CONFIDENTIAL
UNIVERSITI TUN HUSSEIN ONN MALAYSIA
                      TEST 1
               (ONLINE ASSESSMENT)
                   SEMESTER II
                 SESSION 2020/2021
     COURSE NAME            : INDUSTRIAL POWER SYSTEMS
     COURSE CODE            : MEK 10203
     PROGRAMME CODE         : MEE
     EXAMINATION DATE       : 27th APRIL 2021
     DURATION               : 2 HOURS
     INSTRUCTION            : ANSWER ALL QUESTIONS
         THIS QUESTION PAPER CONSISTS OF FIVE (5) PAGES
                                                  CONFIDENTIAL
CONFIDENTIAL                                MEK 10203
Q1   (a)   A new factory is planning to get electricity supply from the local utility company. The
           proper supply voltage for this factory is supposedly 33 kV. Unfortunately, due to
           incorrect maximum demand estimation by the appointed electrical consultant, the
           installed supply voltage is 11 kV. Discuss two (2) main consequences of this problem.
                                                                                         (4 marks)
     (b)   A distribution transformer (Tx) is to be installed in a factory to serve the loadings as
           depicted in Figure Q1(b). The transformer will be connected to the grid system.
           (i) Decide the initial transformer sizing based on maximum demand criteria. The initial
               decision made should be based on the requirements as given in Appendix. The
               sizing should be stated the primary kV/ secondary kV, standard kVA rating and
               impedance % (minimum % should be considered at this stage).
                                                                                       (7 marks)
           (ii) Investigate the voltage variation (in percentage) during the motor starting.
                                                                                           (3 marks)
           (iii) Recommend the proper impedance % of the transformer if the voltage variation
                 during the motor starting is to be limited to a maximum value of 8%.
                                                                                      (3 marks)
           (iv) If the annual growth rate of the load demand is taken as 2%, analyse the maximum
                period (in year) that the standard kVA as selected in Q1(b)(i) is valid based on the
                maximum demand criteria.
                                                                                           (3 marks)
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Q2   (a)   A new glue manufacturer is decided to have an adhesive mixer machine. Describe in
           brief the suitable motor for this application with appropriate justification. Sketch the
           torque-speed characteristics curve for this load.
                                                                                          (5 marks)
     (b)   A 440 V, two-pole, 50 Hz, Y-connected induction motor is used as a pump in an
           industrial plant. It has an inductive reactance of 3 Ω and a stator resistance of 0.4 Ω. The
           rotor resistance referred to the stator is 0.25 Ω. The motor is driving a constant-torque
           load of 80 Nm at operating slip of 3.25%. The braking system of this motor is utilising
           the Fixed Width Modulation based dynamic braking technique. The duty ratio is taken
           as 20%. The motor is driven by a six-step converter with DC link voltage of 250 VDC.
           (i)   If the motor speed is controlled via frequency, point out the motor current at rated
                 frequency and at the maximum frequency.
                                                                                          (6 marks)
           (ii) Analyse the motor speed at rated frequency and at the maximum frequency for the
                case in Q2(b)(i).
                                                                                     (2 marks)
           (iii) Determine the braking current required for this motor.
                                                                                            (2 marks)
           (iv) Analyse the starting current of this motor at rated frequency and at the maximum
                frequency.
                                                                                         (2 marks)
           (v)   Propose a better method so that the starting current is remained at minimum value.
                 Demonstrate the method.
                                                                                          (3 marks)
                                          – END OF QUESTIONS –
                                                  3                         CONFIDENTIAL
 CONFIDENTIAL                         MEK 10203
                                        TEST 1
SEMESTER/SESSION : II/ 2020/ 2021                      PROGRAMME CODE : MEE
COURSE NAME      : INDUSTRIAL POWER SYSTEMS            COURSE CODE    : MEK 10203
                                       Grid system
                                                     Tx
             Lump Load, L1                     Lump Load, L3
           650 kW + 820 kVAr                      950 kVAr
                                               PF = 0.76 lagging
                                                                       M
                           Lump Load, L2
                               500 kW                                1250 hp
                           PF = 0.82 lagging                 Starting current = 6.5 X
                                                               PF = 0.85 lagging,
                                                                Efficiency = 96%
                                     Figure Q1(b)
                                           4                        CONFIDENTIAL
 CONFIDENTIAL                                             MEK 10203
                                                            TEST 1
SEMESTER/SESSION : II/ 2020/ 2021                                                 PROGRAMME CODE : MEE
COURSE NAME      : INDUSTRIAL POWER SYSTEMS                                       COURSE CODE    : MEK 10203
                                                         Appendix A
                                                           Table A1
                                            Supply
    M.D ranges of individual consumer                                          Minimum supply scheme
                                            voltage
   Up to 12 kVA                              230 V     Single phase overhead or underground services from existing LV network.
                                                       Three phase overhead or underground cable service from existing LV
   > 12 kVA to 100 kVA (Non Domestic)        400 V
                                                       network subject to system availability study by TNB.
                                                       Three phase overhead or underground cable service from existing LV
   Up to 100 kVA (Domestic)                  400 V
                                                       network subject to system capability study by TNB.
                                                       Underground cable service from feeder pillar or a new/ existing substation,
   > 100 kVA to 350 kVA                      400 V
                                                       subject to system availability study by TNB.
   > 350 kVA to < 1000 kVA                   400 V     Direct underground cable service from new substation.
                                                       Directly fed through TNB 11 kV switching station. An additional PPU
   1,000 kVA up to < 5,000 kVA               11 kV
                                                       land may need to be allocated subject to system capability study by TNB.
                                                       Directly fed through TNB 22 kV switching station. An additional PPU
   1,000 kVA up to 10,000 kVA                22 kV
                                                       land may need to be allocated subject to system capability study by TNB.
                                                       Directly fed through TNB 33 kV switching station. An additional PMU
   5,000 kVA to 25,000 kVA                   33 kV
                                                       land may need to be allocated subject to system capability study by TNB.
                                                       Directly fed through TNB 132 kV or 275 kV substation respectively. TNB
                                            132 kV,    shall reserve the absolute right to provide alternative arrangements after
   25,000 kVA to < 100,000 kVA
                                            275 kV     taking into consideration the location, economic and system security
                                                       factor.
                                                       Directly fed through TNB 275 kV substation. TNB shall reserve the
   100,000 kVA and above                    275 kV     absolute right to provide alternative arrangements after taking into
                                                       consideration the location, economic and system security factor
                                                           Table A2
                  Secondary                                                                                    Impedance range
   Primary (kV)                                   Rating (kVA)                        Construction Type
                     (kV)                                                                                           (%)
                  380 – 440       150, 250, 300, 400, 500, 630, 750, 1,000, 1,250,    Oil-filled and Dry-
      3 – 33                                                                                                         3–7
                      V                         1,600, 2,000, 2,500                           type
      10 – 12      3 – 7.2               4,000, 5,000, 6,300, 7,500, 10,000                Oil-filled               5 – 10
      20 – 24       3 – 12               4,000, 5,000, 6,300, 7,500, 10,000                Oil-filled               5 – 10
      33 – 36       3 – 12               4,000, 5,000, 6,300, 7,500, 10,000                Oil-filled               5 – 10
        66          3 – 36           4,000, 5,000, 6,300, 7,500, 10,000, 16,000            Oil-filled               5 – 15
                                4,000, 5,000, 6,300, 7,500, 10,000, 16,000, 25,000,
       132         3 – 110                                                                 Oil-filled               5 – 20
                                                  40,000, 50,000
      10 – 33       3 – 11       4,000, 5,000, 6,300, 7,500, 10,000, 16,000, 20,000        Dry-type                 5 – 10
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