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1 KW 3,412.14 1 Refrigeration Ton 3.5168525 KW : Gallons Pounds ° F Gallon Pound F

This document provides equations and calculations for determining the heat transfer rate (Q) in various HVAC and refrigeration systems. It includes standard equations that relate Q to factors like mass flow rate, specific heat, temperature difference, and conversions between common units. Sample calculations are shown applying these equations to determine Q in kW, tons, and BTU/hr given information like flow rates, temperatures, and system type (evaporator, chiller, cooling tower, air handler).

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0% found this document useful (0 votes)
83 views3 pages

1 KW 3,412.14 1 Refrigeration Ton 3.5168525 KW : Gallons Pounds ° F Gallon Pound F

This document provides equations and calculations for determining the heat transfer rate (Q) in various HVAC and refrigeration systems. It includes standard equations that relate Q to factors like mass flow rate, specific heat, temperature difference, and conversions between common units. Sample calculations are shown applying these equations to determine Q in kW, tons, and BTU/hr given information like flow rates, temperatures, and system type (evaporator, chiller, cooling tower, air handler).

Uploaded by

dasmech
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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Q = M * CP * ∆T Volume Flow Rate Of Water 0.

0995 M3/Sec
Volume Flow Rate Of Specific Heat Capacity
Q = Water * Density Of Water * Of Water * Temp. Diff Density Of Water 999.7829 Kg/M3

Q = 0.0995 * 999.7829 * 4.19704 6 Specific Heat Capacity Of Water 4.19704 Kj/Kg K

Q = 2505.09 KW Evaporator Inlet Temp. 12 °C 285.15 °K


Q = 712.28 Tons Evaporator Outlet Temp. 6 °C 279.15 °K
Q = 8547719.07 BTU/Hr 1 °C = 273.15 °K

Volume Flow Rate Of Water


1 M3/Sec = 127133 Ft3/Hr
Conversion

Density Of Water Conversion 1 Kg/M3 = 0.062428 Pound/Ft3

Specific Heat Capacity Of Water


Conversion 1 Kj/Kg K = 0.23884589663 BTU/Pound F

Energy Conversion 1 KW = 3,412.14 BTU/Hr


Energy Conversion 1 Refrigeration Ton = 3.5168525 KW

Density Of Water Conversion 1 Pound/Ft3 = 0.133681 Pound/Gallons

Q = M * CP * ∆T Volume Flow Rate Of Water 12649.7335 Ft3/Hr


Volume Flow Rate Of Specific Heat Capacity
Q =
Water
* Density Of Water *
Of Water
* Temp. Diff Density Of Water 62.4144468812 Pound/Ft3

Q = 12649.7335 * 62.4144468812 * 1.00244578197938 * 10.8 Specific Heat Capacity Of Water 1.00244578198 BTU/Pound F

Q = 8547736.99 BTU/Hr Evaporator Inlet Temp. 53.6 °F


Q = 712.31 Tons Evaporator Outlet Temp. 42.8 °F
Q = 2505.10 KW

Q = M * CP * ∆T Volume Flow Rate Of Water GPM


Volume Flow Rate Of Specific Heat Capacity
Q = Water * Density Of Water * Of Water * Temp. Diff Density Of Water 8.34362567353 Pounds/Gallons

Q = GPM * Pounds/Gallons * BTU/Pound F * °F Specific Heat Capacity Of Water 1.00244578198 BTU/Pound F

Q = GPM * 8.3436256735257 * 1.00244578197938 * °F Evaporator Inlet Temp. °F


Q = GPM * 8.3436256735257 * 1.00244578197938 * °F Evaporator Outlet Temp. °F
Gallons Pounds BTU
Q = * * * °F
Min Gallon Pound F
BTU
Q = * 60
Min
BTU
Q = 501.841941770442 * GPM * ∆T
Hr

Q = 500 * GPM * ∆T BTU/Hr Evaporator In Temp 55 °F Standard Thumb Rule


Q = 500 * GPM * 10 BTU/Hr Evaporator Out Temp 45 °F Standard Thumb Rule
500 * GPM * 10
Q = Tons
12000 Chiller = 2.4 Gallons per Minute / ton
Q(Tons) * 12000 1 ChillerTon = 12,000 BTU / hr
GPM =
500 * 10 Chiller Ton = GPM x ΔT / 24
GPM = Q(Tons) * 2.4 Refrigeration Tons = BTUH/12000

Q = 500 * GPM * ∆T BTU/Hr Evaporator In Temp 55 °F Standard Thumb Rule


Q = 500 * GPM * 10 BTU/Hr Evaporator Out Temp 45 °F Standard Thumb Rule
500 * GPM * 10
Q = Tons
15000 Cooling Tower = 3 Gallons per Minute per ton
Q(Tons) * 15000 1 Tower Ton = 15,000 BTU/hr
GPM =
500 * 10 Tower Ton = GPM x ΔT/30
GPM = Q(Tons) * 3 Cooling Tower Tons = BTUH/15000

Q = M * CP * ∆T Volume Flow Rate Of Water CFM

Density Of Moist Air At Specific Heat Of Moist Specific Heat Of Moist Air At 70O
Q = Volume Flow Rate Of Air * * * Temp. Diff 0.244 BTU/Pound F
70O DB & 50% RH Air At 70O DB & 50% RH DB & 50% RH

1/(Specific Volume Of
* Specific Heat
Of Moist Specific Volume Of Moist Air At
Q = Volume Flow Rate Of Air * Moist Air At 70O DB & * Temp. Diff 13.5 Ft3/Pound
Air At 70O DB & 50% RH 70O DB & 50% RH
50% RH)
Q = CFM * 1/(Ft3/Pound) * BTU/Pound F * °F Coil Inlet Temp. °F
Q = CFM * 0.074074074074074 * 0.244 * °F Coil Outlet Temp. °F
Q = CFM * 0.074074074074074 * 0.244 * °F
Cubic Ft Pound BTU
Q = * * * °F
Min Cubic Ft Pound F
BTU
Q = * 60
Min
BTU
Q = 1.08444444444444 * CFM * ∆T
Hr

Q = M * CP * ∆T Volume Flow Rate Of Water CFM

Q = Volume Flow Rate Of Air *


Density Of Moist Air At
*
Specific Heat Of Moist
* Temp. Diff Specific Heat Of Moist Air At 70O 0.244 BTU/Pound F
70O DB & 50% RH Air At 70O DB & 50% RH DB & 50% RH

1/(Specific Volume Of
Specific Heat Of Moist Specific Volume Of Moist Air At
Q = Volume Flow Rate Of Air * Moist Air At 70O DB & * Air At 70O DB & 50% RH * Temp. Diff 13.5 Ft3/Pound
70O DB & 50% RH
50% RH)
Q = CFM * 1/(Ft3/Pound) * BTU/Pound F * °F Coil Inlet Temp. °F
Q = CFM * 0.074074074074074 * 0.244 * °F Coil Outlet Temp. °F
Q = CFM * 0.074074074074074 * 0.244 * °F
Cubic Ft Pound BTU
Q = * * * °F
Min Cubic Ft Pound F
BTU
Q = * 60
Min
BTU
Q = 1.08444444444444 * CFM * ∆T
Hr
METRIC UNITS

IMPERIAL
UNITS

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