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Fixed Beam Design

This document provides information about the design of a fixed end beam with a span of 5.3 meters that is subjected to a total uniform load of 22.59 kN/m. It includes the beam dimensions, material properties, and calculations for the reactions, bending moments, and required steel reinforcement. The maximum bending moment of 79.31 kN-m occurs at the top of the beam. The design checks show that providing 2 #16 bars at the top and 2 #16 bars at the bottom meets the reinforcement requirements.

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RAVI PRAKASH SAINI
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268 views2 pages

Fixed Beam Design

This document provides information about the design of a fixed end beam with a span of 5.3 meters that is subjected to a total uniform load of 22.59 kN/m. It includes the beam dimensions, material properties, and calculations for the reactions, bending moments, and required steel reinforcement. The maximum bending moment of 79.31 kN-m occurs at the top of the beam. The design checks show that providing 2 #16 bars at the top and 2 #16 bars at the bottom meets the reinforcement requirements.

Uploaded by

RAVI PRAKASH SAINI
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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FIXED END BEAM

Span = 5.3 m
load on beam = 20 KN/m
Width of Beam = 0.23 m
Depth of Beam = 0.45 m
Density of Concrete = 25 KN/m3
Self Wt. of Beam = 2.59 KN/m
TOTAL LOAD ON BEAM = 22.59 KN/m
Fck = 25 N/mm2
Fy = 500 N/mm2
XU max/d = 0.456
Ru = 3.33

22.59KN/m

MA MB
A B

5.3m
ɔc

79.31 (+) A

A B
RA RB

MA MB
(-) A'
A B

(+) 26.44
(-) (-)

Reactions :-
Taking Moment About B
∑MB = 0
RA = 22.59*5.3*5.3/2/5.3 = 59.86 KN ↑
RB = 22.59*5.3-59.86 = 59.86 KN ↑
B.M. :-
MA = MB
A+A' = 0
A= 2/3 xL x WL^2/8 = 280.23 KN-m2
A'= MA x L = -MAx5.3
MA = 52.87 KN-m

Mx = RA x L - MA x Wx X/2 x X/4
X = L/2 = 2.65 m
ML/2 26.44 KN-m

Design of Beam :-

MU (at top) = 79.31 KN-m


d prov. = 407 mm
D prov. = 450 mm
% pt lim. = 0.944 %
XU max = 185.59 mm
MU lim = 126.70 KN-m
Ast (at top) = 502.04 mm^2

MU (at bottom) = 39.66 KN-m


d prov. = 407 mm
D prov. = 450 mm
% pt lim. = 0.944 %
XU max = 185.59 mm
MU lim = 126.70 KN-m
Ast (at bottom) = 235.99 mm^2

Ast provided at top


Thu.
2 # 16 = 402.1 mm2
Ext.
1 # 16 = 201.1 mm2
603.2 mm2
OK

Ast provided at top


Thu.
2 # 16 = 402.1 mm2
Ext.
0 # 16 = 0.0 mm2
402.1 mm2
OK

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