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Deepak Practical 4

The document describes an experiment using an Owen's bridge to determine the self-inductance of air core and iron core coils. The procedure involves adjusting the variable resistance and capacitor in the bridge to achieve a null reading, then calculating the inductance from the component values. The results show the air core coil has an inductance of 45mH and iron core coil has 449.99mH.

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Manish Kumar Bisoi
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452 views5 pages

Deepak Practical 4

The document describes an experiment using an Owen's bridge to determine the self-inductance of air core and iron core coils. The procedure involves adjusting the variable resistance and capacitor in the bridge to achieve a null reading, then calculating the inductance from the component values. The results show the air core coil has an inductance of 45mH and iron core coil has 449.99mH.

Uploaded by

Manish Kumar Bisoi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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National Institute of Technology Raipur

ELECTRICAL MEASUREMENT AND INSTRUMENTATION

Submitted to :
Dr. Dhanavath Suresh Assistant Professor

Name DEEPAK BAJAJ


Branch & Section Electrical Engineering and G
Roll. No. 20117904
Measurement of Self Inductance by Owen Bridge

Aim: To determine the self inductance by owens bridge


Apparatus Required:

S.No Apparatus Qty


1 Owen Bridge Trainer Module 01
2 Multimeter 01
3 Set of patch wires 01

Circuit diagram:
Theory:
This bridge may be used for measurement of an inductance in terms of capacitance.
The above figure represents the connections for this bridge, under balance
conditions.
Let,
L1= Unknown self Inductance of resistance R1
R2=Variable non-inductive resistance,
R3=Fixed non-inductive resistance,
C2=Variable standard capacitor,
C4=Fixed standard capacitor

Procedure:

● Apply Supply voltage from the signal generator with arbitrary frequency. ( V
=3v). Also set the unknown Inductance value from the 'Set Inductor
value' tab.
● Then switch on the supply to get millivoltmeter deflection
● Choose the values of R2, R3, C2 and C4 from the resistance and capacitance
box. Varry the values of R2 and C2 by fixing the values of R3 and C4 to some
particular values to achieve Null.
● Observe the millivoltmeter pointer to achieve "NULL"
● If "NULL" is achieved, switch to the 'Measure Inductor value' tab and click
on 'Simulate'. Observe the calculated values of unknown inductance (L1)
and unknown internal resistance (R1) of the inductor.
● Also observe the Quality factor of the unknown inductor which is defined
as Q =ωL/R, Where ,ω=2πf

Observation table:

Coil R2(ohm) R3(ohm) C2(Farad) C4(Farad) L1(mH) R1(ohm) Q


Air 4.5 10000 100E-8 100E-8 45 10000 0.01413
Iron 45 10000 100E-8 100E-8 449.99 10000 0.14130

Calculation:

The value of air core inductance = R2R3C4=4.5×10000×100E-8=45mH


Resistance of air core coil = C4R3/C2=100E-8×10000/100E-8=10000 ohm
Q-factor of air core coil = ωL1/R1=2×π×50×45mH/10000= 0.01413
The value of iron core inductance = R2R3C4=45×10000×100E-8=450mH
Resistance of iron core coil = C4R3/C2=100E-8×10000/100E-8=10000 ohm
Q-factor of iron core coil = ωL1/R1=2×π×50×450mH/10000= 0.14130

Precautions:
● Connect the circuit carefully without any short circuits.
● Reading must be taken correctly without any error.
● Disconnect the circuit immediately after completion of the experiment.
Result:
[1] The value of air core inductance: 45mH
The value of air core resistance: 10000 ohms
Q-factor of air core coil: 0.01413

[2]The value of iron core inductance: 449.99mH


The value of iron core resistance: 10000 ohms
Q-factor of iron core coil: 0.14130

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