Scribd
Upload
73 views2 pages

Lab03 Subnetting

This document discusses IPv4 subnetting of the network 192.168.192.0/18. It calculates the subnet mask as 255.255.192.0, identifies the network and broadcast IPs as 192.168.192.0 and 192.168.255.255 respectively, and defines the host range as 192.168.192.1 to 192.168.255.254. It also notes that with a /18 prefix, the network size is 16,384 IPs.

Uploaded by

Fyon Chin
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as TXT, PDF, TXT or read online on Scribd
73 views2 pages

Lab03 Subnetting

This document discusses IPv4 subnetting of the network 192.168.192.0/18. It calculates the subnet mask as 255.255.192.0, identifies the network and broadcast IPs as 192.168.192.0 and 192.168.255.255 respectively, and defines the host range as 192.168.192.1 to 192.168.255.254. It also notes that with a /18 prefix, the network size is 16,384 IPs.

Uploaded by

Fyon Chin
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as TXT, PDF, TXT or read online on Scribd
You are on page 1/ 2

LAB 4 Task 1: IPv4 subnetting

IPv4 address : 192.168.192.0/18 Prefix=/18

1. Subnet mask
/18 = 11111111.11111111.11000000.00000000

Reference table
0 1 2 3 4 5 6 7 ->Binary
1 2 4 8 16 32 64 128 ->Decimal

1 1 1 1 1 1 1 1
128+64+32+16+8+4+2+1 = 255

255.11111111.11000000.00000000 ->1st octet

255.255.11000000.00000000 ->2nd octet

1 1 0 0 0 0 0 0
128+64+0+0+0+0+0+0 = 192

255.255.192.00000000 ->3rd octet

255.255.192.0 ->4th octet

Subnet mask (snm) = 255.255.192.0


*************************************************************************
2. Network/Subnet IP address
192.168.192.0/18
Method 1: Method 2:
192/2 = 96 r 0 168-128 = 40 ->1
96/2 = 48 r 0 40-64 = x ->0
48/2 = 24 r 0 40-32 = 8 ->1
24/2 = 12 r 0 8-16 = x ->0
12/2 = 6 r 0 8-8 = 0 ->1
6/2 = 3 r 0
3/2 = 1 r 1 168 -> 10101000
1/2 = 0 r 1

192 -> 11000000

11000000.10101000.11000000.00000000 ->IPv4 add in binary


AND 11111111.11111111.11000000.00000000 ->Subnet mask
-----------------------------------------------------------------
11000000.10101000.11000000.00000000 = 192.168.192.0

Subnet IP = 11000000.10101000.11000000.00000000 = 192.168.192.0


**************************************************************************
3. Broadcast IP address

11111111.11111111.11000000.00000000 -> Subnet mask


00000000.00000000.00111111.11111111 -> Flipped snm

00000000.00000000.00111111.11111111 -> Flipped snm


OR 11000000.10101000.11000000.00000000 -> Subnet IP
----------------------------------------------------------------
11000000.10101000.11111111.11111111 -> Broadcast IP
Broadcast IP = 11000000.10101000.11111111.11111111 = 192.168.255.255
**************************************************************************
4. Host/Usable IP range

Subnet IP = 192.168.192.0
Broadcast IP = 192.168.255.255

192.168.192.1 to 192.168.255.254 -> Host/Usable IP range


(After subnet IP) (Before broadcast IP)

Host/Usable IP range = 192.168.192.1 to 192.168.255.254


**************************************************************************
5. Size of network
192.168.192.0/18 ->/18 is prefix
number of 0 in prefix = 32 - 18 = 14

size = 2^14 = 16384 IPs

Size of network = 16384 IPs

PC1 = 192.168.192.2 255.255.192.0


PC2 = 192.168.192.5 255.255.192.0
VLAN 1 = 192.168.255.254 255.255.192.0

You might also like