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Bearing Capacity

The ultimate bearing capacity of a pile is the maximum load it can carry without failure or excessive settlement. A pile transfers load through end-bearing at its tip and skin friction along its surface. The ultimate bearing load is the sum of the end-bearing resistance and skin friction resistance, with end-bearing resistance calculated based on bearing area and capacity and skin friction based on surface area and unit friction.

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67 views1 page

Bearing Capacity

The ultimate bearing capacity of a pile is the maximum load it can carry without failure or excessive settlement. A pile transfers load through end-bearing at its tip and skin friction along its surface. The ultimate bearing load is the sum of the end-bearing resistance and skin friction resistance, with end-bearing resistance calculated based on bearing area and capacity and skin friction based on surface area and unit friction.

Uploaded by

maaahii
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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The ultimate bearing capacity of a pile is the maximum load which it can carry without

failure or excessive settlement of the ground.


The pile transfers the load into the soil in two ways. Firstly, through the tip-in
compression, termed ‘end-bearing’ or ‘point-bearing’; and, secondly, by shear along the
surface, termed ‘skin friction’.
The ultimate bearing load of a pile is considered to be the sum of the end-bearing
resistance and the resistance due to skin friction:
Qup  Qeb  Qsf

Qup = ultimate bearing load of the pile


Qeb = end-bearing resistance of the pile,
Qsf = skin-friction resistance of the pile
Qeb = qbAb
Qsf = fsAs
Here qb = bearing capacity in point-bearing for the pile
Ab = bearing area of the base of the pile, and
fs = unit skin friction for the pile-soil system,
As = surface area of the pile in contact with the soil
1
qb  cN c  qN q   bN 
2
For piles in sands: c =0
1
qb  qN q   bN
2
For piles in clays Φ = 0
qb  cN c  q

The general form for the unit skin friction resistance is


f s  ca   h tan 
For piles in sands: c = 0
f s   h tan 
For piles in clays: f s  ca

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