2B.
7 Annular flow with inner cylinder moving axially
        o. The momentum balance is the same as that in Eph. 2.3-11
or Eq. 2.4-2, but with the pressure-difference term omitted. We can
substitute Newton's law of viscosity into this equation to get
                    whence
        dr     r                   _ _ c, „,                or — = —Do            + D2
                                                                 ’0
               oz                              . + C2
That is, we select new integration constants, so that they are
dimensionless. These integration constants are determined from the
no-slip conditions at the cylindrical surfaces: t›, (cR) = t›0 £tnd
r, (R) = 0. The constants of integration are D2 = 0 and D1 = —1/ln c.
This leads then directly to the result given in the book.
         â. The mass rate of flow is
                                             oR2
                    rdrd8 —— 2ap
—                                { 2 )|t =                  2c
                                                                  2
                                                                      ln c —4 (1—r 2 ))
                             4
2:r:p
                    2ap
which is equivalent to the answer in the text.
        c. The force on a length L of the rod
        L 2*                                                (/&A)
        0 0                                             0
                                                             In›r
which gives the expression in the book.
       d. When we replacer by l— e and expand in a Taylor series,
we get
                             +2    1               _ 2 nLy)v0
                                                                       (i— 21
                     —(• 2          3*3 + 4
To get this last result one has to do a long division involving the
polynomial in the next-to-last step.
2B.8 Analysis of a capillary flowmeter
        Designate the water by fluid "I" and the carbon
tetrachloride Dy ii". Later the distance irom B to C as "J". One mass
rate or ñow in the tube section "AB" ñ given by
           8yL                     8y£
Since the fluid in the manometer is not moving, the pressures at D
and E must be equal; hence
from which we get
EA   GB + PI8 h —— (PII   PI) gH
Insertion of this into the first equation above gives the expression
for the mass rate of flow in terms of the difference in the densities
of the two fluids, the acceleration of gravity, and the height H.
2B.9 Low-density phenomena in compressible tube flow
        When we replace no-slip boundary condition of Eq. 2.3-17
by ñq. 2ñ.9-i, we get
“          4yL               2yfi
so that the velocity distribution in the tube is
                                2
                            T       (/0 "PL)•r
                                          2pL
                                          2
w —— *        p(z)n (r, z)rdrd8 —— 2 z1
          o                                   RET
where we have introduced the ideal gas law, with g being the gas
constant (we use a subscript g here to distinguish the gas constant
from the tube radius). We have also introduced a dimensionless
radial coordinate. When we introduce the velocity distribution
above, we get
•   2 2zE
      fo 1...
          4
     4p  (,,Tj‹,\—°
                 ../\ —*
This is now integrated over the length of the tube, keeping mind that
the mass flow rate in is constant over the entire length
                                    4(o
              dp
                                                                        2— 14
                        2
             R4   M         — p2 + 4 \}
                       #0            0
                                          (P0 " /L)
This gives
             8L       RT        2          R
which leads then to Eq. 2B.9-2.