9 Marking scheme: Worksheet (AS)
1 B [1]
2 C [1]
3 D [1]
4 D [1]
5 B [1]
6 The two units are: V m–1 [1]
and N C–1. [1]
F 1.5 10 3
7 E = = [1]
Q 5.0 10 8
E = 3.0 104 V m–1 [1]
8 F = EQ = 5.0 105 3.2 10–19 [1]
F = 1.6 10–13 N [1]
V 600
9 a E= = [1]
d 3.0 10 2
E = 2.0 104 V m–1 [1]
The field acts towards the negative plate. [1]
b The electric field is uniform between the plates (except at the ‘edges’). [1]
The electric field is at right angles to the plate. [1]
c i Since the droplet is stationary,
the electric force on the droplet
must be equal and opposite to its weight. [1]
The electric force must act upwards,
so the charge on the droplet must
be negative. [1]
F
ii E =
Q
F 6.4 10 15
Q= = [1]
E 2.0 10 4
Q = 3.2 10–19 C [1]
10 a F QE =1.60 10–19 2.4 106 [1]
F = 3.84 10−13 N 3.8 10−13 N [1]
F
b F ma a = [1]
m
3.84 10 13
a= N
1.67 10 27
a = 2.30 1014 m s−2 [1]
c Zero; the force is at right angles to the field. [1]
AS and A Level Physics Original material © Cambridge University Press 2010 1
9 Marking scheme: Worksheet (AS)
V 200
11 E= = 10−2 = 4.0 103 N [1]
d 5
F 3.2 10 4
F = EQ Q = = [1]
E 4.0 103
Q = 8.0 10−8 C [1]
AS and A Level Physics Original material © Cambridge University Press 2010 2