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"Datos": (KJ/KG-C) (KJ/KG-C) (M) (KG/S) (KG/S) (C) (C) (C) (KW/M - C)

This document contains data and calculations for analyzing heat transfer between air and a geothermal system. The input data includes air and geothermal fluid temperatures, mass flow rates, heat capacities, pipe diameter, and heat transfer coefficient. The analysis calculates the heat transfer rate and temperature differences using this input data. The solution provides the calculated values for heat transfer rate, temperatures, area, and other parameters. A graph is also presented showing the relationship between geothermal inlet temperature and pipe length.

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Andrés Téllez
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38 views1 page

"Datos": (KJ/KG-C) (KJ/KG-C) (M) (KG/S) (KG/S) (C) (C) (C) (KW/M - C)

This document contains data and calculations for analyzing heat transfer between air and a geothermal system. The input data includes air and geothermal fluid temperatures, mass flow rates, heat capacities, pipe diameter, and heat transfer coefficient. The analysis calculates the heat transfer rate and temperature differences using this input data. The solution provides the calculated values for heat transfer rate, temperatures, area, and other parameters. A graph is also presented showing the relationship between geothermal inlet temperature and pipe length.

Uploaded by

Andrés Téllez
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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File:(Untitled) 24/07/2017 5:32:25 p. m.

Page 1
EES Ver. 8.400: #91: Educational version distributed by McGraw-Hill

"datos"
T_a_in=25 [C]
T_a_out=60 [C]
m_dot_a=0,2 [kg/s]
c_p_a=4,18 [kJ/kg-C]
T_geo_in=140 [C]

c_p_geo=4,31 [kJ/kg-C]
D=0,008 [m]
U=0,55 [kW/m^2-C]

"ANALYSI"
Q_dot=m_dot_a*c_p_a*(T_a_out-T_a_in)
Q_dot=m_dot_geo*c_p_geo*(T_geo_in-T_geo_out)
DELTAT_1=T_geo_in-T_a_in
DELTAT_2=T_geo_out-T_a_out
DELTAT_lm=(DELTAT_1-DELTAT_2)/ln(DELTAT_1/DELTAT_2)
Q_dot=U*A*DELTAT_lm
A=pi*D*L

SOLUTION
Unit Settings: [kJ]/[C]/[kPa]/[kg]/[degrees]
A = 0,6011 cp,a = 4,18 [kJ/kg-C] cp,geo = 4,31 [kJ/kg-C]
D = 0,008 [m] T1 = 115 T2 = 66,42
Tlm = 88,5 L = 23,92 ma = 0,2 [kg/s]
mgeo = 0,5 [kg/s] Q = 29,26 Ta,in = 25 [C]
Ta,out = 60 [C] Tgeo,in = 140 [C] Tgeo,out = 126,4
U = 0,55 [kW/m2-C]

No unit problems were detected.

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Tgeo;in [C]

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