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Ecuaciones

This document provides solutions to 15 equations of the first degree: 1) It solves equations by performing algebraic operations like combining like terms and isolating the variable. 2) The solutions provided include integers and fractions. 3) Solving the equations involves algebraic steps like distributing, combining like terms, and solving for the variable.

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Cesar Huayhua Condori
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51 views4 pages

Ecuaciones

This document provides solutions to 15 equations of the first degree: 1) It solves equations by performing algebraic operations like combining like terms and isolating the variable. 2) The solutions provided include integers and fractions. 3) Solving the equations involves algebraic steps like distributing, combining like terms, and solving for the variable.

Uploaded by

Cesar Huayhua Condori
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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ECUACIONES DE PRIMER GRADO

Resuelve las siguientes ecuaciones:

a) x + 16 = 41
b) 9x – 45 + 4x – 16 = 4
c) 2x – 3 + x – 35 = 2 – 9x – 4
d) 3 · (x – 2) + 9 = 0
e) 8x + 7 – 2x + 5 = 4x + 12 – (x – 30)
f) x + (x + 2) = 36
g) 2 · (3x – 2) – (x + 3) = 8
h) 2 · (13 + x) = 41 + x
i) 2 · (x – 3) – 3 · (4x – 5) = 17 – 8x
j) 4x – 3 · (1 – 3x) = –3
k) 4 · (2x) – 3 · (3x – 5) = 12x – 180
l) 6 – x = 4 · (x – 3) – 7 · (x – 4)
m) 3 · (2x – 6) – [(x – (3x – 8) + 2) – 1] = 2 – (3 – 2x)
n) (x – 2)2 = x2
ñ) x · (x + 4) = x2 + 8
ECUACIONES DE PRIMER GRADO (Soluciones)

Resuelve las siguientes ecuaciones:

a) x + 16 = 41

x = 41 – 16  x = 25

b) 9x – 45 + 4x – 16 = 4

9x + 4x = 45 + 16 + 4  13x = 65  x = 5

c) 2x – 3 + x – 35 = 2 – 9x – 4

2x + x + 9x = 2 – 4 + 3 + 35  12x = 36  x = 3

d) 3 · (x – 2) + 9 = 0

3x – 6 + 9 = 0  3x = 6 – 9  3x = 3  x = 1

e) 8x + 7 – 2x + 5 = 4x + 12 – (x – 30)

8x + 7 – 2x + 5 = 4x + 12 – x + 30  8x – 2x – 4x + x = –7 – 5 + 12 + 30  3x = 30 
x = 10

f) x + (x + 2) = 36

x + x + 2 = 36  2x = 2 + 36  x = 17

g) 2 · (3x – 2) – (x + 3) = 8

6x – 4 – x – 3 = 8  6x – x = 8 + 4 + 3  5x = 15  x = 3
h) 2 · (13 + x) = 41 + x

26 + 2x = 41 + x  2x – x = 41 – 26  x = 15

i) 2 · (x – 3) – 3 · (4x – 5) = 17 – 8x

2x – 6 – 12x + 15 = 17 – 8x  2x – 12x + 8x = 17 + 6 – 15  2x = 8  x = 4

j) 4x – 3 · (1 – 3x) = –3

4x – 3 + 9x = –3  4x + 9x = –3 + 3  13x = 0  x = 0

k) 4 · (2x) – 3 · (3x – 5) = 12x – 180

8x – 9x + 15 = 12x – 180  8x – 9x –12x = –180 – 15  –13x = –195  x = 15

l) 6 – x = 4 · (x – 3) – 7 · (x – 4)

6 – x = 4x – 12 – 7x + 28  –x – 4x + 7x = –12 + 28 – 6  2x = 10  x = 5

m) 3 · (2x – 6) – [(x – (3x – 8) + 2) – 1] = 2 – (3 – 2x)

6x – 18 – [x – 3x + 8 + 2 – 1] = 2 – 3 + 2x  6x – 18 – x + 3x – 8 – 2 + 1 = 2 – 3 + 2x
26 13
 6x – x + 3x – 2x = 2 – 3 +18 + 8 + 2 – 1  6x = 26  x  
6 3
n) (x – 2)2 = x2

x2 + 4 – 4x = x2  x2 + 4 – 4x – x2 = 0  4 – 4x = 0  4 = 4x  x = 1

ñ) x · (x + 4) = x2 + 8

x2 + 4x = x2 + 8  4x = 8  x = 2

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