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Logic Gate Simulation Analysis

The document summarizes simulation results for 6 common logic gates - NAND, NOR, NOT, AND, OR, and XOR. It shows the pin voltages and currents for each gate under different input conditions. Circuit simulations using Multisim and actual breadboard implementations are displayed and their outputs are consistent. The gates use both positive and negative logic depending on the gate type. NAND and NOR use negative logic while AND, OR, and XOR use positive logic. NOT can display either positive or negative logic depending on the input.

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Jonnel Vinas
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0% found this document useful (0 votes)
294 views10 pages

Logic Gate Simulation Analysis

The document summarizes simulation results for 6 common logic gates - NAND, NOR, NOT, AND, OR, and XOR. It shows the pin voltages and currents for each gate under different input conditions. Circuit simulations using Multisim and actual breadboard implementations are displayed and their outputs are consistent. The gates use both positive and negative logic depending on the gate type. NAND and NOR use negative logic while AND, OR, and XOR use positive logic. NOT can display either positive or negative logic depending on the input.

Uploaded by

Jonnel Vinas
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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Data and Results:

74LS00 (NAND GATE)


Pin Voltage Current
Number
1 2 3 4 5 6 9 10 8 12 13 11 2.84 V 0.9µA
0 0 1 0 0 1 0 0 1 0 0 1 2.84 V 0.9µA
0 1 1 0 1 1 0 1 1 0 1 1 2.84 V 0.9µA
1 0 1 1 0 1 1 0 1 1 0 1 2.84 V 0.9µA
1 1 0 1 1 0 1 1 0 1 1 0 0V 0A

Simulation using Multisim:

Figure 1.1: Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 1 which means if the inputs are 0-0, 0-
1, and1-0, the LED is in the “ON” state.

Figure 1.2: Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 0 which means if the inputs are 1-1,
the LED is in the “OFF” state.
Actual Simulation using Breadboard:

Figure 1.a: 0-0 input Figure 1.b: 0-1 input Figure 1.c: 1-0 input

Figure 1.d: 1-1 input

The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in 0-0, 0-1 and 1-0 input while it will turn off when the
input is in 1-1.

74LS02 (NOR GATE)


Pin Voltage Current
Number
2 3 1 5 6 4 8 9 10 11 12 13
0 0 1 0 0 1 0 0 1 0 0 1 3.04 V 2.6µA
0 1 0 0 1 0 0 1 0 0 1 0 0.12 V 0A
1 0 0 1 0 0 1 0 0 1 0 0 0.12 V 0A
1 1 0 1 1 0 1 1 0 1 1 0 0.12 V 0A

Simulation using Multisim:


Figure 2.1 Circuit Simulation using Multisim
The figure shows the simulation if it is in the logic 1 which means if the inputs are 0-0,
the LED is in the “ON” state.

Figure 2.2 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 0
which means if the inputs are 0-1, 1-0, and1-1, the LED is
in the “OFF” state.

Actual Simulation using Breadboard:

Figure 2.a: 0-0 input Figure 2.b: 0-1 input Figure 2.c: 1-0 input

Figure 2.d: 1-1 input


The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in the 0-0 input while it will turn off when the input is in
0-1,1-0 and1-1.

74LS04 (NOT GATE)


Pin Voltage Current
Numbe
r
1 2 3 4 5 6 9 8 11 10 13 12
0 1 0 1 0 1 0 1 0 1 0 1 2.73 V 0.1 µA
1 0 1 0 1 0 1 0 1 0 1 0 0.11 V 0A

Simulation using Multisim:

Figure 3.1 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 1 which means if the inputs are 0, the
LED is in the “ON” state.

Figure 3.2 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 0 which means if the inputs are 1, the
LED is in the “OFF” state.

Actual Simulation using Breadboard:


Figure 3.a: 0 input Figure 3.b: 1 input
The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in 0 input while it will turn off when the input is 1.

Pin Voltage Current


Number
1 2 3 4 5 6 9 10 8 12 13 11
0 0 0 0 0 0 0 0 0 0 0 0 1.5 mV 0A
0 1 0 0 1 0 0 1 0 0 1 0 1.5 mV 0A
1 0 0 1 0 0 1 0 0 1 0 0 1.5 mV 0A
1 1 1 1 1 1 1 1 1 1 1 1 2.727 V 8.4 µA
74LS08 (AND GATE)

Simulation using Multisim:

Figure 4.1 Circuit Simulation using Multisim

The figure shows the simulation if it is in the logic 0 which means if the inputs are 0-0, 0-
1 and 1-0, the LED is in the “OFF” state.
Figure 4.2 Circuit Simulation using Multisim
The figure shows the simulation if it is in the logic 1 which means if the inputs are 1-1,
the LED is in the “ON” state.

Actual Simulation using Breadboard:

Figure 4.a: 0-0 input Figure 4.b: 0-1 input Figure 4.c: 1-0 input

Figure 4.d: 1-1 input


The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in the 1-1 input while it will turn off when the input is in
0-0, 0-1, and 1-0.

Pin Voltage Current


Number
1 2 3 4 5 6 9 10 8 12 13 11
0 0 0 0 0 0 0 0 0 0 0 0 0.06 V 0A
0 1 1 0 1 1 0 1 1 0 1 1 2.99 V 2.3 µA
1 0 1 1 0 1 1 0 1 1 0 1 3V 2.3 µA
1 1 1 1 1 1 1 1 1 1 1 1 3V 2.4 µA
74LS32 (OR GATE)

Simulation using Multisim:

Figure 5.1 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 0 which means if the inputs are 0-0,
the LED is in the “OFF” state.

Figure 5.2 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 1 which means if the inputs are 0-1, 1-
0 and 1-1, the LED is in the “ON” state.

Actual Simulation using Breadboard:


Figure 5.a: 0-0 input Figure 5.b: 0-1 input Figure 5.c: 1-0 input

Figure 5.d: 1-1 input


The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in the 0-1, 1-0 and 1-1input while it will turn off when the
input is in 0-0.

Pin Voltage Current


Number
1 2 3 4 5 6 9 10 8 12 13 11
0 0 0 0 0 0 0 0 0 0 0 0 0.06 V 0A
0 1 1 0 1 1 0 1 1 0 1 1 2.73 V 0.1 µA
1 0 1 1 0 1 1 0 1 1 0 1 2.73 V 0.1 µA
1 1 0 1 1 0 1 1 0 1 1 0 0.09 V 0A
74LS86 (XOR GATE)

Simulation using Multisim:


Figure 5.1 Circuit Simulation using Multisim
The figure shows the simulation if it is in the logic 0 which means if the inputs are 0-0,
and 1-1, the LED is in the “OFF” state.

Figure 5.2 Circuit Simulation using Multisim


The figure shows the simulation if it is in the logic 1 which means if the inputs are 0-1,
and 1-0, the LED is in the “ON” state.

Actual Simulation using Breadboard:

Figure 6.a: 0-0 input Figure 6.b: 0-1 input Figure 6.c: 1-0 input
Figure 6.d: 1-1 input
The figure shows the actual simulation using breadboard, the output is the same as in the
Multisim. The LED will turn on if it is in the 0-1 and1-0 input while it will turn off when the
input is in 0-0 and 1-1.

Questions:
1. What kind of logic (positive/negative) are this ICs used? Can this be used to display
the other?
7400 or the NAND gate has an output that is normally HIGH (1) and only goes LOW
(0) when all of its inputs are HIGH (1). It is the logical negation of AND gate.
7402 or the NOR gate has HIGH (1) output results if both the input to the gate are LOW
(0), if one or both of the inputs are HIGH (1), a LOW (0) output results. NOR is the
result of the negation of the OR operation.
7408 or the AND gate has an output which is normally LOW (0) and only goes HIGH
(1) when all the inputs are HIGH (1).
7432 or the OR gate performs logical operation which means output is HIGH (1) if at
least one of the inputs is HIGH (1)

2. How does the ICs behave if an input is disconnected?


Based on the performed experiment, in 7400,7404,7408 and 7432, if an input pin
is disconnected or does not connected to anything, the ICs read HIGH (1) that it thinks
that there is 1 connected on the pin. The other gates were similarly behaved according to
their Boolean logic table.
A signal is said to be floating when its state is indeterminate, that is it not connected to
VCC or to ground. The signal’s voltage will float to match the residual voltage. Floating
is often used to describe a pin which is in the high-impedance state.

Conclusion:
Challenge:

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