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16-Bit Addition with 8085 Program

The document describes an assembly language program that adds two 16-bit numbers using an 8085 microprocessor. The program loads the two 16-bit numbers from memory locations, adds them together, stores the result and any carry back to memory. It provides the algorithm, flowchart and sample assembly language program to perform 16-bit addition on the 8085 microprocessor.

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Raja Patel
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2K views2 pages

16-Bit Addition with 8085 Program

The document describes an assembly language program that adds two 16-bit numbers using an 8085 microprocessor. The program loads the two 16-bit numbers from memory locations, adds them together, stores the result and any carry back to memory. It provides the algorithm, flowchart and sample assembly language program to perform 16-bit addition on the 8085 microprocessor.

Uploaded by

Raja Patel
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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EX.

NO: 16-BIT ADDITION USING 8085


DATE:

AIM:
To learn to write an assembly language program for adding two sixteen bit numbers.

APPARATUS REQUIRED:
 8085 Microprocessor kit,
 Power supply

ALGORITHM:
 Start the program.
 Enter the 1st input in one memory location.
 Enter another input in other memory location.
 Add two inputs.
 Store the result and carry in different memory locations.
 Stop the program.

FLOWCHART:
START

Get the 1stnumber

Get the2ndnumber

Add two number

Is
carry=1

Store the carry

Store the result

STOP
PROGRAM

ADDRESS OPCODE LABEL MNEMONICS COMMENTS


;Load the HL register in
LHLD 4200 H
4100 2A,00.42 ;4200
4103 EB XCHG ;Exchange the contents
4104 2A,02,42 LHLD4202 H ;load the register in4202
4107 AF XRA A
4108 19 DAD D ;Add D with register
;Store the HL register
JNC L1
4109 D2,0D,41 in4204
;Increment the
INR A
410C 3C ;accumulator
;Store the HL register pair
L1 SHLD 4204 H ;location 4204 in the
410D 22,04,42 ;memory
;Store the accumulator
STA 4206 H ;location 4206 in the
4110 32,06,42 ;memory
4113 76 HLT ;Stop the execution

MANUAL CALCULATION:

DATA 1= 1C 15 H
DATA 2 =5A B7 H (+)

SUM = 76 CC H
ADDRESS DATA

Input
4200 15 H (LSB OF DATA 1)
4201 1C H (MSB OF DATA 1)
4202 B7 H (LSB OF DATA 2)
4203 5A H (MSB OF DATA 2)
Output
4204 CC H (LSB OF SUM)
4205 76 H (MSB OF SUM)

Result

Addition of two 16-bit numbers using 8085 is performed and the output is verified.

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