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Material Safety Data Sheet of Chemicals: Lab Report

1. The experiment prepared sodium sulfate (Na2SO4) from magnesium sulfate heptahydrate (MgSO4.7H2O) and sodium carbonate (Na2CO3) through a double displacement reaction. 2. 5g of MgSO4.7H2O reacted with 2.15g of Na2CO3 to produce 2.84g of Na2SO4 theoretically based on the balanced chemical equation. 3. Actual yield of Na2SO4 obtained was 2.81g, yielding a 98% experimental yield.

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75 views2 pages

Material Safety Data Sheet of Chemicals: Lab Report

1. The experiment prepared sodium sulfate (Na2SO4) from magnesium sulfate heptahydrate (MgSO4.7H2O) and sodium carbonate (Na2CO3) through a double displacement reaction. 2. 5g of MgSO4.7H2O reacted with 2.15g of Na2CO3 to produce 2.84g of Na2SO4 theoretically based on the balanced chemical equation. 3. Actual yield of Na2SO4 obtained was 2.81g, yielding a 98% experimental yield.

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mjunaid
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Lab Report
Experiment No. # 1 21-02-2018
Objective/Name of Experiment: Preparation of Sodium Sulphate.
Theory:
Principle: It is based on solubility.

Apparatus: R.B Flask, Beakers, Funnel, Stand, Filter Paper, Glass Rod, Cylinder, China Dish, Burner.
Chemicals Required (along with Corrective and Preventive Action): Na2CO3, MgSO4.7H2O.
MgSO4.7H2O + Na2CO3 Na2SO4 + MgCO3 + 7H2O

Material Safety Data Sheet of Chemicals


Sodium carbonate is only slightly toxic. Excessive contact may cause
Na2CO3 irritation with blistering and redness
May cause eye, skin, and respiratory tract irritation. The toxicological
MgSO4.7H2O
properties of this material have not been fully investigated.
MgCO3 May cause eye, skin, and respiratory tract irritation.
May cause eye, skin, and respiratory tract irritation. Hygroscopic (absorbs
Na2SO4 moisture from the air).
Procedure:
 Take 5g of MgSO4.7H2O with the help of weight balance.
 Calculate the number of moles of MgSO4.7H2O for 5g. It comes 0.020 moles (obtained by dividing given
mass of MgSO4.7H2O with molecular mass of MgSO4.7H2O).
 Multiply this number of moles with 106(molecular mass of Na2CO3) to get mass required of Na2CO3 to react
with MgSO4.7H2Oto produce .020 moles of Na2SO4. It obtained 2.15g.
 After it make solution of Na2CO3 and MgSO4.7H2O in 50mL flask. For this purpose, take required mass of
both reactants in 50mL flask and fill flask with distilled water.
 Make these freshly prepared solutions.
 After mixing, filter this solution to separate MgCO3 from solution.
 Heat this filtered solution with the help of any source available.
 After heating some time water molecules converted into vapours and evaporated
 Crystals of Na2SO4 remains behind.
 Weigh these crystals with help of weight balance.
 Actual yields obtained.
 Theoretical yields can be calculated from balance equation.

Observation Table
No observation table required.
Calculation:
Molecular weight of MgSO4.7H2O=246g/mol
Molecular weight of Na2CO3 =106g/mol
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Lab Report
1 mol of Na2CO3 = 1 mol of MgSO4.7H2O
246g = 106g
5g of MgSO4.7H2O=2.15g of Na2CO3
MgSO4.7H2O + Na2CO3 Na2SO4 + MgCO3 + 7H2O
As we know that
1 mol of Na2SO4= 1 mol of MgSO4.7H2O
Mole of MgSO4.7H2O=5/246=0.02moles
Mass of Na2SO4=0.02*142=2.84g(theoretical)
% of yield= (actual yield in g/theoretical yield in g) *100
% of yield= (2.81/2.84) *100=98%

Conclusion: .

Result: Hence sodium sulphate is prepared 2.81 g.

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