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PART TEST-1 (PT-1) : Paper-2

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PART TEST-1 (PT-1) : Paper-2

jee

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P7-19 ® CODE

1
PART TEST-1(PT-1)
TARGET : JEE (MAIN + ADVANCED) 2021
PAPER-2 | CLASS XI | COURSE : ALL INDIA TEST SERIES (VIKALP)
Date : 30-06-2019 Time: 3 Hours Maximum Marks : 180
Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.
GENERAL %
1. The sealed booklet is your Question Paper. Do not break the seal till you are instructed to do so.
2. The question paper CODE is printed on the right hand top corner of this sheet.
3. Use the Optical Response Sheet (ORS) provided separately for answering the question.
4. Blank spaces are provided within this booklet for rough work.
5. Write your Name and Roll Number in the space provided on the below cover.
6. After the open booklet, verify that the booklet contains all the 54 questions along with the options are legible.

DO NOT BREAK THE SEAL WITHOUT BEING INSTRUCTED TO DO SO BY THE INVIGILATOR


QUESTION PAPER FORMAT AND MARKING SCHEME :
7. The question paper has three parts : Mathematics, Physics and Chemistry. Each part has two sections.
8. Each section as detailed in the following table :
Category-wise Marks for Each Question Maximum
Number of
Section Question Type Negative Marks of the
Questions Full Marks Partial Marks Zero Marks
Marks Section
+3
0
Double digit If only the bubbles No negative
1 12 – If none of the 36
Integer (00-99) corresponding to the correct marks
bubbles is darkened
answer is darkened
+4 +1
If only the bubble(s) For darkening a bubble 0 –2
One or More
2 6 corresponding to all the corresponding to each correct If none of the In all other 24
Correct Option(s)
correct option(s) is(are) option, provided NO incorrect bubbles is darkened cases
darkened option is darkened

OPTICAL RESPONSE SHEET :


9. Darken the appropriate bubbles on the original by applying sufficient pressure.
10. The original is machine-gradable and will be collected by the invigilator at the end of the examination.
11. Do not tamper with or mutilate the ORS.
12. Write your name, roll number and the name of the examination centre and sign with pen in the space provided for
this purpose on the original. Do not write any of these details anywhere else. Darken the appropriate bubble
under each digit of your roll number.
DARKENING THE BUBBLES ON THE ORS :
13. Use a BLACK BALL POINT to darken the bubbles in the upper sheet.
14. Darken the bubble COMPLETELY.
15. Darken the bubble ONLY if you are sure of the answer.
16. The correct way of darkening a bubble is as shown here :
17. There is NO way to erase or "un-darkened bubble.
18. The marking scheme given at the beginning of each section gives details of how darkened and not darkened
bubbles are evaluated.

NAME OF THE CANDIDATE : ………………………………………………………………..………………………

ROLL NO. : ………………………..………………………


I have read all the instructions I have verified the identity, name and roll number
and shall abide by them of the candidate.

------------------------- -------------------------
Signature of the Candidate Signature of the Invigilator

Resonance Eduventures Limited


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MATHEMATICS
PART : I MATHEMATICS

MATHEMATICS
SECTION – 1 : (Maximum Marks : 36)
 This section contains TWELVE questions
 The answer to each question is a DOUBLE DIGIT INTEGER ranging from 00 to 99, both inclusive
 For each question, darken the bubble corresponding to the correct integer in the ORS
 Marking scheme :
+3 If the bubble corresponding to the answer is darkened
0 If none of the bubbles is darkened

1. Number of values of x satisfying the equation log x + 1 (x2 + x – 6)2 = 4 is  then  + 15 =

 lo g 3 7  lo g 3 2 
2. The value of x, which satisfies log4 log2 x + log2 log4 x = 3 , is k then find value of
(k – 200)

2
3. If the solution set of the inequality lo g 0 .9
lo g 5 ( x  5  x) > 0 contains n integral values, then n2 + 1 =

4. In a city 20 percent of the populations speaks Bengali, 50 percent speak Hindi and 10 percent
p 
speak both Hindi and Bengali then people speaking either Hindi or Bengali is 'p' percent then  
5 
equals (p N)

5. Let n(U) = 500, n(A) = 100, n(B) = 250 and n(A  B) = 50, then n(A'  B') is a three digit number
abc, where a, b, c  W. Value of (a + b + c) is

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MATHEMATICS

6. The number of subsets of the power set of A = {1, 2, 3} is k, then highest prime factor of k is

MATHEMATICS
2 2 3 2 2 3 2 2 3
(a – b )  (b – c )  (c – a )
7. If a, b, c are real and distinct numbers, then the value of is
( a – b )(b – c )( c – a )( a  b )(b  c )( c  a )

1 1
8. If x – = 3, then find the value of x4 + 4
– 100.
x x

9. When the polynomials P(x) = x3 + x2 – 5ax – 6 and Q(x) = x3 + ax2 – 12x + 6 are divided by x + 1
and x – 2 respectively leaves same remainder , then value of (a2 + 4) is

10. If complete solution set of (x + 1)2 < (7x – 3) is (c, d), then find the value of (c + d)2

2 1 2x 1
11. If   0 , then x  [a, ). Find a.
x 1
2 3
x  x 1 x 1

1 – log 2 – log 4
12. The value of 2 ( 49 7
 5 5
) is

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MATHEMATICS

SECTION – 2 : (Maximum Marks : 24)

MATHEMATICS

 This section contains SIX questions


 Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these
four option(s) is(are) correct
 For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS
 For each question, marks will be awarded in one of the following categories :
Full Marks : +4 If only the bubble(s) corresponding to all the correct option(s) is(are)
darkened.
Partial Marks : +1 For darkening a bubble corresponding to each correct option, provided
NO incorrect option is darkened.
Zero Marks : 0 If none of the bubbles is darkened.
Negative Marks : –2 In all other cases.
 For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three
will result in +4 marks ; darkening only (A) and (D) will result in +2 marks and darkening (A) and
(B) will result in –2 marks, as a wrong option is also darkened.

13. In a group of 100 people there are 75 people who play hockey and 40 people who play football,
every person plays either hockey or football. Then number of people who can play only football, is
divisible by
(A) 15 (B) 25 (C) 5 (D) 10

14. A and B are two sets such that n(A) = 3 and n(B) = 6, then
(A) minimum value of n(A  B) = 6 (B) minimum value of n(A  B) = 9
(C) maximum value of n(A  B) = 6 (D) maximum value of n(A  B) = 9

15. In a certain town 25% families own a phone and 15% own a car, 65% families own neither a
phone nor a car. 2000 families own both a car and phone then which of following statement is/are
correct
(A) 10% families own both a car and phone (B) 35% families own either a car or a phone
(C) 40000 families lives in the town (D) 3000 families own phone only

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MATHEMATICS
2x – 1
16. If S is the set of all real x for which is positive, then S contains

MATHEMATICS
3 2
2x  3x  x

 3   1  1 1
(A)  – , –  (B)  – 3, –  (C) – ,  (D) (2, 3)
 2  4   4 2 

2
x –3x
 1
17. The set of all solution of the inequality   > 9 is contained by the set
3 

 1 
(A) (–, 0) (B) (0, 2) (C) (0, 1) (D)  , 3
2 

n n 3
e
18. e is simplified to

(A) e3 (B) irrational number (C) 3 (D) prime number

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PHYSICS
PART : II PHYSICS

PHYSICS
SECTION – 1 : (Maximum Marks : 36)
 This section contains TWELVE questions
 The answer to each question is a DOUBLE DIGIT INTEGER ranging from 00 to 99, both inclusive
 For each question, darken the bubble corresponding to the correct integer in the ORS
 Marking scheme :
+3 If the bubble corresponding to the answer is darkened
0 If none of the bubbles is darkened

19. Find the sum of magnitude of the unknown forces X and Y if sum of all forces is zero.
y
5

53º
x 45º
8 2

20. In the graph shown below, the area enclosed between the graph and the x-axis from x = 0 to
x = 12 is 4N, then the value of N is.
y

9
y = x2

x
0 3 8 12

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PHYSICS
21. Position of a particle moving along x–axis is given as :

PHYSICS
x = u(t – 2) + a(t – 2)2

u
where 'u' and 'a' are positive constants and t is time. If initial velocity is zero then 3 will be .
a

22. If two positive numbers x & y are such that x + 2y = 60 then maximum value of xy is 25n, find n :

23. The value of :

 / 4 /4


  y dy 
2 2
24 × cos x dx  s in is
 
 0 0 

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PHYSICS
/2

24. Find the value of


 10 .

PHYSICS
sin( 2 x ) dx
0

25. The displacement (in meters) of particle varies with time (in seconds) as

S = 5t2 + 2t

The velocity (in m/s) of particle at t = 2 sec is :

x 1   1 
26. If f(x) = then find f  f  – 
x 1   15  

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PHYSICS
27. The value of

PHYSICS
2
1

2
(s in x ) d x = x find 10x
 0

28. Find the angle between two vectors 2 iˆ  ˆj – kˆ and iˆ – ˆj .

29. If F(ex) = e2x + 2ex + 1 then find value of F(3).

30. Volume of a right circular cone varies as square of the radius of the base when height is constant

and the height when base is constant. If radius of the base is 7 cm and height is 15 cm then the

volume is 770 cm3. Find the height of a cone whose volume is 132 cm 3 and base radius is 3 cm.

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PHYSICS

SECTION – 2 : (Maximum Marks : 24)

PHYSICS
 This section contains SIX questions
 Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these
four option(s) is(are) correct
 For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS
 For each question, marks will be awarded in one of the following categories :
Full Marks : +4 If only the bubble(s) corresponding to all the correct option(s) is(are)
darkened.
Partial Marks : +1 For darkening a bubble corresponding to each correct option, provided
NO incorrect option is darkened.
Zero Marks : 0 If none of the bubbles is darkened.
Negative Marks : –2 In all other cases.
 For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three
will result in +4 marks ; darkening only (A) and (D) will result in +2 marks and darkening (A) and
(B) will result in –2 marks, as a wrong option is also darkened.

31. Choose the correct option(s) :


2 /4

(A)  sin x dx  0 (B)  cos x dx  0


0 –/4
1 2
e –1

x
(C) e dx = (D) Current is a vector quantity
e
–1

32. If f(x) = x6; h(y) = –y2 + 1 ; g(z) = z – 1


Then the correct general relation(s) is/are
(A) f(x) – h(x3) = 1
(B) f(x) + h(x3) = 1
(C) g(y) + h( y ) = 0
(D) g(y6)– f(y) = –1

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PHYSICS
33. Which of the following physical quantities are considered vectors :

PHYSICS
(A) Pressure (B) velocity (C) Force (D) displacement

34. If f(x) = sinx ; g(x) = cosx and h(x) = cos(2x)


Then choose the correct alternative/s among the following :
(A) h(x) = 2f(x2) – 1 (B) h(x) = 2[f (x)] 2 – 1 (C) h(x) = 1 – 2[f(x)]2 (D) h(x) = 2[g(x)]2 – 1

35. Two functions of x are defined as :


f(x) = sin x and g(x) = cos x
Pickout correct choices :
(A) f(x) = – f(x) (B) f(x) = g(x) (C) g(x) = f(x) (D) g(x) = – g(x)

 x sec(x
2 2
36. ) ta n ( x )d x 

(A) sec(x2) + C
2
sec(x )
(B)  C
2

2
ta n ( x )
(C)  C
2

2 2
ta n (x ) c o s e c (x )
(D) +C
2

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CHEMISTRY

PART : III CHEMISTRY


Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27, Si = 28,

CHEMISTRY
P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn = 65, As = 75,
Br = 80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207] [Assume all gases to be ideal gases]

SECTION – 1 : (Maximum Marks : 36)

 This section contains TWELVE questions


 The answer to each question is a DOUBLE DIGIT INTEGER ranging from 00 to 99, both
inclusive
 For each question, darken the bubble corresponding to the correct integer in the ORS
 Marking scheme :
+3 If the bubble corresponding to the answer is darkened
0 If none of the bubbles is darkened

37. A gaseous mixture is composed of equal number of moles of CH 4, C2H6 and C2H2. The average
molecular mass of mixture (in amu) is :

A
38. The radius of nucleus of an element Z X is 3.6 fm. Find A.

(R0 = 1.2 fm )

39. A gas sample is having 15200 torr pressure, determine corresponding pressure in atm.

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CHEMISTRY
40. Determine the volume (in L) of 14g of CO at 27°C and 0.821 atm pressure (R = 0.0821 L atm

CHEMISTRY
mol–1 K–1).

41. The ratio of highest value of |q/m| to lowest value of |q/m| among the following particles is

(-particle, proton, O2–, Al3+, N3–). Give your answer after multiplying by 3 :

42. In a spot 0.001 gram of carbon is present. How many carbon atoms are present in this spot ?

Report your answer after dividing by 1 × 1018. (Use NA = 6.0 × 1023)

43.

If number of 1º carbon atoms present in the given compound is (X) and number of 3º carbon atoms

is (Y). Then find value of (X + Y).

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CHEMISTRY

CHEMISTRY
44.

In the given structure if number of sp2 C atoms is M and number of sp3–sp2 C–C -bonds is N.

Find the value of M+N.

45. The position of locant methyl group in the given cyclic ring is :

Cl CH3

Cl

46. Find out the double bond equivalent value of the given following compound ?

O O

NH2

O Cl

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CHEMISTRY

47. NH2, , , , N ,
NH— NH
NH2

CHEMISTRY
, , ,
OH OH OH OH

What is the sum of 3º alcohol and 2º amine from above compounds?

48. What is the sum of positions assigned to Chlorine while numbering the Parent Chain in the below

compounds?

Cl Cl

Cl
Cl

Cl Cl
Cl
Cl

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CHEMISTRY

SECTION – 2 : (Maximum Marks : 24)

CHEMISTRY

 This section contains SIX questions

 Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these

four option(s) is(are) correct

 For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS

 For each question, marks will be awarded in one of the following categories :

Full Marks : +4 If only the bubble(s) corresponding to all the correct option(s) is(are)

darkened.

Partial Marks : +1 For darkening a bubble corresponding to each correct option, provided

NO incorrect option is darkened.

Zero Marks : 0 If none of the bubbles is darkened.

Negative Marks : –2 In all other cases.

 For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three

will result in +4 marks ; darkening only (A) and (D) will result in +2 marks and darkening (A) and

(B) will result in –2 marks, as a wrong option is also darkened.

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CHEMISTRY

49. At 1 atm & 273ºC following is graphical representation of volume occupied by different gases.

CHEMISTRY
Which is/are not correctly matched ?

V(L)
22.4 H2
11.2 He
5.6 CH4
2.8 SO2

2 4 6 8
Mass (g)

(A) He (B) CH4 (C) H2 (D) SO2

50. Rutherford’s scattering experiment led to the conclusion(s) that:


(A) nucleus is very small in size
(B) nucleus carries almost the entire mass of the atom
(C) most of the space in the atom is empty
(D) nucleus contains neutrons

51. X and Y are the two elements which form XY2 and X2Y3. If 0.5 mole of X2Y3 weighs 80.0 g and 0.1
mole of XY2 weighs 10.0 g. Then incorrect statement(s) is/are :
(A) The gram atomic mass of X is 20 u (B) The atomic mass of Y is 40 g
(C) The gram atomic mass of Y is 40 u (D) The atomic mass of X is 20 u

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CHEMISTRY
52. Select the correct matching of IUPAC name of the following compound.

CHEMISTRY
(A) Cl 2-(2-chlorocyclopentyl) pentane

(B) 3-(1-ethylpropyl) cyclopentan-1-ol


OH

O Cl

(C) 3-Bromo-4-chlorohexane -2, 5-dione


Br O

(D) 3-ethylidene-4-propylhepta-1,5-diene

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CHEMISTRY
53. Which of the following is/are a correct priority order of functional groups ?

CHEMISTRY
O O O
(A) –COOH > –C–O–R > –C–NH2 > –C–Cl

O O O
(B) –C–NH2 > –C–H > –C– > –NH2

O O
(C) –C–Cl >–CN > –C–H > –OH

O O O O
(D) –C–O–C– > –C–OR > –C–NH2 > –SH

54. Which of the following is/are correct ?

(A) 1-buten-3-yne has 7  & 3 bonds

Cl Br
(B) Total number of substituent in OH is 4.



(C) C2(CN)4 has 9 and 9 bonds.

(D) Cyclohexane has only one type of carbon atoms.

Space for Rough Work

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Website : www.resonance.ac.in | E-mail : contact@resonance.ac.in
P2JBPT1300619C1-18
Toll Free : 1800 258 5555 | CIN: U80302RJ2007PLC024029

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