where: B - breadth, 11m
h - draft, 4 m
0.061 x 112 Cb - 0.49
=
4 x 0.49 k - constant, 0.061
BMT= 3.77 m
Page | 45
ASIAN INSTITUTE OF MARITIME STUDIES
FORMULA 1:
2 2
3 x Cwl x LBP
BML =
40 x d x Cb
where: LBP - 31m
2 2
3 x 0.85 x 31 d - draft, 4 m
=
40 x 4 x 0.49 Cb - 0.49
Cwl - 0.85
BML = 26.57 m
FORMULA 2:
BML = 1.25 x LBP
BML = 38.75 m
BML AVERAGE
BML AVE. = 26.57 + 38.75
2
FORMULA :
Cw
KB= H
Cwl + Cb
where: h - draft, 4 m
0.85 Cb - 0.49
= 4
0.85 + 0.49 Cwl - 0.85
KB = 2.595 m
KMT = KB + BMT
KMT = 6.365 m
Page | 46
ASIAN INSTITUTE OF MARITIME STUDIES
FORMULA :
KML = VCB + BML
where: BML- 26.57 m
= 1.921 + 26.57 VCB - 1.921 m
KML = 28.491 m
FORMULA :
BG = KG - KB
where: KG = VCG = 3.085 m
= 3.085 - 2.595 KB - 2.595 m
BG = 0.49 m
GMT = BMT - BG
GMT = 3.28 m
FORMULA :
IT = BMT x Vol. of Displacement
where: BMT - 3.72m
3
= 3.72 x 668.90 Vol. of Displ. - 668.9 m
IT = 2488.308 m4
FORMULA :
IT = BML x Vol. of Displacement
where: BML - 32.66 m
= 32.66 x 668.90 Vol. of Displ. - 668.9 m 3
IT = 21.846.274 m4
0.44 x B
T=
√GM where: GM - 3.28 m
B - breadth, 11 m
0.44 x 11
=
√3.28
= 2.67 x2
T= 5.34 s
Page | 47
ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 8
SCANTLING
COMPUTATION
Page | 48
ASIAN INSTITUTE OF MARITIME STUDIES
INTRODUCTION TO SCANTLING
The Midship section. The first thing needed for one to have an idea of the various
members that will compose the ship’s frame and hull the design that will compose the ship
frame and the hull is the design of amidship section. This is reference for it will determine
standards and other criteria for the design and construction of marine vessels and
structures, for material, equipment and machinery, b) the review of design and survey
during and after construction to verify compliance with such Rules, Guides, standards or
other criteria and c) the assignment and registration of class when such compliance has
This is reference for it will determine the frame spacing of your members, the
The most important duty of the ships structure design is to supply a strong enough
structure against the internal and external loads. It may be considered as the material
which provides the strength and stiffeners to withstand all of the loads which the ship may
reasonably be expected to experience. The Hull girder is the structure which resist
longitudinal bending, consisting basically of the shell plating, decks inner bottom,
longitudinal bulkheads and girders. The hull girder must withstand to both static and
dynamic storm sea conditions, as well as during launching and dry docking
Page | 49
ASIAN INSTITUTE OF MARITIME STUDIES
PARTICULARS:
VALUE
L.B.P. 31 METERS
BREADTH MOULDED 11 METERS
DEPTH MOULDED 5 METERS
DRAFT 4 METERS
FRAME SPACING
• FRAME SPACING (Chapter E, Section 7.01, page 85)
The standard spacing of frames is to be calculated in accordance with following formula
(whichever is lesser):
S = 720 (L / 100)1/4 mm
1/4 mm
= 720 (31 / 100) where: L - LBP, 31 m
PLATINGS
• BOTTOM SHELL PLATING (Chapter E, 3.01 - (c), page 55)
In a ship transverse bottom framing, the thickness t of bottom shell plating within 0.4 L
amidship is not to be less than:
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 50
ASIAN INSTITUTE OF MARITIME STUDIES
PLATINGS
• SIDE SHELL PLATING ( Chapter E, 3.02 - (b), No. 2, page 56)
Where the side shell is framed transversely, the thickness t of the side shell plating
within 0.4 L amidhips is not to be less than the greates of the folowwing values:
t = 6.55 mm
Chapter L, the thickness of strength deck plating is to satify the relevant requirements of
Section 1: Section 4, Chapter E, but the minimum thickness is to be increased by 1mm
Tugs
above the required by 4.02 of Chapter E. (page 253)
Reference: PRSRules
Reference: PRS Rulesforfor
thethe Contsruction
Contsruction andand Classification
Classification of Steel
of Steel VesselVessel
Page | 51
ASIAN INSTITUTE OF MARITIME STUDIES
TRANSVERSE FRAMINGS
• SIDE STRINGER Chapter G, Section 7.05, page 200)
The section modulus W of side stringers is not to be less than that obtained from the
following formula:
W = 13b (h + 1.2) l2
2
W = 13(b) x ( h + 1.2) x l where: b - half breadth, B/2, 5.5 m
h - vertical distance measured from
= 13(5.5) x ( 1.524 + 1.2) x 22 the stringer deck at side, 1.524m
l - span of frame, 2 m
3
W = 779.064 cm
W = 0.2*n*C*W
where: n - 2 to 5 frames apart, 2 frames apart
W - sectional area of main frame
= 0.2*2*7.07*79.96 20 8.4
79.96 C
200 4.4
W = 226.127 cm 3 C = 7.0676
C - obtained through interpolation
2
t = 0.06 * L + 6.2 mm A = 0.5 L + 2 cm
2
t = 8.06 mm, adopt to 9.525 mm A = 17.5 cm
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 52
ASIAN INSTITUTE OF MARITIME STUDIES
TRANSVERSE FRAMINGS
• SIDE KEELSON (Chapter E, 5.04, page 70)
The depth of side keelson is to be the same as that of floors, and the web thickness t and the
sectional area A of the face plate of side keelsons are not to be less than the following values:
2
t = 0.05 * L + 5 mm A = 0.2 L + 4 cm
t = 6.55 mm A = 10.2 cm 2
= 4.1(245.872) + 340
W = 1348.08 cm3
where: s - frame spacing, 0.508 m
• h = kB mm
d - draft, 4m
= 51*11
h = 561 mm B - breadth, 11 m
*adopt to 930 mm adjustment from
the frame computation
2
• t = 0.01*h + 3, mm s*d*B = 245.872
= 0.05*245.872 + 8, cm2 u
A = 20.29 cm 2
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 53
ASIAN INSTITUTE OF MARITIME STUDIES
TRANSVERSE FRAMINGS
• TRANSVERSE FRAMING (ORDINARY BOTTOM) (Chapter E, 6.17, page 77)
The thickness t of plate floors is not to be less than that obtained from the following formula:
The section modulus of bottom ordinary is not to be less than obtained from the following
formula:
2 3
W = 5.5s*h*l cm
where: s - spacing of stiffeners, in m (1.5)
2
= 5.5 x (1.5) x (5.05) x (0.93) h - tank top to deck + height
of air pipe, 5.05 m
3
W = 36.03 cm l - height of floors, 0.930 m
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 54
ASIAN INSTITUTE OF MARITIME STUDIES
TRANSVERSE FRAMINGS
• DECK BEAMS (Chapter E, 8.02, page 91)
The section modulus W of deck beams for each deck in multi-deck ship is not to be less
than that obtained from the following formula:
2 3
W = 7*S*h*l cm where: S - spacing of transverse in m, .508 m
h - water head in m
2 l - span of deck transverse, 1.375 m
= 7*0.508*1.598*1.83
W = 131.11 cm 3
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 55
ASIAN INSTITUTE OF MARITIME STUDIES
WATERTIGHT BULKHEAD
• PLANE BULKHEAD PLATING (Chapter E, 11.09, page 118)
The thickness t of the plating of plane watertight bulkheads is not to be less than that
obtained from the following formula:
*multiply the * -
computed W to 3
W = 16.76 cm
125%
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 56
ASIAN INSTITUTE OF MARITIME STUDIES
LONGITUDINAL FRAMINGS
• DECK LONGITUDINAL (Chapter E, Section 8.17, page 100)
Where the deck is frame longitudinally, the section modulus of deck longitudinal is to be
determined as follows:
Reference: PRS Rules for the Contsruction and Classification of Steel Vessel
Page | 57
ASIAN INSTITUTE OF MARITIME STUDIES
length (plate)
50.8
thickness
(plate)
0.8
H y=
9 2.716
thickness
(AB)
0.8
7.5
w
DECK LONGITUDINAL
SCANTLING/ SIZE
A dg Adg Adg2 Inertia
MEMBER t l
Deck Plating 0.8 50.8 40.640 0.4 16.256 6.502
Angle Bar 0.8 9 x 7.5 12.64 7.084 89.542 634.314 99.4
2
Total Area: 53.280 Total Adg: 105.798 Total Adg 740.216
24%
Page | 58
ASIAN INSTITUTE OF MARITIME STUDIES
w
7.5
thickness
(AB)
0.8
H
y= 12.5
4.136
0.8
thickness
(plate)
50.8
length (plate)
BOTTOM LONGITUDINAL
SCANTLING/ SIZE
A dg Adg Adg2 Inertia
MEMBER t l
Deck Plating 0.8 50.8 40.640 0.400 16.256 6.502
Angel Bar 0.8 12.5 X 7.5 15.49 9.164 141.950 1300.833 247.3
Total Area: 56.130 Total Adg: 158.206 Total Adg 2 1554.635
2
New A(dg) Area x New dg 445.916 78.26
35%
Page | 59
ASIAN INSTITUTE OF MARITIME STUDIES
w
7.5
thickness
(AB)
0.6
H
y= 10
4.036
0.8
thickness
(plate)
50.8
length (plate)
SCANTLING/ SIZE
A dg Adg Adg2 Inertia
MEMBER t l
Deck Plating 0.8 50.8 40.640 0.400 16.256 6.502
Angel Bar 0.6 10x7.5 10.25 6.764 69.331 468.955 102.4
2
Total Area: 50.890 Total Adg: 85.587 Total Adg 577.857
2
New A(dg) Area x New dg 143.941 36.03
32%
Page | 60
ASIAN INSTITUTE OF MARITIME STUDIES
thickness (web)
0.8
length (plate)
50.8
0.8
thickness (flange)
33%
Page | 61
ASIAN INSTITUTE OF MARITIME STUDIES
length
(web)
40
0.8
thickness
length (web)
(flange) .
22
0.8
thickness (flange)
SIDE STRINGER
29%
Page | 62
ASIAN INSTITUTE OF MARITIME STUDIES
length (plate)
50.8
thickness (plate)
0.8
thickness
(flange)
length (web) 0.6
27
0.6 17 `
thickness(web) length (flange)
DECK GIRDER
15%
Page | 63
ASIAN INSTITUTE OF MARITIME STUDIES
thickness (web)
0.8
thickness (plate)
0.8
16
length
(web)
10
length (flange)
DECK BEAM
27%
Page | 64
ASIAN INSTITUTE OF MARITIME STUDIES
thickness (web)
0.8
thickness (plate)
0.8
14
length
(web)
10
length (flange)
DECK TRANSVERSE
21%
Page | 65
ASIAN INSTITUTE OF MARITIME STUDIES
length
(flange)
0.8
thickness 0.8
(web) thickness
0.8 (flange)
93
length
(web) thickness
(plate)
0.8
50.8
length
(plate)
FLOORS
33%
Page | 66
ASIAN INSTITUTE OF MARITIME STUDIES
2
SM = ( 15.20 - 0.22( 31 ) ) x 0.01 ( 31 ) x 11 ( 0.60 + 0.7 )
SM = 1151.60 m-cm2
DIMENSION 2
a*dg a*dg
2
Qty a (cm ) dg (M) 2 h (M) io
L T (cm -M) (cm -M2) 2
ABOVE A.N.A.
PLATING:
Deck Plating 2 479.3 0.8 766.88 2.154 1651.860 3558.11 0
Stringer Plate 2 71.08 0.8 113.728 1.987 225.978 449.02 0
Sheer Strake 2 100.95 0.8 161.52 1.462 236.142 345.24 0
Side Shell Plating 2 96.64 0.8 154.624 0.483 74.683 36.07 5
GIRDER:
Deck Girder
b. Flange 1 17 0.6 10.2 1.895 19.329 36.628 0 0
c. W eb 1 27 0.6 16.2 2.055 33.291 68.413 0.27 984.15
Deck Side Girder
b. Flange 2 17 0.6 20.4 1.895 38.658 73.3 0 0
c. W eb 2 27 0.6 32.4 2.033 65.869 133.9 0.54 984.15
Deck Side Girder
b. Flange 2 17 0.6 20.4 1.895 38.658 73.3 0 0
c. W eb 2 27 0.6 32.4 1.977 64.055 126.6 0.54 984.15
Deck Side Girder
b. Flange 2 17 0.6 20.4 1.895 38.658 73.3 0 0
c. W eb 2 27 0.6 32.4 1.892 61.301 116.0 0.54 984.15
LONGITUDINALS:
Deck Longitudinals 14 9 x 7.5 0.8 176.96 2.135 377.810 806.6 0 99.4
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BELOW A.N.A.
PLATING:
Side Shell Plating 2 58.55 0.8 93.68 0.293 27.448 8.04 0 0
Chine 2 139.93 0.8 223.888 1.24 277.621 344.25 0 0
Bottom Shell Plating 2 405.02 0.8 648.032 2.932 1900.030 5570.89 0 0
Keel Plating 2 50.4 0.9525 96.012 2.991 287.172 858.93 0 0
STRINGER:
Side Stringer
b. Flange 2 22 0.8 35.2 0.140 4.928 0.7 0.44 709.867
c. W eb 2 40 0.8 64 0.140 8.960 1.3 0 0
LONGITUDINALS:
Bottom Longitudinals 2 12.5 x 7.5 0.8 30.98 2.42 74.972 181.4 0 247.3
Bottom Longitudinals 2 12.5 x 7.5 0.8 30.98 2.56 79.309 203.0 0 247.3
Bottom Longitudinals 2 12.5 x 7.5 0.8 30.98 2.787 86.341 240.6 0 247.3
Bottom Longitudinals 2 12.5 x 7.5 0.8 30.98 2.884 89.346 257.7 0 247.3
TOTAL
TOTAL AREA: 2843.24 TOTAL ADG 5753.46 2 19297.04
ADG
25%
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 9
BOLLARD PULL
COMPUTATION
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Bollard pull is a conventional measure of the pulling (or towing) power of a vessel.
It is defined as the force (tons or kilonewtons (kN)) exerted by a vessel under full power,
sometimes simulated) under test conditions that include calm water, no tide, level trim, and
2/3 3
D xV
BP = (
120 x 60
+ Cmw x B x D1 )xK
Where: BP - Bollard Pull (tons, 70 tons)
D - Displacement of the tow (tons)
B - width of the tow (m, 31 m)
D1 - Height of the wind facing above water level
including deck cargo, freeboard + deck house
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• To get the Displacement of the barge, we are going to use the existing barge particulars to
determine the displacement.
2/3 3
D xV
BP = ( 120 x 60
+ Cmw x B x D1 )xK
D2/3 x V3
BP = ( 7200
+ Cmw x B x D1 )xK
2/3 3
( BP x 7200 ) - ( Cmw x B x D1 x K x 7200 ) =D xV xK
3 3
V xK V xK
6815.136 tonnes = D
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 10
POWERING AND
PROPULSION
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INTRODUCTION TO POWERING
One of the most important considerations for a naval architect is the powering
requirement for a ship. Once the hull form has been decided upon, it is necessary to
determine the amount of engine power that will enable the ship to meet its operational
requirements. Knowing the power required to propel a ship enables the naval architect to
select a propulsion plant, determine the amount of fuel storage required, and refine the
A moving ship experience resisting force from the water and air which must
One of the most important considerations for a naval architect is the powering requirement
for a ship. Once the hull form has been decided upon, it is necessary to determine the
amount of engine power that will enable the ship to meet its operational requirements.
Knowing the power required to propel a ship enables the naval architect to select a
propulsion plant, determine the amount of fuel storage required, and refine the ship’s
Testing of full-scale ships and models determined that the power required to propel
a ship through the water was directly related to the amount of resistance a hull experiences
Ship resistance is defined as the force required towing the ship in calm water at a constant
velocity.
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ASIAN INSTITUTE OF MARITIME STUDIES
POWERING
In powering of tugboats, I'll be using the powering made by Capt. P. Zahalka, Association of
Hanseatic Marine Underwriters to determine the BHP I'm going to use to power my vessel
The requirement for this particular case is that it should have a Bollard Pull of about.
BHP
Fixed Pitch Propeller: (free wheeling) (BHP x 1.00/100) 7000
Fixed Pitch Propeller and Kort Nozzle (BHP x 1.08/100) 6481
Controllable Pitch Propeller: (free wheeling) (BHP x 1.125/100) 6222
Controllable Pitch Propeller and Kort Nozzle (BHP x 1.126/100) 6217
For this particular case we will use a Controllable Pitch Propeller and Kort Nozzle and please
note further that the limited aperture of the hull dictates that it should use 2 propellers. The
estimated BHP is calculated with reference to its bollard pull and on this condition the propeller
is design. The free running speed is also calculated as shown hereunder.
No. of Delivered
BHP EHP
Propeller HP
6217 3419.18
2
3108.35 1709.59 2412.08
To check the BHP and EHP recommened, I'll be using another way to determine the power of the
vessel to be designed by using the Speed and Power of Ships by D.W. Taylor tabular form
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CWS = 15.45
• WETTED SURFACE
WS = CWS √Δ L
= 15.45 √(698.7)(101.68)
WS = 4118.05 ft2
(a) = 0.00307 x Δ x √ L
(a) = 21.62
Ws = Cws / 15.4
15.45 / 15.4
Ws = 1.003
0.085
f(design) x 150
λ= 0.085
L(design) x f150
to get the f, I need to interpolate the value of it from the Table V. Tideman's frictional constant
of ships in salt water
101.68 - 100
fX = 0.0097 + ( 150 - 100
)(0.009570 - 0.00970)
fX = 0.0097
0.085
f(design) x 150
λ= 0.085
L(design) x f150
0.009695 x 1500.085
=
(101.68)0.085 x 0.00957
λ= 1.047
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ASIAN INSTITUTE OF MARITIME STUDIES
• BREADTH-DRAFT RATIO
B/d = 2.75
= 0.333
( Cws )
b= xλ
15.4
15.45
b= xλ
15.4
b= 1.0503
Total = 20%
• HULL EFFICIENCY
(1 - t )
EH =
(1 - w)
where:
Wake Fraction:
= -0.05 + 0.5(0.49)
(w) = 0.195
= 0.3Cb
= 0.3(0.49)
(t) = 0.147
(1 - t )
EH =
(1 - w)
(1 - .147 )
=
(1 - .195)
EH = 1.059
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ASIAN INSTITUTE OF MARITIME STUDIES
•TRANSMISSION EFFICIENCY
ET = Loses between delivered power (at tailshaft) and that provided by engine)
ER = range from 1.0 to 1.10 to all types of ship according to Baxter, Naval
Architecture, p. 212
ER = 1.05
•PROPELLER EFFICIENCY
•MECHANICAL EFFICIENCY
EM = 95% to 100%
EM = 98%
EA = 96% to 98 %
EA = 97%
•PROPULSIVE COEFFICIENT
PC = EH x ET x ER x EP x EM x EA
PC = 0.725
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ASIAN INSTITUTE OF MARITIME STUDIES
HORSEPOWER TABLE
1 2 3 4 5 6 7
Rr/∆ Rf/∆ from
Rr/Δ from contours
correction contours for
Difference Rf/∆
v/√L for B/H
(col.2-col.3)
150' ship
(col.6 * b)
B/H = 3.75 B/H = 2.25 (col.5x B-d and cws
corr.factor) 15.45
1.15 21.50 16.75 1.582 4.750 32.525 34.161
1.20 30.75 27.50 1.082 3.250 39.555 41.545
1.25 39.85 31.65 2.731 8.200 48.675 51.123
8 9 10 11 12 13 14
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ASIAN INSTITUTE OF MARITIME STUDIES
In conclusion, I'll be using the Powering Calculation from D.W. Taylor for it gives a specific
way to determine the required EHP and BHP of the vessel to be designed. From this, I'll be
using the BHP to check the Mechanical effenciency loss and to get the range of my required
main engine BHP requirements
Therefore, the designated engine BHP range is from 3301.944 (2462.26 kW) hp to
3485.385hp (2599.05kW)
ENGINE SELECTED:
MAN L27/38
BHP = 3426.311 hp RPM = 800
• SHAFT HORSEPOWER
3426.311 x 0.97
SHP= 3324 hp
• SHAFT HORSEPOWER
= 3323.52 x 0.98
DHP = 3257 hp
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ASIAN INSTITUTE OF MARITIME STUDIES
PROPULSION
The basic idea behind an azimuth thruster is that the propeller can rotate 360 degrees round
a vertical axis providing omni-directional controlled thrust. This means superior
maneuverability for vessels equipped with azimuth thrusters. It also eliminates the need for a
rudder and a reverse gear.
The system consists of several different devices: azimuth thrusters, steering and control unit
levers and shaft lines. As a whole, they might well be more accurately referred to as
“propulsion and steering system”.
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 11
CAPACITY PLAN
COMPUTATION
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SUMMARY
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CHAPTER 12
MINIMUM SAFE
MANNING
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ASIAN INSTITUTE OF MARITIME STUDIES
MANNING REQUIREMENTS
NT = 243.55 T
COMPLEMENTS
PMMRR 1997, Appendix A, 4.4 Tugs and Dredgers
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 13
WEIGHT
ESTIMATE
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ASIAN INSTITUTE OF MARITIME STUDIES
LIGHTSHIP WEIGHT
• STEEL HULL
SHULL = 93.5704 T
A weight = 20 % of E.W.O.
0.20 x 4.923 MT
A weight = 0.98 T
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NON-PAYING
2. Auxiliaries
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3. Round Trip
No. of Hours = D (6080 ft / 1 NM)
S (6080 ft / 1 NM - hr)
= 75, 383.49 L
= 94.23 m3 x ρ fuel density (0.86 Kg/L = 860 kg/m3 = 0.86 tonnes / m3)
FOCT = 81.04 T
LOCT = 4.052 T
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ASIAN INSTITUTE OF MARITIME STUDIES
= 1440 lbs
= 653.06 kg
F.W.C. = 0.65 T
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ASIAN INSTITUTE OF MARITIME STUDIES
• PROVISIONS
Reference: Principles of Naval Architecture Vol. I, table 4, p. 96
= 320 lbs
= 145.12 kg
• STORES
= 352 lbs
= 159.64 kg
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ASIAN INSTITUTE OF MARITIME STUDIES
• CREW WEIGHT
Reference: Principles of Naval Architecture Vol. I, p. 96
= 1280 lbs
= 580.50 kg
• CREW EFFECT
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SUMMARY
• LIGHTSHIP WEIGHT
Total = 164.473 T
• NON-PAYING
1. Fuel Oil (Total fuel oil consumption per Round Trip) 81.04 T
5. Provisions 0.15 T
6. Stores 0.16 T
7. Crew 0.58 T
Total = 87.949 T
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ASIAN INSTITUTE OF MARITIME STUDIES
• Deadweight
= 164.473 T + 87.949 T
685 T - 252.422 T
Deadweight = 432.578 T
• Paying Deadweight
432.578 T - 87.949 T
DWT = 344.629 T
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 14
FIREFIGHTING
SYSTEM
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ASIAN INSTITUTE OF MARITIME STUDIES
29.3.2 Capacity
Fire pump capacity is to be in accordance with the following:
3
Below 20 m (65ft) 5.5 m / hr (25 gpm)
Power driven fire pumps are to have sufficient pressure to supply the effective
3
stream required. Hand-operated fire pumps are to have a minimum capacity of 1.1 m / hr
(5 gpm)
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ASIAN INSTITUTE OF MARITIME STUDIES
Table 29.1
Classification of Portable and Semi-portable Extinguishers
Table 29.2
Portable and Semi-portable Extinguishers
•Accomodations
1 in each sleeping accommodation
Sleeping
A - II space (where occupied by more than 4
Accommodations persons)
•Service Spaces
B - II or 1 for each 230 m2 (2,500 ft2) or
Galleys
C - II fraction therof for hazards involve
•Machinery Spaces
Internal combustion or
gas turbine engines B - II 1 for each engine
Electric motor or
generators of open C - II 1 for each motors or generators
type
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 15
GENERAL
ARRANGEMENT
PLAN
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ASIAN INSTITUTE OF MARITIME STUDIES
CHAPTER 15
DRAWING PLAN
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