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Design A Simple Surge Tank For One Unit For The Following Data Given

The document provides specifications for designing a simple surge tank for a hydroelectric project including discharge rate, tunnel length and diameter, penstock length and diameter, and head losses. Based on the given data, the solution involves calculating the required area, diameter, and maximum upsurge and downsurge levels for the surge tank.

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Vignesh Tamilan
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216 views6 pages

Design A Simple Surge Tank For One Unit For The Following Data Given

The document provides specifications for designing a simple surge tank for a hydroelectric project including discharge rate, tunnel length and diameter, penstock length and diameter, and head losses. Based on the given data, the solution involves calculating the required area, diameter, and maximum upsurge and downsurge levels for the surge tank.

Uploaded by

Vignesh Tamilan
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as XLSX, PDF, TXT or read online on Scribd
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Design a simple surge tank for one unit for the following data

Given
Upstream MSL = 500 m
Downstream MSL = 200 m
Discharge in 48Hrs = 15000000 m3
Low pressure tunnel
Length, Lt = 4000 m
Diameter, dt = 8m
Friction factor,λ = 0.028
High pressure penstock(4nos.)
Length, Lp = 500 m
Diameter, dp = 2m
Friction factor,λ = 0.016

SOLUTION:
Discharge, Q = 86.80555556 m3s-1
Discharge in 1unit, Q0 = 21.70138889 m3s-1
Area of tunnel, At = 50.24 m2
Area of penstock, Ap = 3.14 m2
Velocity in tunnel, V0 = 1.727817587 ms-1
velocity in penstock, Vp = 6.911270347 ms-1
Head loss in tunnel, P0 = 2.130221742 m
Head loss in penstock, hfp = 9.738156535 m
Net head, H0 = 288.1316217 m
Area of surge tank, As
>V02AtLt/2gP0H0 > 49.8185018 m2
Applying FOS=2 = 99.63700359 m2

Diameter of surge tank


ds = 7.966370542 m
= 8m

Maximum upsurge
r=(gAt/LtAs)1/2 = 0.049731779
Z0=Q0Asr = 8.759168377 m
= 8.8 m
K*0=P0/Zmax = 0.243199086
For sudden load rejection
Z*max=1-2K*0/3+K2*0/9 = 0.844439031
Maximum upsurge, Zmax
=Z*max*Z0 = 7.396583657 m
= 7.4 m

Maximum downsurge
Z*min=-1/(1+7K*0/3) = -0.63797297
Zmin = -5.58811264 m
= -5.6 m
For sudden load demand
Z*min=-1-0.125K*0 = -1.03039989 m
Maximum downsurge, Zmin
Zmin = -9.02544609 m
= -9.1 m
he following data
100-0

0-100-0

0-100
100-0-100

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