Test Booklet Code & Serial No.

A
PHYSICAL SCIENCE
Signature and Name of Invigilator Seat No.
1. (Signature) ......................................... (In figures as in Admit Card)
(Name) ................................................ Seat No. ..............................................................
2. (Signature) ......................................... (In words)

(Name) ................................................ OMR Sheet No.

JUN - 32220 (To be filled by the Candidate)

Time Allowed : 2 Hours] [Maximum Marks : 200
Number of Pages in this Booklet : 28 Number of Questions in this Booklet : 100
Instructions for the Candidates
1. Write your Seat No. and OMR Sheet No. in the space provided 1.
on the top of this page.
2. This paper consists of 100 objective type questions. Each question
will carry two marks. All questions of Paper II will be compulsory. 2.
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requested to open the booklet and compulsorily examine it as
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the correct response against each item.
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A B D (C)
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end of the examination compulsorily and must not carry it with 9.
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to carry the Test Booklet and duplicate copy of OMR Sheet on
conclusion of examination.
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11.
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 JUN - 32220/II—A

2
 JUN - 32220/II—A
Physical Science
Paper II
Time Allowed : 120 Minutes] [Maximum Marks : 200
Note : This Paper contains Hundred (100) multiple choice questions. Each question
carrying Two (2) marks. Attempt All questions.
1. Unit vector perpendicular to 3. A particle passes through a medium

A 2iˆ ˆj kˆ and B 3iˆ 4 ˆj kˆ and is deflected by a small angle

is : 0 upon each collision within the

medium with equal probability in
3iˆ 5 ˆj 11kˆ any direction. The mean square
(A)
155
angular scattering after N such
iˆ ˆj 2kˆ collision, 2 is :
(B)
6
(A) 0
4iˆ ˆj 5kˆ
(C) (B) N 2
42 0

2
iˆ 2 ˆj 4 kˆ 0
(D) (C)
21 N

2. If S is a closed surface enclosing a (D) N2 2

0
volume V and n̂ is the unit vector
4. When a complex number Z is
normal to the surface and r is the
multiplied by i, the resulting vector
position vector, then the value of the
iz, in the z plane, is obtained by
integral nˆ dS is :
rotating the vector z through :
S

(A) V (A)

(B) 2V (B) – /2

(C) 0 (C) 3 /2

(D) 3V (D) /2
3 [P.T.O.
 JUN - 32220/II—A

z2 a b
5. The residue of the function 8. The matrices A = and
z2 a2 b a
at z = ia is :
c d
B= , for some values of
ia d c
(A)
2
a, b, c, d :
(B) –a2

(C) ia (A) have no commutation relation

(D)
between them
6. If y = ezt is a solution of y – 5y
+ ky = 0, then k is equal to : (B) Commute for all values of a, b,
(A) 1
c, d
(B) 4

(C) 5 (C) Commute if and only if a, b, c,

(D) 6 d are real numbers

7. Solution of the differential equation
(D) Anticommute for all values of
dy
x + y = x4 with the boundary
dx a, b, c, d
condition that y = 1 at x = 1 is :
(A) y = 5x4 – 4 9. For any operator A, i (A+ – A) is :

x4 4x (A) Hermitian
(B) y
5 5
(B) Anti-Hermitian
4 x4 1
(C) y
5 5x
(C) Unitary
4
x 4
(D) y
5 5x (D) Orthogonal

4
 JUN - 32220/II—A

10. The complex Fourier transform of

12.
e–|x| is :

2
(A)
1 n2

1
(B)
1 n2

4
(C)
1 n2 A mass of 1 kg is connected to a

spring at one end using a massless,

(D)
1 n2
rigid string. Initially the spring is
11. A mouse of mass m jumps on a freely
in unstretched state. If the mass falls
rotating disc of moment of inertia I
through a distance h before stopping
and radius R. If 0 and are the
(now the spring is in stretched
angular velocities of the disc before
condition), then the distance h is
and after mouse jumps, then the
given as :
ratio / 0 is :

(A) I/mR2 (A) 0.196 m

(B) I/I – mR2 (B) 1.96 m

(C) I/I + mR2 (C) 0.14 m

(D) (I – mR2)/I (D) 1.4 m

5 [P.T.O.
 JUN - 32220/II—A

13. The mutual potential energy V of 15. The number of degrees of freedom
two particles is function of their
for an astronaut constrained to move
mutual distance r, given as :
on surface of a spherical spaceship
a b
V r , a > 0, b > 0
r2 r
freely moving in space, is :
If the particles are in static
(A) 5
equilibrium, then the separation (r)
is : (B) 6

(A) 2b/a
(C) 4
(B) b/2a
(D) 3
(C) a/b
16. A particle falls vertically under the
(D) 2a/b
action of gravity and a frictional
14. A particle of mass m moves in an
ellipitical orbit under the action of force obtainable from dissipation
inverse square central force. If is 1 2
function G(v) = kv , k is constant.
2
the ratio of maximum angular
The Lagrange’s equation of motion
velocity to the minimum angular
velocity, then the eccentricity of the is :

ellipse is given as :
(A) my ky mg 0
(A) /( + 1)
(B) my ky mg 0
(B) ( + 1)/
(C) my ky mg 0
(C) ( – 1)/

(D) ( – 1)/( + 1) (D) my mg 0

6
 JUN - 32220/II—A

17. Suppose a system has holonomic and 19. A frame of reference S is rotating
conservative part, and also some with constant angular velocity
part of forces acting on the system with respect to a stationary frame
are not conservative. Let the typical
of reference S. Both the frames of
non-conservative force acting on jth
reference have common origin. The
particle is denoted as Q i . The
time derivative of vector A in S
Hamilton’s equations of motion
is :
modify to :
dA
H H (A) A
(A) qi , pi Qi dt
pi qi
dA dA
H H (B) A+
(B) qi , pi Qi dt dt
pi qi
dA dA
H H (C) A+
, pi Qi dt dt
(C) qi pi qi
dA dA
(D)
H H dt dt
(D) qi , pi Qi
pi qi
20. A particle as observed in certain
18. A rigid body, whose two of the frame of reference has a total energy
principal moments of inertia are
of 13 GeV and a momentum of
equal and the third is zero, is called
5 GeV/c. Its rest mass is :
as :
(A) 12 GeV/c2
(A) Asymmetrical top

(B) Rotor (B) 12 MeV/c2

(C) Spherical top (C) 1.2 MeV/c2

(D) Symmetrical top (D) 1.2 GeV/c2

7 [P.T.O.
 JUN - 32220/II—A

21. Current I is flowing through an 23. The SI unit of magnetic dipole

infinitely long wire placed along the
moment is .................................. .
x-axis. The Cartessian coordinates of
the points A and B are A(2, 1, 4) (A) Cm
and B(–6, 1, 4). The ratio of
magnitudes of B at point A to that (B) Cm 2

at point B is ............................ .
(C) Cm/s
1
(A)
3
(D) Cm2/s
(B) 3

(C) 1 24. A solid sphere of radius R with its

(D) µ 0 I center at origin has a volume charge

22. A charged particle is released from density A r , where A is a

rest in a region where both uniform
constant. The magnitude of electric
constant electric field and uniform
constant magnetic field are present. field, E , at r < R, varies with r

If these fields are perpendicular to

as ................... .
each other, then the trajectory of the 1
(A) E r 2
particle is a .............................. .
1
(A) Straight line
(B) E r2
(B) Circle 3
(C) E r2
(C) Cycloid
2
(D) Circular helix (D) E r

8
 JUN - 32220/II—A

25. Three point charges q, q and –2q are 27. What is the magnitude of the
Poynting vector at the surface of a
located at (0, –1, 1), (0, 1, 1) and
long cylindrical wire of radius R,
(0, 0, –1) respectively. The
length L, carrying current I, when
magnitude of electric dipole moment its ends are kept at a potential

of this charge distribution is : difference V ?

(A) zero
(A) zero
VI
(B) q (B)
2 R2 2 RL

(C) 2q VI
(C)
R 2L
(D) 4q
VI
26. The electrostatic potential is given (D) 2 RL

by = k(x2 + y2 + z2), where k is 28. Velocity of light in air is 3 × 108

m/s. Velocity of light in a medium
a constant. The volume charge
having relative permittivity 3 and
density giving rise to the above relative permeability 2 is .......... .

potential is ............................ . 3
(A) × 108 m/s
2
(A) 6 0 k
3
(B) × 108 m/s
(B) –6 0 k 4

(C) 8
2 × 10 m/s
(C) 2 0 k
3
(D) –2 (D) × 108 m/s
0 k 2

9 [P.T.O.
 JUN - 32220/II—A

29. Which of the following volume 31. Out of the following particles, all
charge densities J r generates the
having the same kinetic energy,
magnetic vector potential
which has the longest wavelength ?
A r y2 xˆ x2 yˆ ?
(A) An -particle
2
(A) ( xˆ yˆ )
0 (B) An electron
2
(B) ( xˆ yˆ ) (C) A proton
0

2 (D) A neutron
(C) ( x xˆ y yˆ )
0
32. If quantum mechanical operators of
2
(D) ( x xˆ y yˆ ) two observables of a system do not
0

30. A square wave guide with perfect commute, then :

conductor boundaries is of cross-
(A) the total energy of the system
sectional area l2. The wave guide is
placed in vacuum. The minimum must be negative

frequency of the electromagnetic

(B) the parity of the wave function
waves that can propagate through
of the system must be odd
this wave guide is ................... .

c (C) the observables corresponding

(A)
l
to these operators must be time-
2c
(B) independent
l
c (D) it is impossible to know the
(C)
l
precise values of the observables
c
(D) 2 simultaneously
l
10
 JUN - 32220/II—A

35. Given 10 > and 11 > are the ground

33. Given the operators  = i xpy ypx
and first excited state for a one-
and B̂ = ypz zpy the commutator dimensional harmonic oscillator, the
ˆ B
A, ˆ is : uncertainty in position x for a
particle in the state given by
(A) xpz px z
1
(10 > + 11 >) is :
(B) xpz px z 2

(C) xpz px z Given xˆ aˆ aˆ

2m !
(D) xpz px z

34. A particle in one-dimension is (A) "x

2m !
moving under the potential
described by :
(B) "x
m !
for x 0

V x V0 for 0 x a, V0 0 2
(C) "x
0 for x a m !

The minimum depth of the potential 4

(D) "x
for at least one bound state is : m !

2 2 36. A muonic atom is formed by a muon

(A) (µ –) and a proton. The longest
2ma2
wavelength of spectral line (in
2 2
(B) Balmer series) of such an atom is
8ma2
approximately (h = 6.6 × 10–34 Js)
2 2
(A) 20.5 Å
(C) 2
ma (B) 2.05 Å
2 2 (C) 205 Å
2
(D)
ma2 (D) 10.25 Å
11 [P.T.O.
 JUN - 32220/II—A

37. A particle in a one-dimensional 39. In the Born approximation,

infinite potential well of width L is scattering amplitude f( ) for Yukawa
acted on by a perturbation #e r
potential V(r) = is given by
H = b(L – x) 0 x L r
= 0 otherwise $ 2 2
k
(Given data : b = 2k sin , E = )
First order correction to the first 2 2m
excited state is : 2m#
bL (A) 2 2
b2
(A)
2
bL 2m#
(B) (B) 2 2 3
2 b2
(C) 2bL
2m#
(D) bL 2
(C) 2 2
b2
38. Minimum energy of a collection of
six non-interacting electrons of spin 2m#
1 (D) 2 2
and mass m, placed in a one- b2
2
dimensional infinite potential well 40. Which one of the following given
of width L is : below represents the bound state

3 2 2 d2
(A) eigen function of the operator
mL2 dx2
2 2 in the region 0 x with eigen
14
(B) value –4 ?
mL2
2 2
(A) A0 e2x
7
(C) (B) A0 e–2x
mL2
2 2 (C) A0 cosh 2x
91
(D) (D) A0 sinh 2x
mL2
12
 JUN - 32220/II—A

41. Density and specific heat at constant 43. A three-dimensional classical

volume are : Harmonic Oscillator is in thermal

(A) both intensive variables equilibrium with a heat reservoir at
(B) both extensive variables
temperature T. Its average total
(C) intensive and extensive
energy would be :
variables respectively
(D) extensive and intensive (A) 6 kBT

variables respectively
(B) 3/2 kBT
42. A capacitor of capacitance C farads
is charged from a battery of emf V (C) kBT

volts. Out of the work done by the (D) 3 kBT

1
battery an amount CV2 is stored
2
44. A system at temperature 30 K is so
in the capacitor and the rest is

released to the surroundings. If the large that its temperature does

process is carried at temperature T not change if 107 J of heat is added.

the change in the entropy of the The factor by which the number
universe would be : of accessible states increase is
CV 2 (kB = 1.3807 × 10–23 JK–1)
(A)
8T

CV 2 (A) 2.4 ×1014

(B)
T 14
(B) e2.4 ×10
CV 2
(C)
2T (C) 107
CV 2
(D) (D) 30 × 107
4T
13 [P.T.O.
 JUN - 32220/II—A

47. The number of distinct ways in

45. Consider a system with only two
which 7 identical Fermions can be
energy levels with energies E0 = 0 distributed in 3 energy levels is :

and E1 = 1.3806 × 10–23 J. The 7!

(A)
4!3!
level E0 has degeneracy 2 and the (B) 37

level E1 has degeneracy 3. The (C) 0

(D) 210
partition function at T = 1 K is
48. One block at temperature T1 and
(KB = 1.3806 × 10–23 JK–1) : another identical block at
temperature T 2 are placed in
(A) z = 2e0 + 3e–1 thermal contact and come to an
equilibrium, the system being
(B) z = 6e–3 isolated from surroundings. If the
heat capacities at constant volume
(C) z = 6(e0 + e–1)
C depend on temperature as C = aT,
the entropy change of the system
(D) z = 6e–1
would be :
46. Fermi level in a solid is a direct 1/2
T12 T22
(A) a 2 2 !
T1 T2
measure of :

T1 T2
(A) Electronic current (B) a
2
2
(B) Temperature of solid T1 T2
(C) a ln 4T1 T2
(C) Resistivity of solid
2T1 T2
(D) Chemical potential of electrons (D) a ln T T2
1

14
 JUN - 32220/II—A

49. An ideal gas at temperature T 51. In a critically damped series LCR

expands in an isothermal process circuit :

from volume V1 to volume V2. The (A) R2 = 4L/C

work done in the process is :
(B) R2 = 2L/C
1
V1 V2 2 (C) R = L/C
(A) RT ln
V1 V2
! (D) R2 = 4L2C2

V1 52. Johnson Noise in resistor R is given

(B) RT ln
V2 ! by :

(A) vrms = (4KTR"f)1/2

V1 V2
(C) RT ln 1
(B) vrms = (2qI"f)1/2 R
V1 V2 2 !

(C) vrms = A/f2

V2
(D) RT ln
V1 ! (D) vrms = A/f

50. According to Weiss molecular theory 53. A 50 Hz noise signal of 1 mV peak

near the critical point the isothermal value is introduced at the input

susceptibility of the magnetic system of an op-amp based integrator

behaves as : (RC = 1 s). The output will be :

(A) %T |T – TC| (A) 3.2 nV

(B) %T |T – TC|–1 (B) 3.2 V

(C) %T |T – TC|1/2 (C) 3.2 mV

(D) %T |T – TC|–1/2 (D) 3.2 V

15 [P.T.O.
 JUN - 32220/II—A

54. In Millikan’s oil drop experiment the 56. In X-ray diffraction pattern the
positions of the peaks depend on :
electronic charge e could be written
(A) size of the crystal
as K&1.5, where K was a function
(B) shape of the crystal
of other experimental parameters

with negligible error, while the (C) texture of the crystal

viscosity of air & assumed was 0.4% (D) lattice constants of the planes
of the crystals
too low. What was the error in e ?
57. For NMR spectra of proton nuclei,
(A) 1.5%
the commonly used reference is :

(B) 0.7% (A) Ethyl alcohol

(C) 0.6% (B) Carbon tetrachloride

(C) Methyl alcohol

(D) 0.4%
(D) Tetramethylsilame (TMS)
55. Which of the following experiments
58. To measure temperature of more
provides verification of charge
than 3000°C, the most suitable
quantization ? thermometer is :

(A) Millikan’s oil drop E (A) Platinum resistance thermo-

meter
(B) Franck-Hertz
(B) Thermocouple
(C) Davisson and Germer
(C) Radiation pyrometer

(D) Zeeman Effect (D) Gas thermometer

16
 JUN - 32220/II—A

61. Symbols :
59. What is the temporal coherence

ID = Drain Current, VSD = Source

length of a mercury vapour lamp
to Drain Voltage, VGS = Gate to
emitting in the green portion of the
Source Voltage.
spectrum at wavelength of 546.1 nm
In the operation of JFET, the pinch-
with an emission bandwidth of off region has the following

"' = 6 × 108 Hz : characteristics :

(A) The current ID increases with

(A) 0.5 m
the increase in the VSD when
(B) 2 m VGS is negative, reverse biased

(C) 0.25 m (B) The current ID is constant when

the VGS is positive, forward

(D) 1 m
biased and the VSD is near

60. Best vacuum that can be attained break down region

with a rotary pump is : (C) The current ID is constant and

relatively independent of VSD

(A) 10–3 Torr
but the gate is reverse biased,

(B) 1 Torr VGS negative

(D) The current ID is constant and

(C) 10–6 Torr
relatively independent of VSD
(D) 10–10 Torr but the VGS is zero

17 [P.T.O.
 JUN - 32220/II—A
62. In p-n junction photodiode, the 64. A full wave rectifier supplies DC
reversing biasing : voltage to a load resistance of 2 k(.
The AC voltage applied to the diodes
(A) Lowers the carrier transit period
is 300-0-300 Volts rms. If the diode
through the depletion layer
voltage drop is neglected, the
and reduces the depletion
average DC voltage across the load
capacitance
is nearly :
(B) Increases the carrier transit
period through depletion region (A) 300 Volts
and also the depletion capaci- (B) 270 Volts
tance
(C) 150 Volts
(C) Reduces the concentration of n-
type impurity and increases the (D) 100 Volts
photoabsorption efficiency
65. A 5 mV, 1 kHz sinusoidal signal is
(D) Increases the concentration of applied to the input of an op-amp
p-type impurity and photo- circuit shown below. Find the output
absorption efficiency voltage :
63. The frequency of the following
Hartley oscillator

1
(A) (cos 2000 t – 1) mV
20

1
(B) (cos 2000 t – 1) mV
40
is nearly equal to :
(A) 139 kHz 1
(C) (cos 2000 t – 1) mV
60
(B) 159 kHz
(C) 179 kHz 1
(D) (cos 2000 t – 1) mV
(D) 279 kHz 80
18
 JUN - 32220/II—A

66. The AC Gain of the following 67. A flux quantum (fluxoid) is

transistor amplifier approximately equal to 2 × 10–7

gauss-cm2. A type II superconductor

is placed in a small magnetic field,

which is then slowly increased till

the field starts penetrating the

superconductor. The strength of the

field at this point is (2/ ) × 105 gauss.

is nearly equal to :

The penetration depth of this

(A) 200 superconductor is :

(A) 10 Å
(B) 300

(B) 100 Å

(C) 400
(C) 1000 Å

(D) 500 (D) 1200 Å

19 [P.T.O.
 JUN - 32220/II—A

68. The most suitable gates to check 70. A pulse train with a frequency of
whether the number of ones in a 1 MHz is counted using a modulo
digital word is even or odd is : 1024 ripple counter built with J-K
(A) EX-OR flip-flop. For proper operations of the

(B) NAND counter the maximum permissible

propagation delay per flip-flop stage

(C) NOR
is :
(D) AND and OR
(A) 10 nsec
69. In the following circuit, the diode
current flows through the resistance (B) 20 nsec
10 ( :
(C) 50 nsec

(D) 100 nsec

71. The Bohr radius of the hydrogen

atom and the Compton wavelength

of electron are given by :

If the voltage drop across the diode
2 h
is 0.7 Volt, then the diode used (A) a and )c m0 c
me2
should have minimum power rating
2
nearly : h2
(B) a and )c
me2 m0 c
(A) 180 mW
h
(B) 240 mW (C) a and )c
me m0 c2
(C) 280 mW
2 h
(D) a and )c
(D) 350 mW mc 2 m0 c2
20
 JUN - 32220/II—A

74. The wavelength of hydrogen

72. For a singlet state of electronic
spectrum known as Balmer series is

system the Landé splitting factor given by :

1 1 1
will be : (A) RH n = 5, 6, 7 .....
) 42 n2 !

(A) 1 1 1 1
(B) RH n = 4, 5, 6 .....
) 32 n2 !
(B) 3/2
1 1 1
(C) RH n = 3, 4, 5 .....
) 22 n2 !
(C) 1/2
1 1 1
(D) R H n = 2, 3, 4 .....
) 1 n2 !
(D) 5/2

75. The rotational spectrum of 12C16O

73. Te2+ ion has two d electrons in its
and 13C16O provide the values of
outermost shell. With the aid of
rotational constants B and B

Hund’s rule the ground term for the respectively. If B is 1.92 cm–1, what

d2 system will be : is the value of B ?

(h = 6.6 × 10–34 Js)

(A) ML = 2, MS = 1/2, Term = 2D
(A) B = 2.12 cm–1
(B) ML = 3, MS = 1, Term = 3F
(B) B = 1.83 cm–1
(C) ML = 2, MS = 2, Term = 5D
(C) B = 1.06 cm–1

(D) ML = 2, MS = –1/2, Term = 2D (D) B = 4.24 cm–1

21 [P.T.O.
 JUN - 32220/II—A

76. For proton (1H), placed in a magnetic 78. Which of the following molecules
field of 2.3 Tesla, the resonant give no infrared or microwave
frequency observed in an NMR spectra but Rotational Raman
spectrometer is (Given : gN = 5.58,
spectra ?
# N = 5.05 × 10 –27 JT –1 and
(A) HCl, HCN
h = 6.6 × 10–34 Js)

(A) 100 kHz (B) CO2, CH4

(B) 1 MHz (C) O2, H2

(C) 1000 MHz (D) CO, H2O

(D) 100 MHz 79. Auger electron emission cannot be

77. In CO2 Laser it is possible to obtain obtained from :

laser radiations at wavelengths of (A) Nickel

9.6 m and 10.6 m. The energy
(B) Carbon
levels corresponding to the two
transitions are : (C) Oxygen

(A) (10°0) * (02°0) and (02°0) * (D) Hydrogen

(01 0)
80. The correct order of increasing “first
(B) (00°1) * (10°0) and (00°1) * ionization potential” is :
(02°0)
(A) Li, Na, K, Rb
(C) (02°0) * (01 0) and (01 0) *
(B) Li, Be, B, C
(00°0)
(C) Be, Mg, Ca, Sr
(D) (00°1) * (02°0) and (00°1) *
(10°0) (D) B, Al, Ga, In

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81. In a powder diffraction pattern 84. If there are p atoms in the primitive
recorded from a face centered cubic cell, the phonon dispersion relation
sample using X-rays, the first peak will have :
appears at 30°. The second peak will
(A) 3 optical phonon branches
appear at :
(A) 32.8° (B) 3p-3 optical phonon branches

(B) 33.7° (C) 3p-1 optical phonon branches

(C) 34.8° (D) 3p optical phonon branches

(D) 35.3° 85. The kinetic energy of a free electron

at a corner of the first Brillouin zone
82. A single crystal of copper contains
a low angle tilt boundary on (001) of a two-dimensional square lattice
plane with a tilt axis parallel to is larger than that of an electron at
[010]. The tilt angle, if the spacing the midpoint of a side of the zone
of the dislocation in the boundary by a factor b. The value of b is :
is 3 × 10–6 m and their Burgers (A) b = 2
vector is 0.4 × 10–9 m, is :
(B) b = 2
(A) 2.00 × 10–4 rad
(C) b = 4
(B) 2.60 × 10–4 rad
(D) b = 8
(C) 0.50 × 10–4 rad
86. In a p-type semiconductor, the
(D) 1.33 × 10–4 rad
Fermi level lies 0.4 eV above the
83. Atomic weight and density of gold
valence band. If the concentration
are 197 and 1.9 × 10 4 kg/m 3
of the acceptor atoms is trippled and
respectively. If the velocity of sound
kT = 0.03 eV, the new position of
in it is 2100 m/s, the Debye
the Fermi level will be :
temperature for gold will be :
(A) 200 K (A) 0.250 eV

(B) 240 K (B) 0.100 eV

(C) 300 K (C) 0.525 eV

(D) 370 K (D) 0.367 eV

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 JUN - 32220/II—A

87. In a dielectric, the power loss is 90. Considering the BCS theory of
proportional to : superconductivity, which one of
the following statements is not
(A)
correct ?
(B) 2
(A) Presence of energy gap at
(C) 1/ temperature below the critical
(D) 1/ 2 temperature

where is the angular frequency of (B) Different critical temperatures

applied electric field. are possible for isotopes

88. If the static dielectric constant (C) Presence of Meissner effect can
of NaCl is 5.6 and its optical be observed
refractive index is 1.5, the ratio of (D) Quantization of magnetic flux
its electric polarizability to its total in superconducting ring in the
polarizability is : units of (h/e)
(A) 0.5 91. As per the nuclear stability rule, the
(B) 0.6 following nuclear decay :
5 4
(C) 0.8 3 Li * 2 He +P
can be possible because :
(D) 0.9
(A) The mass of 5Li is smaller than
89. The ground state of an alkali metal
the sum of the masses of 4He
is a 2S1/2 state. The difference in
and P
energy levels arising in the presence
of a weak magnetic field B, given (B) The spin of 5Li is less than the
in terms of Bohr magneton sum of the spins of 4He and P
B
is : (C) The mass of 5Li is greater than
(A) the sum of the masses of 4He
BB
and P
(B) 2 BB
(D) The spin of 5Li is greater than
(C) 4 BB
the sum of the spins of 4He
(D) 6 BB and P
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92. The binding energy per nucleon for 95. The beta particles emitted by a
107Ag
47 nuclei is nearly :
radioactive source have continuous
[Given :
energy spectrum, with end point
Mass of proton = 1.007825 amu
energy Emax. This is due to sharing
Mass of neutron = 1.008665 amu
of disintegration energy by :
Mass of silver = 106.905091 amu

1 amu = 931.5 MeV] (A) Emitting nucleus and the beta

(A) 8.10 MeV/nucleon particle in the form of recoil

(B) 8.54 MeV/nucleon energy

(C) 8.95 MeV/nucleon (B) Neutrino and gamma-ray

(D) 9.25 MeV/nucleon
(C) Beta particle and neutron in the
93. The violation of CP invariance
nucleus
theorem was observed in the :

(A) Decay of beta particles (D) Beta particle and neutrino

(B) Decay of alpha particles 96. A gamma-ray of 1 MeV energy is

(C) Decay of heavy ions scattered by the process Compton
(D) Decay of K° meson scattering. If the angle of scattering
94. A nucleus decays from its spin state is 180°, the energy of the scattered
5–/2 to spin state 3–/2 by emission
gamma-ray will approach to :
of gamma-ray. The gamma-ray
decay mode can be classified as : (A) 0.511 MeV
(A) E1, M2, E3, M4
(B) 0.551 MeV
(B) M1, E2, M3, E4
(C) 0.352 MeV
(C) E2, M3, E4, M5

(D) E3, M4, E5, M6 (D) 0.255 MeV

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97. A comparison between HPGe and

99. The following nuclear reaction
NaI(Tl) detectors for recording
spectrum of gamma-rays, it is
P + P * K+ + ++
observed that in general :
(A) the energy resolution and is not allowed due to non-
efficiency of HPGe detector are
higher as compared to those of conservation of :
NaI(Tl) detector
(A) Baryon number and isospin
(B) the energy resolution and
efficiency of HPGe detector are
(B) Strangeness and baryon
almost the same as those of
NaI(Tl) detector
number
(C) for HPGe detector, the energy
resolution is high and efficiency (C) Charge and strangeness
is low as compared to those of
NaI(Tl) detector (D) Isospin and charge
(D) for HPGe detector the energy
resolution is low and efficiency 100. To obtain splitting in the nuclear
is high as compared to those of
energy levels, the concept of spin-
NaI(Tl) detector
98. After absorbing a thermal neutron orbit interaction was used in the
by 235 U nucleus, the following
nuclear :
fission reaction is induced :
235 90
92 U +n * 36 Kr + X + 2n (A) Liquid drop model
The fission fragment X is :
(A) 145La (B) Collective model

(B) 144Ce
(C) Optical model
(C) 145Cs
(D) 144Ba (D) Shell model

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ROUGH WORK

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ROUGH WORK

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