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Portfolio in Descriptive Statistic of Mathematics in Modern World

1) The document summarizes statistical data from a sample of 25 students, including measures of central tendency, dispersion, and graphical representations. 2) The mean weight was 50.44kg, the median was 48kg, and the modes were 43kg, 45kg, 48kg, and 50kg. 3) The range of weights was 48kg, and the standard deviation was calculated to be 9.73kg.

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Jam Gonzales
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0% found this document useful (0 votes)
54 views11 pages

Portfolio in Descriptive Statistic of Mathematics in Modern World

1) The document summarizes statistical data from a sample of 25 students, including measures of central tendency, dispersion, and graphical representations. 2) The mean weight was 50.44kg, the median was 48kg, and the modes were 43kg, 45kg, 48kg, and 50kg. 3) The range of weights was 48kg, and the standard deviation was calculated to be 9.73kg.

Uploaded by

Jam Gonzales
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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PORTFOLIO IN

DESCRIPTIVE STATISTIC
OF MATHEMATICS IN
MODERN WORLD
I-7 Group 5

Leader :
Gonzales, Jamela Marie V
Member :
Fernandez, Donna Mae
Germano, Princess Abegaile
Germono, Michelle
Gusi, Angelika
POPULATION
40, 42, 43, 43, 43, 44, 45, 45, 45, 46, ,48, 48, 48, 50, 50, 50, 51.1, 52, 52, 52, 54, 58, 61, 63, 88
𝑵
Sample: n=
𝟏+𝑵𝒆²

E(margin of error 2%)


25 25 25
n=1+(25)(.02)²= 1+.01= 1.01= 24.75= 25 students

Explanation :

Margin of errors, in statistics, is the degree of error in results received from random
sampling surveys. A higher margin of error in statistics indicates less likelihood of relying on the results of
a survey or poll, i.e. the confidence on the results will be lower to represent a population. Lower margin of
error indicates higher confidence levels in the produced results. (Surendran, 2019). We used the 2% of
margin of error because we already have a low population. We get 24.75 sample size when we round off
it still 25. So we have 25 sample size that we will use for the following data.
TABULAR PRESENTATION

DATA TARA PERCENT


40 I 4%
42 I 4%
43 III 12%
43
43
44 I 4%
45 III 12%
45
45
46 I 4%
48 III 12%
48
48
50 III 12%
50
50
51.1 I 4%
52 III 12%
52
52
54 I 4%
58 I 4%
61 I 4%
63 I 4%
88 I 4%
25 STUDENTS 100%

Explanation:
II. GRAPHICAL PRESENTATION
BAR GRAPH

Weight of student
92
89
86
83
80
77
74
71
68
65
62
59
56
53
50
47
44
41
38
35

Explanation :
LINE GRAPH

Weight of student
100
90
80
70
60
50
40
30
20
10
0

Explanation:
PIE GRAPH

Weight of student

45 43
42 46 54 52
48 44 52
50
50
40 50
43
43
45 58
48 63
61 51.1
52 88
48 43

female female female female male male female female male


female female male male male male male female female
female female female female female female female

Explanation:
PICTOGRAPH
Weight Equivalent

40
42

43

44
45
46
48

50

51.1

52

54

58

61

63

88

Legend
= 2 Person = 1 Person Explanation:
Stem and Leaf Plots

0 2 3 3 3 4 5 5 5 6 8 8

5 0 0 0 1.1 2 2 2 4 8

6 1 3

8 8

Explanation:
THE STATISTICAL DATA OF WEIGHT IN I-19 FROM DFCAM-CLP STUDENTS

DATA X µ x-µ (x-µ)²


54 40 50.44 -10.44 108.99
52 42 50.44 -8.44 71.23
43 43 50.44 -7.44 55.35
52 43 50.44 -7.44 55.35
50 43 50.44 -7.44 55.35
50 44 50.44 -6.44 41.47
45 45 50.44 -5.44 29.59
46 45 50.44 -5.44 29.59
58 45 50.44 -5.44 29.59
63 46 50.44 -4.44 19.71
51.1 48 50.44 -2.44 5.95
88 48 50.44 -2.44 5.95
43 48 50.44 -2.44 5.95
48 50 50.44 -0.44 0.19
52 50 50.44 -0.44 0.19
61 50 50.44 -0.44 0.19
48 51.1 50.44 0.66 0.44
43 52 50.44 1.56 2.43
45 52 50.44 1.56 2.43
40 52 50.44 1.56 2.43
48 54 50.44 3.56 12.67
50 58 50.44 7.56 57.15
45 61 50.44 10.56 111.51
44 63 50.44 12.56 157.75
42 88 50.44 37.56 1410.75
III. MEASURE OF CENTRAL TENDENCIES

∑𝑥
MEAN: =
𝑛
1261.1
25
= 50.44kg

MEDIAN: Odd number 25, We only get the middle number.

48kg

MODE:

43kg, 45kg, 48kg, 50kg, 52kg (POLYMODAL)

IV. MEASURE OF DISPERSION

RANGE: Highest-Lowest

88-40= 48kg

∑(𝑥−𝑥)²
STANDARD VARIATION: s=√
𝑛−1

2,272.21
s=√ 24
= √94.68 = 9.73

∑(𝑥−𝑥)²
VARIANCE s²=√ 𝑛−1

𝜎=97.3² = 94.67

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