CE 362 (LAB) L-1
DESIGN OF MILL BENT
1. DESIGN CRITERIA
2. LOADS AND ANALYSIS
2.1 DEAD LOAD (DL)
2.2 ROOF LIVE LOAD (LL)
2.3 WIND LOAD (WL)
2.4 LOAD COMBINATION
3. DESIGN OF PURLINS
4. DESIGN OF SAG RODS
5. DESIGN OF GIRTS
6. DESIGN OF BOTTOM CHORD
7. DESIGN OF TOP CHORD
8. DESIGN OF WEB MEMBERS
9. DESIGN OF KNEE BRACE
10. DESIGN OF COLUMNS
11. RIVETS AT THE JOINTS
12. DESIGN OF SPLICE PLATE AT BOTTOM CHORD
ENGR. FRANKLIN M. SALAS
BSCE(CIT), M.ENG.(AIT,TH)
1. DESIGN CRITERIA L-2
1.1 DESIGN CODES
1.1.1 National Structural Code of the Philippines (NSCP), Vol.1, 2001 Ed.
1.1.2 American Institute of Steel Construction (AISC)
1.2 MATERIAL SPECIFICATIONS
a.) Min. thickness - 1/4 in. or 6.35 mm
b.) Min. depth of purlin - 1/40 of span
c.) Use 3/8 in. (10 mm) gusset plate
d.) Use 3/4 in. (20 mm) diameter rivets
e.) Yield strength of A36 steel, Fy - 250 MPa (36 ksi)
f.) Allowable stress in bending & tension, Fb or Ft - 0.6 Fy
g.) Allowable stress in shear, Fv - 0.4 Fy
h.) Roofing - corrugated G.I. sheets
i.) Siding - corrugated G.I. sheets
1.3 DESIGN LOADINGS (NSCP 2001)
1.3.1 DEAD LOAD (DL)
Wt. of Roofing - 0.19 kPa
1.3.2 ROOF LIVE LOAD (LL) - 0.75 kPa
(Rain or Snow)
1.3.3 WIND LOAD - 1.90 kPa
(V=200 kph)
STRUCTURAL ENGINEER: ENGR. FRANKLIN M. SALAS
PRC REG. NO.: PTR NO.:
DATE: DATE:
TIN: PLACE:
ENGR. FRANKLIN M. SALAS
BSCE(CIT), M.ENG.(AIT,TH)
2. LOADS & ANALYSIS L-3
Bracing
Roofing
Top chord
L.T.C.
Purlins
rise = 2.4 m
Panel length q
Siding 45O Bottom chord
Knee brace
H = 6.6 m
Girts (spacing = 1.12 m)
Bay = 5.2 m
Data:
Span = 12 m Bay (m)
Bay = 5.2 m
H (m)
2.1 DEAD LOAD (DL) Fy (MPa)
q = tan-1 2.4 / 6 = 21.8O
2 2
L.T.C. = 6 +(2.4) = 6.46 m. ; L.T.C. = Length of Top Chord
Panel length = L.T.C.
4
Spacing of purlins = L.T.C.
8
Dead Load (D.L.) = wt. of roofing + wt. of purlin
T.A. = Tributary Area
= (Panel length)(Spacing of bay)
= ( L.T.C. ) (Spac. of bay)
4
Wt. of roofing = 0.19 kPa (T.A.)
Wt. of purlin = (wt. in kN/m)(Spac. of bay)(2) ; 2 purlins per panel
DL
DL DL
DL DL
DL DL
DL / 2 DL / 2
2.2 ROOF LIVE LOAD (LL)
LL
LL LL
LL LL
LL LL
LL / 2 LL / 2
LL = 0.75 kPa (T.A.)
ENGR. FRANKLIN M. SALAS
BSCE(CIT), M.ENG.(AIT,TH)
2.3 WIND LOAD (NSCP 2001) L-4
WLW WLL
Windward Leeward
0.20 2 2 0.60
WLW WLL
Wind WLW WLL
2 2
q
WLG1 WLG2
0.80 0.50
For q > 10O , 0.20 inward (Windward)
, 0.60 outward (Leeward)
WLW = (1.90 kPa)(T.A.)(0.20) = _____ kN
WLL = (1.90 kPa)(T.A.)(0.60) = _____ kN
WLG1 = (1.90 kPa)(T.A.G.)(0.80) = _____ kN
WLG2 = (1.90 kPa)(T.A.G.)(0.50) = _____ kN
T.A.G. = Tributary Area for Girts
= (Spacing of girts)(Bay)
2.4 LOAD COMBINATION
LC1 = DL + LL Choose bigger
LC2 = 0.75(DL + LL + WL) value
LC1 = Load Combination 1
LC2 = Load Combination 2
ENGR. FRANKLIN M. SALAS
BSCE(CIT), M.ENG.(AIT,TH)