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Kunci Jawaban

1. The document contains math problems and their solutions. It includes calculations related to positive and negative numbers, fractions, percentages, areas of shapes, distances, costs, and sharing amounts. 2. Example problems include calculating amounts owed after deducting payments, dividing candy among siblings, finding distances traveled around pools, and determining costs for fencing circular areas. 3. Solutions are provided for each problem, such as calculating deficits, remainders after sharing, distances using circumferences, and total areas by combining circular and rectangular sections.

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24 views3 pages

Kunci Jawaban

1. The document contains math problems and their solutions. It includes calculations related to positive and negative numbers, fractions, percentages, areas of shapes, distances, costs, and sharing amounts. 2. Example problems include calculating amounts owed after deducting payments, dividing candy among siblings, finding distances traveled around pools, and determining costs for fencing circular areas. 3. Solutions are provided for each problem, such as calculating deficits, remainders after sharing, distances using circumferences, and total areas by combining circular and rectangular sections.

Uploaded by

blueocean999
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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Kunci jawaban

1 C 6 B
0852 7 3
5 216 32 11
C
1
6
C

2 B 7 A 12 B 17 D
3 D 8 C 13 D 18 B
4 A 9 B 14 B 19 C
5 A 10 A 15 B 20 A

II. 1.Positif
2. -12 x -14 + (-150) = 168 – 150 = 18
3. 729 : (-9) - 15 × (-8) = -81 +120 = 39
4. 1736 : 28 – 14 = 62 - 14 = 48

5. + - = = =

6. = = = = =

7. AB = × keliling lingkaran

= . . 56
= 44 cm

8. Keliling = . . 70
= 55 cm

Keliling keseluruhan = 55 + 35 + 35 = 125 cm

9.Luas lingkaran = 3,14 × 25 × 25= 1962,5 cm²

10. Luas lingkaran = 3,14 × 10 × 10 = 314 cm²

Luas persegi panjang = 20 × 12 = 240 cm²


Luas keseluruhan = 314 +240 = 554 cm²
1. Kewajiban yang harus dibayar = hutang + bayar buku
= 20.500 + 43.500
= 64.000

Kekurangan uang = 64.000 – 58.000

= 6000

Jadi kekurangan uang fadil Rp 6.000

2. Permen bagian Abu = = 8 permen


Permen dibagikan ke adiknya =
24 – 8 = 16 permen Permen

yang diambil adik = = 12


permen Sisa permen 16 – 12 = 4
permen
Jadi sisa permen Abu = 8 + 4 = 12 permen
3. Keliling kolam =
3,14× 20= 62,8m

Jarak yang ditempuh =


62,8 × 12= 753,6 m

4. Keliling lingkaran = ×
42 = 132

m Biaya = ×
40.000 = 2.640.000
Jadi biaya yang harus dikeluarkan oleh Pak Amin yaitu Rp 2.640.000

5. Keliling lingkaran = . . 42 = 99 m
Keliling keseluruhan = 99 + 21 +21 = 141
cm
Luas lingkaran = . . 21 . 21 = 1.039,5 cm²

Luas persegi = 21 × 21 = 441 cm²


Luas keseluruhan = 1.039,5 + 441 = 1480,5 cm²

Luas lingkaran = 3,14 × 25 × 25 = 1962,5 cm²


10. Luas lingkaran = 3,14 × 10 × 10 = 314 cm²

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