NBC RULE 7/8 ALE

Based on Current Trends

Ar. Runddy D. Ramilo, Assoc. AIA, UAP

PhD (Architecture) UTM/ Deakin U, Aus.
Founder & Studio Master, ArcStudio
 Your Design Board Exam
Based on Current Trends

Rule 7 & 8 + Estimates + General Terms

(10 Design Problems) 200 questions

Rule 7 & 8 = 40%

Estimates = 50%
General Terms =10%
Rule 8: Light and Ventilation
Computations based on Ar. Cordero Interpretation

AMBF- Allowable maximum building footprint

PSO-Percentage of site occupancy
TLA-Total lot area
ISA-Impervious surface area
USA-Unpaved surface area
MACA-Maximum Allowable Construction Area
TOSL- Total Open Space within Lot
BHL-Building Height Limit
Estimates (Frequently asked questions)
Ceiling tiles 0.60m x 1.20m
Ceiling tiles 1.20m x 1.20m
Roof beam estimates in cu.m.
Slab estimates in cu.m.
Estimates for Class A, B and C concrete mixtures
Computation of concrete in cu.m. and steel bars
Marble flooring 0.60m x 0.60m Ceramic tiles 0.30m x 0.30m
Painting for 2 and 3 coating
Linear meter of fences in the property
Linear meter of walls.
Computation of paints
Computation of floor area in square foot.
Parking spaces allowable in front of the Building
Parking slots for the front setback
Linear meters of Railing for Condominium building.
Linear meters for railing in top of parapet wall.
Question regarding parking slots, basement or easement and others at What
section in Rule VII or VIII and UAP Documents
Sample General Questions
Easy terms about design, bldg tech, structural and utilities
Sample General Questions
NBC RULE 7/8 PROBLEMS
Current Trends of Architecture Licensure Examination
NBC BASED Ar. CORDERO’S INTERPRETATION

AMBF PSO
TLA - SETBACK AMBF / TLA (100%)

AMBF AMBF

SETBACK SETBACK

RROW RROW
NBC BASED Ar. CORDERO’S INTERPRETATION

USA ISA
FRONT SETBACK TLA - USA

ISA

AMBF AMBF

FRONT
USA
SETBACK

RROW RROW
NBC BASED Ar. CORDERO’S INTERPRETATION

AMVB TGFA
AMBF X TOTAL HEIGHT AMBF X NUMBER OF FLOORS

HEIGHT NUMBER
OF OF
BLDG FLOORS

AMBF AMBF
NBC BASED Ar. CORDERO’S INTERPRETATION

PARKING PARKING
PARKING AT FRONT PARKING AT SIDE
SETBACK SETBACK

AMBF AMBF

SIDE
SETBACK
FRONT
SETBACK

RROW RROW
NBC BASED Ar. CORDERO’S INTERPRETATION

HIGHEST ELEVATION DIFFERENCE

IF SLOPE IS GIVEN

3%
AMBF 10M
HIGHEST
X=? ELEVATION
RROW DIFFERENCE

10M

RROW SECTION A
ESTIMATES
VOLUME OF CONCRETE KG. OF REBARS
BASED FROM AMBF THICKNESS BASED FROM COMPUTED VOLUME OF
OF SLAB IS GIVEN CONCRETE, FACTOR OF KILOGRAM OF
REBARS IS GIVEN.

Example: 1 CUM OF CONC.= 15 KGS OF REBARS

AMBF THICKNESS
OF SLAB IS
GIVEN

AMBF

SETBACK

RROW
ESTIMATES
CEILING
BASED FROM AMBF COMPUTE NUMBER
PLYWOOD OR CEILING TILES

CEILING
FOR EAVES

CEILING CEILING
FOR FOR
INTERIORS INTERIORS

SETBACK SETBACK

RROW RROW
ESTIMATES
PERIMETER OF GUTTER
BASED FROM AMBF AND GIVEN EAVE
DIMENSIONS

C
GUTTER AT
PERIMETER

B AMBF D A+B+C+D

RROW
ESTIMATES
PERIMETER OF DRAINGE
BASED FROM AMBF AND CONSIDERING
DRAINAGE AT THE PERIMETER OF
EXTERIOR WALLS

DRAINAGE AT
PERIMETER
B AMBF D
OF EXTERIOR
WALL
A A+B+C+D

RROW
ESTIMATES
VOLUME OF CONCRETE OF BEAM
BASED FROM AMBF AND CONSIDERING THE
GIVEN SIZE OF RC BEAM AT THE PERIMETER OF
EXTERIOR WALLS

DRAINAGE AT
PERIMETER
B AMBF D
OF EXTERIOR
WALL
A (A + B + C + D) X SIZE OF BEAM

RROW
ESTIMATES
VOLUME OF CONCRETE OF BEAM
BASED FROM AMBF AND CONSIDERING THE
GIVEN SIZE OF RC BEAM AT THE PERIMETER OF
EXTERIOR WALLS

DRAINAGE AT
PERIMETER
B AMBF D
OF EXTERIOR
WALL
A (A + B + C + D) X SIZE OF BEAM

RROW
ESTIMATES
LINEAR METER OF FENCE
BASED FROM GIVEN LOT SIZE COMPUTE THE PERIMETER OF FENCE
AND CONSIDERING GIVEN SIZE OF GATE.

PERIMETER
OF FENCE
B AMBF D
(A + B + C + D) – E

E
GATE

A
RROW
Sample Problem
January 2014 ALE
SAMPLE PROBLEM
Problem 1 (Questions 1-25)
1.

RROW

38.20m

A = 38.20m x 0.03
A = 1.146m or 1.15m
2.

AMBF = 33m x 100m

AMBF = 3,300 sq.m.
 3

Based on the given data:

AMBF = 3,300 sq.m.

= (AMBF or area) x thickness of slab x weight of rebar

= 3,300 sq.m. x 0.15 m x 15 kilograms
= 7,425 kilograms
4.

AMBF = 33m x 100m, r = area of roof

r = 34m x 102m
r = 3,468 sq.m.

(Answer) = 3,775 sq.m. – estimates should be the

nearest higher value
from your answer
5.

TOSL = TLA - AMBF

TOSL = 5,348 sq.m. x 3,300 sq.m.
TOSL = 2,048 sq.m.
6.

7.

AMBF = 3,300 sq.m.

Total parking slots = 450 AMVB = AMBF x height of the building/BHL
Each level = 150 parking slots AMVB = 3,300 sq.m. x 9 meters
floor to floor = 3 meters AMVB = 29,700 sq.m.

= 450slots ÷ 150 slots

= 3 storeys or 9 meters
 8.

PSO = AMBF ÷ TLA x 100%

PSO = 3,300 sq.m. ÷ 5,348 sq.m. x 100%
PSO = 61.70% or 62%

9.

10.

11.
12.

13.

14.

15.
16.

= √16 sq.m.
= 4 meters
= 4 meters x 4 sides
= 16 meters
17.

= √16 sq.m.
= 4 meters + 2 meters (for eaves both sides)
= 6 meters x 6 meters
= 36 sq.m.

18.
19.

20.

21.

= √25 sq.m.
= 5 meters

= 9m(2) + 10.50m(2)
= 18m + 21m
= 39 meters
22.

= √25 sq.m.
= 5 meters

TLA = 9m x 10.50m
TLA = 94.50 sq.m.

23.

AMBF = 5m x 5m or 25 sq.m.
TLA = 94.50 sq.m.

TOSL = TLA – AMBF

TOSL = 94.50 sq.m. – 25 sq.m.
TOSL = 69.50 sq.m.
24.

= √36 sq.m.
= 6 meters

TLA = 9m x 10.50m
TLA = 94.50 sq.m.

25.

= √36 sq.m.
= 6 meters

= 12.50m(2) + 10m(2)
= 25m + 20m
= 45 meters
Quiz
Current Trends
Three Design Problems – 30 Questions
Project 1
Project 1
Project 2
Project 2
Project 3
Project 3
Project 3 (Questions 1 – 5)

RROW

24m
A = 24 m x 0.02
A = 0.48 m Elevation

Each unit = 83 sq.m. w/ least dimension of 8 m

600 mm x 600 mm = 0.36 sq.m.

= 83 sq.m. ÷ 0.36 sq.m.

= 230.55 or 231
= 231 – 235 pieces
Project 3 (Questions 1 – 5)

Based on the given data:

AMBF = 800 sq.m.
600 mm x 600 mm = 0.36 m

= 800 sq.m. ÷ 0.36 sq.m.

= 2,222.22 or 2,223
= 2,225 – 2,250 pieces
Project 1 (Questions 6 – 10)
Project 1 (Questions 6 – 10)

Based on the given data:

AMBF = 190 sq.m.

PSO = AMBF ÷ TLA x 100%

PSO = 190 sq.m. ÷ 270 sq.m. x 100%
PSO = 70.37%

Based on Table VIII.2 of Rule 7 & 8:

AMBF = 136 sq.m.

PSO = AMBF ÷ TLA x 100%

PSO = 136sq.m. ÷ 270 sq.m. x 100%
PSO = 50.37%
Project 3 (Questions 11 – 15)

Refer to Table VIII.1 of Rule 7 & 8:

TLA = 1,200 sq.m.

ISA = TLA x factor

ISA = 1,200 sq.m. x 30%
ISA = 360 sq.m.
Project 3 (Questions 11 – 15)

Based on Table VIII.2 of Rule 7 & 8: AMBF

front setback = 8m x 50m or 400 sq.m.

parking slot = 2.50m x 5m or 12.50 sq.m. PARKING
5m
driveway= 3.00m x 50m=150 sq.m DRIVEWAY
3m
= (400 sq.m. – 150sq.m) ÷ 12.50 sq.m.
= 20 slots 50m

Based on the given data:

AMBF = 800 sq.m.

= (AMBF or area) x thickness of slab x weight of rebar

= 800 sq.m. x 0.10 m x 20 kilograms
= 1,600 kilograms
Project 3 (Questions 11 – 15)

Based on the given data:

AMBF = 800 sq.m.

TOSL = TLA – AMBF
TOSL = 1,200 sq.m. – 800 sq.m.
TOSL = 400 sq.m.
Project 2 (Questions 16 – 20)

Based on the given data:

AMBF = 320 sq.m.

PSO = AMBF ÷ TLA x 100%

PSO = 320 sq.m. ÷ 1,080 sq.m. x 100%
PSO = 29.62%
Project 2 (Questions 16 – 20)

Based on Table VIII.1 of Rule 7 & 8 page 132

TLA = 1,080 sq.m.
ISA = Paved Open Space

ISA = TLA x factor

ISA = 1,080 sq.m. x 15%
ISA = 162 sq.m. (Maximum Allowable)

145 – 160 sq.m. = Answer

Based on the given data:

AMBF = 320 sq.m.

TOSL = TLA – AMBF

TOSL = 1,080 sq.m. – 320 sq.m.
TOSL = 760 sq.m.

760 – 780 sq.m. (Answer)

Project 2 (Questions 21 – 25)

Y3

Y2 Y4

ISA = y2 + y3 + y4

ISA = (10x16) + (36x4) + (6x16)

ISA = 160m + 144m + 96m
ISA = 400 sq.m.
Project 2 (Questions 21 – 25)

Based on Table VIII.1 of Rule 7 & 8 page 132

TOSL = TLA x factor

TOSL = 1,080 sq.m. x 10%
TOSL = 108 sq.m.

Refer to Table VII.G.1 of Rule 7 & 8:

GFA = TLA x FLAR

GFA = 1,080 sq.m. x 9
GFA = 9,720 sq.m.
Project 2 (Questions 21 – 25)

Based on the given data:

AMBF = 320 sq.m.

TGFA = AMBF x no. of storey

TGFA = 320 sq.m. x 7
TGFA = 2,240 cu.m.

Based on Table VIII.3 of Rule 7 & 8

AMBF = 736 sq.m.

AMVB = TLA x height of the building/BHL

AMVB = 736 sq.m. x 21 m
AMVB = 15,456 cu.m.
Project 1 (Questions 26 – 30)

Based on the given data:

Each unit = 95 sq.m.

= (AMBF or area) x thickness of slab x weight of rebar

= 95 sq.m. x 0.15 m x 20 kilograms
= 285 kilograms

285 – 290 kilograms (Answer)

Table VIII.2 of Rule 7 & 8:

AMBF = 136 sq.m. x 2 storey
AMBF = ceiling area

= 272 sq.m. ÷ (1.20m x 2.40m)

= 272 sq.m. ÷ 2.88 sq.m.
= 94.44 or 95 pieces

100 – 105 pieces (Answer)

Project 1 (Questions 26 – 30)

Based on the given data:

AMBF = 16m x 20m

= 18m (2) x 10.5m (2)

= 36m x 21m
= 57 sq.m.
Project 1 (Questions 26 – 30)

AMBF = 8.50m x 16m, e = area of eaves c = No. of ceiling boards

e = A(2) + B(2) c = area of eaves ÷ area of ceiling board

e = (16m x 1.20m)2 + (10.40m x 1.20m)2 c = 63.36 sq.m. ÷ (1.20m x 2.40m)
e = (19.20m)2 + (12.48)2 c = 63.36 sq.m. ÷ 2.88 sq.m.
e = 38.4 sq.m. + 24.96 sq.m. c = 22 pieces
e = 63.36 sq.m. 22 – 24 pieces (Answer)
Project 1 (Questions 26 – 30)

AMBF = 8.50m x 16m, g = length of gutter

g = A(2) + B(2)
g = (18.20m)2 + (10.40m)2
g = 36.40m + 20.80m
g = 57.2m

= 60m – 62m (Answer)