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Anchor Bolt Design Analysis

The document summarizes the design of anchor bolts to support an axial load of 7 kN. It specifies the material properties and dimensions of grade A307 anchor bolts with a 20 mm diameter. Calculations show the bolt satisfies requirements for both tension and shear strength with a safety factor of 11.11. An embedment length of 200 mm is selected, which exceeds the minimum required length of 18.83 mm.

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311 views6 pages

Anchor Bolt Design Analysis

The document summarizes the design of anchor bolts to support an axial load of 7 kN. It specifies the material properties and dimensions of grade A307 anchor bolts with a 20 mm diameter. Calculations show the bolt satisfies requirements for both tension and shear strength with a safety factor of 11.11. An embedment length of 200 mm is selected, which exceeds the minimum required length of 18.83 mm.

Uploaded by

Anonymous qejp7t
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© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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The maximum load is considered as 30 kN and the anchor bolt design is based on this.

Data:
Axial load Fc = 7.00 kN
Shear along - X Fx = 0.00 kN
Shear along - Z Fz = 0.00 kN
Resultant shear FR = Sqrt(0^2+0^2)
Details of the anchor bolt connections = 0.00 kN
ASTM A 307 Grade A Foundation anchor bolts
Allowable tensile stress on bolt 0.75fu
Allowable shear stress on bolt 0.40fu
Allowable tensile stress on bolt Table J3.2 AISC 360-05 = 310 N/mm2
Allowable shear stress on bolt Table J3.2 AISC 360-05 = 165 N/mm2
Grade of the foundation concrete = C 35
Diameter of Anchor bolt selected = 20 mm
Net area of anchor bolt = 245 mm2
Number of Anchor bolts on one side = 1 No.
No of sides = 1 No.
Total area of Anchor bolts under Tension = 1*245
Ast = 245 mm2
Total no of bolts = 1X1
= 1 No.
Check for shear:
Resultant shear FR = (Fx2 + Fz2)1/2
= (0^2+0^2)^1/2
= 0.00 kN
Shear strength of bolt Fs = 245*0.165
= 40.425 kN
0.00 < 40.43 SAFE
Tensile force in one bolt Pt,act = 7/1/1 kN
= 7 kN
Allowable tensile stress s tall = 310 N/mm2
Tensile strength of one bolt Pt,allow = 0.31x245/1 kN
= 76
0.80 Tall = 0.80 x76 kN
= 60.8

Shear stress in one bolt FR,act = 0/1/1 kN


= 0.00
Shear strength of one bolt FR,allow = 40.425/1/1 kN
= 40.4 kN

(Pt,act / Pt,allow) + (FR,act / FR,allow) ≤ 1


(Pt,act / Pt,allow) + (FR,act / FR,allow) = (7/76)+(0/40.4)

(Pt,act / Pt,allow) + (FR,act / FR,allow) = 0.09


0.09 < 1.00
Factor of safety 1/0.09 = 11.11
HENCE SAFE
Use 1 no of dia. 20 bolts M20 type at each support
Foundation anchor bolts ASTM A 307 Grade A

Check for embedment length: l = Pt,act / (fb π Φ)


Pt,act = 7 kN
Φ = 20 mm
fb = √fc'
= C 35 N/mm²
fb = C 35 N/mm2
= 5.91608 N/mm2
l = 18.8315 mm
l = 18.8315 mm
Ld = 200 mm
N/mm2
N/mm2

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