Micro Corp.
uses
1,000 units of Chip
annually in its
production. Order
costs consist of
P10 for placing a
long-distance call
to make the order
and
P40 for delivering
the order by truck
to the company
warehouse. Each
Chip costs P100,
and the carrying
costs are estimated
at 15.625%
Micro Corp. uses
1,000 units of Chip
annually in its
production. Order
costs consist of
P10 for placing a
long-distance call
to make the order
and
P40 for delivering
the order by truck
to the company
warehouse. Each
Chip costs P100,
and the carrying
costs are estimated
at 15.625%
Micro Corp. uses
1,000 units of Chip
annually in its
production. Order
costs consist of
P10 for placing a
long-distance call
to make the order
and
P40 for delivering
the order by truck
to the company
warehouse. Each
Chip costs P100,
and the carrying
costs are estimated
at 15.625%
Micro Corp. uses
1,000 units of Chip
annually in its
production. Order
costs consist of
P10 for placing a
long-distance call
to make the order
and
P40 for delivering
the order by truck
to the company
warehouse. Each
Chip costs P100,
and the carrying
costs are estimated
at 15.625%
Cost of carrying
inventory.....................
............... P1.00 per
liter per year
Lead
time.............................
................................. 7
working days
Required: Compute
the following:
(1) Order point (OP) =
Lead Time Usage
(LTU) + Safety Stocks
(SS) = 840
(2) Average inventory
= Order Size (OS)/2 +
SS = 1000/2 + 140 =
640
(3) Maximum
inventory assuming
normal lead time and
usage/Normal
Maximum
Inventory = OP – LTU
+ OS = 840 – 700 +
1,000 = 1,140
(4) Cost of placing
one order; using EOQ;
P20
(5) Absolute
Maximum Inventory =
OP – (LT X Min
Daily Use) + OS ;
= 840 – (7 X 50) +
1,000 = 1,
Cost of carrying
inventory.....................
............... P1.00 per
liter per year
Lead
time.............................
................................. 7
working days
Required: Compute
the following:
(1) Order point (OP) =
Lead Time Usage
(LTU) + Safety Stocks
(SS) = 840
(2) Average inventory
= Order Size (OS)/2 +
SS = 1000/2 + 140 =
640
(3) Maximum
inventory assuming
normal lead time and
usage/Normal
Maximum
Inventory = OP – LTU
+ OS = 840 – 700 +
1,000 = 1,140
(4) Cost of placing
one order; using EOQ;
P20
(5) Absolute
Maximum Inventory =
OP – (LT X Min
Daily Use) + OS ;
= 840 – (7 X 50) +
1,000 = 1,
Cost of carrying
inventory.....................
............... P1.00 per
liter per year
Lead
time.............................
................................. 7
working days
Required: Compute
the following:
(1) Order point (OP) =
Lead Time Usage
(LTU) + Safety Stocks
(SS) = 840
(2) Average inventory
= Order Size (OS)/2 +
SS = 1000/2 + 140 =
640
(3) Maximum
inventory assuming
normal lead time and
usage/Normal
Maximum
Inventory = OP – LTU
+ OS = 840 – 700 +
1,000 = 1,140
(4) Cost of placing
one order; using EOQ;
P20
(5) Absolute
Maximum Inventory =
OP – (LT X Min
Daily Use) + OS ;
= 840 – (7 X 50) +
1,000 = 1,
The standard deviation of the demand during lead time distribution isσdLT
= σd L == 51.96A 92 percent cycle-service level corresponds to z =
1.41Safety stock = zσdLT =1.41(51.96 mixers) = or 73 mixersAverage
demand during lead time = dL =100(3) = 300 mixersReorder point (R) =
Average demand during lead time + Safety stock= 300 mixers + 73 mixers
= 373 mixersWith a continuous review system, Q = 440 and R =
373Copyright © 2010 Pearson Education, Inc. Publishing as Prentice Hall.
