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Single-Phase Transformer: 2 Windings (Primary & Secondary) Around A Magnetic Core (Magnetic Coupling)

Single-phase transformers have two windings (primary and secondary) around a magnetic core. Changes in the primary current induce voltages in the secondary winding via Faraday's law of induction. The ratio of the number of turns determines the voltage transformation ratio between the windings. Transformers convert electric energy from one voltage level to another through magnetic coupling of the windings.
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0% found this document useful (0 votes)
88 views10 pages

Single-Phase Transformer: 2 Windings (Primary & Secondary) Around A Magnetic Core (Magnetic Coupling)

Single-phase transformers have two windings (primary and secondary) around a magnetic core. Changes in the primary current induce voltages in the secondary winding via Faraday's law of induction. The ratio of the number of turns determines the voltage transformation ratio between the windings. Transformers convert electric energy from one voltage level to another through magnetic coupling of the windings.
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© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Single-phase transformer

2 windings (primary & secondary) around a magnetic core


(magnetic coupling)

Faraday’s law
A time-dependent (varying) magnetic flux
density in the magnetic core induces (time-
dependent) electromotive forces (e.m.f.s) in
each winding

The voltage in each winding (~) is


proportional to the number of turns

Open or closed secondary ...

Electric energy conversion from one voltage level to another

21/02/2017 Transformers 1
General transformer relations
Useful flux F
Primary winding equation
F1 = F + F f 1 F 2 = -F + F f 2
u1 = R1 i1 + n1 ¶ t F1 = R1 i1 + n1 ¶ t Ff 1 + n1 ¶ t F
e.m.f in 1
u1 = R1 i1 + l1 ¶ t i1 + e1 due to F

Secondary winding equation

u 2 = -R 2 i 2 - n 2 ¶ t F 2 = -R 2 i 2 - n 2 ¶ t F f 2 + n 2 ¶ t F
Leakage flux
ni n i u 2 = -R 2 i 2 - l 2 ¶ t i 2 + e 2 e.m.f.
F f 1 = 1 1 et F f 2 = 2 2 in 2
Rf1 Rf 2 due to F
Coupling equation
Leakage reluctances
n i - n 2i 2 n12 æ n ö
F = 11 Þ e1 = çç ¶ t i1 - 2 ¶ t i 2 ÷÷
e1 n1 R Rè n1 ø
= =n
e2 n 2 Transformation ratio Magnetic circuit reluctance magnetizing inductance lµ
Transformers 2
Transformer equivalent circuit
u1 = R1 i1 + l1 ¶ t i1 + e1 (a)

u 2 = -R 2 i 2 - l 2 ¶ t i 2 + e 2 1 1
e1 = n u 2 + n 2 R 2 i 2 + n 2 l 2 ¶ t i 2
n n
e1 n1
= =n Secondary quantities as seen from the primary
e2 n 2
e1 = u '2 +R '2 i'2 +l'2 ¶ t i'2 (b)

æ n ö
e1 = lµ çç ¶ t i1 - 2 ¶ t i 2 ÷÷ e1 = lµ (¶ t i1 - ¶ t i'2 ) (c)
è n1 ø

(a) (c) (b)

Transformers 3
Complex formalism: phasors
Complex representation of sinusoidal quantities

a(t ) = A cos(wt + j) A maximum value (amplitude) of a(t) [V, A, ...]


w pulsation of a(t) (2pf, f = frequency) [rad/s]
Sinusoidal quantity
(voltage, current, ...) j phase of a(t) at t = 0 [rad]

(
a ( t ) = Re A e j j e j wt )
jj Im[.] Complex plane
with e = cos j + j sin j

A = A e jj A
j
Quantity as a phasor Re[.]
a(t=0)

( ) ( ) ( )
Re A e j j e j wt = Re A e j j+ j wt = Re A e j (wt + j)
= Re(A cos(wt + j) + j sin(wt + j) )
= A cos(wt + j)

Transformers 4
Limit cases with phasors
No-load case _ _ _ jXµ _
I'2 = 0 Þ U'2 = E1 = U1
R1 + jX1 + jXµ
R1, X1 << Xµ (ratios ~ 400 X, 4000 R)

U1
U'2 » U1 =n
U2
I1 = Iµ << Inominal

Short-circuit case _ _
I R '2 + jX'2 + jXµ
U'2 = 0 Þ _1 =
I'2 jXµ
R '2 , X'2 << Xµ (ratios ~ 400 X, 4000 R)

I1 1
I1 » I'2 =
I2 n
I1 >> !
Transformers 5
Operating points
Simplified equivalent circuit

Phasor representation Exterior characteristic

Transformers 6
Magnetic losses and saturation
Hysteresis & eddy currents

Eddy current losses


proportional to b2, hence to F2, hence to E12

Idem for hysteresis losses (approx.)

E12
p mag = K mag E12 =
R H+F
(frequency dependent!)

Saturation

Transformers 7
Equivalent circuit parameters
Experimental determination of the parameters
from the equivalent circuit

No-load test I << Þ p Joule primary


primaire <<

U12 U12
Pv = Qv =
R H+F Xµ

Short-circuit test U1 << Þ p mag <<

Pcc = (R1 + R '2 ) Icc


2
Qcc = (X1 + X'2 ) Icc
2

Transformers 8
Construction types
Transformer with separate columns

High leakage flux

Transformer with concentric windings

Series or parallel connection of windings


1 : High Voltage, 2 : Low Voltage

Shell-type transformer (« cuirassé »)

1 : High Voltage, 2 : Low Voltage

Transformers 9
Three-phase transformer

3 single-phase transformer Geometric symmetry

advantages!

3 primary windings and 3 secondary


windings with star or triangle connection
Fa + F b + Fc = 0

Three columns Five columns Shell-type

Transformers 10

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