Lecture (12)
Isothermal Operation
Continuous – Stirred Tank Reactor CSTR
"Back-Mix or Mixed Flow Reactor"
o Operate under steady state
o Flow in is equal flow out
o Reactor composition equal exit stream composition.
o Constant rate of reaction throughout the reactor volume
o Composition ≠ f (Position)
o Composition =f (time) ideal restrictions
o Temperature ≠ f (Position)
o Temperature ≠ f (time)
General Mole Balance
Molar flow rate of A - Molar flow rate of A +Disappearance = Accumulation
fed to the system leave the system
V dN j F j ,o
F jo F j r j dV
dt
F j ,o Input Feed
F j Output Stream
dN j Fj
0 No accumulati on( St.St.Opeartion)
dt
V
Fjo Fj rj dV 0
The CSTR is modeled as being well mixed such there are no spatial variations in the rate of
reaction :-
V
r j dV Vr j
1
…Design Reactor Equation
for CSTR
• Consider the general reaction;
Stoichiometry set up of equations with A as basis
b c d
A B C D
a a a
Molar flow rate of species A
moles of A fed moles of A reacted
reacted or consumed
FAo X time
moles of A fed
Molar flow rate of species A Molar flow rate of species A Molar flow rate of species A
leaves the system fed to the system consumed within the system
FA FAo FAo X
FA FAo [1 X ]
Where υo entering volumetric flow rate
FAo FA
V
rA The composition from the
reactor is identical to the
composition inside the reactor,
then the rate of reaction is
evaluated at the exit conditions
FAo X
V
rA exit
C Ao o C A
V
rA
2
Plug Flow Reactor
PFR
V V dV
CA C A dC A
F jo Fj
X X dX
FA FA dFA
o Operate under steady state
o Flow in is equal flow out (constant mass)
o Conversion increases along the length of reactor
o Composition = f (Position , or direction of flow)
o Composition ≠ f (time) at a given position
o Composition ≠ f ( radial position) ideal restrictions
o Temperature = f (Position , or direction of flow)
o Temperature ≠ f (time) at a given position
o Temperature ≠ f (radial position)
o Degree of completion of a reaction depend on
reactor volume
General Mole Balance
Molar flow rate of A - Molar flow rate of A +Disappearance = Accumulation
fed to the system leave the system
V dN j
Fjo (Fjo dFj ) rj dV 0
dt
The balance is made over a finite reactor volume, dV , then
Fjo (Fjo dFj ) rj dV 0
dF j r j dV
dF j
dV
rj
3
Integrating with the limits at V=0,FA=FAo…..at V=V1, FA=FA1
FA1 FA 0
dF j dF j
V
FAo
rj
V r
FA1 j
FA FAo [1 X ]
Reactor Design Equation
Of PFR
FA1 FA 0
dF j dF j
V rj
V r
FA1 j
FAo
X
dX
V FAo
0
rj
Constant Volume (Constant Density) 0 (ε=0)
liquid-phase and some of gas phase reaction system fall into this category.
CSTR
FAo X
V
rA
C Aoo X
V
rA
C Ao X
rA
space time V
o
1 1
rA rA Area
Area
4
X CA CAo
V VC
Area= F
Ao
Area= FAo C Ao Ao
Constant Volume (Constant Density) 0 (ε=0)
liquid-phase and some of gas phase reaction system fall into this category.
PFR
X
dX
V FAo
0
rj
V V X
dX
FAo C Ao o C Ao 0 r j
X
dX
C Ao
0 rj
1 1
rA rA
Area Area
X CA
V VC Ao
Area= Area=
FAo C Ao FAo
5
First order and Irreversible :-
AB , rA kCA
CSTR PFR
FAo X X
dX
V V FAo
rA 0
rA
C Ao
CA C A C Ao e k
1 k
Second order and Irreversible :-
AB , rA kCA2
CSTR PFR
X
FAo X dX
V V FAo
rA 0
rj
C Ao C A 1 1 1 C Ao
k CA
C A2 k C A C Ao 1 C Ao k
,
Bimolecular Reactions
Stoichiometric Table Flow System
Specie Initial Change Remaining Concentration
A FAo -FAo X FA = FAo(1 – X) C A C A0 1 X
B FBo = FAo B -(b/a)FAo X FB = FAo[B –(b/a)X] b
CB C A0 B X
a
C FCo = FAo C +(c/a)FAo X FC = FAo[C +(c/a)X]
CC C A0 C X
c
a
D FDo = FAo D +(d/a)FAo X FD = FAo[D +(d/a)X] d
CD C A0 D X
a
I FI = FAo FI = FAo I C Io
FTo = FAo i FT = FTo +FAoX
i = Fio/FAo = Cio/CAo= yio/yAo = (d/a) + (c/a) – (b/a) - 1
6
Variable Volume (Variable Density, but with Constant T and P )
0 (1 X )
– Concentration (CSTR, PFR): C F j Pj
j
Z j RT j
FT P
– Total Concentration CT
ZRT
Fo Po
– At entrance to the reactor concentration Co
Z o RTo
FT T P0 Z
0
FT 0 T0 P Z 0
with constant temperature and pressure, and the compressibility factor will not
change significantly during the course of the reaction ,
FT
0
FT 0
F F j
C j To
0 FT
Fj
C j CTo
FT
n
Total molar flow rates FT=FA+FB+FC+FD+……= F
j 1
j
FT
FT = FTo +FAoX sub in 0
T0
F
FTo FAo X
0
FT 0
0 1 y Ao X
0 1 X
Molar flow rate of species j is Fj FA0 j j X
7
Stoichiometric Table Flow System
Concentration at variable volume or density
Specie
N FA0 1 X FA0 1 X C A0 1 X
CA A
V o (1 X ) (1 X )
N FA0 B - (b/a) X FA0 B - (b/a) X C Ao B - (b/a) X
CB B
V o (1 X ) (1 X )
N FA0 C (c/a) X FA0 C (c/a) X C Ao C (c/a) X
CC C
o (1 X ) (1 X )
V
N FA0 D - (d/a) X FA0 D (d/a) X C Ao D (d/a) X
CD D
V o (1 X ) (1 X )
N FA0 I FA0 I C Ao I
CI I
V o (1 X ) (1 X )
8
Non-Isothermal Operation Reactor
CSTR
Although the CSTR is well mixed and the temperature is uniform throughout the reaction
vessel , these conditions do not mean that the reaction is carried out isothermally.
Isothermal operation occurs when the feed temperature is identical to the temperature of
the fluid inside the CSTR.
FAo , To
Energy Balance in CSTR
FA , T , X Ta
FA , T , X
Heat Accumulated
Heat Flow Heat Flow Heat Generated by Heat Removal by
in
- out
+ Reaction
- wall
= by Reaction
No accumulation in CSTR (steady state operation) then:-
FAo i C piT tion
FAo i C piTio tion
tion H r T (rAV ) UA(T Ta ) 0
FAo i C pi Tio T H r T (rAV ) UA(T Ta ) 0
H r T (rAV ) UA(T Ta ) ………………1
T Tio
FAo i C pi
9
FAo X
For CSTR design equation V
rA
sub for FAo X rAV in energy balance equations then :-
FAo i C pi T Tio UA (T Ta )
X
H r T ………………2
PFR
V V V
Q
F jo Fj
Fi H i Fi H i
Tubular reactor with heat gain or loss
Consider a tubular reactor in which heat is either is add or removed through the cylindrical
walls of the reactor ,we assume that there are no radial gradients in the reactor and that the
heat flux through the wall per unit volume or reactor is shown in figure above.
Fi H i V Fi H i V V Q 0
Q UATa T
11
Ta= ambient temperature K ,T =reactor temperature K
Taking the limit V 0 , we get:-
d Fi H i
UATa T 0
dV
dFi
UATa T
dH i
H i Fi 0 ……………………………….3
dV dV
dFi
From mole balance of species i , ri i (ri ) …………………..4
dV
T
Enthalpy of each species i , H i H TR Cpi dT H io TR Cpi T TR
i
o
TR
dH i dT
Differentiating enthalpy equation with respect to V : Cpi …5
dV dV
Sub equation 4 and 5 in 3
UATa T i H i (ri ) Fi Cpi
dT
0
dV
UATa T H R (ri ) Fi Cpi
dT
0
dV
dT UATa T H R (ri ) Heat Heat
dV Fi Cpi generated removed
dT H R (ri ) UAT Ta
dV Fi Cpi
11