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Caculation Lab5

1. The document contains data on belt tensions (T1 and T2) measured at different angles of lap (θ) for a flat belt system. 2. It also includes data on belt tensions for V-belt systems with different groove sizes measured at θ=90°. 3. The key results are that the ratio of T1/T2 increases as the angle of lap increases for the flat belt system. The log of this ratio ranges from 0.399 to 0.571 over the lap angles tested.

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0% found this document useful (0 votes)
43 views8 pages

Caculation Lab5

1. The document contains data on belt tensions (T1 and T2) measured at different angles of lap (θ) for a flat belt system. 2. It also includes data on belt tensions for V-belt systems with different groove sizes measured at θ=90°. 3. The key results are that the ratio of T1/T2 increases as the angle of lap increases for the flat belt system. The log of this ratio ranges from 0.399 to 0.571 over the lap angles tested.

Uploaded by

AriffDyamim
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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Angle of lap for flat belt,θ

No 90 120 150 180


m 1(g) m 2(g) m 1(g) m 2(g) m 1(g) m 2(g) m 1(g) m 2(g)
1 1600 500 1600 500 1300 500 1100 500
2 2000 700 2000 700 1900 700 1500 700
3 2600 900 2800 900 2700 900 2200 900
4 3400 1100 3800 1100 3000 1100 2500 1100
5 4200 1300 4200 1300 3400 1300 3200 1300
DATA FOR TEST 1
T 1(N) T 2(N) T 1(N) T 2(N) T 1(N) T 2(N) T 1(N) T 2(N)
1 15.70 10.79 15.70 10.79 12.75 7.85 10.79 5.89
2 19.62 12.75 19.62 12.75 18.64 11.77 14.72 7.85
3 25.52 16.68 27.47 18.64 26.49 17.66 21.58 12.75
4 33.35 22.56 37.28 26.49 29.43 18.64 24.53 13.73
5 41.20 28.45 41.20 28.45 33.35 20.60 31.39 18.64
∑ T 1 /T 2 7.45 7.32 7.91 8.87
log e T 1 /T 2 0.399 0.381 0.459 0.571
Table 5.2 TEST1

Angle of lap for flat belt, at angle of,θ=90


V-belt with correct/ fit
No Flat belt (a) V-belt large groove(b)
groove (c)
m1(g) m2(g) m1(g) m2(g) m2(g) m 1(g)
1 1600 500 700 500 600 500
2 2000 700 900 700 850 700
3 2600 900 1200 900 1100 900
4 3400 1100 1400 1100 1300 1100
5 4200 1300 1600 1300 1500 1300

T 1(N T 2(N) T 1−T 2 T 1(N) T 2(N) T 1−T 2 T 1(N) T 2(N) T 1−T 2


) (N) (N) (N)
1 15.79 10.79 4.91 6.87 1.96 4.91 5.89 0.98 4.91
2 19.62 12.75 6.87 8.83 1.96 6.87 8.34 1.47 6.87
3 25.51 16.68 8.83 11.77 2.94 8.83 10.79 1.96 8.83
4 33.35 22.56 10.79 13.73 2.94 10.79 12.75 1.96 10.79
5 41.20 28.45 12.75 15.70 2.94 12.76 14.72 1.96 12.76
Calculation
For table 5.2 Test1

At 90 degree

T 1=m 1g T 2=( m1−m2 ) g

1.
T 1=(1600 ×10−3)9.81 T 2=( 1600−500 ) ×10−3 × 9.81
T 1=15.70 N T 2=10.79 N

2.
T 1=(2000 ×10−3)9.81 T 2=( 2000−700 ) ×10−3 × 9.81
T 1=1 9. 62 N T 2=12.75 N

3.
T 1=(2600 ×10−3)9.81 T 2=( 2600−900 ) × 10−3 ×9.81
T 1=25.51 N T 2=1 6.68N

4
T 1=(3400 ×10−3)9.81 T 2=( 3400−1100 ) × 10−3 ×9.81
T 1=33.35 N T 2=22.56N

5
T 1=( 4200 ×10−3 )9.81 T 2=( 4200−1300 ) × 10−3 ×9.81
T 1=41.20 N T 2=28.45N

T 1 15.70 19.62 25.51 33.35 41.20


∑( ) = + + + +
T 2 10.79 12.75 10.68 22.56 28.45
T1
∑( ) T2
=7.45

T1
T1
∑ ( )
T 2 7.45 =1.49
( )
T2 average
=
5
=
5

T1
log e =log e 1.49
T2
T
log e 1 =0.399
T2
At 120 degree

T 1=m 1g T 2=( m1−m2 ) g

1.
T 1=(1600 ×10−3)9.81 T 2=( 1600−500 ) ×10−3 × 9.81
T 1=15.70 N T 2=10.79N

2.
T 1=(2000 ×10−3)9.81 T 2=( 2000−700 ) ×10−3 × 9.81
T 1=1 9.62 N T 2=12.75 N

3.
T 1=(2 8 00 ×10−3)9.81 T 2=( 2 8 00−900 ) ×10−3 × 9.81
T 1=27.47 N T 2=1 8.64N

4
T 1=(3400 ×10−3)9.81 T 2=( 3 8 00−11 00 ) × 10−3 ×9.81
T 1=37.28 N T 2=2 6 . 49N

5
T 1=( 4200 ×10−3 )9.81 T 2=( 4200−1300 ) × 10−3 ×9.81
T 1=41.20 N T 2=28.45N

T 1 15.70 19.62 27.47 3 7.28 41.20


∑( ) = + + + +
T 2 10.79 12.75 18.64 2 6.49 28.45
T1
∑( ) T2
=7.32

T1
T1
∑ ( )
T 2 7. 32 =1.464
( )
T2 average
=
5
=
5

T1
log e =log e 1.4 64
T2
T
log e 1 =0.3 81
T2
At 150 degree

T 1=m 1g T 2=( m1−m2 ) g

1.
T 1=(1 3 00 ×10−3 )9.81 T 2=( 13 00−500 ) ×10−3 × 9.81
T 1=12.75 N T 2=7.85N

2.
T 1=(1 9 00 ×10−3)9.81 T 2=( 1 9 00−700 ) ×10−3 × 9.81
T 1=1 8.64 N T 2=11.77N

3.
T 1=(2 7 00 ×10−3)9.81 T 2=( 27 00−900 ) ×10−3 × 9.81
T 1=2 6.49 N T 2=17.66 N

4
T 1=(3000 ×10−3)9.81 T 2=( 30 00−1100 ) × 10−3 × 9.81
T 1=2 9.43 N T 2=1 8.64N

5
T 1=(3 400× 10−3 )9.81 T 2=( 3 4 00−1300 ) ×10−3 × 9.81
T 1=3 3.35 N T 2=20.60N

T 1 12.75 1 8.04 26.49 2 9.43 3 3.35


∑( ) T2
= + + + +
7.85 11.77 17.66 18.64 20.60
T1
∑( ) T2
=7.91

T1
T1
∑ ( )
T 2 7.91 =1582
( )
T2 average
=
5
=
5

T1
log e =log e 1582
T2
T
log e 1 =0. 459
T2
At 180 degree

T 1=m 1g T 2=( m1−m2 ) g

1.
T 1=(1 1 00× 10−3 )9.81 T 2=( 11 00−500 ) × 10−3 ×9.81
T 1=1 0.79 N T 2=5.89N

2.
T 1=(1500 ×10−3)9.81 T 2=( 1500−700 ) ×10−3 × 9.81
T 1=1 4.72 N T 2=7.85N

3.
T 1=(2 2 00 ×10−3 )9.81 T 2=( 2200−900 ) × 10−3 ×9.81
T 1=21.58 N T 2=12.75N

4
T 1=(2500 ×10−3)9.81 T 2=( 2500−11 00 ) × 10−3 ×9.81
T 1=24.53 N T 2=13.73N

5
T 1=(32 00 ×10−3)9.81 T 2=( 3200−1300 ) ×10−3 × 9.81
T 1=31.39 N T 2=18.64 N

T 1 1 0.79 1 4.72 21.58 24.53 31.39


∑( ) T2
=
5.89
+ + + +
7.85 1 2.75 13.73 18.64
T1
∑( ) T2
=7.32

T1
T1
∑ ( )
T 2 8.87 =1.774
( )
T2 average
=
5
=
5

T1
log e =log e 1.774
T2
T
log e 1 =0.571
T2
For table 5.3 Test2
a) Flat belt (same T 1∧T 2 at Test 1 at θ=90 degree)

No T 1- T 2 (based onT 1∧T 2 at Test 1 at θ=90 degree)

1 T 1- T 2 = 15.70-10.79 = 4.91N

2 T 1- T 2 = 19.62-12.75 = 6.87N

3 T 1- T 2 = 25.51-16.68 = 8.83N

4 T 1- T 2 = 33.35-22.56 = 10.79N

5 T 1- T 2 = 19.62-12.75 = 6.87N

b) V-belt large groove,

No T1 T2 T 1- T 2

(7 00 ×10−3)9.81 ( 7 00−500 ) × 10−3 ×9.81


1 6.87-1.96 = 4.91N
= 6.87N = 1.96N
(9 00 ×10−3)9.81 ( 9 00−700 ) × 10−3 ×9.81
2 8.83-1.96 = 6.87N
= 8.83N =1.96N
(12 00 ×10−3 )9.81 ( 1 200−900 ) ×10−3 × 9.81
3 11.77-2.94 = 8.83N
= 11.77N =2.94N
(14 00 × 10−3 )9.81 ( 14 00−11 00 ) ×10−3 × 9.81
4 13.73-2.94 = 10.79N
= 13.73N =2.94N
(16 00 ×10−3)9.81 ( 16 00−1300 ) × 10−3 ×9.81
5 15.30-2.94 = 12.76N
= 15.70N =2.94N
c) V-belt with correct/fit groove

No T1 T2 T 1- T 2

(6 00 ×10−3)9.81 ( 6 00−500 ) × 10−3 ×9.81


1 5.89-0.98 = 4.91N
= 5.89N = 0.98N
(85 0 ×10−3)9.81 ( 850−700 ) × 10−3 ×9.81
2 8.34-1.47 = 6.87N
= 8.34N =1.47N
(1 100× 10−3 )9.81 ( 1 100−900 ) ×10−3 × 9.81
3 10.79-1.96 = 8.83N
= 10.79N =1.96N
(1 3 00× 10−3 )9.81 ( 1 3 00−11 00 ) ×10−3 × 9.81
4 12.75-1.96 = 10.79N
= 12.75N =1.96N
(1 5 00× 10−3 )9.81 ( 1 5 00−1300 ) ×10−3 × 9.81
5 14.72-1.96 = 12.76N
= 14.72N =1.96N

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