CMC Unit 1 PPT 20181 PDF
CMC Unit 1 PPT 20181 PDF
COMMUNICATIONS
by
VIDYA SAGAR POTHARAJU
Associate Professor,
Dept of ECE,
VBIT.
The large number of subscribers created a high blocking probability during busy hours.
Although service performance was undesirable, the demand was still great.
It is likely that half the initiating calls will be blocked in the MJ system, a very high
blocking probability.
a mobile unit, a cell site, and a mobile telephone switching office (MTSO)
Mobile units: A mobile telephone unit contains a control unit, a transceiver, and an antenna system.
Cell site: The cell site provides interface between the MTSO and the mobile units. It has a control
unit, radio cabinets, antennas, a power plant, and data terminals.
MTSO: The switching office, the central coordinating element for all cell sites, contains the cellular
processor and cellular switch. It interfaces with telephone company zone offices, controls call processing,
and handles billing activities.
Connections: The radio and high‐speed data links connect the three subsystems. Each mobile unit
can only use one channel at a time for its communication link.
The MTSO is the heart of the cellular mobile system. Its processor provides central coordination and
cellular administration.
R everse C hannel
1 Mbps 3G
(144Kbps to 2Mbps)
100 Kbps
2.5G
(10-150Kbps)
10 Kbps
2G
(9.6Kbps)
1 Kbps
1G
(<1Kbps)
Years
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Cellular networks: From 1G to 5G
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Problems Unique to Wireless systems
• Interference from other service providers
• Interference from other users (same network)
• CCI due to frequency reuse
• ACI due to Tx/Rx design limitations & large number of users sharing finite BW
• Shadowing : Obstructions to line-of-sight paths cause areas of weak received signal strength
• Fading :
• When no clear line-of-sight path exists, signals are received that are reflections off
obstructions and diffractions around obstructions
• Multipath signals can be received that interfere with each other
• Fixed Wireless Channel → random & unpredictable
• must be characterized in a statistical fashion
• field measurements often needed to characterize radio channel performance
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Mechanisms that affect the radio propagation ..
• Reflection
• Diffraction
• Scattering
• In urban areas, there is no direct line-of-sight path between:
• the transmitter and the receiver, and where the presence of high- rise buildings causes
severe diffraction loss.
• Multiple reflections cause multi-path fading
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Reflection, Diffraction, Scattering
• Reflections arise when the plane waves are incident upon a surface with dimensions
that are very large compared to the wavelength
• Reflection - occurs when signal encounters a surface that is large relative to the
wavelength of the signal
• Diffraction occurs according to Huygens's principle when there is an obstruction
between the transmitter and receiver antennas, and secondary waves are generated
behind the obstructing body
• Diffraction - occurs at the edge of an impenetrable body that is large compared to
wavelength of radio wave. (Waves bending around sharp edges of objects)
• Scattering occurs when the plane waves are incident upon an object whose dimensions
are on the order of a wavelength or less, and causes the energy to be redirected in
many directions.
• Scattering – occurs when incoming signal hits an object whose size is in the order of
the wavelength of the signal or less
• location 1, free space loss (Line of Sight) is likely to give an accurate estimate of path
loss.
• location 2, a strong line-of-sight is present, but ground reflections can significantly
influence path loss. The plane earth loss (2-Ray Model) model appears appropriate.
• location 3, plane earth loss needs to be corrected for significant diffraction losses, caused
by trees cutting into the direct line of sight.
• location 4, a simple diffraction model is likely to give an accurate estimate of path loss.
• location 5, loss prediction fairly difficult and unreliable since multiple diffraction is
involved
•
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Radio Propagation Mechanisms
• Path Loss
• Signal attenuation as a positive quantity measured in dB and defined as the difference (in dB)
between the effective transmitter power and received power.
• Friis is an application of the standard “Free Space Propagation Model “
• It gives the Median Path Loss in dB ( exclusive of Antenna Gains and other losses )
• clear, unobstructed line-of-sight path → satellite and fixed microwave
• Friis Transmission Equation (Far field)
• The Friis free space model is only a valid predictor for “Pr ” for values of “d” which are in the far-field of the
“Transmitting antenna
38
Speed Of The Mobile
The relative motion between the base station and the mobile results in random
frequency modulation.
Different Doppler shifts on each of the multipath components.
Doppler shift will be positive- moving toward BS.
Doppler shift will be negative-away from the BS.
The phase change in the received signal due to the difference in path and results in
change in frequency.
Doppler shift positive-increase in frequency.
Doppler shift negative-decrease in frequency.
39
Speed Of Surrounding Objects
If objects in the radio channel are in motion, they induce a time varying Doppler shift
on multipath components.
If the surrounding objects move at a greater rate than the mobile, then this effect
dominates the small-scale fading.
Otherwise, motion of surrounding objects may be ignored, and only the speed of the
mobile need be considered.
40
The Transmission Bandwidth Of The Signal
If the transmitted radio signal bandwidth is greater than the "bandwidth" of the
multipath channel, the received signal will be distorted, but the received signal strength
will not fade much over a local area.
The bandwidth of the channel can be quantified by the coherence bandwidth which is
related to the specific multipath structure of the channel.
The coherence bandwidth is a measure of the maximum frequency difference for
which signals are still strongly correlated in amplitude.
If the transmitted signal has a narrow bandwidth as compared to the channel, the
amplitude of the signal will change rapidly, but the signal will not be distorted in time.
41
Parameters Of Mobile Multipath Fading
Many multipath channel parameters are derived from the power delay profile.
Power delay profiles are generally represented as plots of relative received power as a
function of excess delay with respect to a fixed time delay reference.
Power delay profiles are found by averaging instantaneous power delay profile
measurements over a local area in order to determine an average small-scale power
delay profile.
42
Time Dispersion Parameters
Multipath channel parameters can be given as
Mean excess delay
RMS delay spread
Excess delay spread
These parameters can be determined from power delay profile.
The time dispersive properties of multipath channels are most commonly
quantified by their mean excess delay and rms delay spread .
43
Mean excess delay
where
44
Depends only on the relative amplitude of the multipath components.
Typical RMS delay spreads
Outdoor: on the order of microseconds
Indoor: on the order of nanoseconds
Maximum excess delay (X dB) is defined to be the time delay during which
multipath energy falls to X dB below the maximum.
excess delay =
45
46
Coherent Bandwidth(Bc)
Coherent band width ,Bc , is a statistic measure of the range of frequencies over
which the channel can be considered to be “flat”.
A channel which passes all spectral components with approximately equal gain and
linear phase.
Two sinusoids with frequency separation greater than Bc are affected quite
differently by the channel.
47
If the coherent bandwidth is defined as the bandwidth over which the frequency
correlation function is above 0.9, then the coherent bandwidth is approximately.
48
Doppler Spread and Coherence Time
Doppler spread and coherent time are parameters which describe the time varying
nature of the channel in a small-scale region.
When a pure sinusoidal tone of fc is transmitted, the received signal spectrum, called
the Doppler spectrum, will have components in the range fc-fd and fc+fd, where fd is
the Doppler shift.
49
• Coherent time Tc is the time domain dual of Doppler spread.
• Coherent time is used to characterize the time varying nature of the frequency
dispersiveness of the channel in the time domain.
50
Two signals arriving with a time separation greater than Tc are affected differently
by the channel.
A statistic measure of the time duration over which the channel impulse response is
essentially invariant.
If the coherent time is defined as the time over which the time correlation function
is above 0.5, then
51
Doppler Shift Calculation
2l 2 d cos( )
Phase difference,
1 v
Doppler Shift, f d cos( )
2 t
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Frequency Carries/Channels
The information from sender to receiver is carried over a well defined frequency band.
This is called a channel.
Each channel has a fixed frequency bandwidth (in KHz) and Capacity (bit-rate)
Different frequency bands (channels) can be used to transmit information in parallel and
independently.
Replacing a single, high power transmitter (large cell) with many low power transmitters
(small cells).
Each providing coverage to only a small portion of the service area.
Each base station is allocated a portion of the total number of channels available to the entire
system,
Nearby base stations are assigned different groups of channels.
All the available channels are assigned to a relatively small number of neighboring base
stations.
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Example
Channel 1 (b - b+30)
Station A Channel 2 (b+30 - b+60) Station B
Channel 3 (b+60 - b+90)
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Frequencies for communication
1 Mm 10 km 100 m 1m 10 mm 100 m 1 m
300 Hz 30 kHz 3 MHz 300 MHz 30 GHz 3 THz 300 THz
Satellite
In-Building
Urban
Suburban
Global
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Cellular Geometries
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FREQUENCY REUSE
Each cellular base station is allocated a group of radio channels within a small geographic
area called a cell.
Neighboring cells are assigned different channel groups.
By limiting the coverage area to within the boundary of the cell, the channel groups may
be reused to cover different cells.
Keep interference levels within tolerable limits.
Frequency reuse or frequency planning
“The design process of selecting and allocating channel groups for all of the cellular base
station within a system is FREQUENCY REUSE/PLANNING”
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Cell
Cell is the small geographic area covered by the base station.
The area around an antenna where a specific frequency range is used.
Cell is represented graphically as a hexagonal shape, but in reality it is irregular in shape.
cell
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Cell Shape
R
R
R
Cell
R R
(a) Ideal cell (b) Actual cell (c) Different cell models
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Cellular Geometries
• The most common model used for wireless networks is uniform hexagonal
shape areas
– A base station with omni-directional antenna is placed in the middle of the cell
d 3R
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Fundamentals of Cellular Systems
BS
Cell
MS
Alternative MS
Hexagonal cell area
shape of a cell
used in most models
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Why hexagon for theoretical coverage?
For a given distance between the center of a polygon and its farthest perimeter points, the hexagon has the
largest area of the three
Thus by using hexagon geometry, the fewest number of cells can cover a geographic region, and hexagon
closely approximates a circular radiation pattern which would occur for an omnidirectional BS antenna and
free space propagation
When using hexagons to model a coverage areas, BS transmitters are depicted as either being in the center of
the cell (center-excited cells) or on the three of the six cell vertices (edge-excited cells)
Normally omnidirectional antennas are used in center-excited cells and directional antennas are used in
corner-excited cells
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Signal Strength
Signal strength
(in dB)
Cell i Cell j
-60 -60
-70 -70
-80 -80
-90
-90 -100
-100
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How Often Are Frequencies Reused (Frequency Reuse Factor)?
Cells with the same number have the same set of frequencies
Frequency Reuse
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Cluster:
2
1 7 3
1
3 1
3
2 6 4
2
4 5
7 3 2
1 7 3
6 4 1
5 6 4
2 5
7 3 2
1 7 3
6 4 1
5 6 4
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Frequency Allocation Concepts
• Consider a cellular system which has a total of S duplex channels.
• Each cell is allocated a group of k channels, k S .
• The S channels are divided among N cells.
• The total number of available radio channels S kN
• The N cells which use the complete set of channels is called cluster.
• The cluster can be repeated M times within the system. The total number of channels, C, is used as a
measure of capacity
C MkN MS
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Frequency Reuse
The frequency reuse concept can be used in the time domain and the space domain.
Frequency reuse in the time domain results in the occupation of the same frequency in
different time slots. It is called time-division multiplexing (TDM). Frequency reuse in the
space domain can be divided into two categories. F7 F2
1. Same frequency assigned in two different
geographic areas, such as AM or FM radio F7 F2 F6 F1
F1 F3
stations using the same frequency in different
cities. F6 F1
F1 F3 F5 F4 F7 F2
2. Same frequency repeatedly used in a same
general area in one system2—the scheme is used F5 F4 F7 F2 F6 F1
F1 F3
in cellular systems. There are many cochannel
cells in the system. The total frequency spectrum F6 F1
F1 F3 F5 F4
allocation is divided into K frequency reuse
patterns, as illustrated F5 F4
in Fig. for K = 4, 7, 12, and 19.
VBIT 7 cell reuse cluster
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Fx: Set of frequency
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• Hexagonal geometry has
– exactly six equidistance neighbors
– the lines joining the centers of any cell and each of its neighbors are separated by
multiples of 60 degrees.
• Only certain cluster sizes and cell layout are possible.
• The number of cells per cluster, N, can only have values which satisfy
j
N = 1, 3, 4, 7, 9, 12, 13, 16, 19, 21, 28, …, etc.
The popular value of N being 4 and 7. 60o
N i 2 ij j 2 i
where i and j are integers.
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j=1
j=1 i=2
i=2 j=1
j direction
i=2
60° i=2
i direction j=1
j=1
1 2 3… i i=2 i=2
j=1
(a) Finding the center of an adjacent cluster using integers i
and j (direction of i and j can be interchanged). (b) Formation of a cluster for N = 7 with i=2 and j=1
(c) A cluster with N =12 with i=2 and j=2 (d) A Cluster with N = 19 cells with i=3 and j=2
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Reuse Distance
R Cluster
• For hexagonal cells, the reuse distance is given by
F7 F2 D 3N R
F6 F1
F1 F3
where R is cell radius and N is the reuse pattern
(the cluster size or the number of cells per cluster).
F5 F4 F7 F2
D
F6 F1
F1 F3
• Reuse factor is q 3N
R
F5 F4
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Frequency Reuse
• For hexagonal cells, the number of cells in the cluster is given by
N I 2 J 2 ( I J ), I , J 1,2,3,4...
N {1,3,4,7,9,12,16,19,21,...}
D R 3N
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Smaller N is greater capacity
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D R 3N
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Geometry of Hexagonal Cells (1)
How to determine the DISTANCE between the nearest co-channel cells ?
Planning for Co-channel cells
D is the distance to the center of the nearest co-channel cell
R is the radius of a cell
3R
i
30o
R
3R
0
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where D = Distance between the cells using the same frequency,
R = Center to vertex distance,
N = Cluster size,
q = Reuse frequency.
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D2 = 3 * R2 * (i2 + j2 + i * j)
As N = i2 + j2 + i * j
D2 = 3 * R 2 * N
D2 /R2 = 3*N
D/R = √3 N
As q = D/R
q = √3N
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Co-channel cells for 7-cell reuse
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Cochannel Interference
R
D6
D5
D1
D4 Mobile Station
D2
D3
C Carrier C
M
Ik
I Interference
k 1
C C
where g is the propagation path loss slope
g
I M D and g = 2~5.
k
R
k 1
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Co-Channel Interference
Consider only the first tier of interfering cells,
if all interfering base stations are equidistant from the desired base station and if this
distance is equal to the distance D between cell centers,
then the above equation can be simplified to:
(i.e., r=R and assume Di=D and use q=D/R):
S r R ( D / R ) q
NI
I NI D NI NI
Di
i 1
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DESIRED C/I FROM A NORMAL CASE IN AN OMNIDIRECTIONAL ANTENNA SYSTEM
Assume that all Dk are the same for simplicity, as shown in Fig; then D = Dk , and q = qk , and
the value of C/I is based on the required system performance and the specified value of γ
is based on the terrain environment. With given values of C/I and γ , the cochannel
interference reduction factor q can be determined. Normal cellular practice is to specify
C/I to be 18 dB or higher based on subjective tests.
this acceptance implies that both mobile radio multipath fading and cochannel interference
become ineffective at that level. The path-loss slope γ is equal to about 4 in a mobile radio
environment
1/4
q = D/R = (6 × 63.1) = 4.41
The 90th percentile of the total covered area would be achieved by increasing the transmitted power at each cell;
increasing the same amount of transmitted power in each cell does not affect the result of Eq. (2.7-4). This is because
q is not a function of transmitted power. The computer simulation described in the next section finds the value of q
= 4.6, which is very close to Eq. The factor q can be related to the finite set of cells K in a hexagonal-shaped cellular
system by
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Example:
Co-Channel Interference
If S/I = 15 dB required for satisfactory performance for forward
channel performance of a cellular system.
Assume 6 co-channels all of them (same distance from the mobile), I.e. N=7
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Example: Co-Channel Interference
a) NI =6 => cluster size N= 7, and when =4
The co-channel reuse ratio is q=D/R=sqrt(3N)=4.583
S q 1
6 (4.583) 4 75.3
I NI
Or 18.66 dB greater than the minimum required level ACCEPT IT!!!
b) N= 7 and =3
S q
16 (4.583)3 16.04
I NI
Or 12.05 dB less than the minimum required level REJECT IT!!!
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Example: co-Channel Interference
We need a larger N (thus q is larger). Use eq. N =i2+ij+j2, for i=j=2 next
possible value is N=12.
S q
111 (6)3 19.6
I NI
Or 15.56 dB N=12 can be used for minimum requirement, but it decreases the capacity
(we already gave an example: when cluster size is smaller, the capacity is larger).
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Worst Case Co-Channel Interference
i.e., mobile terminal is located at the cell boundary where it receives the weakest signal from its own cell but
is subjected to strong interference from all all the interfering cells.
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• For hexagonal geometry with 7-cell cluster, with the mobile unit being at the cell
boundary, the signal-to-interference ratio for the worst case can be approximated as
S R 4
I 2( D R) 4 ( D R / 2) 4 ( D R / 2) 4 ( D R) 4 D 4
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Example: Worst Case Cochannel Interference
A cellular system that requires an S/I ratio of 18dB. (a) if cluster size is 7, what is the worst-case
S/I? (b) Is a frequency reuse factor of 7 acceptable in terms of co-channel interference? If not, what
would be a better choice of frequency reuse ratio?
Solution
(a) N=7 q = 3N 4.6 . If a path loss component of =4, the worst-case signal-to-interference ratio is
S/I = 54.3 or 17.3 dB.
(b) The value of S/I is below the acceptable level of 18dB. We need to decrease I by
increasing N =9. The S/I is 95.66 or 19.8dB.
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Example: Worst Case Cochannel Interference
For a conservative estimate if we use the shortest distance (=D-R) then
S 1
4
1
6 ( 3.6 ) 4
28
I 6(q 1)
Or 14.47 dB.
REMARK: In real situations, because of imperfect cell site locations and the rolling nature of
the terrain configuration, the S/I ratio is often less than 17.3 dB. It could be 14dB or lower
which can occur in heavy traffic.
Thus, the cellular system should be designed around the S/I ratio of the worst case.
REMARK:
If we consider the worst case for a 7-cell reuse pattern We conclude that a co-channel interference
reduction factor of q=4.6 is not enough in an omnidirectional cell system.
In an omnidirectional cell system N=9 (q=5.2) or N=12 (q=6.0) the cell reuse pattern would be a better
choice. These cell reuse patterns would provide the S/I ratio of 19.78 dB and 22.54 dB, respectively.
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CAPACITY EXPANSION IN CELLULAR SYSTEM
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CELL SPLITTING
Cell splitting increases the capacity of cellular system since it increases the
number of times the channel are reused
Cell splitting - defining new cells which have smaller radius than orginal cells by
installing these smaller cells called MICROCELLS between existing cells
Capacity increases due to additional number of channels per unit area
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Cell Splitting
Large cell
(low density)
Small cell
(high density)
Smaller cell
(higher density)
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CELL SPLITTING
Split congested cell into smaller cells.
– Preserve frequency reuse plan. Reduce R to R/2
– Reduce transmission power.
microcell
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• Transmission power reduction from Pt1 to Pt 2
• Examining the receiving power at the new and old cell boundary
Pr [at old cell boundary ] Pt1R n
Pr [at new cell boundary ] Pt 2 ( R / 2) n
• If we take n = 4 (path loss) and set the received power equal to each other
Pt1
Pt 2
16
• The transmit power must be reduced by 12 dB in order to fill in the original coverage area.
• Problem:
if only part of the cells are splited
– Different cell sizes will exist simultaneously
• Handoff issues - high speed and low speed traffic can be simultaneously accommodated
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CELL SPLITTING
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Cell Sectoring by Antenna Design
c
c
120o 120o
a
b a
b
d f
90o e 60o a
a
c
d b
b c
C
X
A
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Microcell Zone Concept
• Antennas are placed at the outer edges of the cell
• Any channel may be assigned to any zone by the base station
• Mobile is served by the zone with the strongest signal.
• Handoff within a cell
– No channel re-assignment
– Switch the channel to a different zone site
• Reduce interference
– Low power transmitters are employed
Microcell
• Micro cells can be introduced to alleviate capacity problems
caused by “hotspots”.
• By clever channel assignment, the reuse factor is unchanged. As
for cell splitting, there will occur interference problems when
macro and micro cells must co-exist.
Microcells-Reduced power, Good for city streets, along roads and
inside large buildings
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Terminology : Cellular traffic
Trunking : Trunking is the concept that allows large number of users to use a smaller number of
channels(or phone lines, customer service representatives, parking spots, public bathrooms, …)
as efficiently as possible.
Grade of service (GoS) : A user is allocated a channel on a per call basis. GoS is a measure of the
ability of a user to access a trunked system during the busiest hour. It is typically given as the
likelihood that a call is blocked (also known as blocking probability mentioned before).
Trunking theory : is used to determine the number of channels required to service a certain
offered traffic at a specific GoS.
Call holding time (H) : the average duration of a call.
Request rate (λ) : average number of call requests per-unit time.
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Trunking and Grade of Service
• Erlangs: One Erlangs represents the amount of traffic density carried by a channel that is
completely occupied.
– Ex: A radio channel that is occupied for 30 minutes during an hour carries 0.5 Erlangs of traffic.
• Grade of Service (GOS): The likelihood that a call is blocked.
• Each user generates a traffic intensity of Au Erlangs given by Au H
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Traffic flow or intensity A
Measured in Erlang, which is defined as the call minute per minute.
Offered traffic for a single user is given as Au = λ ⋅H
λ average number of call request
H duration of a call
For a system containing U user, total offered traffic A = U⋅ Au
Exercise :
There are 3000 calls per hour in a cell, each lasting an average of 1.76 min.
Offered traffic A = (3000/60)(1.76) = 88 Erlangs
If the offered traffic exceeds the maximum possible carried traffic, blocking occurs. There are
two different strategies to be used.
Blocked calls cleared
Blocked calls delayed
Trunking efficiency : is defined as the carried traffic intensity in Erlangs per channel, which
is a value between zero and one. It is a function of the number of channels per cell and the
specific GoS parameters.
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Capacity
S = no of duplex channels available
K = no of channel in one cell
N = no of cell/cluster
M = no of cluster in a given system
C = total no of duplex channel available in a cellular system (capacity)
C=M*K*N=M*S
Example:
For K = 100, N = 7, calculate system capacity for M = 6 and M = 4
i) C = 6 * 100 * 7 = 4200 channels
ii) C = 4 * 100 * 7 = 2800 channels
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Example 1
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Formula (Cellular Traffic)
i) Total number of channel per cell (NC)
Iii) Total no.of user (U) = total traffic (A) / traffic per user ( Au)
Iv) number of call that can be made at any time = NC x no.of cell
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Example 2
How many users can be supported for 0.5% blocking probability for the
following number of trunked channels in a blocked calls cleared system.
(a) 1
(b) 5
(c) 10
(d) 20
(e) 100
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Example 3
A city has an area of 3000 sq.km and is covered by a cellular system using 7 cell per cluster. The area of
a cell is 100 sq.km. The cellular system is allocated total bandwidth of 40 MHz of spectrum with full
duplex channel bandwidth of 200 KHz. For the GOS of 2 % and the offered traffic per user is 0.03
Erlangs, calculate;
a) The number of cell in the city
b) The number of channels per cell
c) Traffic intensity of each cell
d) Traffic intensity for the city
e) The total number of users that can be served in the city
f) The number of mobiles per channel
g) Number of call that can be made at any time in the city
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Erlang B Trunking GOS
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Erlang B
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125 Thank you………………