Physical Chemistry Laboratory Course - Section B
BP 21
                          Experiment 2
            To Determine the order of the reaction
                   2Fe3+ + 3I-    2Fe2+ + I3-
                with respect to Fe3+ and I- at 35°C
                                          Ashen Samaranayake
                                          144097
                                          19/09/2016
pg. 1
Date: 12/09/2016
Theory:
This experiment is known as the iodine clock reaction. Chemical kinetic is the study of rates of
chemical reactions, the change of concentration of reactants to products with time, the
following reaction takes place was determined:
                                    2Fe3+ + 3I-          2Fe2+ + I3-
The rate equation can be expressed as:
Rate = k [Fe3+] a. [I-] b           Where, k – rate constant
                                             [ ] – Concentration of reactants used
                                             a – The order of the reaction with respect to Fe3+
                                             b – The order of the reaction with respect to I-
The rate constant and the order of reactants cannot be derived from the stoichiometry of the
balanced reaction alone, it can only be determined experimentally. In this experiment the rate
constant and the order was determined using the initial rate method. The results indicates a
dependence between the initial rate and the concentration of reactants, and the dependence
of the reaction by the limiting reagent.
The experiment was performed in two method by varying the concentration of one reactant
and keeping the other constant. The order of ‘a’ with respect to Fe3+ making up reaction
mixtures with varying Fe3+ concentration but keeping the iodide concentration constant. This
can be expressed as:
                            Rate = k’ [Fe3+] a                     (where k’ = k [I-] b)
Or
                            log (rate) = a.log [Fe3+] + constant   (where constant = log k’)
                  log (rate)
                                                      Slope = a
 Intercept = Constant
pg. 2                                                          Section B Physical-BP21
The initial rate is determined using the time taken for a small amount of I3- to be produced in a
reaction mixture. This is done by keeping the medium with a constant amount sodium
thiosulphate which reacts very rapidly with the I3- formed in the reaction. Starch was used an
indicator. When all the sodium thiosulphate is used up, I3- is produced and the final colour
change is a blue colour solution.
The same method was done with varying the iodide concentration in order to determine ‘b’
with respect to I-, and keeping the concentration of Fe3+.
Reactions for the experiments:
2Fe3+ + 3I-            2Fe2+ + I3-      (Slow Reaction)
I2 + 2S2O32-          2I- + S4O62-      (Fast Reaction)
Pre-lab questions:
    1)
               a) The relationship between the rate of a chemical reaction and the concentration
                  of the reaction at a given temperature.
               b) Temperature and Activation energy
    2) The molecules in the reaction medium must collide, the collision occurring must have
       enough energy and the collision should occur in the correct orientation.
pg. 3                                                     Section B Physical-BP21
Procedure:
X – 0.1 mol dm-3 ammonium ferric sulphate acidified with 5% H2SO4 solution
Y – 0.1 mol dm-3 KI solution
Z – 0.002 mol dm-3 sodium thiosulphate
  i.    Determination of ‘a’
5 Conical flasks of 250 cm3 labelled 1,2,3,4, and 5. Into each flask the respective volumes were
added with reagents (expect for the Fe3+ solution). 5 drops of starch solution was added into
each flask.
 Conical Volume          Volume of      Volume of    Volume of acidified    Time taken for the
  Flask   of 0.1         0.002 mol       distilled   0.01 mol dm-3 Fe3+       blue colour to
 Number mol dm-3        dm-3 Na2S2O3     water /      solution / cm3 (C)    develop / min.sec
         KI / cm3         / cm3 (Z)        cm3
            (Y)
    1      5.00                20.00      00.00             25.00
    2      5.00                20.00      05.00             20.00
    3      5.00                20.00      10.00             15.00
    4      5.00                20.00      15.00             10.00
    5      5.00                20.00      17.00             8.00
   I.   Immersed all five flasks in a water bath maintained at 35oC.
  II.   The flasks were shaken frequently to help the contents to reach the bath temperature.
 III.   In another flask (C) 150 ml of prepared 0.01 mol dm-3 of Fe3+ solution and immersed
        into the water bath.
 IV.    All the flasks containing with the respective volumes and flask C were allowed to reach
        at 35oC. Two different thermometers were used to measure the temperature of the
        contents in the interested flask and flask C.
 V.     After the contents reached to 35oC, 25.00 cm3 of Fe3+ solution was pipetted out and
        added into flask 1.
 VI.    The stop watch was started in the midpoint of the delivery. The time was measure from
        the first appearance of the blue colour.
VII.    The procedure was repeated with the rest of the flask.
pg. 4                                                  Section B Physical-BP21
 ii.       Determination of ‘b’
The same procedure was done as ‘i‘(without the Fe3+ solution added at first). 5 drops of starch
solution was added into each flask. The time was recorded.
 Conical        Volume of       Volume of       Volume of          Volume of           Time taken for
  Flask          0.01 mol       0.002 mol        distilled       acidified 0.01      the blue colour to
 Number          dm-3 KI /     dm-3 Na2S2O3     water / cm3      mol dm-3 Fe3+       develop / min.sec
                  cm3 (Y)        / cm3 (Z)                       solution / cm3
                                                                       (C)
       1          25.00           10.00               05.00          10.00
       2          20.00           10.00               10.00          10.00
       3          15.00           10.00               15.00          10.00
       4          12.00           10.00               18.00          10.00
       5          10.00           10.00               20.00          10.00
Results:
  i.
 Conical       Volume        Volume of    Volume of       Volume of       Time taken       Time taken
  Flask         of 0.1       0.002 mol     distilled       acidified      for the blue     for the blue
 Number        mol dm-          dm-3       water /         0.01 mol        colour to        colour to
                3 KI /       Na2S2O3 /       cm3          dm-3 Fe3+        develop /        develop/
               cm3 (Y)        cm3 (Z)                     solution /        min.sec             min
                                                            cm3 (C)
       1         5.00          20.00          00.00          25.00            4.04             4.67
       2         5.00          20.00          05.00          20.00            5.01             5.17
       3         5.00          20.00          10.00          15.00            6.10             6.17
       4         5.00          20.00          15.00          10.00           13.14            13.23
       5         5.00          20.00          17.00           8.00           16.11            16.18
 ii.
 Conical Volume              Volume of    Volume of       Volume of       Time taken       Time taken
  Flask  of 0.01             0.002 mol     distilled     acidified 0.01   for the blue     for the blue
 Number mol dm-3                dm-3       water /       mol dm-3 Fe3+     colour to        colour to
         KI / cm3            Na2S2O3 /       cm3           solution /      develop /        develop /
            (Y)               cm3 (Z)                       cm3 (C)         min.sec             min
    1     25.00                10.00          05.00          10.00            2.20             2.33
    2     20.00                10.00          10.00          10.00            3.07             3.12
    3     15.00                10.00          15.00          10.00            4.56             4.93
    4     12.00                10.00          18.00          10.00            9.33             9.55
    5     10.00                10.00          20.00          10.00           13.15            13.25
pg. 5                                                         Section B Physical-BP21
Calculations
  i.
        Flask Number                       t/ min           loge (1/t)             loge (V) *
             1                              4.67                -1.54                3.218
             2                              5.17                -1.64                2.996
             3                              6.17                -1.82                2.708
             4                             13.23                -2.58                2.302
             5                             16.18                -2.78                2.080
               Δ𝑦
 ii.      m=
               Δ𝑥
                 𝑦2 −𝑦1       −2.87−0
          m=              =              = 0.87
                 𝑥2− 𝑥1        0−(3.3)
          According: log (rate) = a.log [Fe3+] + constant
          Where ‘a’ is the gradient, therefore a = 0.87 ≈ 1.0
 iii.
        Flask Number                       t/ min           loge (1/t)             loge (V) *
             1                              2.33                -0.85                3.218
             2                              3.12                -1.14                2.996
             3                              4.93                -1.60                2.708
             4                              9.55                -2.26                2.485
             5                             13.25                -2.58                2.302
 iv.
               Δ𝑦
          m=
               Δ𝑥
          (The value of the gradient is inaccurate during to experimental errors (m = 0.82), thereby
          the gradient is found with the given values in the table)
                 𝑦2 −𝑦1       −2.58−(−0.85)
          m=              =                   = 1.88
                 𝑥2− 𝑥1        2.302−3.218
          According: log (rate) = b.log [I-] + constant
          Where ‘b’ is the gradient, therefore b = 1.88 ≈ 2
pg. 6                                                       Section B Physical-BP21
  v.    I2 + 2S2O32-                   2I- + S4O62-
 vi.    Statement b), this is about the measurement of time. As soon as the iodide is reacting
        with the iron (III), the starch won’t indicate the colour blue, the moment iron (III) is over
        the reaction between thiosulphate and iodine takes place and when the blue colour is
        observed the time is easily measured.
vii.    Rate = k [Fe3+] a. [I-] b a = 1 and b = 2
                     1        1
        Rate =           =          = 0.214 min-1
                     𝑡       4.67
        Assume the volume of Fe3+ (25.00 cm3) and I- (5.00 cm3) ∝ to their concentration
                                       25              5
        0.214 min-1 = k x (1000 ) 1 x (                      )2
                                                      1000
        k = 3.424 x 10-7
viii.   Flask 1 :                 Volume of Fe3+ = 25.00 cm3
             1           1
    Rate =       =           = 0.214 min-1
             𝑡       4.67
Assume the volume ∝ concentration
Rate = k’ [Fe3+] a
                                  25
    0.214 min-1 = k’ (1000 )a                                Equation 1
Flask 2:             Volume of Fe3+ = 20.00 cm3
             1           1
    Rate =       =           = 0.193min-1
             𝑡       5.17
Assume the volume ∝ concentration
Rate = k’ [Fe3+] a
                                  20
    0.193 min-1 = k’ (1000 )a                                     Equation 2
pg. 7                                                                      Section B Physical-BP21
𝐸𝑞𝑢𝑎𝑡𝑖𝑜𝑛 1
𝐸𝑞𝑢𝑎𝑡𝑖𝑜𝑛 2
0.214          k′ ×(25 ÷1000)𝑎
           =
0.193          𝑘 ′ ×(20 ÷1000)𝑎
1.1088 = (1.25) a
log 1.1088 = log (1.25) a
log 1.1088 = a log (1.25)
a = 0.46
Discussion:
 ix.
          We are determining the average rate of the reaction and assume as the initial rate. This
           is a major error in this experiment.
          The intensity of blue colour varies with different people performing the experiment, to
           ensure proper colour change hot and freshly prepared starch solution was used.
          The experiment was performed at 35°C in water bath to maintain constant temperature
           since the rate constant is dependent on temperature.
          The solution of KI was slightly yellow in colour before the experiment was conducted. Its
           means the iodide has oxidized to iodine and liberation is possible. This can lead to an
           error with the experiment.
          The rate equation Rate = k [Fe3+] a. [I-] b is actually a 3rd order reaction (a + b = 1 +2 = 3).
          The starch solution provided is a warm solution and addition (1 – 2ml) to the contents
           can cause small temperature changes and affect the rate constant by change of
           temperature.
          The reason why the 2nd experiment, the gradient of the graph was inaccurate was due to
           the KI was slightly yellow colour (liberation of iodine), the thermostat solution of Fe3+
           because it was clamped (random error).
pg. 8                                                          Section B Physical-BP21
Post lab question:
   1) Concentration was assumed to be directly proportional to the volume, this won’t effect
      on the order of the reaction but it will slightly affect the rate constant of the reaction.
      This is because we assume the average rate = the initial rate, but the way the experiment
      was conducted and time measured is different due to the midpoint of delivery of Fe3+ can
      change from person to person.
   2) The measurements can be triplicated, to obtain an average time taken. An error can occur
      during the midpoint of delivery from each replication can vary.
   3) We assume concentration directly proportional to the volume but it is inversely
      proportional.
                          No.of moles
        Concentration =
                           Volume
        This can affect the order of the reaction values.
Reference:
       Determining-the-Rate-Law-for-a-Reaction-between-Iron-III-and-Iodide-Ion -
        https://www.scribd.com/doc/227422374/Determining-the-Rate-Law-for-a-Reaction-
        between-Iron-III-and-Iodide-Ion (accessed Sept 12, 2016).
       http://www.chemguide.co.uk/physical/basicrates/orders.html (accessed Sept 12, 2016)
pg. 9                                                       Section B Physical-BP21