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Skin Friction of 6

The document calculates the ultimate skin friction capacity of a 6.0 meter diameter shaft that is 20 meters in length. It divides the shaft into 6 layers based on depth and calculates the ultimate skin friction for each layer using a formula that considers the coefficient of earth pressure, angle of friction between the pile and soil, and average effective overburden pressure. The total ultimate skin friction capacity of the 6.0 meter diameter shaft is calculated to be 1348.94 tons or 468.10 kN/m^2.

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Devendrasinh Padhiyar
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71 views2 pages

Skin Friction of 6

The document calculates the ultimate skin friction capacity of a 6.0 meter diameter shaft that is 20 meters in length. It divides the shaft into 6 layers based on depth and calculates the ultimate skin friction for each layer using a formula that considers the coefficient of earth pressure, angle of friction between the pile and soil, and average effective overburden pressure. The total ultimate skin friction capacity of the 6.0 meter diameter shaft is calculated to be 1348.94 tons or 468.10 kN/m^2.

Uploaded by

Devendrasinh Padhiyar
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Skin Friction of 6.0 M Dia.

And 20 m length Shaft

ULTIMATE SKIN FRICTION IN LAYER WITHIN 1.50 m. to 4.50 m. DEPTH


Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 11.40 t/m2
Therefore,
SFult = 1.00 x 11.40 x tan15 o = 3.05 t./m2
Therefore, Skin Friction Capacity of 500mm diameter piles = π x 6.00 x 3.0 x 3.05 = 172.47 t.

ULTIMATE SKIN FRICTION IN LAYER WITHIN 4.50 m. to 7.50 m. DEPTH


Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 13.20 t/m2
Therefore,
SFult = 1.00 x 13.20 x tan17o = 4.04 t./m2
Therefore, Skin Friction Capacity of 500mm diameter piles = π x 6.00 x 3.0 x 4.04 = 228.46 t.

ULTIMATE SKIN FRICTION IN LAYER WITHIN 7.50 m. to 10.50 m. DEPTH


Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 12.80 t/m2
Therefore,
SFult = 1.00 x 12.80 x tan17o = 3.91 t./m2
Therefore, Skin Friction Capacity of 500mm diameter piles = π x 6.00 x 3.0 x 3.91 = 221.29 t.
ULTIMATE SKIN FRICTION IN LAYER WITHIN 10.50 m. to 13.50 m. DEPTH
Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 12.40 t/m2
Therefore,
SFult = 1.00 x 12.40 x tan18o = 4.03 t./m2
Therefore, Skin Friction Capacity of 500mm diameter piles = π x 6.00 x 3.0 x 4.03 = 227.83 t.

ULTIMATE SKIN FRICTION IN LAYER WITHIN 13.50 m. to 16.50 m. DEPTH


Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 12.00 t/m2
Therefore,
SFult = 1.00 x 12.00 x tan18o = 3.90 t./m2
Therefore, Skin Friction Capacity of 500mm diameter piles = π x 6.00 x 3.0 x 3.90 = 220.48 t.

ULTIMATE SKIN FRICTION IN LAYER WITHIN 16.50 m. to 20.00 m. DEPTH


Ultimate Skin Friction = K σeff tan φ
Where,
K = coefficient of earth pressure = 1.00 (IS 2911-1979)
φ = angle of friction between pile and soil
σeff = average effective overburden pressure along pile shaft = 11.60 t/m2
Therefore,
SFult = 1.00 x 11.60 x tan20o = 4.22 t./m2
Therefore, Skin Friction Capacity of 6.0 m diameter shaft = π x 6.00 x 3.5 x 4.22 = 278.41 t.

Total Skin Friction Capacity of 6.0 m diameter shaft


= 172.47 + 228.46 + 221.29 + 227.83 + 220.48 + 278.41
= 1348.94 t
= 468.10 Kn/m2

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