0 ratings0% found this document useful (0 votes) 578 views114 pagesBruhn - Supplement
Supplemental information to Bruhn's analysis and Design of flight Vehicle Structures.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content,
claim it here.
Available Formats
Download as PDF or read online on Scribd
N\
SUPPLEMENT
To :
ANALYSIS & BESIGN
OF
FLIGHT VEHICLE
STRUCTURES
Bruhn
FOR
INCREASED SCOPE
AND USEFULNESS
William F. McCombs >PUBLISHED BY
DATATEC
DALLAS, TEXAS
Current price $15.95 plus $2,00 postage/handling.
For insured mailing add $2,00, Pay by postal money
order or cash only, please, to avoid delay of weeks,
Make Payments To
William P, McCombs
P.O, Box 763576
Dallas, TX 75376-3576
Tel. 214 337-5506
Other planned books includes
Engineering Colum Analysis (Columns, Beam-Columns,
Truss Members, Arches and Ben‘
An Introduction To Stress Analysis Of Light Structures
Te
wisi PaconseA SUPPLEMENT TO ANALYSIS AND DESIGN OF FLIGHT VEHICLE STRUCTURES
Willian PF, McCombs
‘TABLE OF CONTENTS
Article and Main Topic Page
Beam-Columns
Beam-Column Pormulas
Beam-Column Deflections
Bean-Column Formulas
Margins of Safety
‘Truss Analyais
Tangent Modulus
Multispan Bean-Colunns
Approximate Buckling Formula
Plastic Torsion
Beam Deflections
Numerical Analysis
Moment Distribution
Column Analyt
Column Analysis
Torsional Buckling
Colunn/Bean-Column Date
Material Properties
XD Crushing Loads
Margins of Safety
Dealing With Tolerances
Combined Stres:
Column Curve ¢
Free-Ended Columns
Shear Effect on Buckling
Multispan Columns
Stepped Columns
Nunerical Column Analysis
Initially Bent Columns
Column Design Data
Column Elastic Supports
Need for Successive Trials
Column Elastic End Restraint
Tangent and Effective Moduli
Buckling Load Data
End Friction Effects
References for Chapter C2
Flastic Bending Data
Plastic Bending Example
Plastic Bending Procedure
Complex Plastic Bending
Shear Stres:
ruction
nding Modulus
Apparent Margins of Safety
Flat Plate Shear Buckling
Bending Buckling
Unequal Angle Leg Thickn
Crippling Method Three
Torsional Buckling
Article and Main Topic
C9,13a Frame Stiffness criteria
C10,15b Thick-Wed Beam Analysis
611.29a Tension Field Beam Hole:
C11, 2he Rivet Design
C11,31a Stringer Construction
C11,32a Diagonal Tension - Stringe:
611.33a Stringer syst
¢11.34a Stringer
Diagonal
Longeron
Longeron Construction Example
Tension Summary
for Part 2
for Part 1
Monocoque Shell Buckling Data
Shell Axial Comp, Buckling
Effect of Internal Pressure
Shell Bending Buckling
Effect of Internal Pressure
External Hydrostatic Pressure
Shell Torsion Buckling
Effect of Internal Pressure
Combined Loads Buckling
Conical Shell Buckling
Buckling of Spherical Caps
Fitting Design
Pitting Margins of Safety
Factors of Safety
Bolte
Wate
‘ly Loaded Lugs
Obliquely Loaded Lugs
Riveted Splice:
‘Tnread Design and Strength
Filler (shim) Effects
Curved Beam Data
Tension Clip Allowable Data
Flush Rivet Joints
Blind Rivet Joints
Bolt Strengths
31|Design Check List
31|Margins of Safety
31) Tension Clips
31|Preload Torque Factors for Bolts
1
‘in Plastic Range32|Rockwell and Brinell Hardness Data
3|
35| Minimum I for stiffeners
33| stress-strain curves
3 Sheet and Other Buckling Data
36| Material Properti
35| Joint Design No
39|Fastener/Joint Allowable Data
0] Nut/Cotlar Tension Allowable
43] Bolt Allowable Bending Mosente
44] Bean Fornulas
us| Additional References
Bulkhead, Praze and Arch Analyses
wii P hecomePREFACE
The widely used and recommended college/industry textbook
“analysis and Design of Flight Vehicle Structures" by Dr, E.P,
Bruhn has had only one revision since its inception in 1965,
That was the 1973 edition in which Chapter A23 was revised and
expanded, Chapter C13 was completely rewritten by another
author and a few minor changes were made in Chapter 11, Aside
from these the book remains in its original form,
‘The purpose of this Supplement is to increase the scope
and usefulness of the textbook in numerous specific areas of
analysis, These include columns, beam-columns, bending
strength, margins of safety, tension field analyses, fastener/
joint data, arches, bulkheads and numerous others, The
practical use of the Supplement is discussed in the Introduction,
Only one or two applications of the Supplement's contents can
be worth much more than its coi
The Supplement may be expanded in some future year, so any
suggestions for this, or for corrections or changes in its current
text will be appreciated, Those readers who wish to be informed
of any future revisions or who have suggestions can contact the
author at P.O, Bor 763576, Dallas, TX 75376-3576 (Tel.214 337-5506).
‘The author is one of the coauthors of the textbook, His
career includes over forty years of experience in structural
analysis and design of numerous aircraft and missile projects in
the aerospace industry, Also included are technical papers and the
preparation and teaching of practical courses in structural design
and analysis for engineers working in the aerospace and other
industries,
William F, McCombs
POREWORD
I am pleased to have the opportunity to recommend this
Supplement to late fathe: widely used college/industry
textbook “Analysis and Design of Plight Vehicle Structures",
I hope its practical applications will be a benefit to all who
have the textbook, The additional data contained in this
Supplement can be applied to both the study and the work of
structural design and analysis, The Supplement should also be
of interest to, and eventually benefit, those who may be
considering purchasing the textbook.
Patricia Bruhn Beachler
aLINTRODUCTION
Tne purpose of this Supplement 1s to increase the scope and
usefulness of the widely used and reconmended college/industry
textbook “analysis and Design of Flight Vehicle structures" by
E.F.Bruhn. As auch it is by no means a revision of that book”
Rather, it 1s an expansion and clarification of numerous topics
and data in the book, along with the introduction of additional
topics and data.
For best coordination with the textbook the following has
been done, Where an existing article such as, for example,
Art. Cl.13 has been expanded or otherwise caanged or corrected,
the Supplement includes it as art. Cl.13a, the letter indicating
@ change or addition. When a new topic is added to a chapter it
1s given an article number which is subsequent to the last article
number in that chapter and includes no letter. For example, the
jast article in Chapter C3 is art. 03.14. Two additional topic,
pyield Stress Bending Modulus" and "Residual stresses Following
Plastic Bending" have been added, so they have been given article
numbers 03.15 and 3.16 respectively with no letters.
The same thing has been done with figure numbers and table
numbers, Where a figure has been changed or added to, it retains
the same figure number with an added letter. For example,
Figure 2.27 has added information go it has the designation
Fig.2.27a in the Supplement. Ynen a new figure is added it 19
given a number which is subsequent to the last figure number in
the caapter, so no letters are used with its number in the
Supplement. ‘This procedure also applies to tables.
Although the Supplement provides an Index, for most usefulness
the textbook aust be marked in such a manner as to guide the reades
directly to revised, corrected and new topics, figures, tables and
references in the Supplement. A highly recommended scheme for doing
this is provided later.
Structural design and analyses are based on theory, empirical
methods and data, various assumptions and individual judgement. The
assembled structure is a result of various specific manufacturing
methods and procedure: Because of these things and also the Possi-
bility of inadvertent calculation errors, it 18 alnays necessary to
Brove,vhe adequacy and safety of the completed structure by meas of
2 sufficient test program before it 1s put into use. Such teste most
denonstrate the structure's adequacy as to ultimate and yield
strength, fatigue life, fracture and stiffness. The test results
must be properly evaluated since the test article's materials
usually gave properties in excess of the miniaun required values.
Frocuring agencies such as the military, the airlines and other
government and private organizations usually specify the design and
test requirements and other criteria which gust be used or met.
wutoordis
ton of Su nt _and the Textbo.
In order to easily guide the reader from the textbook to
the Supplement, the following marking of the textbook is
recommended,
1
2
5.
On the textbook's Table of Contents place an asterisk, in
red ink, after "Contents" and add the following footnote
at the bottom of the page:
* A red asterisk preceding any article or figure number
in the textbook means that additional material is
available in the same’ article or figure in the
Supplement,
For each textbook article listed in the Supplement's Table
of Contents, place a large asterisk, in red ink, just to
the left of each corresponding article number in the
textbook (e.g., #A11,2),
The 12 articles in the Supplement's Table of Contents not
having a letter in the article number are new articles,
(e.g. C3,18 Beam-Column Analyses), Their numbers and
titles should be written in at the end of their chapters,
with a red asterisk just to the left of their article numbers,
The following figures in the textbook should have an
asterisk, in red ink, placed just to the left of their
figure numbers, to indicate that a revision or additional
data 1s in the Supplements
A5.1_ C2.17 62,26 «C5414 C8415 C8428 = c11,
A18.8 2,18 C2,27 C8.8a ¢8.20 8,29 cit,
C1.8 2,19 3,27 C811 C8125 c10.15 D145
2,2 2,20 03,28 c8.13 68.26 «011.43
€2.16 2.25 5,118.14 C827 C11 ab
7
8
The additional references shown on p, 30 (for Chapter C2)
and on p.A21 (for Chapters C3, C4, C7 and C11) should be
written in at the end of the list of references for
these chapter:
Put 6 black asterisk after "RINGS" on the title of p.A9.1
and at the bottom of the right hand column add the footnote
* See Appendix B of the Supplement for alternative analyses
of bulkheads, frames, arches and bents,
tvA SUPPLEMENT 10 “ANALYSIS AND DESIGN OF PLIGHT VEEICLE STRUCTURES 1
45.230 Introduetion
‘Ma_the following at the end of art.
(5.23. For a discussion of all types of
beam-columns, including non-unifora
bers, with numerous example probleme see
“Engineering Coluan Analysis" described
in Art.Al6.278,
25.240 Effects of Combined Axial and Lateral Loads
Add the following at the end of Art.
5.24, Porgulas and example problems for
beams in tension are available in the
ook described in Art. Al8.27a.
258 Equations for a compressive axially Loaded
10-050 Serut sit Miugerely Besteibaved Coad
Add the following at the end of Art.
45.25. The deflection, y, at any beam
station can be calculated as follows.
Mon ig + lp # ig + Py
y = -(M = Mg)/P
= Wig = w/e
therefore
Te negative sign is introduced since a
positive bean bending moment produces «
Regative (downward) deflection. a te
the goaent due to the lateral ioad
and Ute the final aoment.
only
very slightly to the left of the station
and then very slightly to the right, the
sane amount, AL. The slope is then
slope = (yg ~ y,)/24L
45.264 Formulas for Oter single Bpen Loedings
sla presents numerous addi-
of single span loadings.
‘The case
varying EI or a varying axial loading re-
of a beam-column with a
quires a numerical analysis, just as do
@ column of this nature. ‘The numerical
analysis procedure is presented in (3.18.
45,274 Goabinations of Load syatene, uargine of
Safety and Acoureey of Caleulations
For a bean-coluan the true margin of|
safety aust be calculated as discussed in|
Art, 0h.23 oF,
bending moments are calculated as dis-
cussed in art, 03.18.
15.208, Beaay
In Example Problem 2 member BD 16
conaidered to be pinned to ABC at Joint
This 18 why it does not pick up any of the
36,000 in 1b bending moment at joint B.
45.298 Stresses Above Proportional Limit sree
If @ column curve is not available
Probiews
for the beam material, the axial str
P/A, Le caloulated, fo/Fo,7 18 calculated
Fig. 62.16 1s entered with this value and
Evi fe obtained. Tuon Br S BEy/E). “Et
in Art. 45.29 18 actually Ey.
45.318 Bean-Columne in continuous Structures
Multispan deam-columns require a mo-
ment distribution analysis to determine
the end moments acting on each apan. Cnce
these are known the applicable single
span formulas in Table A5.1 and A5.1a can
be used to determine the bending aonents
at any station within a span.” Tats te
discussed in Art. 03.16,
45.32 Approzinate Formula for Besa-dolumns
For preliminary sizing when there
are no end moments the following formula
can be used to determine the final bend-
ing moment at any station
Mm Me/(1 = P/Fon)
where Mg is the moment due to the tran:
verse dads only and Per te the critical
load as a column (Chapter 2). Tis le
Gost accurate for a uniform lateral load
and least accurate for a concentrated
load. Por is calculated
member hae a stable o:
if this is not the case. For a bean in
tension the negative sign in the formula
is replaced with @ positive eign (ten-
Sion makes the bending moment smaller).
46.7a Torsion of Seli4 Hon-Cireular Mapes
All of the previous formulas are
jd on the shear atré being in the
etic range. With ductile materials
failure (rupture) does not occur until
the shear deformation has gone well in-
to the plastic range (similar to the
plastic bending case). The toreson:
Moment at which rupture occurs can b
Predicted ae discussed in Art. C4.20a.
For the special case of tubes ha-
ving @ circular cross-section the failing
torque ean be calculated as discui
art. 0é.20 and ite associated Fig
4.17 to 04.30 and in the exanple
lems of art. 04,21.
AT-1a Introduation
For practical purposes the deflec-
tion and slopes of beams are calculated
4 discussed in Art. A7.12a, standard
formulas being used for unifora bean
and for varying section beans using
tables such as Table C3.3.and the "ind
Fixity" discussion,
41-328 Dethections and Angular cuanges 9
70128 Setas‘by uethod ofStkinerte Sates
For beams of uniform section def-
Lections and slopes are most easily cal-
© Provided tuat 1/369 for the apnSINGLE-SPAN BEAN-COLUMN FORMULAS
Table A5.1a Continuation of Table AS.1
M = Cysinx/) + Cocosx/j + f(x)
Fain irr)
|
Pr pleteing
7)
Pawnee uy | totais ana | 0
4
mem edt at
[Tears se
ve Eo sews
com
—|
vm ey
Peet «
[ravsoen} - a?
Seen
aeeg
‘anbel there
for same reaulte
2 f Or uae Case IIT oy poser
+ with iegeang wa
lave ane v there bmn
- for sane reaulte
or eateu
2
= Mssine/4_sosb/ -zint/(1cest/1)/atnt/3
> (Occurs under the loads
w tis tsa superposition of Cases VMOMENT DISTRIBUTION WITH AXIAL LOAD
culated by using beam deflection and
slope formulas widely available in the
structural literature. The
are based on bending atresi
are accurate unle
or otherwise quite flexible due to hole.
eto.
only and
‘the wed 1s very thin
ieflections and the
at any station can be calculated
din Art. A5.25%
For beams with a varying ET a nun-
1 analysis 1a necessary to deter-
mine the deflections and slopes. This of
be done as discussed and illustrated in
Art. 03.18 where Table C3.3 shows the de-|
flections due to the transverse loade on-|
ly and Tables 03.4 and 03.5 show the ad-
ditional deflections due to the axial
loads, the final bending moments being in|
Table'c3.5. The deflections at any sta-
tion are then calculated per the formula
in Art. A5.25a using the final momenta
from Table 03.5. Tables for end fixity
are discussed in art, 03.18. With
elastic end restraint a t distribu-
tion analysis 1a required to det
the end
med to be a "Joint"
en though the member may be continuous
across the Joint, The sketoh in Fig.
11.92 shows the direction of (+) and (-)|
moments as they act upon the spane and
also upon the Joint. As seen there (+)
oments act clockwise on the span and
counterclockwise on the Joint. This is
different from conventional beam sign
convention where a (+) moment produces
compression in the "upper" surface.
"Joint"
Fig, 411.92 ign Convention
411.508 Example Probleas
The stiffness factor, K, ae used in
Art. All.5a and subsequently, 1s a "rel-
je" factor rather than a true one. It
has the value EI/L for the far end fixed
and .75 EI/L for the far end pinned. As
such 1t applies only when there is no ex-
ternal elastic restraint, k (in-lbs per
radian)at the ends or at any joint, and
when there is no axial load in the spans,
In auch cases “correction factors" aust
be applied to it, as shown in Art.All.14
for example. In’ general, to avoid inad-
Vertent calculation errors it 4.
the true value of the
» SF, which te in in-1bs per radian
ana’is
t to
SF = 4SCEI/L
coefficient ana
obtained from Fig. 411.47 (as "o")
or calculated per Art. Ail.l3a. Doing
this eliminates the need for introducing
the correction factors otherwise neededs
‘The carry over factor, COF, can be ob-
tained from Fig. A11.46 or calculated per
Art. All.13a.
In doing moment distribution calcu-
lations, unleas the “far end” of a span
ie pinned (or free) it 1s assumed to be
fixed for determining the values of the
etiftn
and carry over factor
32.006 Fined Red uomante, seicraees ane
Over Fastors for Beams
Golldina of Constant Grose-section
value:
All.5aa) for larger values of L/j than
are given in Fig. Al1.46, All.47° and
11.56 (for 28-4). Those values can be
culated as follows for compre:
of the SC and the COF
8¢ (far end pinne
) = 3/48
far en: : 6
a (fay gra fix Ae )
where & = 6(coseo4- 1)/(L/))
B= 301 - Soot (1/3)
jane formulas
1 but the trigonometric
functions are replaced with the hyperbo-
lic functions, cosech and coth. Exten-
sive tables of the 3¢ and COP values (to
6 significant figures) fron L/} = 0 to
2n for compression members and’ from 0 to
50 for tension members are in the book
@esoribed in art. A18.27a,
421.150 secondary Beading tmente in
FRIED nighe eants
Art. A11.25 gives a procedure for
deteraining the secondary bending moments
in such trusses but no illustrative exam
ple is provided. ‘The following illus-
trates the procedure except that in step
one one finds the relative rotation of
each member using the method of virtual,
work, step 2 19 omitted and in step 3
"ita relative rotation" 1 used 11
‘PP ri
jointe move, and therefore the members& SECONDARY BENDING MOMENTS IN TRUSSES
Fotate relative to each other. These ro-|
fixed end moments
1. Por the applied loads the resulting
internal loads in the members are de-
termined
2. Me Ao arbitrarily
the "base member" from
‘tations of all other a
oulated.
3. For each other meaber (one at a tine)
a olockwise 1 Sn-1b moment in the form
of couple loads (2/L) at ite ends ie
applied and reacted with a counter
clockwise gouple at the ends of the
Teaber BG. The resulting loads
mombers are then deter
Pig. Al1.93 and note that
(3 oF 4) meabers are losd-
in this procedure,
4, Then for each loaded member the quan-
tity SuL/AE is caleulated and the re-
aulte eummed to obtain the relative
rotation, 0, of the to which
‘the clockwise couple was applied.
5. Steps (3) and (4) are repeated for
each of the remaining members to get
‘their relative rotation: ‘Table
All.4 presents the basic data and
Table All.5 summarizes the calou-
‘Teble Alla
Fig. ALL.95 Relative Rotation Losds
For each of the above members ti
fixed end moments are calculated as
FEMS -6E10/L( 28 - )
where 24 -c 18 obtained from Fig.
A11,56 and socounts for the effect of
the’axtal load, $, in the meaber. A
positive (clockwise) relative rotation,
&, produces negative (counterclookwi sa
PEu's (per Example 2 sketch on p.All.2)
hence the minus sign ir the formula.
If @ member has one end pinned a fixed
nd moment ocours only at the other
end and 1s caloulated ai
FEM= ~6£10(1 + COF)/L(28- «)
where COF is from the pinned end to
the fixed end. Table Ai1.5
the calculations for the value
The fixed end coments at all truss
Joints are nom known and the moment
Atetripution procedure oan be carried
out as illustrated in Fig. All.43 to
obtain the final moments at the ends
of each member.
Table All.5 Calculation of Relative Rotation:
fuem=| SL7AE, Gouple
joer 4
2s :
BC 0289] 593
BD 0577 | 1183
cD 1155 |-2367
2 TBs
sol 8
Gop = -59T|
NotSECONDARY BENDING MOMENTS IN TRUSSES
je Effecke of Tharensed internal.
‘SNASD Pesan oh dasondery Bending Wonents
Although the secondary bending mom-
ente in the truss of Art. All.15a were
relatively small, they can become quite
large as the internal axial loads in the
truss weabers increase. As the applied
loading on the truss approaches the crit~
eal loading these moments will approach
infinity. This 16 why the theoretical
critical loading for a truss can n
attained; bending failure will pre:
The following example,
be
it]
A 1s 8 rigid joint and ends B and ¢ are
pinned. Assuming A to be a pinned joint
only to determine the axial loada in AC
and BC, they are as shown in the figure,
With the axial loads know this simple
truss can be analyzed for stability
(buck2ing) ‘tro-span caluan with
is Allustrated and di
st By oue-
ions, when P
‘Pap © 68072 and Pag = 50850.
(1/3)4p = 30/-V5-% 1078B0TR =3.9816
S0qp = 2.5428
Pap = 4(01.5428)(5 x 10° )/30
=:1028500
(1/3)ac =17.3/V5 x 10°750850 = 1.7445
S0ag = «89059
SFag 2 4( .89059)(5 x 109/17.3
= 1029600
Hence, at Joint A ESF = 1029600-1028500% 0
1
101700 16 the buckling (critical) load|
F If A were Ascumed to be al
aa pin=
ended coluin, since for pinned ends P;
for AB ie 54831 and +866 63915 = S46s0,
ffeate of applied|
loading on
eondary bending moments, assume that
P=100000 and find the resulting moments,
+ Een Far at aay joint $ 0 there 16 ne reaiewanee te rotation
TnFiniceml Sonsae sili eauae rotation tod faltanes
Let AG be the base member, apply a 1 in-
Yb couple on AB and react iv with an op-
Posite couple on AC as in Fig. al1.95.
Pigs 11.95 virtua York Lost
%
The relative rotation of member AB is
then calculated as follo
‘Ssul/ As]
x10
1380 |
Brats
=BBOS
The only FEM ie at A since end 8 is
pinned (and AC has no relative rotation).
FEMAB= ~6(.5x10* )(-5603x10% )(1+ 2-325)/
30(1.44)
= 13391 in lbs
Doing the moment distribution for the
final moments at A
ayy pe 19 aoe rou
4
gc .0068|-1.398
BF 1027109 |-933670
Bes
8
oF 30.877 (°9.877
ee ees tie
vanax Kon 102635]
zs
Fig. 411,96 aooent ptatribution
of
since bending fail-
ure would occur (if P were 101700 the ao-
ments would be infinite). Therefs
when the applied loading on a truss is
near the critical loading bending failure
will ocour (and prevent the eritical
loading from being reached), due te the
deflection of the truss joints under load,
peating the abeve caloulatiens for
successively snaller values of the app-
lied loading, P, results in the final mo-
Mente shown in Table All.6. Nete that as
the applied loading decreases from near
the critical loading the final moments
decrease very rapidly at first. nen the
loading decreases to the value which is
‘the critical value assuming pin Joints6 CURVED BEAMS.
Table 411.6 Variation of Final Moments
mith Applied Loading
‘Applied | % of | Final
Loading | Gritical| woments
Loading
101700 | 100.0 eo
100000] 96.4 | 145640
96000 | 94.5 50000
g1440 | 90.0 24638
81280} 80.0 12169
63315 | 62.3 6049.
40000 | _39.3 2380
(63325) the final moments are relatively
small. This ie hy an assumed pin- Joint
analyaie which ignores the secondary mon-
ents, @ common precedure, is unlikely te
reault in strength failures. Fatigue
life might be a concern fer very light
structures. If a trusa neaber ts subject
te @ lateral loading, that causes an add-
Ational type sf secondary moment te occur
and additienal bean-column effects.
Although this illustrative example
uses only the simplest type of rigid
jeint truss, the results would bo similar
fora conventional type of truss. The
analysis would, of cours, be more te-
dious. More about trusses 1s in the beok
mentioned in Art.A18.27a (and Fig.Al1.43}|
423,118 curved Benge
For compact cross-sections the bean
1m net subject te flange instability ef-
fects (Chapter 7). Therefore, with duc-
tile materials, the ultimate bending
strength can be calculated as discussed
in Chapter C3, ignoring the curvature.
hen the cross-section has relative:
ly thin flanges, ae with an I, channel,
Z etc. there is another effect of curv
It causes the flange to bend a
Fig. A13.22a, and therefore be.
effective, resulting in higher
bending stresses forthe beam. It also
generates bending stresses in the flange:
in a direction normal to the plane of the
web woloh are a maxioun at the flange-to-
curved Beam Section Bending’
Fig. At3,220
For syametrical cross-sections the oir-
cumferential bending strese at any point
on the section can be caloulated as
fp = AD 2 GAS]
where A= Area of crosa-seotion
R=Radius of curvature at the
centroidal axis
Ms Applied coment, positive for
tension in the outer fibera
and vice-ver:
y=diatance from centroidal ax1,
being + outward from thie ax!
and = if inwar.
z
width at distance y
Table 413.4 presente formulas for Z for
several cross-sections. Where a flange
width 1s required, it is not the actual
width, b, but rather an effective width,
to the deflection shown in Fig.
This can be caloulated
bores ai
Alsv2za.
Derr = cyb
where 0) 1 obtained from Fig. A13.22b.
Derr 18 used for determining A and Z
when flanges are pré Being less
than the actual b, 1t results in high-
er bending stre:
Fig.A13.22b
curved Beam
Bending
Coefficients
Pint
The transverse bending stress in
the flange, fpe, aan De caloulated ae
fot = Cafy
muere Cp 4s obtained fron Fig.A13.220
and fp fa the stress calculated previ-
ously uaing C1. Again, thie diecuseion
applies only to sysnetrical cros:
ations ae in Fig. Al3.22
When weight 18 important and rele
thin flanges reault in high
oan be reduced
by using thin, closely spaced, machined in
place "bulkheads" between the flanges, or
Beneath a T-member's flange. This reduaeCURVED BEANS,
the flange deflection and therefore re
reduces the beam bending stresses and the
flange's trangverse bending etre: uns
fortunately, there 18 apparently no de.
sign criteria for this, ao one aust rely
on judgement and tei to, both, lim
it and ultimate load adequacy.
Unaymmetrical oross-sectiona should
be avoided in fittings and hooke with
e curvature since there are no fora
or data for predicting bending atr
in such flanged members (teste required ).
Finally, much curvature with flanged
‘The: 6
03.28 and stiffeners are needed
there to prevent crushing or buckling.
‘The machined bulkheads also do thie in
in the case discussed for gachined iteus.
Equation 16(b) applies only when the
axial stress is in the elastic range and
when the cross-section of the column re
mains stable (1.¢., no local buckling oo-
cure before Por ta attained). hen th
conditions do not exist the critical load
‘than predioted by Eq. 16(b),
jd in Art. 418.88
428.60 Iapertect columns, tangeat
hips
Add the following at the end of art.
18,8, Since Ey (in Eq. 16d, 30 and 34)
‘Ae the compressive stress in-
‘above the proportional limit (Ey
slope of the stress-strain
being th
curve), @ successive triale solution for
Por 18 indicated. That ie, Ft must be
the value corresponding to'Ser.. ‘Tae suo
cessive trials oan be avoided if a colum|
curve ie available ae in Fig. A16.11, en-|
tering with L/r and reading Gor on the
ordinate. If a column curve fe not ave
ailable the procedure illustrated in Art.
2-10 can be used.
Equations 16b, 30 and 34 also do not|
apply, nor does the column curve, if
part of the cross-section t@ thin enough
to have @ local buckling stress which ie
eualler than Gor as predicted by the
Dove equations. In this cage a special
column curve which accounts for this lo-
cal instability must be constructed and
used ap shown in Art. C7.25 and C216,
TORSIONAL BUCKLING 7
Table A13,4 Some Formulas for z
“Gy
ot Berth fp te donne ee
a it T see hey soa ih ?)
eae ; : uJ
i
Se 2 [bimttecdeirns
Wes teats
428.00 Torsional Buckling
The previous discussions are for the
conventional form of general instability
involving only a bent (buckled) shape,
also referred to as bending buckling.
There is another form of general instabi-
lity which oan result in amaller values
of Por . This form of buckling involves
a twisting of the colunn (even tno
there is no applied twisting wouent) and
ie called “torsional buckling". Depend-
upon the cross-sectional enape, the buck-
led shape aay be either a pure twisting
or @ combination of twisting and bending
about one or both axes. It ocours for
open crose-seotions having thin elements
and 46 usually gore critical than bend-
ing buckling in the short to gediun range
column range. Toraional buokling is dis:
cussed further in Art. 07,31 and in de-
tail in the book described in Art.Al6.2788 RIB CRUSHING LOADS.
The broad coverage (180 pages) of
coluan design referred to in Art. 18.27
ag being in an originally planned “Volume|
2" was not included when 1t was decided
to publish only the current single volune|
rather than two volumes because of space
requirements. However, this material 1s
available in the book “Engineering Column|
Analysia" by W.F. MoComba, Datatee , P.0.
Box 763576, Dallas, TX 75376-3576. ‘Top-
ies include columns, beam-columns, truss
meabers, Dents, arches, torsional buck-
ling, local buckling, crippling, buckling
of shells and members on elastic or oth-
erwise sagging supports. Both, unifora
and varying section menbers are included.
428.260 uchantcal_ and Physical Proper
ees*oe "tome Aurorare waterfels
‘The last paragrapbe of Art. A18.26
refer to @ planned Voluze 2 which was
finally included as Parte B, ¢ and D of
the textbook. Therefore, it 1s Chapters
Bl and B2 of the textbook to which the
reference is made.
429-23 crushing Loade on Ribs Dus to
Wing Bending.
chapter a9
rovides methods for de-|
termining the stress in the flang
shear webs, stringers and skin panels of
the wing structure. Chapter 4.21 discus-|
sea the shear loada and stresses in wing
ribs. Neither of these chapters discus:
sea the crushing loade on the rib webs at|
a rib-stringer Joint which are caused by
the bending of the wing or of any box
besa having stringers supported by ribs.
Since the ribs provide simple eupport for|
the stringers in compression, if a rib
fails locally its simple support for the
wringer will vanish and tip stringer 111)
fail as a column. Mnen the rib web is
‘thin mith no local reinforcement and the
crushing loads are large such failure can|
occur. The manner in which these crush-
ing loads arise 1s as follows.
Fig.A19.44 showa a front view of a
wing in ite bent form (greatly exaggera-
ted), the upper stringers being in com
pression, the lower ones being in ten-
sion and'the load line froa rib to rib
shown by the broken line. Due to the
bonding radius of curvature, R, the angle|
@ will be @=L/R, @ very small’ angle
since R is very large in a practical win,
structure. The load, P, in any stringer,
located at a rib will have components of,
FACTORS OF SAFETY
acted by the rib load, Q, in the amount
@ = 2Pein(@/2) = Pe
or, Q= PLR
Since R = EI/i
Q 5 PLW/EI
If Ly and Lg are different rib spacings
Q = P(Ly + Lg) M/2er
Mnere Q is the crushing load on the rib
web at the stringer, Mis the bending mo-
Went on the wing at the rib station and
EI te that of the wing at the rib station.
Therefore, each stringer will need a clip
to the rib (or ivs equivalent) «hich can
pasa the load Q into the rib web, and if,
the load ie large enough to crush the rib
the clip will also need to be extended
and fastened ao as to serve as a stiffen-
for the rib, to prevent crushing of the
rib web.
C1.A36 Feotore of safety and uargine
of Safety von
These items are discussed in article
4.2 and in Cl.13 through C1.15, but they
do not provide specific assoclated num-
bers for factors of safety or aethods for
calculating the margin of eafety for nem
bers under many combined load system
The purpose of the following digcussion
is to do that,
Eactors of Safety
Ultimate loads, also called design
loads, are obtained by multiplying the
Limit'loads (the actual or expected
loads) by a factor of safety. For pilo-
Ved aerospace vehicles the factor of sat
ty le usually 1.5. For miasiles, which
are not piloted, the factor of safety 1s
Ae usually 1.25 except for any load con-
dition where the safety of people is in-
volved where it is 1.5 (e.g., for the ej=
ection loads from a carrier airplane).
Naval airplanes are designed for a very
fast sinking speed, about 26 feet per
load parallel to the rib which are re-
cond, so no safety factor 1s applied toMARGINS OF SAFETY
‘these loads. However, the landing gear
guat continue to function after such a
landing and the wajor attach fittings
(landing gear to wing or fuselage, wing
to fuselage and major fuselage section
splices) must chow a aargin of safety of
£25 for thie landing condition. In gen-
eral, factors of safety are specified by
the procuring agency.
Margins of Safety
The aargin of safety for a structur-
al member subject to a single load or
stress 1s calculated a
Allowable Load
MeS= TT ei
and gust tw zero or more. However, in
some cases it must have a specified posi-
tive value as aentioned for Naval air-
planes and .15 for fittings. This margin|
ie also required if addit{onal fitting or|
ing factors have been specified. For|
shear Jointe a ainiaum wargin of safety
of «15°16 required and for tension jointe|
At de .50. Also for these jointa there
Bust be no yielding at limit load. For
shear Joint attachments if the bearing
yield strength ts less than 2/3 of the
ultimate bearing strength, the bearing
allowable strength 1s taken as 1.5 times
the bearing yield strength and the joint
Ae said to be "yield critical". For riv-
r and tension Joint allowable
Chapter Dl. Also see Appendix A.
The previous simple formula for the
U.S. gives the deciual fraction by which
the load may be increased and still have
a M.S. of zero. For e: Af 8.2.20)
the applied loads may ised by a
factor of 1.20. However, the simple for-|
aula applies only when ail of the follow
conditions exist
vo @ single|
type of loading, hot to several types
such ae shear plus compression etc,
The internal loads vary linearly with
applied loads.
All applied loads are variable, 1.6
none are fixed in magnitude such as a
conatant pressurization.
‘the
conditions are discussed ae follons|
For exaaple a bolt may be subject to
shear, bending and tension simultan-
gously. In such cases so-called
“interaction equations", derived from
tests rather than theory, are used to
show structural adequacy. A typical in-
Yeraction equation os of the form
RU + R34 85+ ----- R= 1.0
Were R1=f4/F), Ro=fo/Po, Ry = f5/F5 and
Baz fo/Fa, } deing*tne“ultinate atrede
(Or load)"and F being the allowable
(or load). Ris called the
ratio". When the left side of
the equation 18 1.0 the M.S. 1e zero.
Woen it 1s less than 1.0 the M.S. is po:
itive but undefined and wnen it is more
than 1.0 the M.S. i negative but unde-
fined.
Interaction Equatio
+333 + 667 = .778 (<1.0)
Hence the M.S. 16 positive but undefined.
There are two cases for which the K.S.
ean be calculated directly using the in-
teraction stress ratios, R, as follows.
4) When all exponents (a, b, c, n) have
values of 1.0 and/or 2.0: In this c
ee
MS° SRy 4 VERE aaRe ~ ++?
b) When all exponents have the same value,
n, in whieh ease
MAS. = QR REG seer Ryn w2+0
For all other cases the M.S. 18 found by
using plot of tne applicable interaction
equation (discussed later) or by succe
sive trial calculations. The latter 18
done by finding, by successive trials,
by what common factor, A, all of the
loads must be multiplied to satisfy the
interaction equation. The M.S. te then
A= 1.0. Or, when
(anf (ang? (ars f+ (argh = 1.0
M8. = A= 10
Example:
For tne previous example
Ax 333+ (Ax .667P = 1.019 MARGINS OP SAFETY, INTERACTION EQUATIONS
After several trials the equation is sat-| uonoc! Linder (Various) Table 08.1
defied when A= 1.271, 90
Gurved_sheet 095
M.8. = A - 1.0 = 1,171-1,0=.173/ Compression or Tension and Shear
Since all exponent are 1.0 and/or 2.0 | gtiffened cylinder 9.41
the M.S. oan also be calculated Shear and Compression
by formula as
. Torsion and Bending 09.13
M.8,2 2 -1,02 a
3334 Vesa ee x OTE Shear and Bending 09613
When using this formula with other more
Jengthy interaovion equations the paren- | Stringer Friaary and 011.338
@ around the termER) gust be noted | Secondary stre:
tnd useds ER te the aumlof ait strege.
ratios having the exponent 1.0 and z! Ring (Frame) Primary and 011.338
the sus of Ulose having the exponent £.0:| Secenuary Sereases (for
Stringer systen)
hen plots of interaction equations
are available the M.3. oan be determined | Longeron Prigary and Secondary 11.368.
by @ graphical construction. This is 11-| stre,
lustrated in Art. C4.2ka in the textbook
using Fig. C4.36. However, graphical so-| Ring (Frame) Primary and 11.360
lutions are not needed when the prior
formulas apply, and in many other oa:
‘the successive trials procedure may be
easier with calculators or when the inte-
raction curves are not available
Listing of Interaction Equation:
Numerous interaction equations ap-
rin various parts of the book per
fhe following Iiating.
03.13
Bending and Shi 03.12
Bending and Bending 03.8
‘Tuping
Bending and Compression chee
Bending and Tension ch. 238
Bending and Torsion ohm
Compression, Bending and Torsion Ch. 24a,
Bending and Shear 4.25
Compression, Bending , shear ch. 26
and Torsion
on and Torsion ch, 27
Tat,
Bending and Compression 5.9
Bending and shear 5.10
Shear and Tension or Compression (5.12
Compression, Bending and shear 5.12
Secondary stro: (tor
Longeron system)
2. There are cases where the internal
loads in a member do not vary linearly
with the applied loads. One example is
‘the beam-column where the bending mom-
ent inort
plie
es Taster than does the sp-
loading. Another exanp:
in etringera due t
id action. For such cai
M.S; ae previously caloulated would be
an “apparent” M.S., not a true M.S,
Whether the apparent M.S. 18 positive
a8 follow
ive trials find the com
gon factor, A, by which the applied
Joade (which produce the int
in the members) aust all be gultiplied
to give a calculated M.S, of zero. The
true M.S. ta then A- 1.0, Por a beam
golumn the applied loada are the axial
load and the transverse loads. Multi-
plying these by any factor, F, will
generate a bending moment in the beam
ooluan which increases faster than the
eonmon factor, F. A te the value of F
for which the calculated M.S. 1a zero,
and then the true M.S. 1a A= 1.
‘Tie procedure applies for any inter-
action equation that. may be applicable.
Note that this requires a greater ef-
fort than that in (1) previously. This
ia because increasing the applied loads
requires another analysis to determin
the internal loads, since they do notDEALING WITH TOLERANCES,
vary linearly with the applied loads.
Thie ie important because mar-
gine of safety are reported for struc-
tural gembere and are use!to seo if
the gembers can withetand an increase
in the applied loads. If the applied
Joada increased by a factor of, aay,
1,20'and the report showed a XS. of,
say, 1420 1t would be Judged to be ac-
ceptable as an incr But if thie
happened to be an apparent K.S. the
true M.S. would be smaller and the in-
crease in applied loads would not
acceptable. Hence, the true value
‘the M.S. should be in the report.
not they should be “flagged” as being
Apparent ones so that a proper eval-
uation can be made when needed.
The intemal loads in a member
are due to the applied loads. Some~
times the applied loads consist
of "fixed" loads which do not vary
such as, for example, constant pres-
urization loads. When such are pres-|
ent the internal loads or stresses in
the member due to them should not be
gultiplied by the common factor, A, in
(1) previously or by the factor, F, in
(2) since they are constant. If auch
were done the calculated M.3.
conservative (too
loads were "additive" and vice-versa
Af they were "subtractive". Tnis alad|
applies when the M.S, 16 calculated by|
the formulae in (1a) and (1b), and
woen the M.S. 18 determined graphical.
ly, which makes these calculations no
applicable for for such cases (the
successive trials procedure is then
needed).
3
1,13 Dealing with Tolerances
When calculating margins of safety
for @ structural member nominal (mean)
@imensions are used to determine the
rand its allowable
Ideally, the M.S. 18 zero, gener-
ally,
manufacturing tolerance which accompan-
ies each dimension such as, for example
However, all drawinge specify the
+03" and these are considered as follow)
In aerospace structures 1t 18 com-
mon practice to aoneider only the two
worst tolerances affecting any dimension
and to compute the reduced margin of
safety based on the reduced diuensions.
Tois will give a negative M.S. when the
nominal M.S. 16 zero. Such negative
warging are acceptable if they do not
COMBINED STRESS EQUATIONS a
or ~.25 for redundant mombers. ‘These are
arbitrary liaits, some companies allowing
ore negative values such as -.19 and
=.39 respectively. Such negative margins
esused by tolerances are acceptable since
the probability is quite low that, eigul-
taneously, the material will have minigun
properties, the tolerances will be as
large as alloned, the loading condition
will be achieved and the internal loads
in the members will be as large as pre-
dicted. If the M.S. had to be zero or
more based on euch @inimum, rather than
nominal,dimensions coneiderable weight
would be added to the structure.
When dimensioning structural members care
should be used to prevent the bulld-up of
large tolerances affecting the final din-
eneion. Unacceptable tolerance effects
are most likely to occur when digension-
ing small machined or cast protuberances
or holes, where email internal corner
However, the above should in no way
be construed as sanctioning negative aar-
gine based on nominal diueneions or en-
dorsing the salvage of parte having less
strength than required por tne drawing.
62.60 Combined streas Equations
For practical calculation purposes
the following summary and exaaple problen
are helpful. Fig.Cl.8a@) shows the posit
direction of known or given applied
Fig. (b) shows the resulting
% endo , on any plane @ (posi-
tive directions shown), which can be
calculated as follons
(Gy. + dy 1# HC, ~dy 00828 + Tysin2e
[= Hoy,-dy Jain 26 - Fy coa2e
1. The principle stresses,
culated as follows. on
= HOyt dy 18 VRS, dy Prag
The plane for the largest principle
stress, Op, 1s meaaured froa the
plane of the larger of dy ordy and te
calculated as follows.
» are cal-
Op = tarctan(2%y/(d, -dy ))
The plane of the aller principle
stress 1s 90° amay from this plane.
3+ The maxioum ahear etr
exceed -.15 for single load path meabers
+ Toaxe 18
calculated ag folewes t” TSX
Taax = Vile - oy + Tae12 COMBINED STRESSES,
Tote plane on entch Tyq te located Le
farctan( (oy -o5 /-eay)
ies
4
%
ty
eI,
Fig. Chee
Exaople Problem
(>)
500
Fz000
For the stresses shown in the sketch
above (no! ty 18 compressive, hence
nogative) what areg and on a plane
at @ = 60°? What are cq, Gy Tnax and @|
G, =4 (10000 - 2000)+ }(10000+ 2000 )cosi26|
+ 4500sinlat = 4897
(10000 + 2000)sinl2d"=4500c08 120°
= Tas
#(10000 - 2000) + $(10000+2000FFu5 00" |
= 11509 and 3500.
= tarctan(2 x 4500/(10000 + 2000))
Taax = #110000 + 2000}"+ A50G = 7500
@y = tarctan( 10000 + 2000/-2( 4500
%
"
on
Gy 1a always 45° away from ep
If any of the above calculated values had
deen negative they would be acting or lo
cated in a direction opposite to that
shown in Fig.c-1Ba.
Usually one is interested only in deter-
FREE-ENDED COLUMNS
mining the value of the largest a and of
the largest Tmax:
G2sla Methods of Colum Fatlure.
ua Tauatione
‘The last paragraph 19 extended to
include the following. Predicting fail-
ure due to local instability requires
that tne column curve be reconstructed in
the short to intermediate ranges. Tals
Feconstruction is discusaed and illus~
trated in Art. C7.25 through C7.27
62.20 Free-Mded colume
Fig.G2.2 shows only a special case
of the free-ended column, one end being
fully fixed and the load remaining paral-
el to the axis of the member in it
straight (unbuckled) form. In general,
however, the load, P, may be directed
either to or from’a given point, "o", as
shown in Fig.2.2¢
a= aflasd)
(Ls Le)/ty
Fig, 02:28 Pree-Rded Goluma, Fixed tn
As snown in Ref.4 (Art.Al8.27a), the
buckling load 18 defined by the tran
cendental equation
(L/j)etnl/y = 2 = (1/n)"
of m (Fig.C2.28), Por
ye trials. ‘That is,
@ value for P, calculates
thie’ in the equation,
Pop the equation will be satin
However, thia effort can be great-
ly reduced by using Fig.c2.2b, entering
the figure with mand obtaining (1/4 )on.
Pop 18 then” calculated
Por = (1/3 )ap( EI/1? )
jote that shen a orl,zoo, a= 1.0 and
cen, te Caryie) mona
and Por = q?(EI/L?); whe
and Per = 0. Toat ie, ae a°decteasca
Pop increase, but aa Ly decreases Por
) tgeRtermate fore te pant) = =e/3FABE-ENDED COLUMNS WITH ELASTIC END RESTRAINT
. — fe
an
as
-— ght te
Ss lf |
Figs 62.2 Wi)ge ¥
dof being fully fixea, the
ond may be elastically restrained as
shown by the “torsion spring”, K, in Fig.
2.20, which has a value in in-1be/radien
Tole results in a smaller buckling load
than when fully fixed (k=e),
(a) Load advected
eee k)
EIS
k aoe wey
7" tb) Lond directed from "9"
Be (Lt lol/ty
Pree-inded colvan Having a9
Hisetiosldy Restrained Bnd
Fig. 2.
For this case, as suown in Ref.4, the
Duckling load’1s given by tne equation
Pep t8 found by successive trial calcu-
13
lations as follows. For a given k and a
one assumes a value of P, calculates J
and uses these values in the equation.
When P= Por the equation te satisfied.
For the spectal case whore a or Ly to
infinity, 20 that a= 1.0, Pop can be e-
termined directly by entering Fig. C2.44
witn KL/El, obtaining the value of Cand
caloulating Pop 88
Pop = Om EI/I
Note tnat when k= (fully fixed) ¢=.25
as given in Fig.c2.2.
It must be remembered that in all
coluan calculations E is Et, which de-
creases as the compressive stress ox-
ceeds the proportional limit. Also, when
the coluan has an unstable (thin) erose-
section E is an “effective” modulus* To
determine it one finds the buckling
stress from the aodified column curve
(Art.7.26) and then calculates 1t aa
ef = Fon L/ph /ar?
For free-ended columns Fig.02+17 18 ap
plicable only when a = 1.0
If the column has lateral Lo:
initially bent
eam-col!
For @ column as in Fig.C2-2a(a) assuge
that_a = 30", L = 30", E = 10.5 x 10¢
(1075-76 Extrusion, p.Bl.11), I = «191,
A > 150 sq in and & stable cross-section
Wnat is Per?
& = 30/(30 + 30)
for m= 45, (L/J)or:
Por = 2,05°(10-5210° }( 192)/30° = 9183
For = 7183/.50 = 18366
150. Per Fig.c2.2b
03. Therefore,
Since Fer< Prop. Limit, Ey=E as assused.
Example Problem 2
Repeat Example 1 assuming the fixed end
ie replaced with an elastic restraint of
& = 50000, ae in Fig.c2.2c. This must be
solved by’ succeseive trial:
Trial 1: Aseume Pop = .Sr® 51/417 = 4
Then) = VERS Oe Oe SEES
= 21.35 and L/j = 1,405
i
‘Then 50000- 0,
0:
=1.405 ctaTy
(#0)
=i
56849
‘ee art, 2.1614 EFFECT OF SHEAR ON COLUMN BI
After several gore trials it 1s found
‘hat when P 19 2622 the equation to st
Leried, so thie 1a the critical load,
follows.
3 = Vi0.5 x10"(. 191) 72688
L/} = 30/27.656 = 1.0848
25)(30.
50000 = =e HORAN oBnBT
2-47
27.656
which 1 essentially sero.
So thie particular elastic restraint has
reduced the critical load from 9148 for
a fully fixed end to only 2622 lbs.
2.38 Te ert
ot of shear on Dusxling stress
Equations (1) and (2) of Art.c2.2
consider only the bending stiffness of
columns. Wien a bean bends because of
applied transverse loads and the reoult-
ing bending moments, the usual def
tion formulas consider only the bending
moment. There 1s, nowever, an addition
al deflection due'to shear. For example,
a simply supported bean of uniform ET
having @ load, Q, at mid-span will have a|
maxinum deflection given by
y= QU /sBEI + ngl/saa
‘Tne first term 1s due to bending and the
second term is due to shear, where n 1 a|
form factor which depends upon th
of the cross-section. Thia te us
negligible, but ae n increases due to @
thin or perforated or otherwise more
flexible web it can become significant.
For @ column there te no applied
transverse load, but a shear load 18 gen-|
erated by the axial load as the column
takes on a bent (buckled) shape, aa shown
in Pig,C2,24
heart
Fig. 02.24 Generation of Sear in « column
At.any station the bending aoment te
M= Py and the shear in the aember te
V = al/ax = Pay/ax
where dy/dx 1a the slope of the bent
enape. Hence, for the uniform simply
upported colucn the shear varies from a
waxinun at the ends to zero at the
load used in
UCKLING.. MULTISPAN COLUMNS
middle where dy/dx, the elope, 18 zero.
Consequently there is arin the aen-
ber which, in effect, aakea the ooluan
more flexible and tnereby reduces the
buckling load or stresi
As discussed in Ref.5, for unifora
coluans the buckling load, conaidering
shear, 1
EA TITIAN
2n7AC
Fer ©
where Por is the buckling load ignoring
sh
ry n 1s the form factor for the
ction, A ta the cross-sectional
and @ ie’tne shear modulus of ela
theity (@ = £/2(1+ p)) where yp te Pois-
son's ratio. The values of n for several
etions are shown in Table C2.2-
Table 02.2 Cross-Section Form Factors
Cross-Section
Rectangle T.200
solid Circle 1100
thin Round Tube 2.000
[i-Beam or Rectangular Tube| Area/Web Areal
n can be calculated for other cros:
sections as
ne (Mt) {a ano
@ A 18 cross-sectional area, Q is the
etatic moment of area beyond dA about the
neutral axis and b is the width at the
neutral axis. For columns having lat-
‘iced etruts (trussed columne or "batten"
plati
Ref. 5
r stiffne:
that the column buckling load te signifi-
cantly reduced.*
62.30 Multtepan columns
Unfortunately, this and aost other
textbooks do not disouss coluans having
Bore than one span. Such columns are e
ily checked for stability by applying a
1 in-1b couple at any “Joint™ (support)
not having full fixity and carrying out
the moment distribution procedure as di
cussed and illustrated 1n Art. Alls13 ~
All,14 and its example problem:
The larger the axial load
slower" the convergence. If they
diverge at any Joint the column is un-
stable. Te critical load 19 that for
whioh they do neither, found only by su0-
cessive trial analyses, varying the axial
ch Moment distribution.MULTISPAN COLUMNS:
There are some helpful techniques
for doing this in Ref. 4, including some
“quick checks" for detecting instability
sometimes without the ubove procedure.
Ref. 4 also contains numerous example
problems for aultispan columna including
those on elastic or otherwise deflecting
supports, those having free-ended meabers
and those having varying loads and El
Values within the apang
The alternative to doing the moment
@istribution analysis 18 to conservative-
Ly assume that each epan 1s simply sup-
ported and check each span individually.
This 1s accurate only when all spans are
identical, the two ends are simply sup-
ported and the axial load is constant.
"Quick Check" Ingtability Criteria
1) The following can be done when each
span is uniform and the axial load
does not vary along the span (j is
constant). If any span has a value of
L/} greater than shown in Table C2.3
the column is known to be unstable.
If less than these values it aay or
may not be unstable, but a mouent die-|
tribution analysis is required.
Table C2.3 Instability criteria’ *
Ty
3 Suport Tapa
tne end elastically
aw
restrained, one end free
Both ends eimply
aupported
One end simply supported,
one elastically restrained|
Both ends elastically
restrained
AND
an
Elastic restraint 1s provided by an
adjacent span in a multiepan column
or by @ torsion spring as in Fig.C2.2¢
If at any joint the aum of the stiff-
ness factors, ESF, 12 negative the
column 1s unstable (see the footnote
for art. All.15b).
‘Tmo-Span Column
The following applies not only to a
‘wo-span column but to any number of
spans meeting at a common Joint (support}|
If the outer ends of the members aro ei-
ther siaply supported or fully fixed erthee|
(no elastic supports) the coluan is known|
to be stable if at the eommon joint ESF
is positive. If it is negative the col-
umn is known to be unstable. No moment
distribution 1s,therefore, required go
the analyeis is quite simple. The criti-|
2)
45
cal load 1 that for which ESF = 0,
found by sugcesaive trial values of ‘the
axial load.*
Example Problem 2
Ie the three-span coluan shown in
the sketch below stable or unstable?
ee
The analysis 8 carried out as snown, ap-
plying a 1 in=lb couple to the Joint at
B. Note tnat the SC, SF and CoF are on-
itted at the ends, A’and D, since they
are simply supported and no initial mom
ents (FEM's) are present there. As the
Moment distribution process shows, the
successive carry over momenta (COM's) at
all Joints are decreasing. Therefore the
coluan 1s known to be stable.
85
Actually, one should aleays calculate the
compressive stross, P/A, for each span
and use the corresponding value of f% (or
Bete) in calculating the value of J. Al-
s0, Ref. 4 contains extensive tables giv-
tae values of SC and COF to aix.sianifi-
cant figures (better than Fig.All.%-47).
Example Problea 2
Ie the two-span coluan shown in the
sketch below stable or unstable?
bw 4 —__
before for the
span column, it is seen that SSF at
the common Joint, B, 1s negative. There
fore, the column'ts inown to be unstable.
By successive trials 1t 1s found that
when the axial load 1s 93040 1baZisr = 0,
so that 1s the buckling load.
Tan AF ertterta (1) steve is aes
+ The Listed 1/3 vatea
fare tor Po For = ontaritt
If the axial load were 168750 to 219600
© Por 4 tree-ended column when a = 1 (Pig.c2, 2a)
the S.P. ie =Pitant/316 STEPPED COLUMNS
ZF would be positive, indicating stabi1-| For (= Per/A) should be calculated for
ity, but this would not be applicable bi used
cause L/J for span BC would exceed the
waximun (4.49+) allowed in Table ¢2.3.
Taie 1s why the Table C2.3 criteria
snould always be checked first, before
proceeding with any other analy.
In auamary, the moment distribution
procedure can be used to check any multi-
span column for stability. But before
doing thie instability can be detected
quickly per the criteria of Table C2.3
and if at any Joint ESF 19 negative.
Toon, for any two-span colunn if TSF 1s
positive at the common joint the column
ia known to be stable.
Uniform Two-Span Coluan Foraula
For the special case of a uniform
member on three sinple supports an ap-
proximate formula for the buckling load
ie
Per = of81(2 ~ b/a)/at
whore a is the longer apan and b is the
shorter span. When a= b (=L/2) the for-
aula is exact. When D becomes zero (1:
L) the error ia only 2.44%
id is conservative (one end becomes
The formula can be verified numerically
by caloulations for a two-span column
previously illustrated, or theoretically
ae in the book "Theory of Limit Design"
by J.A. Van Den Broek (J. Wiley and Sone)|
€2.60 Stepped Colum
are a epecial case for which
formulas (buckling equations) are avail-
din Ref. 7, Formulas
are presented for the cages of simply
supported members having one, two and
thr Por more than three
steps the formulas become too lengthy for|
practical useage, so a simple tabular
calculation form’is presented with an ex-
ample problea show.
re transcenden-|
tal in form, a successive trials proce
dure 1s necessary to determine the criti-
eal load. This consiate of assuming a
value for P (and Ey) ,oaleulating any
Associated parameters’ and using these v:
lues in the equations. When the assumed
P te Pop the equation will be satisfied.
for Ey (Fig.¢2.16) or Egee (art.c2,16)
correspond to Fer, which they auat.®
Sin
4 19 possible for more than
of P to satisfy the equations
(quite different values), 1t 19 best to
Use a longth-weignted avérage EI, calou-
lgte a, corresponding value for Por as
WEI/I? and use this as the initially as-
sumed value for P. For the special cases
of one-step and symmetrical two-step col-
uma graphical plote are available in
Fig. 02.21 and 02.22 for a direct deter-
mination of Per.
L
-eant VB ©
wnere 9 = VEE
Syametricel Coluan
‘Two-Ste)
Tr
‘gyaaetrieal Coluan
x tan(Le V2/EaTa/2)
Veena
‘Three-step Column
petrect sto
71g.62.20b Taree-step column
Tapes, sasattons are eastiy programed for rep!
SOLIEAOG ty computer or etitanle salsulators®STEPPED COLUMNS,
NUMERICAL COLUMN ANALYSIS
woere Bn=VP¥iala and f= Gain
The equations are easily programmed
for rapid evaluation using # suitable
calculator (or computer). The derivation|
of the equations is available in Ref. 7.
Goluans Having More than Three Steps
For the: 8 (and also for 2 or 3
ateps) the following tabular numerical
procedure can be used, as illustrated in
Table (2.4, It, too, 18 a auccesaly
trials procedure (aucceasive table;
umes 4 value for P (and E) as us:
ed later and carries out the tabular
calculations as shown. When the assumed P
1a Pop the value in Col. 6 for the last
sognent, W,
in|
gnent N-1 multiplied by
of segments can be used.
The exaaple below shows the last of seve-
ral auccesetve trials with different va
lues for P, the last being 79200 lbs.
As discussed previously, to start
with a reasonable value for # a length-
weighted average EI should be used and
P calculated as sEI/L?. When Col. 6y
Ae less than ~Col. Gy.) a larger value
for P should be assumed for the next
trial and vice-versa for 6y > -8y-1-
petospee py
Fig.c2.200 bata for Table c2.4 Exeaple Probiet
Table 62.4 Stepped Column Analyeis
oI
{tat
ore
P= 79200 lbs,
‘As discussed for the formulas in Art,
the proper values of E must be
used for each segment
62.60 Mumerteal Column Analyeee
casee discussed in
1 Fig.C2-21 through
Except for tho
Art.c2.1 through G2:
heck for atability under a given load, Py age cnet
EUG Sic be eek ashe) a thee
17
02.27 or other similar type data, a nun-
erical analysis is required to determine
the oritical load or stress. Art.c2.6a
and G2.6b presented a numerical solution
for the special case of etepped coluans
on aimple supports. The following pre-
sents @ procedure for any variation in
shape and for simple and fixed supports.
These procedures are in tabular form, ra-
ther than as computer programa, since
this gives a better understanding of what
1a being done. ‘The procedures are, of
Course easily programmable for solution
by computer. As before, the critical
load is determined byauccessive trial:
high means successive tables of caleu-
lationa. Example problems illustrate the
procedures.*
The basic procedure uses the method
gf discrete elastic weights (alao called
“Mobr's Method" and the "Conjugate Bean
Method") to replace the M/EI diagram and
calculate deflections and 1s due to New=
mark, Ref. 6. ‘The formulas for the el-
Qetic melghta are discussed in Ref. 4,
Simply Supported column,
Referring to Fig.C2.20d and Table
(2.5, the procedure 1s aa follows.
1. Divide the column into several equal
length segments, S, at least five or
six ate, but ten or more will
Give @ more accurate value of Por+
Assume (sketch) an initial buckled
(deflected) shape. Any initial shape
will do (even two straignt linea),
but the gore realistic it 13 the goon-
er the effort mill be completed.
At the station in (2) above which hae
the largest deflection, y, let ite
lection be taken as 1", and let the
deflections at the other stations be
Proportional to thie (per the aketah).
Lot P be one 1b. Then at any station,
By the bending goment will be Mn = Py,
Yns 0 the values in (3) above are ef-
Vered in Col. 2. Positive deflections
are upward and poaltive bending som-
nte produce compression in the upper
surface, hence the ainua sign used in
‘ne headings for Col. 2 and 4,
At each station enter the value of EI
in Col. 3. If there 1a a “atep" in EI
an adjustaent 1a made to EI at the
vation nearest to the step, discussed
Fy and ite EI is "flagged" with an
risk to indicate thie sd justaont,
* Baee (and ovter) tantes are saatty programmed
rapid solucion ty conputer or multatls talents18. VARYING SECTION COLUMNS
6. The “equivalent concentrated elastic
loads" ("elastic weights") are then
calculated per the foraulas below the
table for each atation and are entered|
in Gol. 5. These formulas are dis-
cussed in Ref. 4,
7. The tabular operations are then car-
ried out as shown, and a range of Pep
Values is obtained in Col. 10. If the
axial load is below this range the oo-|
lum ia stable, and if above it the
column is unstable. An average value
for Pop 19 calculated as shown, U4, 150
ibs, “Note that several checks are
Gade to detect any errors made after
the Col. 5 data are calculated. Co:
lumn 9 (and 8) defines a new shape
which will be different from that as-
sumed in Col. 2.
8. Using the deflections tn col. 9 or in
Gol. 8, let the larges.of these be one|
inch and get the others by dividing
thetr deflections by the largest de-
flection. Hnter these in a second
table's Gol. 2 and complete the table.
9. Repeat (8) as needed until the range
of Pop Values is quite small
oan then be taken ae the average of
the values in Gol. 10.
10.If at any station For (=Por/A) 18 sige
nificantly above the propertional lis
it stress (or above any local buckling
stress) the value of Et (or ferr) used
in the term EI gust correspond to For
(or to the local buckling stress),
which can require gore successive
trial tabular caloulatione (art. C2.16),
Tables ¢2.5 through 2.7 illustrate
the procedure. ‘Tree or four tables are
Usually sufficient. For the example
shown Por = 45000 Ibe per Table 02.7,
(actually between 44200 and
45900 lbs). If the applied load were
less than 39300 the column would be
knom to be atable after only the first
table. or, if wore than 47600 it would
be known to be unstable, without further
effort. Using ten segnents instead of
five results in a more accurate value of
Por = 4200 Lbs. values of Et and
of Eorr at any strees level are obtained
as discussed in Art.C2.16+
Ady t for a Step in EI
Referring to Fig.C2.20e, this 1s
done to keep the tabular operations
sinple.
a longer table te n
NUMERICAL COLUMN ALALYSIS
Figsc2.200 Adjuataent for « step decaetry
Let the station nearest to the step be
‘n" and that on the other elde of the
step be "a",
In x Ealy
eine fale)
R= Eley - Enln
(Enla)err = EnIn + (1-2a/3)R
(Entn)ore in Column 3 for station
Note thal if the etep is aiteay
between n and @, (EnIn)ert = Enin so
no adjustment 18 necessary. I? a =°0
then (Enln Jerr = Elay-
Examp:
For the column in Fig.¢2.20d station
3 18 nearest to the atep, which 1s be-
‘tween stations 3 and 4, a = 3.8" and
S= 9.4". Therefore, EI at station 3 is
adjusted as follows where n=3 and a
in'the above formulas. £= 10.5 x 10".
Calculate
Elay
Calculate
Calculate
Use
len =3ande
2 ery
275 x10"
3
Ae
R = .75(10”) = 1.5(10")
E3I
Serr
145(107) + (1-2x3.8/9.4)(~.75)(107)
26 x 10”
5+ Therefore 1.36 x 107 18 entered in
Table C2.5 for EI at station 3.
Golumn Fixed at tt
Left End
Tae following procedure is used for
@ column fully fixed at it left end. if
the right end te fixed, rotate the colunn
80 that it becomes the left end. The pro-
cedure is the aame as before except that
ded to account for
te the left end.
@ shown as Table c2.8.
Une fixed end moment
The table
The data in the table are for the
aber shown in Fig.c2,.20d except that
the Lert end ie fully fixed. ‘Therefore,NUMERICAL COLUMN ANALYSIS
19
seas Det eoged su
BE ee oe APN
[>-—20. 1s—4
Fig.d2,204 Staply Supported Varying-Section Goluan
eee pees Wen 5
es, res lan
Hastie Wotghte and Reactions
N= No. of Segments
5 Lengtn of Segment
Table 2.5 Determination of Por (First Trial) She n36
M Mom. ot | Unit | unt | tre
su. a | ae ‘aie | Sdpe | at | bat Fon
a | me | re | -O/@ @@O | %-2@s | 7D. | Oxsv2 | -Q/@
Pe [x | aw zie zi | xi [a
= z = z cr z z z
Tar
Pe la-eiatoy as rar Tar | ory CO
Tae
z eaiesleoe te ei er | ar Eo
Tz
z re] 6 73a ma ar EBD
TE
7 ao ie a ee] Te TB
TE
z z ed Ta az z
“See formulas below . a 46, oo
: = 4150
**Adjusted for step cray™ “4
136.27 a
ng -2@.. 1627. as Rye t@= Rye Os mas6
-Qy.1+@x= Fr
EQUIV. CONC. EL. LOADS OF coL.@ On -0
2 At Ends, Sta. O48,
Qo = 3.5x@o +3.9%Q@ - .5xQ;
On + 35% Oy + 3.0% Oy - 52 Ox True elope =Unit slope x s/12
1) Av omer Stations, 8 Slope at left ond = Ry x 5/12
@a= @e1*19%@+ Opa Slope at right end = Ry ¥ S//2
Beam Sign Convention
(+) Loads act upward
(+) Reactions act downward
(+) Deflections are upward
(+) Slope ts up to the right
(+) M puts top in compression
(+) Axial load 1s compression
The development of the calculation table
ie shown tn Ref. 420
NUMERICAL COLUMN ANALYSIS
Table C2.6 Determination of For (Second Trial)
SOLO lo © |o], oO 16
iene linear ee cntae Poa
Sa, | Me EL El, Loads Loads Slope Det.
2 | me | pe Out. | OO | L-2O, | 20, | Oxs72 | -O/@
tote te tet ts
=
7 np oee me
: at ore wef as
pare et ee ee on
* Use applicable formula z= 44.80 137.04
Bhat os ae Bia
2Q ae
te = 2Q. s31.06 Re t= ge = 2. se necks
mhen sketching the assumed initial buck-
ied shape its slope at the left end should|
Same as before
=|
i280
be sero, to be realistic. The unit va-
lues (due to the left end fixity) in
oo
ae ed
pa
— 12 »—|
a. got “tere oa Pend Yaying-oection Golan
p pot ts
Atm ee
Elastic Weights and Reactions
Fig.
Table 2.8 Determination of Por (First Trial)
®|O@lTOToOoToOTel[o/e[sle, ole
swat | aye] Co |e, Cone [ temo item ot] oy | Toad | ome | var
Kade [vena |G) NG) | ace | donee [stone [be | BT | Pom
+ | pe | ome} buts |-O/G}-O/YOu tw |Ou ee |OK- DlOH-DIO- nfO- G|-2@|20 |@x5-/O
a be ae be peter oee
chor ar mess tar aor ore re er
Sane a ae os ere or te ae
= Te eat =r | aa or fs ear A
ststr tt} a} oar or 7 z
Te aust ae ganes Ea same
ther. os Ponay, = ae
mS HID +1O+1@: Ons One: ert
f 7 (and 8) te omteulated aitrerentiy for this case (about the right end).NUMERICAL COLUMN ANALYSIS,
INITIALLY BENT COLUMNS
aa
Table 02.9 Determination of For (Secona Trial)
{fo efotetTeotToto @lelel ele
sia. | ae» [orgy] at | aver | aspen] 4; Sone] Ee; Cone = Sie mes
meer peer niet Lei Teor a
is Sor ss ae
Sareea ao
Sar rae ma rer ae pe
=H
San ne ote ore re arf et
ae aoe oa pe ee a
mene} —} a ao 5
rere BH apm aw ne
a Make eame checks as before Peay, * $6.025¢
3,6, 8, and 10 do not eaange in
successive tables. For any station, n,
the entry in coluan 3 ie 1 - n/N where N
is tne number of segments used. Hence,
these decrease uniferaly from i.0 for
station 0 to zero for station N. Columns
1 through 10 are completed, then My is,
culated as shown and the reat of the
table 1s coapleted. For the meaber in
Fig. C2.20f using five segnents Por le
found to be 66025 after two tables are
completed. A third table would reduce
the spread in the Col. 16 values for Pop.
Coluan Ft:
Bach md
The procedure is the same as for the|
previous left end fixed case except that
additional columns are needed to account
for the fixed right end. The initial as-
sumed buckled shape should be aketched in|
with zero slope at each end to be realie-
tic. Table C2.10 shows the procedure,
‘The values entered in Col,3,4,7,8,10
11,134 14 do not change in successive
tablée. For any station, n, tne entry in|
Golumn 4 is n/N, where Nis’ the number
of segments used. Hence, the
uniforaly from tero at station 0}
t station N. Columns 1 through
"9 completed; then My and ig are cal-
culated and the reat of the table is com-
pleted. Using five segmenta the buckling|
load, Por, 18 found to be 172250 lbs
after tno tables are completed. lore
tablea would give more accuracy. The
euggeeted checks should be made to detect
any errors made after Column 11.
These tables, with a ainor change,
are also letermine the bending
moments in bean-columns with a varying EI|
38 discussed in Art. C3.18. The value of|
for the aeaber aa a column can also be|
calculated as shown in Table C3.6%.
Qther Uses of the Table.
For a complete discussion of the
tabular method development, the "equiv-
concentrated ic loads" and addition-
al examples seo Ref. 4 (described in Art.
A18.27a) which also diacusses the follow
ing application
1. Axial loads between the ends
2. A column conatating of two pieces
®onnected by a torsion spring (which
could also be a splice).
Multiepan columns having one or gore
spans of @ varying EL
Free-ended columns having a varying EI
The numerical determination of carry-
over factors and stiffness factors
Multispan columns on elastic supports
which may be present as either dis-
crete isolated supports or another
beam or colusn.
2.60 Columns Having an Initial Beat saps
When a column has an initially bent
shape as in Fig. C2.40 the axial load
will generate a bending moment along th
colum in the amount M=Py, where y is
the deflection of the bent shape at any
station. The coluan may be uniform or it
may have @ varying £1.
0S
ve.c2,00 Gstemn Vien Initial bent ape
Therefore, the column ia actually a
Deam-column, as discussed in Art.C3.18,
Beam-Columns Having an Initially Bent
Shape" except that there are no trane-22 NUMERICAL COLUMN ANALYSIS
Anavaed Dertecged
fess no
=
bP fy
F1g.02.205 e Bade FLaed Yarying-Section Column,
t
nt a 3 Hee
R,=0. rat lan=o
Elastic eignts and Ranctions
Table 2.10 Determination of Por (Firat Trial) Stet Hemche
Do lololoT oToToTolT@[6le[6[e/e][e]ele|e, a fs
ur, “F l@.mlQx
shin] | 3 ia | om
[on fon fone ona -B
amjom>Phoho
Ee a a wa
1810.4 19-2028
988.19 2" 79.8
4) ** See Table 62.5
ahi at im ee
2Q) oy 2 2@ omg x2 G) 2 Pemans WD
10: =O:
10-90 7
Table C2-1i Determination of Por (Second Trial)
© |o[olo]/ OTOT@ To [eee |e ele @|elelala
“|-8|-8] SRS Boole:
5 &
[8+ 40x Bl 6|:@ |O+27u1.0/9
Mer ge
verse loads and their initial banding mo-| gin 1s based on ueing Pop.
Rents, Mg. Thus, the column would be and
alyzed a8 discussed there using an equiv. Therefore, an alternative approuch
Pegs yeaeanse loading such as that in| 1s to assume an initial Dent shape having
Fig.C3.33 or thereabouts, a "bow" of L/800 inches or thereabout,
QF of what the drawing specifies such aa
Actually, no colum 1s perfectly traight within X inches" where X is us-
straight although this te assumed in us- | ually on the order of L/600 or aos YS
ing the numerous buckling load formulas actually a tolerance for deviation from
and data for Por. Because of this gany | straightness of tX inches, so the moss
analyats and designers maintain a smail | would be *X/2 ani this would be used to
Positive margin of safety when tne aar- | Show a cero or positive margin of dafety.COLUMNS WITH ELASTIC SUPPORTS
Then a check 18 nade using X to be sure
that there ts not a negative margin
of safety greater than ~.15 or -.25 (per|
‘rt,Ci.13b). Sonetines X, rather than
X/2,18 used to show a positive aargin,
which 13 a conservative procedure. In
any case @ beaz-column analysis 13 aade.
2.74 Design Coluan Curves for Columns with Rone
778 alters Crose-Sectione
For columns with other steps the
procedures in Art.C2.6a are used. For
columns whose taper does not geet th
requirements of Fig. 02.23 or 02.24 ei-
ther a conservative assumption (adJust-
ment) for the taper aust be used or a
numerical analysis as in art. C2.6b is
required.
2,80 Colman Pirity coefrielents ¢ for U
Ceolasns with Elastic Side Beatraint
Known Eod Beoding bestreints
Fig.02.25a and ¢2,26a provide the
envelopes (for q=eo) for Fig.C2.25 and
02.26.
© 8 0a 03 4
Pig.c2, 26a
3 08 O71 Of O08 10
ML
23
€2,10a Solution Without Using Coluan Curves
The inside scales for Fig. C2.17
are not shown in the textbook. Flg.02.17a
shows the inside scales for the ordinate
and for the absciasa.
It must be understood that, like a
coluan curve, Fig.C2.17 (and 2:17) can-
Rot be used when deteraining the critical
load requires using a paraneter which is
also a function of E. Tis occurs, for
example, with Fig.C2.25, 02.26, 2.27
(and 2-27a) where the parameter C 1s a
function of E. This also occurs for
other such data. In these cases a suc-
cessive trials procedure aust be used
(as in art.c2.12, Case 2 Inelastic Fail-
ure, Portion 2). That is, the value of E
used in determining Pop por the figures
muet also be the valus of E corresponding
Lo For= Por/A when the stress te in the
plastic range (£ 18 By) or when local in-
stability is present (z ta bere). Ey and
eff are discussed in Art.c2ci6
C2198 gel serengen vith Known End Bestraining
ents
Fig.02.27a 18 auch more useful than
Fig.02.27 since 1t provides curves for
numerous values of k and kj, wnere the
symbol "k" 16 “uY in Fig.C2-27 and in Art
2.12. The curves can be obtained by us-
‘he wonent distribution procedure.
Referring to the example shown for
Fig.c2.34, for each of the restraining
members, AC, AE and AF the value of k is,
calculated as k= 4SC(EI)/L where SC is
obtained as C in Fig.all.47, conserva-
tively using the "far end pinned" curves.
for tension or compression in the aeaber.
The total restraint at end A of the uea-
ber AB will then be
ka = kag + Kar + kag
The same thing would be done ut end B for
members BF, BG and BD to obtain kg.
Then having the values of k Por for nem-
ber AB ts obtained by using Fig.c2.27a.
Note in Fig.all.87 when L/} exeseds a
for compression members C becones neg-
tive for the pinned end case.
This procedure ts more accurate than
that in Art.c2.13, but it is still an
approximate one. ‘For more exactness the
procedure discussed in art.All.15b should
be used, Many trusses are designed accuy
Bing pinned joints which ts generatiy
conservative
discussed in All.15b.NON-DINENSIONAL DATA FOR COLUMNS
¢
E sol 0
3 a ©
e
Fa ‘0
| ©
®
za *
«J ©
20
Tel RACK TRV
10 -10
Ola ope 20 Sa ag War coe)
Pig.C2,l6a Dimensionless Tangent Modulus Curves
ay
0:
230 32 14
Fg. c2.17
Fig.C2.17a Non-Dimensional Column Curves
Bis also\VF0,7/For wnere For = "*E/(t/p#, E veing Youngs Modulus (not Ey)TANGENT AND EFFECTIVE MODULI 25
Example Problem
Proceding as discussed, recalculate
For for member AB of Fig.c2.3 asauming
that the loads in the restraining members|
at ends A and B are due to an applied ups]
ward load of 3,000 1bs at joint D, react
ed at A and B. The following table showsl
the calculations for k at ends A and B.
7
ml? =) aye]
ed
sles
Hes
B580h uaa,
S83 2
Bono
Using Pig,C2,27a, ky = kp (the larger i)
and k= eae
kyL/EL = 246300(30)/1,121,000 = 6.59 so
Wy = 180 and Cia obtained tro Sa”
2,278 as 2,2,
For this member D/t = 1.25/.058 = 21.6
and per Fig.Cl.9 its crushing (crippling)
strength 45 quite high, 67500 psi,’ There.
fore, the coluan curve of Pig.c2,3 for RT|
can be used without modification, For
member AB
Ls LT = 59/V2 = 20,2
Up = 20,2/,422 2 47,9
Then, per the column curve, for member Aa|
For = 53,000, This ts slightly less then
obtained per the Art,c2,13 procedure,
If pinned ends were assumed for all
Joints then C = 1.0, L/p = 30/,422 = 71,1
and For = 43,000 (too small), but worde
about bending failure in Art-All-isb o
applies here. If the truss has meabecs
subject to local instability see art,
62.16, Also if the members’ b/t were
darEe. say 9 or gore, and of open sestion|
torsional buckling might be critical
(are,c7,31),
62.16 The Use of By ant Bere
ngent Modulus, Ey,
As the axial stress in a column be=
comes increasingly greater than the prow
portional limit stress, the tangent bodu~
jus which ts the slope of the stresas
Tats Teduction in Ee ts shown in FigsBles
Tight being Et) and
also in the following sketeh,
has shown and experimental data has veri-
fied (Fig.A18.11 and A18.12) that the use
of Et is justified for determining the
buckling stress of columns, It ts also
used for beam-columns having significant
axial stresses. Hence, the use of Ey in
Art.C2.1 and subsequent articles is tn-
derstood,
However it must be understood that
Et 1s applicable only for columns of
stable cross-sections (reasonably thick
flanges ete.). That 1s, there must be
no flange having a local buckling stress
smaller than the column's buckling stress
If there ts then Et does not apply and
an "effective" aodilus, Eerr, suet oo
used instead, Te 4s snaliey than By.
The Effective Modulus, Fore
When any flange has a local buck-
ling stress smaller than Fp for the col-
wsnyassuming a stable cross-section, an
"effective" value for E, Bere, aust’ be
used, Eerr is obtained as follows,
A coluan curve is constructed as
discussed in Are.C?,25 and iilusteatsd in
Art.C?.26, Method i there is the most
frequently used, followed by vothou 3:
tiaving this adjusted coluan curve chesh
accounts for the reducing effort offen
cal instability, For can be obtained for
any value of Lp,
However, when the buckling stress is
deterained for other than the bere
Simple case it is necessary to use Eery
which can be gotten as follows. For’ sty
Yalue of Foy the value of Lip ia avualned
froa the coluan curve and Eerr is catee,
lated a
Eert = For(i/pl? /n*
4
~ Proportional tints stresa
It 4s for cases where For 1s determined
using a “constant” which ts a function of
E that Eerr aust be determined and used:
Examples of such cases are Pig.¢2,25
C226, €2.27, C2,41 ete, In these cases
As discussed in art.Al8-8, Shanley
a successive trials procedure 1s needed26 COLUMNS WITH ELASTIC SUPPORTS, COLUMNS WITH INTERMEDIATE Loap
aes Podeety 8 dee,
That is, one assuues a value for Eerr. de-| 5 =.
termines For and then determines the vs lue| 2 Aytanky by 2 Ayiands 4
of err corresponding to this For per the 1 ‘
above formula, If it ts not the sane (es-| eh 2 fe Pity Pe
sentially) as the assured Eger another va-| were 12 arg amg te
lue for Eere 45 assumed and’ the procedure 2 > 1
1s repeated. This 1s repeated as neccore ‘The critical load combination,
The value ‘cortesmenaaratee 28 essentially | .,.,42%9, ruitcel load combination, |
Staata'aS SOUTS2O eg fogs Bia’ ro-) cabled ti and Ya guste, the sate
Solng Et ag diarissed ret qreeazegmnen | paete es the applied Toads Pyand Fo 3
using Et as discussed in art.C2.10a. er; oads calculate a = » Assume Pp is
1p noe aed Sith tean-coutans Condy geis] toads calculate a= Py/Fo" Assuse PS
Po.and per the foraulas find by sucsesive
Since the beas-coluan allowable steect ais the value of My which sotseres
considers any local buckling effect when | tials th e
fethod 2 theveln ts ween ge eteet whe af
Method 1 Eerrwould be used when loca’ tee
stability 1s present, see art.c3 18. lo
2.47 sition Dutting ond ate th 8
Tis article provides additional ICT e8 8
buckling load data’ for various trons or 5
goluans, It 1s generally self-explana~ : i‘ °
tory., 3 S a
° { : a
: st = . 3 ®
Askin taorm pee on ee ~ 5
sal sala self nd : a
|e oe nec ae i i} dss
Ftg.c2.41 Column On Elastic Foundation | +, s é :
8
be ‘ $ alls y i
® 3
Bole tn pe toe 3 i
eddie 3
+ [+] sfesfeafon Jordon fo [loo zy. & aes
Eeteiepe are ee fev * pas B “3
F1g.c2.62 Column On Elastic Foeieiis | «| sau dl] FE
With a Distributed axial Los 27: ze
ps] =
a ae &
or lo
Pie. C2.43 column With Intermediate Load
Note that the intermediate load, Py, ke
in Fig,C2.43 must be located at the step, *
Af one exists, The buckling equation ¢> eCOLUMNS WITH ELASTIC END BENDING RESTRAINT
the equation and then calculate «= Pi/P3] portion then the value
If a’ # @ assume @ different
calling 1t Pb, and repeat, Repeat as
necessary until a PL and P2 are
then the critical load codbination:
margin of safety is then
Yalue of Po,
The
MS. = PL/PL - 1.0 (or ¥2/P2 ~ 1.0)
If For ts 1n the plastic range for either|
22
of Et aust be used,
and the value of Ey corresponding to Fee
Bust be the sane , essentially, as the
Yelue used in calculating it, (successive
trials). If local instability is present
Eerr would be used instead of Ey. Pane
procedure is, of course, auch siapler
for the special case where there ts no
step (Ely = Elz),
Por = CntEI/L? Bhs ote cot EE
Lo = 7
i
3)
35 p-
}——T {| | | _—__
[«| | ——J | | 4
3.0 |
BX fe, |
09 | _—_—_—7
25
=|
c }—1_5, |
ce ee el Leh ae Eas,
i 0%,
_e a
Ls >(@ Q)< 4
ie .—s
1.0 1 i i 14
Ls ce 30 100, 150 200,
Pig.
Note that interpolation for ¢
fhe Lines* is non-linear, For an exact
Yalue here, or for KiL/EI > 200, Pee can
be found by successive trials, as f5lisus
1.Use the figure to get an approximate
value of Cand calculate Per.
"between
2, Get the corresponding values of J, L/y
COF and SF (= 4SCEI/L).
3. Enter the values in the following
buckling equation (see Ref, & “for
derivation of the equation),
SF (COPF Atky + SP)(k + SP) = 1,0
4 If the lert side of the equation
ky, te the larger of the txo eprings
©2+27a Constant Section Colurn Having Elastically Restrained Ends
is < 1,0 assume a slightly larger va-
lue for Pop and repeat steps (2)=(u);
if > 1,0 aSsume a smaller value,
5-Repeat steps (2)-(4) until the equation
As satisfied and Por is as assumed.
The value used for £
respond to Er
is in the plastic range,
Bust cor
for Fer when Pop
or to Farr,
To check a column's adequacy under
a given load enter its values of SF and
COF in the equation, Ir the left side 1s
£1,0 tt ts stable; if>1.0 tt is une
gtable. Seo All.3a for SC and COF values.
‘The k/ky curves in the above figure were,
generated using the buckling equation,COLUMNS WITH DISTRIBUTED AXIAL LOADS
Table 2,13 Unifora Colunn with Distributed Load and end Load
antes
cummcat(suexung voaos
=e | ae | om Tem [am
G2
cenmcar Gent) ionns
= | ame] a
ot larity | rowel vot
The above data are used as follows. For a Given Py the orit-
teal value of g 13 found. Or, for a given value of q the criieci
value of P is found. Positive values for the loads Sct as snercs
Regative Values actin the opposite direction. if F >i—
then ger will be negative. If q>aep (for P= 0) then Zp will be
negative.
For 2 given q Pep 1s found as follows.
2+ Compute Py using the equation in Table 1 (20th row)
2. Compute gf/P— observing tne proper sign for s
3; Obtain 2/P» from either Table 1 (interpolating) or Fig. 2
42 compute Por = Pal?/Fe)
For a given P dcr (the auximum allowable value of q) is found as
above, but using P/Pe in step (2), qL/Pg in atep (3) and couputing
Ger = Pe/L x (qL/Pe) in step (4).
Example 1 (For all cases 1=50, El=10)| Example
(UfEI/IE) =80773, P/Pe=.619. Per Fig.2| FoxI9478, aL/Pent.6t, Per Ble.
QE/Fe=1.05. So qormt.05(80773)/50=1696| P/Pe=.34. So Bor=,30(39478 )= 13423,
2 Example &
FESSBQ50;, case 1, nat 4s P's 133000) Case 3, what 49 aor?
eg?
Pent! EL/If =39478, P/Penn.76e ber tadie| 2, 80773, B/Peni.65. Per Table L
ab/Pen}.17. So ger=3.17 (39478)/50=2503| qh/Pax-2:02, Gex==2,02(80773)/5
263