FIITJEE – Phase Test (JEE-Advanced)

BATCHES – NWCM2022X1R, NWCM2022X1W, Y1W,Z1W _PT1 PHYSICS, CHEMISTRY & MATHEMATICS

Pattern - CPT-1 QP Code: PAPER - 2

Time Allotted: 3 Hours Maximum Marks: 183

▪ Please read the instructions carefully. You are allotted 5 minutes specifically for
this purpose.
▪ You are not allowed to leave the Examination Hall before the end of the test.

INSTRUCTIONS
Caution: Question Paper CODE as given above MUST be correctly marked in the answer
OMR sheet before attempting the paper. Wrong CODE or no CODE will give wrong results.

A. General Instructions
1. Attempt ALL the questions. Answers have to be marked on the OMR sheets.
2. This question paper contains Three Sections.
3. Section-I is Physics, Section-II is Chemistry and Section-III is Mathematics.
4. All the section can be filled in PART-A of OMR.
5. Rough spaces are provided for rough work inside the question paper. No additional sheets will be
provided for rough work.
6. Blank Papers, clip boards, log tables, slide rule, calculator, cellular phones, pagers and electronic
devices, in any form, are not allowed.

B. Filling of OMR Sheet

1. Ensure matching of OMR sheet with the Question paper before you start marking your answers on
OMR sheet.
2. On the OMR sheet, darken the appropriate bubble with Blue/Black Ball Point Pen for each
character of your Enrolment No. and write in ink your Name, Test Centre and other details at the
designated places.
3. OMR sheet contains alphabets, numerals & special characters for marking answers.

C. Marking Scheme For Only One Part.

(i) Part-A (01-07) – Contains seven (07) multiple choice questions which have One or More correct answer.
Full Marks: +4 If only the bubble(s) corresponding to all the correct options(s) is (are) darkened.
Partial Marks: +1 For darkening a bubble corresponding to each correct option, provided NO
incorrect option is darkened.
Zero Marks: 0 If none of the bubbles is darkened.
Negative Marks: −1 In all other cases.
For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three
will result in +4 marks; darkening only (A) and (D) will result in +2 marks; and darkening (A) and (B)
will result in −1 marks, as a wrong option is also darkened.
(ii) Part-A (08-14) – Contains seven (07) multiple choice questions which have ONLY ONE CORRECT answer
Each question carries +3 marks for correct answer and -1 marks for wrong answer.

(iii) Part-A (15-18) - This section contains Two paragraphs. Based on each paragraph, there are Two multiple
choice questions. Each question has only one correct answer and carries +3 marks for the correct answer
and -1 marks for wrong answer.

Name of the Candidate :____________________________________________

Batch :____________________ Date of Examination :___________________

Enrolment Number :_______________________________________________

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2

S
SEEC
CTTIIO
ONN--1
1 :: P
PHHY
YSSIIC
CSS
PART – A
(Multi Correct Choice Type)
This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONE OR MORE may be correct.

1. The velocity-time graph for a particle moving on a straight v m/s

line is shown in figure. 10
(A) the particle has constt. acceleration 10 20 30
O t(s)
(B) the particle has never turned around
(C) the particle has zero displacement −10
(D) the average speed in the interval 0 to 10 s is the same −20
as the average speed in the interval 10 s to 20 s.

2. If the kinetic energy of a body is directly proportional to time ‘t’, the magnitude of the
force acting on the body is
(A) directly proportional to t
(B) inversely proportional to t
(C) directly proportional to the speed of the body
(D) inversely proportional to the speed of the body

3. A particle is projected from origin with velocity

u = ( ˆi + ˆj + 2kˆ ) m/s. Horizontal surface lies in X – y ( ˆj )

Y plane, then (take g = 10 m/sec2)

2
(A) Time of flight = sec
5
2
(B) horizontal range = m
5 0 X ˆi( )
1
(C) Maximum height m
10
z ( kˆ )
1
(D) Maximum height = m
5

4. A body of mass 5 kg is suspended by the strings

making angles 60° and 30° with the horizontal as
shown in the figure (g = 10 ms–2). Then T2 T1
(A) T1 = 25 N
(B) T2 = 25 N 60° 30°
(C) T1 = 25 3 N 5 kg

(D) T2 = 25 3 N

5. The force exerted by the floor of an elevator on the foot of a person standing there is
more than the weight of the person if the elevator is
(A) going up and slowing down (B) going up and speeding up
(C) going down and slowing down (D) going down and speeding up.

6. A man is standing on a weighing machine with a block in his hand. The machine records
W. When he takes the blocks upwards with some acceleration the machine records W1.
When he takes the blocks down with some acceleration, the machine records W2. Then
choose incorrect option.
(A) W1 W W2 (B) W1 W W2
(C) W2 W W1 (D) W2 W1 W

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7. A spring connects two particles m1 and m2 horizontal force

F acts on m1 shown in figure. When the elongation of the
spring is x then
kx
(A) a2 = a2
m2 a1

F − kx
(B) a1 =
m1 m2 m1

(C) F = m1a1 + m2a2

F
(D) a1 = a2 = at the maximum elongation of spring
m1 + m2

(Single Correct Choice Type)

This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONLY ONE is correct.

8. A vector of magnitude a is turned through angle . The magnitude of change in the

vector is given by
(A) 2a sin (B) 2a sin (  / 2 )
a a 
(C) sin  (D) sin  
2 2 2

9. ( )
A force F = −k yiˆ + xjˆ where k is a positive constant acts on a particle moving in the xy
plane. Starting from the origin, the particle is taken along the positive x axis to the point
(a, 0) and then parallel to the y axis to the point (a, a). The total work done by the force F
on the particle is
(A) –2Ka2 (B) 2Ka2 (C) –Ka2 (D) Ka2

10. System shown in figure is in equilibrium and at rest. The spring and
string are massless, now the string is cut. The acceleration of mass 2 m
and m just after the string is cut will be 2m

m
(A) g/2 upwards, g downwards

(B) g upwards, g/2 downwards

(C) g upwards, 2g downwards

(D) 2 g upwards, g downwards

11. A particle is thrown from ground level with an initial velocity 4iˆ + 3ˆj . It range on
horizontal ground is (The origin is taken at point of projection, x – axis along the ground
and y – axis perpendicular to the ground) g = 10 m/s2
(A) 1.2 m (B) 2.4 m
(C) 4.8 m (D) 3.6 m

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12. A external agent moves the block m slowly from A to B, B

along a smooth hill such that every time he applies the
force tangentially. Find the work done by agent in this Fagent H
interval.
m2g2H2 mgH2 A
Smooth hill
(A) (B)
L L
(C) mg(H+L) (D) mgH

13. Velocity time equation of a particle moving in a straight line is V t 2 5t 6 . The

distance travelled by the particle in the time interval from t = 0 to t = 4 sec
17 16
(A) 0 (B) (C) 6 (D)
3 3

a(m/s2)
14. A particle starts from rest. Its a-t graph is as shown in the
10
figure. The maximum speed of the particle will be
(A) 110 m/s (B) 55 m/s
(C) 550 m/s (D) 660 m/s
t(s)
O 11

(Paragraph Type)
This section contains 2 paragraphs. Based upon the paragraphs 2 multiple choice questions
have to be answered. Each of these questions has 4 choices (A), (B), (C) and (D) out of which
ONLY ONE is correct.

Paragraph for Question no. 15 to 16

m
In the adjacent figure, x axis has been taken down the O
inclined plane. The coefficient of friction varies with x as
 = kx, where k = tan. A block is released at 0.


15. The maximum velocity of block will be

(A) g (B) gsin
(C) g cos  (D) g tan 

16. Maximum distance travelled by the block

(A) 1m (B) 2m
1
(C) 3m (D) m
2

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Paragraph for Question no. 17 to 18

A block of mass m is kept in an elevator which starts

moving downward with an acceleration a as shown in
figure. The block is observed by two observers A and B
for a time interval t0. B is in rest with respect to ground.

17. The observer B finds that the work done by gravity on the A
block is
1
(A) mg2 t 02
2
 m a


B
1
(B) − mg2 t 02
2
1
(C) mgat 02
2
1
(D) − mgat 02
2

18. The observer B finds that the work done by Pseudo force on the block is
(A) zero (B) −ma2 t0
(C) ma2 t 0 (D) −mgat0

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6

S
SEEC
CTTIIO
ONN--2
2 :: C
CHHE
EMMIIT
TRRY
Y
PART – A
(Multi Correct Choice Type)
This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONE OR MORE may be correct.

1. Which of the following pair of species have same number of unpaired electrons?
(A) Fe and Fe2+ (B) Fe+ and Fe3+
2+ 4+
(C) Fe and Fe (D) Fe and Fe3+
1. ABC

2. Which of the following statement(s) is/are correct for PCl5?

(A) Phosphorus undergoes sp3d hybridization.
(B) Two sets of P−Cl bond length are observed in the molecule
(C) It’s solid contains [PCl4]+ and [PCl6]− ions
(D) The maximum value of ClPCl angle is 120°.
2. ABC

3. According to Aufbau principle, which quantum number(s) is/are used to decide the filling
up of electrons in atomic orbitals?
(A) principal quantum number (B) Azimuthal quantum number
(C) Magnetic quantum number (D) Spin quantum number
3. AB

4. Which of the following expression(s) is/are correct for gases which deviate from ideal
behaviour at extremely high pressure?
(A) PV = Pb + RT (B) a  0
(C) PV > n RT (D) Z > 1
4. ABCD

5. Which of the following statement(s) is/are correct for the following reaction?
(NH4 )2 Cr2O7 ⎯⎯ 
→ Cr2O3 + N2 + 4H2O
(A) It is an intramolecular redox reaction
(B) The n-factor of (NH4)2Cr2O7 is 6
(C) It is a decomposition reaction
(D) ‘N’ atom is oxidized from −3 oxidation state to +3 oxidation state
5. ABC

6. A

B
C

Z
D

In the above figure the first two gases having lower values of ‘a’ are
(A) A (B) B
(C) C (D) D
6. AB

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7. Which of the following is/are disproportionation reaction(s)?

(A) 2H2O2 ⎯⎯ → 2H2O + O2 (B) 2KClO3 ⎯⎯ → 2KCl + 3O2
(C) 2H2S + SO2 ⎯⎯
→ 3S + 2H2O (D) Cl2 + 2NaOH ⎯⎯
→NaCl + NaOCl + H2O
7. AD

(Single Correct Choice Type)

This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONLY ONE is correct.

8. For which of the following orbit of hydrogen atom 2 has maximum value?
(A) n = 1 (B) n = 2
(C) n = 4 (D) n = 5
8. A

9. The non-bonding electrons of a molecule

(A) are considered to find bond order
(B) can be delocalized if suitable situation arises
(C) have energy higher than the antibonding electrons which are formed by combination
of orbitals of same sub-shell
(D) participate in sigma bond formation
9. B

10. The easily liquefiable gases have higher value of (a, b are van der Waal’s constants)
(A) a (B) b
a
(C) (D) a  b
b
10. C

11. In Lothar Meyer atomic volume curve the peak positions are occupied by
(A) inert gases (B) alkali metals
(C) halogens (D) group-14 elements
11. B

12. Li2CO3 undergoes decomposition reaction unlike the carbonates of it’s group elements
because
(A) the lattice energy of Li2CO3 is the lowest than its group elements
(B) Li2+ ions has highest polarizing power than the other monopositive ions of its group
elements
(C) Li+ is more hydrated than the other monopositive ions of its group.
(D) oxidizing nature of CO32− ions
12. B

13. Which of the following oxide is most soluble in water?

(A) BaO (B) CaO
(C) MgO (D) BeO
13. A

14. Which of the following contains one mole atoms?

(A) 17 g of NH3 (B) 14 g of CO
(C) 64 g of SO2 (D) 4.4 g of CO2
14. B

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(Paragraph Type)
This section contains 2 paragraphs. Based upon the paragraphs 2 multiple choice questions
have to be answered. Each of these questions has 4 choices (A), (B), (C) and (D) out of which
ONLY ONE is correct.

Paragraph for Question no. 15 to 16

A 15 g mixture of NaCl and CaO was dissolved in 2.5 L of 0.2 M HCl solution. After complete
reaction, the reaction mixture consumed 200 mL of 0.5 M NaOH solution for neutralization of the
excess acid(HCl).
CaO + 2HCl ⎯⎯ → CaCl2 + H2O
NaOH + HCl ⎯⎯ → NaCl + H2O
Answer the following questions on the basis of above write up.

15. How much NaCl is present in the mixture?

(A) 3.8 g (B) 0.6 mole
(C) 0.4 equivalent (D) None
15. A

16. What is the percentage purity of the mixture?

(A) 30.88 (B) 25.34
(C) 69.12 (D) 74.66

16. D

Paragraph for Question no. 17 to 18

2( ) 2( )
Ca ( s ) ⎯⎯⎯⎯⎯ → P ( s ) ⎯⎯⎯ → Q ( sol ) + R ( g)
N g +O g
⎯ H2O

Mixture

U ( sol) + T ( sol ) ⎯⎯⎯⎯ Cl2 /Cold

S ( sol) ⎯⎯⎯
Na2CO3
⎯
V ( sol ) + T ( sol ) ⎯⎯⎯
Cl2 /Hot
⎯ PPt.

Answer the following question.

17. The mixture(P) contains

(A) Ca(NO3)2 and CaO (B) Ca3N2 and CaO
(C) Ca(NO2)2 and Ca(NO3)2 (D) CaO and Ca(NH2)2

17. B

18. Compound(U) can undergo disproportionation reaction to produce(V) and an unknown

compound. The unknown compound is
(A) S (B) T
(C) Q (D) P

18. B

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S
SEEC
CTTIIO
ONN--3
3 :: M
MAAT
THHE
EMMA
ATTIIC
CSS
PART – A
(Multi Correct Choice Type)
This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONE OR MORE may be correct.
1. If log12 27 = a then log6 16
3−a 3+a
(A) 4   (B) 2  
3+a 3−a
4ln2
(C) 4log6 2 (D)
ln2 + ln3

1. ACD

3 5
2. If cos  = and cos  = then
5 13
33 56
(A) cos (  + ) = (B) sin (  +  ) =
65 65
  −   1 63
(C) sin2  = (D) cos (  −  ) =
 2  65 65

2. BCD

3. If the lines joining the origin to the points of intersection of the line 3y = mx + 3 and the
curve x2 + y2 = 1 are at right angle then value of m + 3 is
(A) 5 (B) 6
(C) 1 (D) Zero

3. BD

4. Which of the following is/are CORRECT?

xn+1
 x dx = + c  n R  sec x dx = − ln sec x − tanx + c
n
(A) (B)
n +1

(( ))
x
(C)
dx
 1+ ex = − ln c e + 1
−x
(D)
d
dx
( x)= , x0
x
4. BCD

5. Which of the following is INCORRECT ?

d  1+ x + x  2 4
(A) If   = ax + b , then a + b = 3
dx  1 + x + x 2 
dy
(B) If y = etan x , then =0
dx x =0
x −1
(C) lim =0
x →1 2x − 7x + 5
2

x +h − x 1
(D) lim =
h→0 h x
5. ABCD

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6. A vertex of an equilateral triangle is ( 2, 3 ) and the equation of its opposite side

is x + y = 2 . The equations of the remaining sides are

(
(A) ( y − 3 ) = 2 + 3 ) ( x − 2) ( )
(B) ( y − 3 ) = 2 3 + 1 ( x − 2 )

(C) ( y − 3 ) = ( 2 3 − 1) ( x − 2 ) (D) ( y − 3 ) = ( 2 − 3 ) ( x − 2 )
6. AD

( )
n
1
7. Let fn (  ) =  n
sin4 2n  . Then which of the following alternative(s) is/are correct?
n=0 4
  1  2+ 2
(A) f2   = (B) f3   =
4 2 8 4
 3 
(C) f4   = 1 (D) f5 (  ) = 0
 2 
7. CD

(Single Correct Choice Type)

This section contains 7 multiple choice questions. Each question has four choices (A), (B), (C)
and (D) out of which ONLY ONE is correct.

sin4 A cos4 A 1 sin8 A cos8 A

8. If + = , then + is equal to
a b a+b a3 b3
1 1
(A) (B)
(a + b) (a − b)
3 3

1 1
(C) (D)
(a + b) (a − b)
2 2

8. A

9. The number log20 3 lies in the interval

1 1  1 1
(A)  , (B)  , 
4 3  3 2
1 3 3 4
(C)  , (D)  , 
2 4  4 5
9. B

10. The maximum value of sin ( cos x ) is equal to

(A) sin1 (B) 1
 1   3
(C) sin   (D) sin  

 2  2 
10. A

11. The equation of the circle passing through the points (2, 0) and (0, 4) and having the
minimum possible radius is
(A) x2 + y2 + x + y = 3 (B) x2 + y2 − 2x − 4y = 0
(C) x2 + y2 − 7x − y + 8 = 0 (D) none of these
11. B

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12. If x2 + y2 + (  +  − 4) xy − x − y − 20 = 0 represents a circle, then the radius of the

circle is
21 42
(A) (B)
2 2
(C) 2 21 (D) 22

12. B

sin x + cos x
13. If = a tan3 x + b tan2 x + c tan x + d , then a + b + c + d =
cos3 x
(A) 0 (B) 2
(C) 4 (D) –2

13. C

sin  sin3 + sin3 sin7 + sin5 sin15

14. =
sin  cos3 + sin3 cos7 + sin5 cos15
(A) sin11 (B) cos11
(C) tan11 (D) cot11

14. C

(Paragraph Type)
This section contains 2 paragraphs. Based upon the paragraphs 2 multiple choice questions
have to be answered. Each of these questions has 4 choices (A), (B), (C) and (D) out of which
ONLY ONE is correct.

Paragraph for Question no. 15 to 16

 2 2
A (1, 3 ) and C  − , −  are the vertices of a ΔABC and the equation of the angle
 5 5
bisector of ABC is x + y = 2 .

15. The coordinates of vertex B are

 3 7   17 3 
(A)  ,  (B)  , 
 10 10   10 10 
 5 9
(C)  − ,  (D) (1, 1)
 2 2

15. C

16. The equation of side AB is

(A) 3x + 7y = 24 (B) 3x + 7y + 24 = 0
(C) 13x + 7y + 8 = 0 (D) 13x − 7y + 8 = 0

16. A

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Paragraph for Question no. 17 to 18

If sin  − sin  = a and cos  + cos  = b , then

17. cos (  + ) =
a2 − b2 2ab
(A) (B)
a2 + b2 a + b2
2

a2 + b2 − 2
(C) (D) none of these
2

17. C

18. tan (  − ) =
2ab 2ab
(A) (B)
a2 − b2 a2 + b2
2ab
(C) 2 (D) depends on the values of a and b
b − a2
18. D

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ANSWERS
S
SEEC
CTTIIO
ONN--1
1 :: P
PHHY
YSSIIC
CSS
PART – A

1. AD 2. BD 3. ABC 4. AD
5. BC 6. ABD 7. ABCD 8. B
9. C 10. A 11. B 12. D
13. B 14. B 15. B 16. B
17. C 18. A

S
SEEC
CTTIIO
ONN –– 2
2 :: C
CHHE
EMMIIS
STTR
RYY
PART – A

S
SEEC
CTTIIO
ONN –– 3
3 :: M
MAAT
THHE
EMMA
ATTIIC
CSS
PART – A

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