JANGAN LUPA BAYAR Yach … OK!!!!!!!!!!!!
NGGAK ADA YG GRATIS DI DUNIA INI
(UANG ADALAH SEGALANYA)
50
2
51
2
52
53
54
2
55
2
56
57
2
3
58
2
59
2
60
61
2
62
63
1
2
110m/s
64
2
65
4
5
66
2
67
3
68
2
69
3
4
70
4
71
3
4
5
72
73
2
74
3
75
Apply the Arquimede´s Principle to the bubble inside the water
76
3
77
Fb
= ρmilk g V
The normal force FN
exerted (upward) on the glass ball of mass m has magnitude
0.0948 N. The buoyant force exerted by the milk (upward) on the ball has magnitude, where V =
πr
3
is the volume of the ball. Its radius is r = 0.0200 m. The milk density is
ρmilk = 1030 kg/m3
. The (actual) weight of the ball is, of course, downward, and has
magnitude Fg
= mglass g. Application of Newton's second law (in the case of zero
acceleration) yields
FN
+ p(milk) g V − m(glass) g = 0
which leads to mglass = 0.0442 kg. We note the above equation is equivalent to Eq.14-19
in the textbook
m = 0.0442kg
78
79
31N - 26N = 5N
Loss of weight in the liquid.
31N - 22N = 9N
Loss of weight in the water.
3
5/9
density of the loss of liquid / density of the loss water
5/9 * 1000 kg/meters cubed = 555.6 kg/meters cubed
Density of the unknown liquid.
80
81
4
82