ELECTRICAL ENGINEERING DEPARTMENT
Electrical Circuits 2 Manual
                                          ACTIVITY 2B
              IMPEDANCE OF RL CIRCUITS: PARALLEL RL CURCUITS
2B.1   Program Outcomes (POs) Addressed by the Activity
       b. ability to design and conduct experiments, as well as to analyze and interpret data
       d. ability to function on multidisciplinary teams
       e. ability to identify, formulate, and solve engineering problems
       g. ability to communicate effectively
2B.2   Activity’s Intended Learning Outcomes (AILOs)
       At the end of this activity, the student shall be able to:
       a. measure properly the voltage and current in a parallel RL circuit.
       b. calculate the voltage and current in a parallel RL circuit.
       c. evaluate results by comparing measured and calculated values.
2B.3   Objectives of the Activity
       The objectives of this activity are to:
       1. determine the characteristics of parallel RL circuits by using calculated
          and measured values.
       2. verify the result with an oscilloscope
2B.4   Principle of the Activity
When inductors are in parallel, the total inductive reactance is determined from reciprocal formula.
                                           1
                              𝑋𝐿𝑇 =    1   1   1
                                         +   +
                                      𝑋𝐿1 𝑋𝐿2 𝑋𝐿3
       When the two inductors are in a parallel, use the product-over-sum method to find the
inductive reactance.
                                      𝑋𝐿1 × 𝑋𝐿2
                              𝑋𝐿𝑇 =   𝑋𝐿1 +𝑋𝐿2
Inductive reactance decreases as the number of inductors in parallel increases. The result is higher
circuit current and lower circuit impedance
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
As in circuits with resistors only, the voltage drop across each component in a parallel RL circuit
is the same. Figure 2.2-1 shows a parallel RL circuit. The total inductive is reactance is
determined as follows.
                                 𝑋        ×𝑋
                       𝑋𝐿𝑇 = 𝑋𝐿1 + 𝑋𝐿2
                                     𝐿1        𝐿2
                                 1000 ×1500
                       𝑋𝐿𝑇 =     1000 +1500
                                 15 × 105
                       𝑋𝐿𝑇 =         2,500
                                 𝑋𝐿𝑇 = 600 Ω
Total resistance is that of R1
                                                    RT = R1 = 750Ω
                                                     Figure 2.2-1
        The coil resistance of L1 and L2 were ignored to simplify the calculation. If coil resistance
is so small that they have minimal or no measurable effect on circuit performance, you can ignore
them.
       Knowing total resistance and reactance, you can simplify the parallel circuit to two distinct
branches. Figure 2.2-2 shows the simplified (equivalent) parallel circuit.
                                                     Figure 2.2-2
       The individual branch currents are determined from the applied voltage (Vac), Ohm’s law
and the branch Impedances. The current flowing through the resistive branch is show below.
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
                                    IR = Vac / RT
                                    IR = 8/750
                                    IR = 0.0107 Apk-pk
      The current through the inductive branch is determined as follows.
                                   IL = Vac/ XLT
                                    IL = 8/600
                                    IL = 0.0113 Apk-pk
      The total circuit (LT) current in milliamperes is calculated as shown.
                                    IT = √IR 2 + IL 2
                                    IT = √[0.0107)2 + (0.0113)2 ]
                                    IT = 17.070 mApk-pk
      Finally, the circuit impedance is determined from Vac, IT and Ohm’s Law
                                    Z = Vac / IT
                                    Z = 8 / 0.01707
                                    Z = 468 Ω
2B.5 Materials/Equipment
      1 – F.A.C.E.T. Base Unit
      1 – AC1 FUNDAMENTALS Circuit board
      2 – 15 Vdc Power Supply
      1 – Osilloscope, dual trace
      1 – Generator, sine wave
      1 – Multimeter
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
2B.6   Procedure/s
       1. Turn off the power sources. Insert the AC1 FUNDAMENTALS circuit board into the
       base unit. Install the GENERATOR BUFFER if required. Turn on the power sources.
       3. On the INDUCTANCE/ INDUCTIVE REACTANCE circuit bock, connect the
          circuit shown Figure 2.2-3(a). Adjust VGEN so that Vac’ the voltage across R3 and L4’
          equals as 3 Vpk-pk 20 kHz sine wave. Consider Vac as the input voltage to the circuit so
          that the series resistor R1 can be ignored. With R1 ignored, the circuit shown in Figure
          2.2-3(b) results.
                                                Figure 2.2-3
       3. Calculate XLT an RT (XLT = 2πfL4, RT = R3). Record your result in Table 2.2-1.
          What type of circuit is shown in Figure 2.2-3(b)? __________________________.
        XLT           RT           IL4         IR3               IT                           IT
                                                            (CALCULATED)                  (MEASURED)
                                             Table 2.2-1
       4. Calculate the current flowing through L4 (IL4 = Vac / XLT) and R3 (IR3      =   Vac / RT).
          Record your results in Table 2.2-1.
       5. 5. Using the individual branch current (IL4 and IR3), calculate the total circuit [IT
       (calculated) =√IR4 2 + IL3 2]. Record your result in Table 2.2-1.
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
      6. Measure IT by using current sensing resistor R2 [IT (measured) = VR2/R2]. Record your
      result in Table 2.2-1. Do the calculated and measured values of IT agree?
         IT = ___________A
      7. Copy the values for XLT and IT (measured) from Table 2.2-1 to Table 2.2-2(under the
      column for parallel circuit with a single inductor).
                     PARALLEL RL CIRCUIT                 PARALLEL RL CIRCUIT WITH A
                    WITH A SINGLE INDUCTOR                    TWO INDUCTORS
          XLT
           IT
           Z
                                              Table 2.2-2
      8. Determine the circuit impedance (Z = Vac/IT). Record your result in Table 2.2-2.
      9. Use a two-post connector to add inductor L to the circuit as shown in Figure 2.2-4.
      Readjust Vac to 3 Vpk-pk. Calculate the new value of XLT [XLT = XL3 XL4) / (XL3 + XL4)].
      Record your result in Table 2.2-2. Did the added parallel inductor cause the total inductive
      reactance to increase or decrease? ____________________________________________.
                                             Figure 2.2-4
      10. Measure the new IT, and record your result in Table 2.2-2 (IT = VR2/R2). Did IT increase
      with the added parallel inductor? _____________________________________________
      11. Use Vac and the measue value of IT to determine the circuit impedance (X = Vac/ IT).
      Record your result in Table 2.2-2. Did the added parallel inductor cause the circuit
      impedance to increase or decrease? ___________________________________________
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
2B.7   Activity Report
         Section:                      Date Performed:
         Course Code:                  Date Submitted:
         Course Title:
         Instructor:
         Group No.:                    Activity No.:
         Group Members:                            Signature:
            1.
            2.
            3.
            4.
            5.
2B.7.1 Calculations
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
2B.7.2 Conclusion/s: Write at least three (3) conclusions.
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS
2B.7.3 Rating (See Attached Rubric)
ACTIVITY 2: IMPEDANCE OF RL CIRCUITS