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H0: μd = 0 versus H1: μd ≠ 0 - Correct?

Noodles & Company conducted taste tests of two spaghetti sauces to determine which would be added to their menu. Thirty tasters rated their satisfaction with each sauce on a scale of 1-10. The mean difference in ratings between the sauces was -0.28 with a standard deviation of 2.565. A two-tailed t-test was conducted and resulted in a t-value of -0.601, which is not significant at the 0.05 level since the critical value is +/- 2.045. The p-value was 0.553.

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0% found this document useful (0 votes)
82 views1 page

H0: μd = 0 versus H1: μd ≠ 0 - Correct?

Noodles & Company conducted taste tests of two spaghetti sauces to determine which would be added to their menu. Thirty tasters rated their satisfaction with each sauce on a scale of 1-10. The mean difference in ratings between the sauces was -0.28 with a standard deviation of 2.565. A two-tailed t-test was conducted and resulted in a t-value of -0.601, which is not significant at the 0.05 level since the critical value is +/- 2.045. The p-value was 0.553.

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mobinil1
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We take content rights seriously. If you suspect this is your content, claim it here.
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In 2009 Noodles & Company introduced spaghetti and meatballs to its menu.

Before putting it
on the menu, it performed taste tests to determine the best-tasting spaghetti sauce. In a paired
comparison, 30 tasters were asked to rate their satisfaction with two different sauces on a scale of
1–10, with 10 being the highest. Assume equal population
variances. The mean difference in ratings was = -0.28129 with a standard deviation of sd =
2.56540. Use α = 0.05. 

(a) Choose the appropriate hypotheses for a two-tailed test. Assume μd is the average difference
in the taste of the
two sauces.

H0: μd ≥ 0 versus H1: μd < 0 

H0: μd = 0 versus H1: μd ≠ 0 - Correct?

H0: μd ≤ 0 versus H1: μd > 0

(b) Find the test statistic tcalc. (Round your answer to 3 decimal places. A negative value should
be indicated by a minus sign.)

tcalc. -0.601

(c) Find the critical value tcrit for α = .05. (Round your answer to 3 decimal places.)

tcrit. +/- 2.045

(d) Find the p-value. (Round your answer to 3 decimal places.)

p-value. 0.553

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