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Heat Load Computation Sheet

This document provides a heat load computation sheet for room RM 501, a laboratory room on the 5th floor of a building. It calculates the external and internal heat loads on the room from various sources. The external heat loads include heat from the walls, glass, solar gain, and partitions. The internal loads include sensible heat from lights, people, appliances, ductwork; and latent heat from people. The total effective room sensible heat load is calculated to be 48,286.07 BTUH.
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0% found this document useful (0 votes)
109 views5 pages

Heat Load Computation Sheet

This document provides a heat load computation sheet for room RM 501, a laboratory room on the 5th floor of a building. It calculates the external and internal heat loads on the room from various sources. The external heat loads include heat from the walls, glass, solar gain, and partitions. The internal loads include sensible heat from lights, people, appliances, ductwork; and latent heat from people. The total effective room sensible heat load is calculated to be 48,286.07 BTUH.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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HEAT LOAD COMPUTATION SHEET

Project: PUP – MAIN (South Wing)


Room #: RM 501 – CMIT Laboratory Room
Name of Area: 5th Floor
Sheet No.: 1/18
Prepared by: VALENCIA, Guillermo T.

I. External Heat Loads

ROOF
Qroof = UroofAroofCLTDroof
Since there is no roof on 5th Floor,
Qroof = 0

WALLS
𝐵𝑇𝑈
Q = U x A x CLTD; U = 0.263 ℎ𝑟−𝑓𝑡 2 −°𝐹 (From Table 6.3 in 1989 ASHRAE Handbook: Group F)

CLTDC = {(CLTDm + LM) (K) + (Tc – Tr) + (Tm – Ta)}


Where: CLTDC = Corrected Cooling Load Temperature Difference
CLTDm = Maximum Cooling Load Temperature Difference
LM = Latitude per Month
K = Correction Factor for Color of Surface
Tc = Human Comfort Body Temperature
Tr = Actual Room Temperature
Tm = Average Mean Temperature
Ta = Room Temperature Design

Anorth wall = Awall – Awindows From Table 6.2 ASHRAE Handbook Group F
Walls @1400 Hr. (Peak time 2 P.M)
Anorth wall = (29.68 ft. x 8.53 ft.) – (88.89 ft.2) CLTDm (north) = 17°F – North Exposure
Anorth wall = 164.28 ft.2 CLTDm (south) = 32°F – South Exposure
Asouth wall = Awall – Awindows – Adoors From Table 6.4 ASHRAE Manual, October
Design, Latitude/Month
Asouth wall = (29.68 ft. x 8.53 ft.) – (57.78 ft.2) – LM = -3 North
(44.42 ft.2) = 150.97 ft.2 LM = +7 South
Color Factor (K) = 0.83 (Rural Medium Color)

CLTDC (north) = {(17°F – 3) (0.83) + (78°F – 77°F) + (81°F – 85°F)} = 8.62°F (North Wall)
CLTDC (south) = {(32°F + 7) (0.83) + (78°F – 77°F) + (81°F – 85°F)} = 29.37°F (South Wall)

𝐵𝑇𝑈
Qnorth wall = U x A x CLTDC (north) = (0.263 ℎ𝑟−𝑓𝑡 2 −°𝐹) (164.28𝑓𝑡 2 )(8.62°F) = 372.43 BTUH
𝐵𝑇𝑈
Qsouth wall = U x A x CLTDC (south) = (0.263 ℎ𝑟−𝑓𝑡 2 −°𝐹) (150.97𝑓𝑡 2 )(29.37°F) = 1166.14 BTUH
Qt Walls = 1538.57 BTUH

GLASS CONDUCTION
𝐵𝑇𝑈 From Table A.8 - 1997 ASHRAE Handbook
Q = U x A x CLTD; U = 1.01 ℎ𝑟−𝑓𝑡 2 −°𝐹

CLTDC = 13°F From Table 6.5 1993 ASHRAE Handbook


@1400 Hr. (Peak time 2 P.M)
CLTDC = 13°F + 3°F = 16°F From Table 10 1993 ASHRAE Handbook Rule
(a) For Glass

Awindows (north) = 88.89 ft.2


Awindows (south) = 57.78 ft.2

Q = U x A x CLTD
𝐵𝑇𝑈
Qnorth = (1.01 ℎ𝑟−𝑓𝑡 2 −°𝐹) (88.89𝑓𝑡 2 )(16°𝐹) = 1436.46 BTUH
𝐵𝑇𝑈
Qsouth = (1.01 ℎ𝑟−𝑓𝑡 2 −°𝐹) (57.78𝑓𝑡 2 )(16°𝐹) = 933.72 BTUH
Qt Glass Conduction = 2370.18 BTUH
SOLAR HEAT GAIN
Q = A x SC x SHGF x CLF
Where: A = Area of glass
SC = Shading Coefficient
SHGF = Solar Heat Gain Factor
CLF = Cooling Load Factor

Awindows (north) = 88.89 ft.2


Awindows (south) = 57.78 ft.2

SC = 0.81 From Table 6.7 1993 ASHRAE Handbook, for


Single clear glass with dark interior
shading

𝐵𝑇𝑈
SHGFnorth = 33.28 From Table 15, at 16° Latitude/October
ℎ𝑟−𝑓𝑡 2
𝐵𝑇𝑈 1997 ASHRAE Handbook
SHGFsouth = 150.26 ℎ𝑟−𝑓𝑡 2

CLFnorth = 0.86 From Table 6.10, at 2 P.M. for Glass


CLFsouth = 0.68 with Interior Shading (All Room
Constructions) 1989 ASHRAE Handbook

Q = A x SC x SHGF x CLF

𝐵𝑇𝑈
Qnorth = (88.89 𝑓𝑡.2 )(0.81) (33.28 ℎ𝑟−𝑓𝑡 2 ) (0.86 ) = 2060.72 BTUH
𝐵𝑇𝑈
Qsouth = (57.78 𝑓𝑡.2 )(0.81) (150.26 ℎ𝑟−𝑓𝑡 2 ) (0.68 ) = 4782.06 BTUH
Qt Solar Heat Gain = 6842.78 BTUH

CEILING
Qceiling = U x A x TD
Since there is no roof/ceiling on 5th Floor,
Qceiling = 0

PARTITIONS
𝐵𝑇𝑈
Qwest partition = U x A x TD; U = 0.263 ℎ𝑟−𝑓𝑡 2 −°𝐹 ; TD = 3°F
(From Table 6.3 in 1989 ASHRAE Handbook: Group F)

Awest partition = 187.51 ft.2

𝐵𝑇𝑈
Q = (0.263 ℎ𝑟−𝑓𝑡 2 −°𝐹) (187.41𝑓𝑡 2 )(3°F)
Qt Partition = 147.87 BTUH

EXTERNAL TOTAL HEAT LOAD


- Summation of #’s 1-6

QTotal External = 1538.57 + 2370.18 + 6842.78 + 147.87


QTotal External = 10899.40 BTUH

II. Internal Heat Loads

A. Sensible Heat Components


LIGHTS
QS = Input x CLF
Where: Input = Watts Actual Light Load
CLF = Cooling Load Factor of Lights (Depending on how long it is turned on)

CLF = 0.93 From Table 45 Group A in 1993 ASHRAE


Handbook: CLF when lights are on for 12
hours

QS = Input x CLF **RM 501 has 4 fluorescent lights


𝐵𝑇𝑈𝐻 QS = 114.17 BTUH x 4
QS = 36 W x 0.93 x 3.41 𝑊
QS = 114.17 BTUH / Light
QS Lights = 456.67 BTUH
PEOPLE
QS = No. of People x SHG x CLF
Where: SHG =Rate of Sensible Heat Gain from Occupants
CLF = Cooling Load Factor for People
**RM 501 has approximately 40 students a day
SHG = 250 BTU/H From Table 6.13 in 1997 ASHRAE Handbook
for moderately active office work
CLF = 0.89 From Table 6.14 in 1989 ASHRAE Handbook
CLF factors for people (10 hours after
people enter)

QS = (40 𝑠𝑡𝑢𝑑𝑒𝑛𝑡𝑠)(250𝐵𝑇𝑈𝐻)(0.97)
QS People = 𝟏𝟐𝟏𝟐𝟓. 𝟎𝟎 BTUH
APPLIANCES

QS = Heat Gain x CLF


Where: Heat Gain = Rate of Sensible Heat Gain from Equipment
CLF = Cooling Load Factor for Appliances

Heat Gain for Computers = 460.64 BTUH From Table 8 in 2001 ASHRAE Handbook for
Computers with Medium Monitor
Heat Gain for Ceiling Fans = 200 BTUH

CLF for Ceiling Fans = 1 From Table 39 in 1997 ASHRAE Handbook


for Hooded Equipment (12 hours
CLF for Computers = 0.87 operation)

**RM 501 has 35 personal computers and 4 ceiling fans

QS = (35 𝑐𝑜𝑚𝑝𝑢𝑡𝑒𝑟𝑠)(460.64 𝐵𝑇𝑈𝐻)(0.87) = 14026.49 BTUH


QS = (4 𝑐𝑒𝑖𝑙𝑖𝑛𝑔 𝑓𝑎𝑛𝑠)(200 𝐵𝑇𝑈𝐻)(1) = 800 BTUH
QS Appliances = 𝟏𝟒𝟖𝟐𝟔. 𝟒𝟗 BTUH

ROOM SENSIBLE HEAT LOAD


- Summation of #'s 1-3 x (1.05)

Q1-3 = (456.67 BTUH + 12125.00 BTUH + 14826.49 BTUH) x 1.05

QS Room = 𝟐𝟖𝟕𝟕𝟖. 𝟓𝟕 BTUH

DUCT HEAT GAIN


- 8% of Room Sensible Heat Load

QS = 28778.57 BTUH x 0.08


QS Duct Heat Gain = 𝟐𝟑𝟎𝟐. 𝟐𝟗 BTUH

DUCT LEAKAGE LOSSES


- 10% of Room Sensible Heat Load

QS = 28778.57 BTUH x 0.1


QS Duct Leakage Losses = 𝟐𝟖𝟕𝟕. 𝟖𝟔 BTUH
FAN HORSEPOWER
- 3% of Room Sensible Heat Load

QS = 28778.57 BTUH x 0.03


QS Fan HP = 𝟖𝟔𝟑. 𝟑𝟔 BTUH
FAN VENTILATION
QS = (1.10) x (CFM/person) x (To – Tr)
Where: CFM/person = Ventilation Requirement Rate
To = Outside Air Temperature
Tr = Room Temperature Design

CFM/person = 17 (From Table 2 in 2015 ASHRAE Handbook:


Design Criteria for Educational
Facilities)
To = 95°F
Tr = 77°F
𝐵𝑇𝑈𝐻
QS = 1.10 𝐶𝐹𝑀− °𝐹 x (17 CFM/person) x 40 persons x (95-77) °F = 13464.00 BTUH
QS Fan Ventilation = 𝟏𝟑𝟒𝟔𝟒. 𝟎𝟎 BTUH
EFFECTIVE ROOM SENSIBLE HEAT LOAD
- Summation of #’s 4-8

QERSHL = 28778.57 + 2302.29 + 2877.86 + 863.36 + 13464.0


QERSHL = 48286.07 BTUH

B. Latent Heat Components

PEOPLE
QL = No. of People x LHG x CLF
Where: LHG =Rate of Latent Heat Gain from Occupants
CLF = Cooling Load Factor for People
**RM 501 has approximately 40 students a day
LHG = 187.67 BTU/H From Table 3 in 1997 ASHRAE Handbook for
moderately active office work
CLF = 0.89 From Table 6.14 in 1989 ASHRAE Handbook
CLF factors for people (10 hours after
people enter)

QL = (40 𝑠𝑡𝑢𝑑𝑒𝑛𝑡𝑠)(187.67 𝐵𝑇𝑈𝐻)(0.97)


QL People = 𝟕𝟐𝟖𝟏. 𝟔𝟎 BTUH

APPLIANCES

QL = Heat Gain x CLF


Where: Heat Gain = Rate of Latent Heat Gain from Equipment
CLF = Cooling Load Factor for Appliances
Latent Load = 0 if appliance under exhaust hood (See Note # 2)

QL Appliances = 0

ROOM LATENT HEAT LOAD


- Summation of #'s 1-2 x (1.05)

Q1-2 = (7281.60 BTUH) x 1.05

QL Room = 𝟕𝟔𝟒𝟓. 𝟔𝟖 BTUH

DUCT HEAT GAIN


- 10% of Room Latent Heat Load

QL = 7645.68 BTUH x 0.10


QL Duct Heat Gain = 𝟕𝟔𝟒. 𝟓𝟕 BTUH

SUPPLY DUCT LEAKAGE


- 5% of Room Sensible Heat Load

QL = 7645.68 BTUH x 0.05


QS Supply Duct Leakage = 𝟑𝟖𝟐. 𝟐𝟖 BTUH

VENTILATION

QL = (CFM/person) x ΔW x 4840 x No. of person


Where: CFM/person = Ventilation Requirement Rate
ΔW = Change in Specific Humidity = W2 – W1

CFM/person = 17
(From Table 2 in 2015 ASHRAE Handbook: Design Criteria for Educational Facilities)
𝑘𝑔𝑤𝑣
W2 = W for 92°F DB/ 81°F WB = 0.0205 𝑘𝑔𝑑𝑎
𝑘𝑔𝑤𝑣
W1 = W for 77°F DB/ 55%RH = 0.00988 𝑘𝑔𝑑𝑎
𝑘𝑔𝑤𝑣
ΔW = 0.0106 𝑘𝑔𝑑𝑎

𝑘𝑔𝑤𝑣 𝑘𝑔𝑑𝑎
QL = (17 CFM/person) x 0.0106 x 4840 x 40 students
𝑘𝑔𝑑𝑎 𝐶𝐹𝑀−𝑘𝑔𝑤𝑣

QL Ventilation = 34886.72 BTUH


EFFECTIVE ROOM LATENT HEAT LOAD
- Summation of #’s 3-6

QERLHL = 7645.68 + 764.57 + 382.28 + 34886.72


QERLHL = 43679.25 BTUH

SUMMARY

A. Total Internal Heat Load = ERSHL + ERLHL = 48286.07 + 43679.25 =


Total Internal Heat Load = 91965.31 BTUH
B. Return Duct Heat Gain = 6% of A = 91965.31 BTUH x 6% = 5517.92 BTUH
C. Return Duct Leakage Losses = 3% of A = 91965.31 BTUH x 3%
Return Duct Leakage Losses = 2758.96 BTUH

Grand Total Internal Heat Load = Summation of A - C


= 91965.31 + 5517.92 + 2758.96
= 100242.19 BTUH

Total Room Heat Load = External Heat Load + GTIHL


= 10899.40 + 100242.19
= 111141.59 BTUH

TOTAL ROOM REQUIREMENT = 𝑇𝑅𝐻𝐿⁄12000 𝐵𝑇𝑈𝐻⁄𝑇𝑜𝑛𝑠


111141.59 𝐵𝑇𝑈𝐻
= 12000 𝐵𝑇𝑈𝐻
⁄𝑇𝑜𝑛𝑠

TOTAL ROOM REQUIREMENT = 9.262 TONS

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