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Heat Exchangers Types & Applications, LMTD Derivation & Problems

1) A heat exchanger transfers heat from a hot fluid to a cold fluid without mixing the two fluids. Common types include shell and tube, plate, and compact heat exchangers. 2) The logarithmic mean temperature difference (LMTD) method is used to calculate the heat transfer rate in a heat exchanger. The LMTD accounts for varying temperature differences by using the mean temperature difference. 3) For a parallel flow heat exchanger, the LMTD is calculated as the difference between inlet and outlet temperatures divided by the natural log of the ratio of temperature differences. For a counter flow heat exchanger, the LMTD substitutes the cold fluid inlet for the hot outlet and

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100% found this document useful (3 votes)
5K views11 pages

Heat Exchangers Types & Applications, LMTD Derivation & Problems

1) A heat exchanger transfers heat from a hot fluid to a cold fluid without mixing the two fluids. Common types include shell and tube, plate, and compact heat exchangers. 2) The logarithmic mean temperature difference (LMTD) method is used to calculate the heat transfer rate in a heat exchanger. The LMTD accounts for varying temperature differences by using the mean temperature difference. 3) For a parallel flow heat exchanger, the LMTD is calculated as the difference between inlet and outlet temperatures divided by the natural log of the ratio of temperature differences. For a counter flow heat exchanger, the LMTD substitutes the cold fluid inlet for the hot outlet and

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ananth2012
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Chapter 4

Heat Exchangers
Types & Applications,
LMTD Derivation & problems

1
http://

HEAT EXCHANGERS www.chemicalpro


cessing.com/
articles/2013/
shell-and-tube-
Definition heat-exchanger-
best-practices/
A heat exchanger is defined as an equipment which transfers the heat
from a hot fluid to a cold fluid
fluid.

Types of heat exchangers:

Criteria for classification of heat exchangers:

(i) Nature of heat exchange process


(ii) Relative direction of fluid motion
(iii) Design and constructional features
(iv) Physical state of fluids

I Nature of heat exchange process:


I.

a) Direct contact heat exchangers or Open heat exchangers


Examples: Cooling g towers, Direct contact feed heaters
b) Indirect contact heat exchangers.
Examples: IC engines, gas turbines, Air pre heaters, Economisers. 2
HEAT EXCHANGERS
II. Relative direction of fluid motion:

a. Parallel flow heat exchanger – Fluids move in same direction


b Counter flow heat exchanger – Fluids move in opposite direction
b.
c. Cross flow heat exchanger – Fluids make right angle to each other

III. Design and constructional features:

a. Concentric tubes
b. Shell and tube (most widely used)
c
c. Multiple shell and tube passes
d. Compact heat exchangers

IV. Physical state of fluids:

a. Condensers
b. Evaporators.

3
HEAT EXCHANGERS
A li ti
Applications
• Automobiles (Radiators, Air preheater, Exhaust gas heat removal)
• Gas turbines
• Cooling towers
• Industrial Furnaces (Economizers)

Temperature variation in a heat exchanger

Parallel flow Counter flow

4
HEAT EXCHANGERS
Introduction to LMTD

• Temperature difference between the hot and cold fluids in a heat


exchanger varies from point to point

• In addition various modes of heat transfer are involved

• Hence,
Hence based on the concept of appropriate mean temperature difference
difference,
also called logarithmic mean temperature difference, the total heat transfer rate
in the heat exchanger is expressed as

Q = UA (∆T)lm

where

U – Overall heat transfer co-efficient, W/m2K


A – Area, m2
((∆T))lm – Logarithmic
g mean temperature
p difference.

5
HEAT EXCHANGERS
LMTD Derivation - Assumptions

In order to derive expression for LMTD for various types of heat


exchangers the following assumptions are made
exchangers,

1. Flow is steady
2. The overall heat transfer co-efficient is constant.
3. The specific heats of both fluids are constant.
4. The mass flow rate of both fluids are constant.
5. Axial conduction along the tube is negligible.
6 The chance in kinetic and potential energies of the fluids are negligible
6. negligible.

6
HEAT EXCHANGERS
LMTD Derivation – Parallel flow

A single pass parallel flow heat exchangers is shown in fig

Let us consider an elemental area dA of the heat exchanger.


The heat flow rate is given by

dQ = U dA (T – t) Æ(1)
Let
mh – Mass flow rate of hot fluid We know that
mc – Mass flow rate of cold fluid
Cph – Specific heat of hot fluid dQ = -mhCph dT = mcCpc dt Æ ((2))
Cpc – Specific heat of cold fluid dQ = -mhCph dT
T1 – Entry temperature of hot fluid dT = -dQ / mhCph
T2 – Exit temperature of hot fluid dT = -dQ / Ch [since Ch = mh x Cph] Æ (3)
t1 – Entry temperature of cold fluid
t2 – Exit temperature of cold fluid
U – Overall heat transfer co-efficient From equation (2),
dQ = mcCpc dt
dt = dQ / mcCpc
dt = dQ / Cc [since Cc = mc x Cpc] Æ (4)
7
HEAT EXCHANGERS
LMTD Derivation – Parallel flow
dT – dt = (–dQ / Ch) – (dQ / Cc)
= –dQ [(1 / Ch) + (1 / Cc)]

dθ = –dQ [(1 / Ch) + (1 / Cc)] [since dθ = dT – dt] Æ (5)

Substituting dQ value from Equation (1) in Equation (5),

dθ = – U dA (T – t) [(1 / Ch) + (1 / Cc)]


= – U dA θ [(1 / Ch) + (1 / Cc)] [since θ = T – t]
(dθ / θ) = – U dA [(1 / Ch) + (1 / Cc)]

Integrating
2

∫(dθ / θ) = – [(1 / Ch) + (1 / Cc)] ∫ U dA


1
2
[ln θ] = – U [(1 / Ch) + (1 / Cc)] A
1

[ln θ2 - ln θ1] = – U A [(1 / Ch) + (1 / Cc)]


ln (θ2 / θ1) = – U A [(1 / Ch) + (1 / Cc)] Æ (6)
8
HEAT EXCHANGERS
LMTD Derivation – Parallel flow
We know that,
Q = mhCph(T1 – T2) = mcCpc(t2 – t1)
Q = Ch (T1 – T2) = Cc (t2 – t1) [since C = m x Cp] Æ (7)
Q = Ch (T1 – T2)
1/Ch = (T1 – T2) / Q Æ (8)

From equation
F ti (7),
(7)
Q = Cc (t2 – t1)
1/Cc = (t2 – t1) / Q Æ (9)

Substitute 1/Ch and 1/Cc values in equation (6) and rearranging,


rearranging
ln (θ2 / θ1) = – U A [((T1 – T2) / Q) + ((t2 – t1) / Q)]
ln (θ2 / θ1) = – (U A / Q) [T1 – T2+ t2 – t1]

Q = – U A [T1 – T2+ t2 – t1] / ln (θ2 / θ1)


= U A [T2 – T1+ t1 – t2] / ln (θ2 / θ1)
= U A [(T2 – t2) – (T1 – t1)] / ln (θ2 / θ1)

Q = U A [(T2 – t2) – (T1 – t1)] / ln ((T2 – t2) / (T1 – t1)) [since θ = T – t]


Q = U A [(T1 – t1) – (T2 – t2)] / ln ((T1 – t1) / (T2 – t2)) Æ (10) 9
HEAT EXCHANGERS
LMTD Derivation – Parallel flow
Q = U A [(T1 – t1) – (T2 – t2)] / ln ((T1 – t1) / (T2 – t2))

(or)

Q = UA (∆T)lm

where (∆T)lm – logarithmic mean temperature difference


(∆T) lm = [(T1 – t1) – (T2 – t2)] / ln ((T1 – t1) / (T2 – t2))

10
HEAT EXCHANGERS
LMTD Derivation – Counter flow

Let
LMTD for Counter
flow heat exchanger mh – Mass flow rate of hot fluid
mc – Mass flow rate of cold fluid
Cph – Specific heat of hot fluid
Cpc – Specific
p heat of cold fluid
T1 – Entry temperature of hot fluid
T2 – Exit temperature of hot fluid
t1 – Entry temperature of cold fluid
t2 – Exit temperature of cold fluid
U – Overall heat transfer co-efficient

Q = UA (∆T)lm

where (∆T)lm – logarithmic mean temperature difference


(∆T) lm
l = [(T1 – t2) – (T2 – t1)] / ln ((T1 – t2) / (T2 – t1))

11

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