SAMPLE BEAM- COLUMN MOMENT CONNECTION AS PER IS 800: 2007
The moment connection from sample drawing number PDRP0142-8320-46-023-0262
 is considered for prepararing the sample calculations
The picture showing the beam-column moment joint connection is as follows
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The following codes were refered in preparing the moment connection calculations
        1) IS 800 - 2007
        2) IS 3757 - 1985 ( Reaffirmed 1998)
        3) IS 4000 - 1992( Reaffirmed 1998)
        4) SP 6 (4) - 1969 ( Reaffirmed 1995)
        5) IS 12278 - 2004
        6) IS 808 - 1989( Reaffirmed 1999)
        7) IS 2062
While preparing the connection details the following inputs are assumed
- It is assumed that connection to be designed for Special Moment
Frame SMF (Clause 12.11 / IS 800 -2007)
- Grade B steel is used - E250 B as per IS 2062
-Bolts are high strength of property class 8.8 comforming to IS 4000
( for mechanical properties)
- The HSFG bolts conform to IS 3357 (for bolt sizes) - Diameter of bolt - M36
- Beam section - WPB 900 x 300 ( Mass 198 kg /m) -IS12278 - 2004
(Plates are not considered for simplicity of calculation)
-The joint is designed for a moment of 1.2 Mp as per clause 12.11.2.1
-The joint is designed for 60% of shear capacity of the beam (It should be done for
 load data related to shear forces from seismic combinations - Cl 12.2.3 )
-The column stiffner calculations are not shown presently.
- The beam end plate thickness calculations are not shown presently
-The weld calculations for end plate connection to the beam not shown presently.
-The prying forces are accounted in the HSFG bolt tension calculations
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-It is to be noted that HSFG bolts are designed for no slip condition at both
serviceability and ultimate limit state condition.
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Connection design:
Design force M =                   1.2 Mp
                  V=               0.6 Vp
Section properties of beam                                   WPB       900      x 300
      d=            830 mm                           fy =                250 Mpa
      D=            870 mm                           Zpx =           7999.37 cm3
       T=            20 mm
      tw =          15 mm
Plastic moment capacity Mp = fy x Zpx
             Mp =            250 x 7999370.00                        = 1999.84 kN-m
Plastic shear capacity Vp = ( Ar x fy x tw)/ √3
             Vp =            870              x 15           x 250
                                                √3
                             = 1883.61 kN
Design force M =                   1.2 Mp            = 2399.81 kN-m
                    V=             0.6 Vp            = 1130.17 kN
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Calculation of bolt forces :
It is assumed bolt forces 2F1 = 2F2
by taking moments about the centre of the bottom flanges
M =          ( 2F1 + 2F2 ) x 850 + 2F3 x 680 + 2F4 x 580 + 2F5 x 480 + 2F6x 370
             + 2F7 x 270 + 2F8 x 170 + 2F9 x 70
             Calculating in terms of F1
M =          ( 2F1 + 2F1 ) x 850 + ( 2F1 x 6802 / 780) + ( 2F1 x 5802 / 780) +
             + (2F1 x 4802 / 780) + (2F1 x 3702 / 780) + (2F1 x 2702 / 780) +
             + (2F1 x 1702 / 780) + (2F1 x 702 / 780)
M =          ( 2F1 + 2F1 ) x 850 + ( (2F1 /780 ) x ( 6802 + 5802 + 4802 + 3702 + 2702 + 1702 +702 ) )
    =        4F1 x 850 + 2F1 x      1631.794871795
    =        F1 x ( 4 x 850 + 2 x 1631.75 )
    =        F1 x 6663.6
      F1 =      M    =                  2399.81 x    106                     = 360.14 kN
              6663.6                          6663.6
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Calculation of prying force ( Clause 10.4.7)
                       l                      f o be t 4 
                    Q v               Te            2
                                                            
                      2 le                   27 l  l
                                                    e v     
                      l   v
                              =       (150 / 2) -(15/2) - 8 = 59.5 mm
                      l=  e           (450 -150)/2 = 150 mm
           Prying force Q =
      Q = (59.5 / (2 x 150)) x { 300.03 - [(1.0 x 1.5 x 0.56 x 300 x 56 4 )/( 27 x 150 x 59.52)] }
      Q = 0.19 x ( 300.03 - 172) = 24.3 kN
Hence, tension in the fartest bolt (T e) =                    360.14 kN
                                  Prying force Q =              24.3 kN
           Total bolt tension = Te + Q
                      =                        360.14 + 24.30 =           384.4 kN
           Shear force in each bolt =                  V / no. of bolts
                      =                    1130.2      =                  70.64 kN
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