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A11 Cabantog 2019151106

This document contains a student's answers to problems involving analyzing signals from an oscilloscope image. The student provides calculations to determine a signal's peak-to-peak value, RMS value, frequency, and period based on the oscilloscope settings. The student also draws and labels the front panels of a Tektronix oscilloscope, Fluke multimeter, and function generator to identify their main components and uses.

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MALAKIPWETKO
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48 views4 pages

A11 Cabantog 2019151106

This document contains a student's answers to problems involving analyzing signals from an oscilloscope image. The student provides calculations to determine a signal's peak-to-peak value, RMS value, frequency, and period based on the oscilloscope settings. The student also draws and labels the front panels of a Tektronix oscilloscope, Fluke multimeter, and function generator to identify their main components and uses.

Uploaded by

MALAKIPWETKO
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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CABANTOG, Gerard John T.

ECE20L-2 / A1
2019151106
Activity 1.1

Answer the following questions:

Given the figure above, solve the problems below.

1. If the volts per division setting is 5 V/div, determine the signal’s peak to
peak value. Vpk-pk = 12.5V

2. If the volts per division setting is 5 V/div, determine the signal’s rms value.
Vrms = 4.4V

3. If the time per division setting is 5ms / div, determine the signal’s frequency.
Frequency = 80Hz

4. If the time per division setting is 5ms / div, determine the signal’s period.
Period (T) = 0.0125s
CABANTOG, Gerard John T.
ECE20L-2 / A1
2019151106
Activity 1.1

A. Given the problems above (problems 1 to 4), explain and show your
computation for each and every problem.

1. Based on the figure above, the wave is 2.5.

(2.5)(5.0) = 12.5𝑉
-
2. By using the formula: 𝑉𝑟𝑚𝑠 = 𝑉𝑝𝑘 − 𝑝𝑘
. .

-
𝑉𝑟𝑚𝑠 = 12.5𝑉 = 4.4V
. .

3. The size of the wave is 2.5 wide.

(2.5)(5) = 12.5𝑚𝑠

12.5
= 0.0125𝑠
1000
1
𝑓=
𝑝𝑒𝑟𝑖𝑜𝑑

1
= 80𝐻𝑧
0.0125
4.

Using the formula in no.3 and converting it to get the desired result.

1
𝑓=
𝑝𝑒𝑟𝑖𝑜𝑑
- -
𝑝𝑒𝑟𝑖𝑜𝑑 = = = 0.0125𝑠
: ;<
CABANTOG, Gerard John T.
ECE20L-2 / A1
2019151106
Activity 1.1

B. Given a Tektronix TDS 210 model, draw the façade and enumerate the parts
and discuss its uses.

• Display - This shows the calculated and measured waves and graphs.
• Horizontal Controls - It pushes/move the horizontal waveforms.
• Vertical Controls - It pushes/move the vertical waveforms.
• Channel Keys - It controls channels.
• Trigger Controls - This defines the waveform type and can be
changed manually to create a reliable display of the input signal.

C. Given the Fluke model in the video link above, draw the façade and
enumerate the parts and discuss its uses.

• Display - It shows calculated values


• Knob - Gives the user the ability to select in various units, such as
milliamps, etc.
• Buttons - This is to change from the various operations.
• Jacks - It is where test leads are inputted or inserted.
CABANTOG, Gerard John T.
ECE20L-2 / A1
2019151106
Activity 1.1

D. Given the function generator above, draw the façade and enumerate the parts
and discuss its uses.

• Display - Shows the frequency level.


• Power Button - It allows user to turn On/Off the power supply to the
device.
• Main Output - The source output of the piece.
• Main Knob - It changes the level of frequency.
• TTL Output - Shows the square wave by the help of the display.
• Wave Keys - It adjust the settings to convert into waves.
• Frequency Keys - It manipulates the frequency levels.

Proof that I have watched the videos:

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