Question no.
1
Classify the following as qualitative or quantitative variables.
i.     Weight measurements of students
ii.    Race of the people of a country
iii.   Likings or dislikings of 1000 persons for a certain product
iv.    Expenditure Government servants of a city
v.     Color of eyes of 1000 persons
Solution:
i.     Quantitative
ii.    Qualitative
iii.   Qualitative
iv.    Quantitative
v.     Qualitative
Question no.2
Define quantitative and qualitative variables.
Solution:
Quantitative variable:
        A variable is called a quantitative variable when a characteristic can be expressed
numerically such as age, weight, income or number of children.
Qualitative variable:
        If the characteristic is non-numerical such as education, sex, eye-color, quality,
intelligence, poverty, satisfaction, etc. the variable is referred to as a qualitative variable.
A qualitative characteristic is also called an attribute.
Question no.3
Name five fields where statistics can contribute?
Business and industry
Health and medicine
Natural and social sciences
Natural resources
Education, Government media and law
Question no.4
Find the Cumulative frequencies for the frequency distribution given below:
  Out put in
                 50 - 59    60 -69     70 - 79     80 - 89     90 - 99    100 - 109
    tons
      f             3         11          19          28         20           15
                                                           Cumulative
       Out put in tons                   f                 Frequency
                                                              (F)
             50-59                       3                       3
             60-69                      11                      14
             70-79                      19                      33
             80-89                      28                      61
             90-99                      20                      81
            100-109                     15                      96
             Total                      96                      ….
Question no.5
If frequency =15 and frequency density=0.3, then find the class width.
Solution:
Frequency density= frequency/class width
Calss width=frequency/frequency density=15/0.3=50
Question no.6
Calculate the frequency density when class width =6 and frequency=24
Solution:
Frequency density= frequency/class width
              =24/6=4
Question no.7
Find the frequency density for the distribution given below:
     Class
                 50 - 59     60 -69      70 - 79    80 - 89     90 - 99   100 - 109
   intervals
       f              4        11            18       28             22      15
Solution:
      Class intervals               Class width                  f             Frequency density
                                                                                      (F)
             50-59                      9                        4                    4 /9
             60-69                      9                       11                    11/9
             70-79                      9                       18                    18/9
             80-89                      9                       28                    28/9
          90-99                      9                       22                     22/9
         100-109                     9                       15                     15/9
Question no.8
Find the Relative frequencies for the frequency distribution given below:
  Out put in
                50 - 59    60 -69    70 - 79    80 - 89      90 - 99    100 - 109
    tons
      f            15        12           10       28          25           10
                                                           Relative
       Out put in tons               f                    Frequency
                                                             (F)
          50-59                      15                 15/100=0.15
          60-69                      12                 12/100=0.12
          70-79                      10                   10/100=0.1
          80-89                      28                 28/100=0.28
          90-99                      25                 25/100=0.25
         100-109                     10                  10/100=0.1
          Total                     100                      ….
Question no.9
Following is the group frequency distribution of 94 students which shows their test result
in a class. Find the arithmetic mean.
                        Class Interval            No. Of Students
                            10-20                         5
                            20-30                        16
                            30-40                        12
                            40-50                        25
                            50-60                        17
                            60-70                         8
                            70-80                         6
               Class Interval       f1           Class                 X1           fxi
                                               Boundry
                   10-20             5          9.5-20.5      (9.5+20.5)/2=15         75
                   20-30            16         19.5-30.5            25               400
                   30-40            12         29.5-40.5            35               420
                   40-50            25         39.5-50.5            45              1125
                   50-60            17         49.5-60.5            55               935
                   60-70             8         59.5-70.5            65               520
                   70-80             6         69.5-80.5            75               450
                           Arithmetic mean = Sum fxi/sumf = 3925/89= 44.10
       Note: Class boundry column is not necessary. If student directly calculate Xi by
       taking average of class interval then it is also correct.
       Question no.10
       Complete the following table by finding angles for the pie chart:
                 Medium of
                                             Frequency         Angle
                 Institution
                 Urdu                        436
                 English                     764
                                             1200
       Medium of
                                      Frequency        Angle
       Institution
       Urdu                           436              130.8
       English                        764              229.2
                                      1200             360o
       Question no.11
       For grouped data the median is given by:
                   h n     
       M e  Lo    F 
                   fo  2   
       in this formula what these things stands for?
       Lo , f o , h, F
         L0 = Lower class boundary of the median class
h = Width of the median class
f0 = Frequency of the median class
F = Cumulative frequency of the pre-median class
       Question no.12
       The data of profit (in Rs lakh) earned by 60 companies is given below:
Profits                  Below 10      10-20        20-30    30- 40    40-50        50 and over
No. of companies         5             18           22       16        7            2
Cumulative               5             23           45       61        68           70
frequency
Find Median for the above data.
Median= size of n/2 th observation which lies in the class 20-30
                       h n    
               Q2  l     C
                        f 2   
                         10
               Q2  20   35  23
                          22
               Q2  20  5.45
                    25.45 lakh
Question no.13
Consider the data set:       67   25   42      57     38    49    36   29      61       31   71 53 73
84 87
Find the 50th percentile point.
First arrange the data in ascending order
25 29 31 36 38 42 49 53 57 61 67 71 73 84 87
Location of 50th Percentile is (15+1) (50/100) = 8th value = 53
Question no.14
Give a five number summary of the data.
            15, 17, 18, 19, 35, 25, 14, 45, 37, 51, 42
Re arrange data in ascending order
       14, 15, 17, 18, 19, 25, 35, 37, 42, 45, 51
Minimum = 14
First Quartile = ( 11+1)(25/100) = 3rd position = 17
Median = 25
Third Quartile = (11 + 1) ( 75/100) = 9th position = 42
Maximum = 51