Henry Dave D.
Demorito
Problem Set 1
14-6
Determine the electric field intensity for the same point in problem 14.1.
P rad 1000 W
P= P= 2
P=0.2 µ 2 E= √30 Prad E= √30 ( 1000 ) E=8.66 mV
4π R 2
4 π ( 20 km ) m R 20000 m
14-8
For a radiated power Prad = 10kW, determine the voltage intensity of a distance 20 km from the
source.
√30 Prad E= √30 ( 10000 ) E=27.39 mV H= 1 1 AT
E= H= H=7.96
R 20000 m 2 πd 2 π ( 20000 ) m
14-10
If the distance from the source is reduced to one-half its value, what effect does this have on the
power density?
Prad Prad
P rad P= P=
R 2 Therefore, power density increases by a factor of 4.
2
P= R
4π R 2
4 π
2 ( )
4π
4 ( )
14-12
For a dielectric ratio √ € r 2/ € r 1 = 0.8 and an angle of incidence θi =260, determine the angle of
refraction, θr.
sin θ i € r 2 sin 26 =0.8
sin θr
=
√
€ r 1 sinθ r
θr =33.23 ᵒ
14-14
Determine the distance to the radio horizon for an antenna that is 40 ft above the top of a 4000-ft
mountain peak.
h=h1 +h2h=40+ 4000h=4040 ft d= √ 2 hd= √2 ( 4040 )d=89.89 mi
14-16
Determine the power density for a radiated power of 1200 W at distance of 50 km from and
isotropic antenna.
P rad 1200 W
P= 2
P= 2
P=0.038 µ 2
4π R 4 π ( 50 km ) m
14-18
Describe the effects on power density if the distance from a transmit antenna is reduced by a factor
of 3.
Decrease by a factor of 9.
14-20
Determine the maximum usable frequency for a critical frequency of 20 MHz and angle incidence of
350.
fc 20 MHz
MUF= MUF= MUF=24.42 MHz
cos θi cos 35
14-22
Determine the voltage intensity for the same point in problem 14-17.
E=
√30 Prad E= √30 ( 1200 ) E=1.9 mV
R 100000 m
Increase by a factor of 64.
14-24
Determine the change in power density when the distance from the source increase by a factor of 8.
P rad Prad Prad
P= 2 P= 64 P=
4 π (8 R) 4 π (64)( R¿¿ 2)¿ 4 π R2
Increase by a factor of 64
. Determine the characteristic impedance
for an air-filled concentric transmission
line with D/d ratio of 4.
Solution:
Zo = 138/ (√E
r
) log D/d
= 138/ √2.23 log 4