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Koomey 2

The accumulator is a unit that stores gas and hydraulic fluid under pressure to operate hydraulic systems like blowout preventers (BOPs) on an oil rig. It supplies hydraulic power to open and close the BOP stack for normal operations and emergencies. Stored hydraulic fluid in the accumulator can provide power to close the BOPs during a well kick to minimize the kick volume. Accumulators must have sufficient volume to open and close all preventers and maintain pressure at all times.

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100% found this document useful (1 vote)
181 views2 pages

Koomey 2

The accumulator is a unit that stores gas and hydraulic fluid under pressure to operate hydraulic systems like blowout preventers (BOPs) on an oil rig. It supplies hydraulic power to open and close the BOP stack for normal operations and emergencies. Stored hydraulic fluid in the accumulator can provide power to close the BOPs during a well kick to minimize the kick volume. Accumulators must have sufficient volume to open and close all preventers and maintain pressure at all times.

Uploaded by

nabi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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Accumulator (Koomey) is a unit used to hydraulically operate Rams BOP, Annular BOP,

HCR and some hydraulic equipment. There are several of high-pressure cylinders that
store gas (in bladders) and hydraulic fluid or water under pressure for hydraulic activated
systems. The primary purpose of this unit is to supply hydraulic power to the BOP stack
in order to close/open BOP stack for both normal operational and emergency situation.
Stored hydraulic in the system can provide hydraulic power to close BOP’s in well control
operation, therefore, kick volume will be minimized. Accumulators should have sufficient
volume to close/open all preventers and accumulator pressure must be maintained all
time.

This post you will learn how to calculate usable volume per bottle by applying Boyle’s
gas law:

Use following information as guideline for calculation:

Volume per bottle = 10 gal


Pre-charge pressure = 1000 psi
Operating pressure = 3000 psi
Minimum system pressure = 1200 psi
Pressure gradient of hydraulic fluid = 0.445 psi/ft
For surface application
Step 1 Determine hydraulic fluid required to increase pressure from pre-charge
pressure to minimum:
Boyle’s Law for ideal gase: P1 V1 = P2 V2
P1 V1 = P2 V2

1000 psi x 10 gal = 1200 psi x V2

10,000 ÷ 1200 = V2

V2 = 8.3 gal

It means that N2 will be compressed from 10 gal to 8.3 gal in order to reach minimum
operating pressure. Therefore, 1.7 gal (10.0 – 8.3 = 1.7 gal) of hydraulic fluid is used for
compressing to minimum system pressure.

Step 2 Determine hydraulic required increasing pressure from pre-charge to


operating pressure:
P1 V1 = P2 V2

1000 psi x 10 gals = 3000 psi x V2

10,000 ÷3000 = V2

V2= 3.3 gal

It means that N2 will be compressed from 10 gal to 3.3 gal. Therefore, 6.7 gal (10.0 –
3.3 = 6.7 gal) of hydraulic fluid is used for compressing to operating pressure.

Step 3 Determine usable fluid volume per bottle:


Usable volume per bottle = Hydraulic used to compress fluid to operating pressure –
hydraulic volume used to compress fluid to minimum pressure

Usable volume per bottle = 6.7 – 1.7

Usable volume per bottle = 5.0 gallons

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