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Offshore Pipeline Tension Analysis

The document calculates the pull force required for a J-tube by summing the tension at several points along the J-tube. It starts with the tension at the soil contact and adds the effects of soil friction and the suspended span. It then calculates the tension at bends and straight sections between the bends. The total tension at the pulley is calculated and then several safety factors are applied to determine the factored maximum tension of 5.51 metric tons.

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ferry
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76 views1 page

Offshore Pipeline Tension Analysis

The document calculates the pull force required for a J-tube by summing the tension at several points along the J-tube. It starts with the tension at the soil contact and adds the effects of soil friction and the suspended span. It then calculates the tension at bends and straight sections between the bends. The total tension at the pulley is calculated and then several safety factors are applied to determine the factored maximum tension of 5.51 metric tons.

Uploaded by

ferry
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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JTUBE PULL FORCE

J tube bend angle (Aj1) 0.10 rad (= Aj11-Aj10)


Span Length from Bell Mouth to Seabed, L span 4.27 m Hbm/1.1*((1/tanAj11)2+1)0.5
Tension at soil contact (T1) 58.0 kg From Static Lay Bottom Tension
Before J Tube
Tension due to soil friction (T2) 93.6 kg (= L x fs x Ws)
Tension due to Suspended span (T3) 44.4 kg (= Lspn x Ws)
Tension at J tube entrance (T4) 1196.0 kg (= T1 + T2 +T3 +Fj)
Result

Tension due to straight Section before Bend (T5) 1210.3 kg (= T4+L0*Ws*(cos(Aj11)+fj*sin(Aj11))


Segment 1 Tension after first bend (T6) 1625.1 kg (= [T5+Ws*R1*Aj10] x exp(Aj10 x fj))
Tension due to straight Section after Bend (T7) 2723.7 kg (=T6+L1*Ws*(cos(Aj1)+fj*sin(Aj1)))
Segment 2 Tension after second bend-below water level (T8) 2883.7 kg (= [T7+ Wd*R2*Aj2]x exp(Aj2 x fj))
Tension due to straight Section before Bend-above Water Level (T9) 2961.1 kg (=T8+L3*Wd*(cos(Aj3)+fj*sin(Aj3)))
Segment 3 Tension after third bend (T10) 3249.2 kg (= [T9+Wd*R3*Aj3] x exp(Aj3 x fj))
Tension due to straight Section after Bend-above Water Level (T11) 3256.2 kg (= T10+L4*Wd*(cos(Aj4)+fj*sin(Aj4))))
TOTAL Tension at Pulley (T12) 3956.2 kg (= T11+Wp+Wrig)
Load Factor (C1) 1.3 -
Contengency factor Catenary allowance (C2) 1.02 -
Weight contengency (C3) 1.05 -
Result Factored max tension 5.51 MT (=C1 x C2 x C3 x T12)

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