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Questions: "I Can Competitive Exams Centre" 9657413496 1

This document contains 49 multiple choice questions related to percentages. The questions cover a variety of percentage calculation problems involving markups, discounts, profit/loss, and other scenarios. Answers are provided after the questions in a separate section.

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0% found this document useful (0 votes)
1K views37 pages

Questions: "I Can Competitive Exams Centre" 9657413496 1

This document contains 49 multiple choice questions related to percentages. The questions cover a variety of percentage calculation problems involving markups, discounts, profit/loss, and other scenarios. Answers are provided after the questions in a separate section.

Uploaded by

smruti parida
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Contents

Questions ............................................................................................................................................................................. 1
Answers ............................................................................................................................................................................. 16

Questions

1) If 12.5% of a number is 12.5 ×1.25, then find the 200% of that number?
a) 2.5
b) 1.25
c) .75
d) 1.75

2) 75% of a number is added to the number itself then the result is 35% of 200.Then
find the number?
a) 20
b) 30
c) 40
d) 50

3) x% of y is equal to z% of w, then find the value of 75% of X?


a) 4zw/3y
b) 3zy/4
c) 2zy/3y
d) zy/3

4) The price of a scooter is increased by 33.33% and then a discount of 6.75% is given at
an increased price. What will be the effects on sale?
a) 25% Increase
b) 25% Decrease
c) 20% Increase
d) 20% Decrease

5) Find the successive percentage of 6.66% and 3.33%?


a) 65/ 25%

“I Can Competitive Exams Centre” 9657413496 www.icanclasses.com 1


b) 63/9%
c) 67/25%
d) 92/9%

6) If 25% of (A + B) = 5/2×( A – B), then find how many % A is more than B?


a) 200/9%
b) 100/9%
c) 50/3%
d) 75/3%

7) Find the percentage change in the area of the rectangle, whose length is decreased by
6.75 % and breadth is also decreased by 12.5% (rounded off two decimals)?
a) Decreased by 16.66%
b) Decreased by 18.40%
c) Increased by 15%
d) Increased by 12.06%

8) If 25% of X is added to 80% of X then the results becomes to 30% of 70 then find the
value of 300 % of X?
a) 50
b) 40
c) 60
d) 80

9) Find the relation between X and Y, where 200% more than X = 75% less value of Y.
a) 2X = 5Y
b 3X = 5Y
c) 2X = 3Y
d) 12X=Y

10) The yearly income of Mohan is Rupees 144000. He invested his monthly income in
different parts of his lifestyles.15% on his food, 10% on the cloth 12% on the other
households, 18% on education and health. Rest of the total savings of income on life
insurance policies. Then find how much money he saves monthly?
a) 6400/-
b) 5400/-
c) 6000/-
d) 4500/-

11) The income of X is 37.5% less than Y. Then the income of Y is how much percent
more than that of X -
a) 60% more than X
b) 200/11% less than X
c) 100/9% more than X
d) 200/9% less than X

12) If the price of sugar is decreased by 62.5% then how much consumption of milk is
increased to there is no change in the expense on it?
a) 133.33%

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b) 16.666%
c) 166.66%
d) 13.333%

13) A dealer of kerosene oil is increased by 12.5% then decreased by 25% then again
decreased by 20%. Find the overall change in its rate?
a) It becomes 78.75%
b) It becomes 67.5%
c) It becomes 178.75%
d) It becomes 168.75%

14) If the price of a washing machine is first increased to 22.5% and then decreased to
22.5%. Then in the price of the machine is changed to-
a) Decreases by 5.0625 %
b) Decreases by 6.0625%
c) Increases by 5.0625%
d) Increases by 6.0625%

15) In a hotel, 30% had coffee while 20% had tea. 10% of them had coffee and tea both.
If 360 people were present then find the number of people who did take either of two?
a) 146
b) 216
c) 220
d) 190

16) Income of Swathi is first decreased 12 % and then it is increased by 12%. What is
the change in her income?
a) 1.44%(decrease)
b) 1.44 %( increase)
c) 1.25 %( decrease)
d) 1.25 %( increase)

17) Rashmi scored 32.5% marks and failed by 20 marks. Shyamali scored 37.5% marks
and get 10 more marks than required to pass. Then find the maximum number of marks
of the exam?
a) 500
b) 600
c) 750
d) 800

18) The Price of PPE kit includes the manufacturing cost, 12.75% is sales tax, 12.25% is
profit. What is the manufacturing cost if the price is rupees 25670. Here sales and profit
to be calculated on manufacturing cost.
a) 52700/-
b) 62700/-
c) 42700/-
d) 72700/-

19) A reduction of 27 % in the price of sanitizer enables us to buy 13.5 litres more for

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Rupees 100. What is the reduced price per litre?
a) 3.4 Rupees per litre
b) 2.5 Rupees per litre
c) 2 Rupees per litre
d) 3.5 Rupees per litre

20) In an examination, A gets 20 % less marks than B. B gets 25% more marks than C
and C gets 20 % less marks than D. If A gets 420 marks out of 600 then how much marks
getting by D?
a) 58.33%
b) 66.66%
c) 33.33%
d) 58.66%

21) In an election, a candidate who gets 72% of the vote is elected by a majority of 880
votes. What is the number of polled votes?
a) 5000
b) 3000
c) 4000
d) 2000

22) Monthly income of Madhu is Rupees 12000. Monthly expenses of Madhu is on food
is 22% of his income. Remaining of the income spent on clothing is 20% and rest of the
30% on health and education and Gst of 20% on other households. Then find the
monthly savings of Madhu ?
a) 40123/-
b) 41200/-
c) 4193.28/-
d) 40896/-

23) If successive % of x and y is M. Then find the value of M-x ?


a) y(100 – x)/200
b) y(100 + 2x)/100
c) y(100 + x)/200
d) y(100 + x)/100

24) There were 5 questions in an examination. 10% students have done all questions
and 10% of students don't do any questions. Rest 20% of students do only one question
and 20% of students do 4 questions. If out of 15% of students do 2 questions and 400
students do 3 questions then how many students do all questions?
a) 160
b) 120
c) 180
d) 200

25) A person purchases a plot for Rupees 34300 and builds a building with costing of
Rupees 219700. If the value of the plot increases with 30% yearly where the price of
building depreciated by 30% yearly then in how many years the price of both will be
equal?

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a) 3 years
b) 2 years
c) 6 years
d) 4 years

26) In a calculation, a number is multiplied by 7/6 instead of 6/7, what will be the
percentage error in the solution?
a) 25.25%
b) 30.95%
c) 30%
d) 35.95%

27) In a cricket match, two batsmen Abhay and Ballu scored some runs. Difference
between 20% of run scored by Abhay and 24% of runs scored by Ballu is equal to 40%
of run scored by Ballu. Find the ratio of their runs.
a) 16 : 5
b) 16 : 7
c) 8 : 5
d) 8 : 7

28) Giving two successive discounts of 15% and 18% are given on the bag. Find out the
overall discount in percentage to purchase the bag.
a) 30.3%
b) 30%
c) 30%
d) 33.333%

29) In an area having a population of 2500, an election was held for the post of
Panchayat leader. There were three candidates, and each one gets 10% more votes
respectively. Due to some reason 183 votes were rejected. Find out the number of votes
gotten by Panchayat leader?
a) 784
b) 748
c) 847
d) 874

30) Raza purchases an item by paying Rs.3363. He gets a discount of 5% on it. After
getting the discount, he also pays GST of 18%. Find the Marked Price of the item Raza
purchased.
a) 3300
b) 3000
c) 4000
d) 4300

31) A Shopkeeper sells some bananas. He sells 37.5% of bananas and still, he has 500
bananas left. Originally, he had:
a) 750 bananas
b) 850 bananas
c) 872 bananas

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d) 800 bananas

32) If the cost price of any article increased by 22% and then after some time due to
Diwali sale shopkeeper is offering a 22% discount. By what per cent percentage cost of
the article has been increased or decreased?
a) Decreased by 8.44%
b) Increased by 8.44%
c) Decreased by 4.84%
d) Increased by 4.84%

33) In an examination the passing percentage is 35%. Sajal got 220 marks and failed by
25 marks. The maximum marks are:
a) 650
b) 700
c) 750
d) 800

34) What percentage of numbers from 1 to 20 has 7 or 3 in the unit's digit?


a) 25%
b) 20%
c) 15%
d) 4%

35) The population of Dholakpur was 2,20,000 three years ago. If it is increased by 4%,
5% and 5% respectively in the last three years, then the present population of city
Dholakur is:
a) 252252
b) 262262
c) 222222
d) 242242

36) The ratio 1/5 : 1/4 will be expressed in the form of percentage be :
a) 125%
b) 45%
c) 54%
d) 80%

37) If A is 60% of B, then how much per cent percent of 3A is B?


a) 33.33%
b) 44.44%
c) 55.55%
d) 66.66%

38) If the numerator of a fraction is increased by 20% and the denominator of the
fraction is increased by 50%, the resultant fraction is ½ what is the original fraction?
a) 5/8
b) 5/7
c) 4/6
d) 7/8

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39) 33 1/3% of 69 + 28% of 25 = x% of 120.Find the value of X?
a) 30
b) 25
c) 20
d) 15

40) Fresh peas have a 35% quantity of water, while dry peas contain 5% water. How
many kgs of dry peas can be obtained by 50 kg of fresh peas?
a) 7.00 Kg
b) 7.14 Kg
c) 7.25 Kg
d) 7.50 Kg

41) How much is 60% of 180 is greater than 3/5 of 30?


a) 90
b) 80
c) 100
d) 18

42) In an examination, 26% failed in Science and 29% failed in Mathematics. Find the
pass percentage in both the subjects if 16% failed in both the subjects?
a) 51%
b) 61%
c) 71%
d) 76%

43) What will come in place of the question mark (?) in the following question?
62.5% of 800 + 17% of 5500 = ? + 773
a)773
b) 772
c) 663
d) 662

44) If the given two numbers are respectively 14% and 35% of a third number, then
what percentage is the first of the second?
a) 25%
b) 30%
c) 35%
d) 40%

45) 25% of one-seventh of a land is sold for Rupees 30,000. What is the value of 40% of
the land?
a) 366000
b) 636000
c) 336000
d) 333000

46) Convert the fraction √49/23 into percentage

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a) 75%
b) 37.5%
c) 87.5%
d) 80%

47) If 9/10th of 7/4th of a number is 1008, then 45% of that number is _____.
a) 144
b) 264
c) 288
d) 298

48) When a number is increased by 11, it becomes 112.5% of itself. What is the
number?
a) 77
b) 88
c) 112
d) 111

49) 30% discount is offered on an item. By using Membership card the customer wins
10% cashback. What is the effective discount percent?
a) 40%
b) 36%
c) 37%
d) 33%

50) If x = 847 and y = 1111, then x is how much percentage less than y?
a) 20%
b) 24.67%
c) 23.2%
d) 23.76%

51) Rohit Sharma scored 264 runs which included 28 boundaries and 18 sixes. What
per cent of his total score did he make by running between the wickets?
a) 15%
b) 15.75%
c) 16.66%
d) 33.33%

52) A person spends 62.5% of his income. If his income increases by 37.5% and
expenditure increases by 80% but savings decreases by Rupees 1200 then find his
initial income.
a) 1200
b) 2400
c) 9600
d) 10800

53) In a city number of female is 12.5% more than the number of children, but 20%
more than the number of males. If the number of male increases in ratio 5 : 6 but the
number of female increases by 22 2/9% and in the number of children increases by 630.

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Due to this total population increases by 28 4/7%. Find the increment in the number of
females.
a) 320
b) 340
c) 360
d) 380

54) A and B invest in a business in the ratio of 6 : 7. A spend 60% of its amount in
electricity and 20% of rest on medical, whereas B spends 40% of its amount on personal
expenses and 60% of the rest on Goods charges. The total amount left with them is
Rupees 36,000 then calculate their individual sum.
a) 60000 /- and 60000/-
b) 60000/- and 70000/-
c) 70000/- and 70000/-
d) 70000/- and 80000/-

55) A person went to the shopping mall, he starts buying items costing 1, 2, 3, 4, 5…
upto 20 terms. Also, he spends 75% of the total amount of buying a shirt. Now he is left
with Rupees 190 then calculates the original amount he had.
a) 1800
b) 1600
c) 2000
d) 2200

56) There were only two candidates in an election, 10% of the voter list did not cast
their votes and 68 voters cast their ballot paper blank. The winner was supported by
47% of all voters in the list and he got 368 votes more than the rival. The number of
voters on the list was:
a) 7,500
b) 8,000
c) 8,500
d) 6,500

57) In a company number of employees is increased by a% and also time duration is


increased by a% Due to this production of the company increases by 224%. If a total of
440 new employees joins the company then find the initial number of employees in the
company.
a) 300
b) 400
c) 500
d) 550

58) The price of rice is increased by 22.22%, then increased by a% and again it is
reduced by 15 5/8%. But a person reduced his consumption by 35% and his
expenditure is 2.5% less than previous. Find the value of a.
a) 45.45%
b) 204%
c) 20.4%
d) 55.45%

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59) In a cylinder, the ratio of radius and height is 1 : 2. If the radius is increased by 50%
and height is decreased by 40%. Find the percentage change in volume of the cylinder.
a) 25%
b) 32%
c) 30%
d) 35%

60) In a cuboid breadth is decreased by 11 1/9%. Length is decreased by 12.5% and


height is decreased by 10%. What is the effect on the original value?
a) 30% decrease
b) 30% increase
c) 40% decrease
d) 40% increase

61) The monthly income of a person was Rupees 15300/- and his monthly expenditure
was 10200. If his income increased by 15% and expenditure increased by 10%. The %
increase or decrease in savings?
a) 20% Increase
b) 25% Decrease
c) 20% decrease
d) 25% Increase

62) The salary of an officer, 10% is deducted as house rent. 15% of the rest he spends
on children education and 10% of the balance, he spends on clothes. After this
expenditure, he is left with him as Rupees 4,131. What is his salary?
a) 4000
b) 4500
c) 5000
d) 6000

63) If 135 is increased by x% and 405 is decreased by y%. Results are equal, then x/2%
of 180 is what % more than (100 + x%) of 75?
a) 60%
b) 50%
c) 30%
d) 20%

64) The price of an article was increased by x% and again decreased by x%. If the latest
price was Rupees 1.Then the original price was?
a) 10000/ (10000 – x2)
b) 10000/ (1000 – x2)
c) 1000/ (10000 + x2)
d) None of these

65) Price of diesel increased from Rupees 45/Litre to 50/litre. How much should the
consumption of diesel be reduced (in%) so as to increase expenditure by only 5%?
a) 4.5%
b) 5.25%

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c) 5%
d) 5.5 %

66) If 223% A = 2007% of B and B = x% of A, then the value of x is?


a) 11.11%
b) 10%
c) 12.5%
d) 11.5%

67) 30 Litres of water is added to 60 litres of a solution containing 30% alcohol in


water. What is the concentration of alcohol in solution now?
a) 45%
b) 46%
c) 46.66%
d) 45.66%

68) The monthly salary of A and B together are amounts of Rs. 40000. A spends 85% of
his salary and B spends 95% of his salary. If their saving is same then the salary of A is?
a) 10,000
b) 8,000
c) 9,500
d) 12,000

69) If the salary of Sonu is 37.5% less than the Monu, then salary of Monu is how much
percentage more than Sonu?
a) 45%
b) 50%
c) 60%
d) 166.66%

70) The price of petrol is increased by 66.66%. By how much % a car driver should
reduce his consumption of petrol so that there is no extra expenditure?
a) 40%
b) 75%
c) 60%
d) 70%

71) The price of sugar is reduced by 20%. Now, a person can buys 5 kg more sugar for
Rs. 320. What is the reduced price of sugar per Kg?
a) 12.8
b) 13.8
C) 14.8
d) 15.8

72) The population of a city decreases by 100/17%, 100 /13% and 100/23%
respectively in three years. If the population of the city the decreases by 3680 during
2nd year then find the total decrement in population for three years.
a) 8590
b) 8580

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c) 8560
d) 8540

73) Rohit spent of his 100/19% on food and 100/9% of remaining part on medicine and
donate Rs. 400 and finally 25/3% of remaining part on travelling and save Rupees 5500.
Find the difference between his expenditure on food and travelling.
a) 100/-
b) 200/-
c) 300/-
d) 400/-

74) Price of a commodity is first increased by x% and then decreased by x%. If the new
price is A/100 then find the original price.
a) 100(100 - x2)
b) 100A/(100 - x2)
c) 100A/(1 - x2)
d) 100(100A - x2)

75) A man went to the market with Rs.1200 in his pocket. He spent 33.33% on buying
medicine. 5x% of the remaining on buying food items and he spent 50% of the
remaining on travelling, at last, he left with him Rupees 360. Find 5x%
a) 20%
b) 15%
c) 10%
d) 25%

76) The price of the entry ticket of a theatre increases by Rupees 70 but the number of
visitors decreases by 50/3% and total revenue increases by Rupees 5000. If the initial
price of the ticket is Rupees 210 then find the initial revenue of the theatre.
a) 45000/-
b) 30000/-
c) 60000/-
d) 50000/-

77) Australia scored a total of Z runs in 20 over. India ties the scores in 20% fewer over.
If the initial average run rate had been 100/3% higher. The scores would have been tied
earlier in how many over?
a) 8 Over
b) 10 Over
c) 6 over
d) 12 Over

78) Sanjeev, a salesman is appointed on the basic salary of Rupees 1500 per month and
the condition that for every sale of Rupees 20,000, he will get 20% of basic salary and
20% of the sales as a reward, this incentive scheme does not operate for the first 20,000
rupees of sales. What should be the value of sales if he wants to earn 23,000/- rupees in
a particular month?
a) 90000
b) 60000

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c) 120000
d) 145000

79) In a city 60% are male and remaining are females. Out of total males, 25% of the
male are government employees. Out of the remaining male's ratio between private
employees to unemployed the male is 4 : 5. Out of total female, 60% of females are in
government jobs and out of the remaining females 60% of female work for private firms
and remaining are unemployed. If the difference between male and female who are
unemployed is Rupees 6510 then find the total number of male and female who are
government employees?
a) 12,650
b) 13,650
c) 11,750
d) 10,500

80) Sonu spends 11.76% of his monthly salary on rent, 20% of the rest is spent on
goods 5.55% of the rest is spent on clothes and 46.66% of the rest is invested in
travelling. He gives 11.11% of his salary to his friend. If the salary is Rupees 31500 then
find his savings?
a) 6,575
b) 7,000
c) 7,700
d) 8,500

81) A boy found the answer to the question subtracted the sum 1/5 and 1/8 from the
unit and express the answer in decimals 0.075. The percentage of errors in his answer
has.
a) 89.99%
b) 66.66%
c) 88.88%
d) 67.77%

82) On a certain date, England has a success rate of 80% against India in all ODI's played
between the two countries. England lost the next 90 ODI's against India in a row India
and their (England) success rate come down to 40%. Find the total number of ODI's
played between the two countries?
a) 140
b) 180
c) 160
d) 200

83) In the mock test package of SSC CGL MAINS, Amit has scored 74, 67, 62, 60 out of
100 each in four mock tests. How much should his score out of 100 in the 5th exam to
have an aggregate percentage greater than 70 %?
a) > 87
b) < 85
c) =79
d) = 67

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84) An alloy of gold and zinc weight of 80 grams. It contains 70% gold. How much gold
should be added to the alloy so that percentage of gold is increased to 90%?
a) 12 grams
b) 15.66 grams
c) 15 grams
d) 16 grams

85) In an examination, 52% of the candidates failed in math. 30% of the candidates
failed in Hindi and 15% of the candidates failed in both the subjects. If 198 candidates
passed in both the subjects then find the total number of candidates?
a) 350
b) 300
c) 600
d) 675

86) In a class, the ratio of students who pass in only maths and only physics is 7 : 15,
and the ratio of those who passed in both subjects and fails in both subjects is 1 : 3. If
210 students fail in Math and fail in both the subject is 2/5th of the pass only in Physics
then find the total number of students in the class?
a) 300
b) 250
c )210
d) 200

87) In an examination, a student who gets 33.45% of the maximum marks failed by 23
marks another student who scored 44.45% of the maximum marks gets 32 marks more
than the pass marks. The necessary percentage required for passing is:
a) 38.05%
b) 39.5%
c) 37.5%
d) 33.33%

88) In a party number of female guests is two times the male guest. 50% male like a soft
drink but 20% like both soft and hard drink. Male guest who like both drinks is one
fourth of female guests like both. And the ratio of female guest who like only soft drinks
and only hard drink is 5 : 3.
If the difference between the male and female who like the only hard drink is 100 then
find the total number of the guest at the party. Find the total member of guests in the
party if the difference between the male and female who like only hard drinks is 100.
a) 3,200
b) 2,500
c) 3,000
d) 2,700

89) The pressure of a gas is directly proportional to the square of the number of
molecules and directly proportional to its temperature but inversely proportional to its
volume of the number of molecules decreases by 50/3%. Temperature increases by
12.5% and volume decrease by 8.33%. Find the change in pressure of the gas.
a) 15.75%

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b) 14.77%
c) 16.75%
d) 12.5%

90) In a maternity Center, 15% of the childbirth cases are twins. What is the
approximate percentage of twins out of total children born?
a) 27.75%
b) 22.75%
c) 26.08%
d) 33.05%

91) Every year the value of a machine depreciated by 50/3%. If it's present value is
108000. Find it's the value after 3 years.
a) 62,500
b) 65,500
c) 45,675
d) 52,590

92) One type of liquid contains 26.66% water and the second type of liquid contains
25% of water. A glass is filled with 15 parts of the first liquid and eight parts of the
second liquid. The water in the new mixture in the glass is -
a) 600/23%
b) 300/23%
c) 150/17%
d) 390/17%

93) How much pure alcohol has to be added to 600 litres of a solution containing
50/3% of alcohol to change the concentration of alcohol in the mixture to 36%?
a) 183.26 litres
b) 175.75 litres
c) 181.25 litres
d) 171.75 litres

94) The percentage of metals in a mine of lead ore is 80%. Now the percentage of gold is
5/6% of metals and the rest is lead. If the mass of ore extracted from this mine is 12000
kilogram. Find the mass of lead is.
a) 8,950Kg
b) 1,205Kg
c) 1,025Kg
d) 9,520Kg

95) A's income is 40% less of B's income, and expenditure of A is 75% if B's
expenditure. If A's income is 80% of B's expenditure. If the saving differences of A and B
is Rupees 5100 /- then find the value of saving of B.
a) Rs. 6,500/-
b) Rs. 7,500/-
c) R.s 8,000/-
d) Rs 6,000/-

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96) 30 Kilograms of fresh watermelon contains 80% water. After some time water
remains 60% in the fruit. Find the present weight of watermelons?
a) 15Kg
b) 18Kg
c) 20Kg
d) 13.5Kg

97) The cost of the table is 47.1/17% more than the cost of the chair. The cost of 15
chairs is how much % more or less than the cost of 12 tables.
a) 12.5% More
b) 14.75% less
c) 15% less
d) 16.66% More

98) The number of students who appeared from a school for the Madhyamik
examination in three consecutive years is in the ratio 5 : 7 : 9 and 70%, 85.5%, and
96.5% of students at respective years were successful. What is the percentage of
students who were successful during these three years taken together?
a) 86.51%
b) 86.52%
c) 88.66%
d) 88.55%

99) 20% of the soldiers of an army camp are killed in the battle. 35% of the remaining
soldiers died of corona and 50/3% of the remaining soldiers were disabled. Now only
1757600 soldiers were left in the army camp. How many totally soldiers were there at
the beginning?
a) 556500
b) 4456000
c) 4056000
d) 4546000

100) The tax on an article decreases by 33.33% and it's consumption increases by
50/3%. Find the percentage effect on its revenue?
a) 35.65%
b) 33.33%
c) 34%
d) 28.75%

Answers

1) Answer: A
According to the question,
Let the required number be x
12.5% of x = 12.5×1.25
or, 25x/2 = 25/2 × 25/20
or, x= 25/20= = 5/4
So, 200% of 5/4= 200/100× 5/4= 10/4= 2.5
Hence, the correct option is A.

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2) Answer: C
Let the number be X.
According to the question,
75%x + x = 35%×200
Or, 3x/4 +x = 7/20×200
Or, 7x/4 = 70
Or, x = 70×4/7 = 40
Hence, the correct option is C.

3) Answer: A
As per the given data in question,
x% of y = z% of w
Or, x×y/100 = zw/100
Or, x×y = zw
Or, x= zw/y
Now,
75%×x = zw/y
Or, 3/4×x = zw/y
Or, x = 4zw/3y
Hence, the correct option is A.

4) Answer: A
According to the question,
X= 33.33% =100/3 %, and Y = 6.75% = 25/4 %
By using the % change method = (x – y – xy/100)
=( 100/3 - 25/4 - 100×25/1200)
= ( 100/3 - 25/4 - 25/12)
= (400 – 75 - 25/12)
= 300/12 = 25% (increase)
Hence, the correct option is A.

5) Answer: D
As we know that successive percentage of a and b = (a + b + ab/100)%
According to the given data in the question,
Here, a =6.66% = 100/15= 20/3 and b= 3.33%= 10/3
Now,
(20/3+ 10/3 + 20×10/900)% = (20/3 + 10/3 + 2/9) %
= 92/9%
Hence, the correct option is D.

6) Answer: A
As per given data in the question,
25% of (A + B) = 5/2(A – B)
Or,1/4×(A + B) = 5/2(A – B)
Or, A + B = 10(A – B)
Or, 11B = 9A
Or, A/B = 11/9
So, Required % = (11 – 9)×100/9% = 200/9%
Hence, the correct option is A.

7) Answer: B
According to the question,
Successive change in % for a and b

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= a + b + (ab/100)
Here,
a = - 6.75% and b = -12.5%
Now,
-6.75 – 12.5 + 6.75×12.5/100
= -19.25 + 84.375/100
= -19.25000 + 0.84375
= - 18 .40625% (Decrease)
Hence, the correct option is B.

8) Answerer: C
According to the question,
25% of X is added to the 80% of X then the result becomes to 30% of 70,
25% of x + 80 % of x = 30 % of 70
Or,x/4 +4 x/5 = 30×300/100 = 21
Or,5x + 16x/20 = 21
21x = 21×20
So, x = 20
Now,
Value of 300% of 20 = 300×20/100 = 60.
Hence, the correct option is C.

9) Answer: D
According to the question,
(200 + 100)% of X = (100 – 75)%of Y
Or, 300% of X = 25% of Y
Or, 300X = 25Y
Or, 12X=Y
Hence, the correct option is D.

10) Answer: B
According to the education total investment of Mohan on all the things,
15% on his food + 10% on cloth + 12% on the other households + 18% on education and health
= 55%
Rest amount on the life insurance policy as a savings = (100 – 55)% = 45%
Now,
Yearly or 12 months income of Mohan = 144,000
So, monthly income = 144,000/12= 12000
Therefore, monthly savings, =12000×45% = 12000×9/20 = 5400
Hence, the correct option is B.

11) Answer: A
According to the question,
Required percentage =(x/(100-x))x100
=(37.5/(100 - 37.5))×100 = 60% more than X
Hence, the correct option is A.

12) Answer: C
As we know that if x % decreases with changes in the price of any commodities then x/(100 - x)
% increases with changes it's consumption then there was no effect on it.
So, Here x = 62.5%
Required increases in % = [62.5/(100 – 62.5)]x100
= (62.5 × 100/37.5) = 166.66%
Hence, the correct option is C.

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13) Answer: B
Let the basics, fixed price of kerosene = 100
According to the question,
Increased by 12.5% then decreased by 25% then again decreased by 20%,
100×(1 + 25/200)(1 – 25/100)(1 – 20/100)
= 100×( 9/8)(3/4)(4/5)
= 67.5%
Overall, it becomes 67.5% from 100%.
Hence, the correct option is A.

14) Answer: A
As we know that successive % of - a and b is [-a + b –(a×b) /100)]
According to the question,
Here, a= +22.5 & b= - 22.5
Now,
[22.5 – 22.5 - (22.5×22.5)/100] %
= (0 - 506.25/100)%
= - 5.0625%
Hence the correct option is A.

15) Answer: A
According to the question,
The number of persons who take only coffee(C) = 30% of 360 = 108
The number of persons who take only tea (T) = 20 % of 360 = 72
The number of persons who take both coffee and tea (X) = 10% of 360 = 36
The number of persons who take either coffee or tea
= C + T - X = 108 + 72 – 36 = 146
Hence, the correct option is A.

16) Answer: A
In such cases, there is always decrease.
Given that, x=(common increase or decrease)=12%
According to the formula
Decrease percentage=x2/100%
=122/100%
=1.44%

17) Answer: B
By the equating rule of, Passing marks or % is equal to Passing marks or % because in both of
the cases full marks and pass mark are the same.
Let, Full marks = 100%,
So, Passing marks for Rashmi = Passing marks for Shyamali
32.5% + 20= 37.5% - 10
Or, 5% = 30
Or, 1% = 6
Or, 100% = 600.
Hence, the correct option is B.

18) Answer: B
According to the question,
Since, sales tax and profit can be calculated on manufacturing cost,
Therefore single % change = 12.75% +12.25% = 25%,
Now,

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Manufacturing cost×(1+25%)
Manufacturing cost×1.25= 15675
Manufacturing cost=15675/1.25= 627×100 = Rs.62700
Hence, the correct option is B.

19) Answer: C
According to the question
Let, A person used to purchase x litre at price Rupees 100/- before reduction. Then after
reduction, he gets 13.5 litres more in added with x litres for the same price is 100/-
Now,
A reduction of 27% in Rupees 100 that is Rupees 27/- enables him to buy 13.5 litres more.
Therefore, the reduced price is Rupees 27/- for 13.5 litres
So, the reduced price per litres = 27/13.5= 2 Rupees per litre.
Hence, The correct option is C.

20) Answer: A
Let the marks of C is 100.
According to the question,
B gets 25% more marks than C
B= (100 + 25) = 125
A gets 20 % less marks than B
A= 125×(100 – 20)/100 = 125×80/100 = 100
And C gets 20 % less marks than D
D= 100×100/80 = 125
Now,
Ratio of marks of A: B: C: D = 100: 125: 100: 125 = 4: 5: 4: 5
A gets 420 marks out of 600;
A = 4k and A = 420; k = 420/4 = 70
Therefore, D = 5k = 5×70 = 350
% marks getting by D = (Marks obtained by D/ Full marks)×100
= 350×100/600 = 58.33%
Hence, the correct answer is A.

21) Answer: D
Let the total number of votes polled is x
Now, according to the question;
(100 – 72)% of x = 28% of x
So, 72% of x - 28% of x = 880
Or, 44% of x = 880
Or, x = 880×100/44 = 2000
Number of polled votes is 2000
Hence, the correct option is D.

22) Answer: C
According to the question,
As we all know that if the concept of % in removing the % part from the whole and all times
removing part of % is on the base of always new % on rest value of remaining %
Then,
Monthly, savings of Madhu can be,
Value×{100 – a/100}×{100 – b/100)}×{100 – c/100}×{100 – d/100}
= 12000×{(100 – 22)/100}{(100 – 20)/100)}{(100 – 30/100)}{(100 – 20/100)}
= 12000×(78/100)×(80/100)×(70/100)×(80/100)
=12000 × 78 × 8 × 7 × 8/100 = Rupees 4193.28 /- is monthly savings of Madhu.
Hence, the correct option is C.

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23) Answer: D
According to the question,
The successive percentage value of x and y
X + y + xy/100 = M
Or, M – x – y = xy/100
Or, M – x = y + xy/100
Or, M – x = y(1 + x/100) = y(100 + x)/100
Hence, the correct option is D.

24) Answer: A
Number of students of total questions solved = 10%
Number of students who can't do any questions = 10%
Remaining = 100 – 10 – 10 = 80%
Number of students who solve only one question = 20% of 80 = 16%
Number of students who solve four questions = 30% of 80 = 24%
Remaining = 80 – 40 = 40%
Number of students who solve two questions = 15%
Number of students who solve three questions = 40 – 15 = 25%
According to the question,
25% = 400
25×4% = 400×4
Or, 100% = 1600
So, Number of students who solve total questions
= 10% of 1600 = 160
Hence, the correct option is A.

25) Answer: A
Let that the value of both will be equal in "t" years.
34300(1 + 30/100)t = 29700(1 – 30/100)t,
Or, (13/10)t×(10/7)t = (219700/34300)
Or, (13/7)t = 2197/343 = 13×13×13/7×7×7 = (13/7)3
Or, t = 3 years.
Hence, the correct option is A.

26) Answer: B
Let the number = 100
As per the question,
700/6-600/7=(4900-3600)/42
=1300/42= 30.95%
Hence, the correct option is B.

27) Answer: A
Let the runs scored by Abhay = A and Ballu = B
According to the question,
20% of A – 24% of B = 40% of B
Or, 0.2A – 0.24B = 0.4B
Or, 0.2A = 0.4B + 0.24B
Or, 0.2A = 0.64B
Or, A/B = 64/20
Or, A : B = 16 : 5
Hence, the correct option is A.

28) Answer: A

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Total discount offered on the bag
= (15 + 18 - (15×18)/100)%
=(33 – 2.7)%
=3 0.3%
Hence, the correct option is A.

29) Answer: C
Total number of voters = 2500 – 183 = 2317
Let the third candidate got 100 votes
So, the second candidate got 100 + (10% of 100) = 110 votes
So, first candidate (Panchayat leader) got 110 + (10%of 110) = 121 votes
Total votes = 100 + 110 + 121= 331
331 : 121 : : 2317: Panchayat leader
Or, 331/2317=121/ Panchayat leader
Panchayat leader = 847
Hence, the correct option is C.

30) Answer: B
Let the Marked Price = 100
Cost after 5% discount = 95
Cost after 18% GST = 95+(18% of 95) = 112.1
As per the question,
112.1 : 100: : 3363 : Marked Price
Marked price = 3363×100/112.1 = 3000.
Hence, the correct option is B.

31) Answer: D
Percentage of Left out bananas = 100% - 37.5% = 62.5%
As per the question,
100/62.5×500 = 800 bananas
Hence, the correct option is D.

32) Answer: C
Let the original cost = 100
So,
100 × 122/100 × 78/100 = 95.16
Cost after Diwali offer= 95.16
i.e. 100 – 95.16 = 4.84 less than the original
Hence, the correct option is C.

33) Answer: B
According to the question,
Maximum marks = (220 + 25)×100/35 = 700
Hence, the correct option is B.

34) Answer: B
According to the question,
Numbers having 3 or 7 in the unit digit = 3, 7, 13, 17
Percentage= 4/20×100 = 20%
Hence, the correct option is B.

35) Answer: A
As we know that, if percentage population is increased by a %, b% and c % then present
population can be find from last three years

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= Population before three years×(100+a)/100×(100+b)/100×(100+c)/100
So,
220000×104/100×105/100×105/100 =252252
Hence, the correct option is A.

36) Answer: D
According to the question,
1/5: 1/4= 4/5= (4/5 )x100 = 80%
Hence, the correct option is D.

37) Answer: C
According to the question,
A = 60% of B
Or, A = 60/100 ×B
Or, 3A = 180/100× B
Or, (3A×100)/180 = B
Or, B = 3A×100/180×100%
Or, B = 3A×55.55%
Hence, the correct option is C.

38) Answer: A
The original fraction is 1/2 ×(100+50)/(100+20)
=1/2×150/120 = 5/8
Hence, the correct option is A.

39) Answer: B
According to the question,
33 1/3% of 69 + 28% of 25 = x% of 120
Or, 100/3% × 69 + 28% × 25 = x% × 120
Or, 23+7 = x% × 120
Or, x=25
Hence, the correct option is B.

40) Answer: B
According to the question,
Let 'x' kgs of dry peas are obtained from the 50 kgs of fresh peas
=> 50×5/100 =35x/100
=> x = 7.14 kgs
Hence, the correct option is B.

41) Answer: A
According to the question,
(60% of 180) – (3/5 of 30)
= 108 – 18
= 90
Hence, the correct option is A.

42) Answer: B
Required % = 100- (10+16+13) = 100-39 = 61% according to the below mentioned Venn
diagram.
Hence, the correct option is B.

43) Answer: D
According to the question,

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62.5% of 800 + 17% of 5500 = ? + 773
500 + 935 = ? +773
? = 662
Hence, the correct option is D.

44) Answer: D
According to the question,
14/35×100% = 40%
Hence, the correct option is D.

45) Answer: C
According to the question,
Let the total land = x
25/100×1/7×x = 30000
Or, x = 8,40,000
Hence, 40% × 840000 = 336000
Hence, the correct option is C.

46) Answer: C
According to the question,
√49/23 = 7/8×100% = 87.5%
Hence, the correct option is C.

47) Answer: C
According to the question,
9/10 × 7/4x = 1008
Or, x = (1008 × 10 × 4)/(9×7) = 640
So,
640 × 45% = 288
Hence, the correct option is C.

48) Answer: B
Let the number = x
According to the question,
12.5% of x = 11
Or, 12.5/100×x = 11
Or, x = 88
Hence, the correct option is B.

49) Answer: C
Let the Marked Price of item = 100
Cost after 30% discount = 70
Cash back = 10% of 7 = 7
Total discount=30+7 = 37 or 37%
Hence, the correct option is C

50) Answer: D
According to the question,
Difference between y and x= 1111 – 847 = 264
x is less than y = (difference/y)×100%
= 264/1111×100 = 23.76%
Hence, the correct option is D.

51) Answer: C

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According to the question,
The batsman scored 28×4 + 18×6 = 220 runs by boundaries and sixes respectively.
The runs scored by running between the
= 264 – 224 = 44
So, Required % = 44/264×100= 16.66%
Hence, the correct option is C.

52) Answer: C
According to the question,
62.5% : 5/8
As we know, income - Expenditure = Savings,
Here we can go through the below table with given data in the question,

62.5% = 5/8 Income Expenditure Savings


Initial 8 5 3
37.5% = +3/8 80% = 4/5 Difference of 3
and 2 = 1
Final 11 9 2
Now, The difference between savings of initial and final = 1 Unit,
1 unit = Rupees 1200
So, Initial Income is 8 units = Rupees 9600/
Hence the correct option is C.

53) Answer: C
According to the question,
As we know, 12.5%=1/8
The ratio of Children : Female = 8 : 9 and we also know that 20% = +1/5,
And Male : Female = 5 : 6,
Now, we can find the ratio of M: F: C by the below table
M F C
5 9 8
6
5×9; 15 9×6;18 6×8;16
So, M : F : C = 15 : 18 : 16,
Again, By the help of the 2nd table for initial and final required value,
M F C Total
Initial ; 15 18 16 49
Male = 5 15 18×(22 2/9) +7 49×(28 4/7)
Units = 15
Final; And 6 18 22 23 63
= 18

7 units = 630; therefore, 1 units = 90


So, 4 units = 360.
Hence correct option is C.

54) Answer: B
Let A= 600, B = 700,
According to the question,
600×(100−60)/100×(100−20)/100+700×(100−40)/100×(100−60)/100=36600
Or, 192+168 Units = Rupees 36600,
Or, 360 Units = Rupees 36000
Or, 1 unit = 100 Rupees

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So, 600 units = Rupees 60000/-
And 700 units = Rupess 70000/-
Hence correct option is B.

55) Answer: B
Let total amount = x,
According to the question,
As we know that sum of A.P n terms = n/2(a= first term + l = last term)
So, 1+2+3+4……….+20= (20/2)×21=210
(Sum of A.P of 20 terms where a = 1and l = 20)
As per question,
x = 3x/4 + 210 + 190
Or, x/4 = 400
So, x = 1600.
Hence the correct option is B.

56) Answer: A
Let, Total voters = 100x
Number of casted vote = 90x
Valid vote = 90x – 68
The winner got 47x votes,
So, Looser got 90x – 68 – 47x = (43x – 68) votes,
According to the question,
47x – 43x + 68 = 368
Or, 4x = 300
Or, x = 75
So, 100x = 7500
Hence, the correct option is A.

57) Answer: D
According to the question,
We go through the below table with given data in question,
Initial Final
Employees X y
Time duration X y
100 324
Now, Initial and Final, I : F = x2:y2 = 100:324
Or, x2/y2 = 100/324
Or, x/y =10/18
Ratio ⇒ 5 : 9
And, 4 units = 440, 1 Unit = 110
So, 5 units = 550.
Hence, the correct option is D.

58) Answer: A
As we know that E=P×Q or, E = P×C ,
P =22.2% = +2/9, 11(Final)/ Initial(9),
15.5/8% = - 5/32, 27(Final)/ 32(Initial),
a% = b(Final) / a(Initial),
And, Q = 35% = -7/20, 13 (Final)/20 (Inital),
E = 2.5 % = -1/40, 39( Final ) / 40 (Initial),
Now, applying Ratio method,
Initial Final

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P = 22.22% = +2/9 9 11
a% = b/a a B
15.5/8% = -5/32 32 27
Q = 35% = -7/20 20 13
E = 2.5% = -1/40 40 39
Ratio 9×a×32×20×40; 16a 11×b×27×13×39;11b
So, 16a = 11b, a/b = 11/16,
Required % = (16-11)×100/11 = 500/11% = 45.45% .
Hence, the correct option is A.

59) Answer: D
As we know that volume of the cylinder is directly proportional to the square of the radius and
its height. Volume of cylinder = πr2h,
According to the question, we have drawn a table with given information,
Initial Final
r2 = 50% = +1/2 2 3
2 3
h = 40% = -2/5 5 3
2×2×5 = 20 3×3×3 = 27

So, Ratio between initial and final = 20 : 27,


Change in volume of cylinder = 27 - 20 = 7
Now, Required % = (change in volume / Initial volume)×100 = (7/20)×100 % = 35%
Hence, the correct option is D.

60) Answer: A
As we know that volume of the cuboid is directly proportional to its length, breadth and height.
The volume of cuboid = l × b × h,
Initial Final
Length = 12.5% = -1/8 8 7=8–1
Breadth = 100/9% = -1/9 9 8=9–1
Height = 10% = -1/10 10 9 = 10 – 1
Volume = l×b×h 8×9×10, 10 7×8 × 9,7

Ratio of volume of cubiod is initial to final = 10: 7,


Decrease in volume. = 10-7 = 3,
So, Required % = (3/10)×100 = 30% decrease.
Hence, the correct option is A.

61) Answer: D
As we know that Income = Expenditure + Savings,
According to the question,
Ratio of Income : Expenditure: Savings = 15,300 : 10,200 : 5,100= 3 : 2 : 1,
Income = Expenditure + Savings,
As per derived and given data as well as information, here we can go through below table,
Income Expenditure Savings
= 3 + 15 % of 3 = 2+ 10% of 2 =1
= 3.45 % = 2.20% = 3.45% - 2.20% = 1.25%
According to the above table, we savings become as 1.25 %,
Since, Initial savings us 1% Unit, Final savings = 1.25%
So, 25 % increased in the previous savings.
Hence, the correct option is D.

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62) Answer: D
As we now know that
10% = -1/10 (10% deduction on House Rent), Initial = 10 and Final = 9
15% = -3/20 (15% spends on children education), Initial = 20 and Final = 17
10% = -1/10 (10% spends on clothes) ,Initial = 10 and Final = 9
Ratio of initial and final = 10×20×10 : 9×17×9 = 2000 : 1377
Or, 2000×3 : 1377 × 3
Income = Rupees 6000 and savings = Rs.4131.
Hence, correct option is D.

63) Answer: A
According to the question,
135(100+ )/100 = 405(100− )/100
Or, 100 + x = 300 – 3x
Or, 4x = 200
Or, x = 50
Now,
180× /(100×2) = 45
And,
75×100+50100 = 112.5
So, (67.5/112.5)×100=60
Hence, Correct option is A.

64) Answer: A
Let the original price = x,
Now, according to the question, /(100+ )100×(100− )/100=1
Or, x(10000 – x2) = 10000, Or, x = 10000/ (10000 – x2)
Hence, the correct option is A.

65) Answer: D
As we know, E = Q×P,
Here, we can draw a table with given information in question,
Initial Final
P 459 5010
Q x Y
E = 5% = +1/20 20 21
So, x/y = 20×10 = 200/ 21×9 = 189
Required % = (11/200 )×100 = 5.5 %
Hence, correct option is D.

66) Answer: A
According to the question,
A×223% = 2007%× B
Or, A/B = 2007/223 = 9, Or, A = 9B
Now,
B=O.1111A
x = 11.11%
Hence, the correct option is A.

67) Answer: C
As per given data and information in question,
Water = 60×30/100 = 18 Litres

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Alcohol = 60 – 18 = 42 Litres
Adding water= 18 + 30 = 48 Litres
So, Mixture = 42 + 48 = 90 Litres
According to the question,
(42/90)× 100 = 46.66%
Hence, the correct option is C

68) Answer: A
As we know that Income = Expenditure + Savings
For A, I = E + S, 100(Income) = 85 (Expenditure) +15 ( A Savings ),
For A, Ratio of I : E : S =20 :17 :3
For B, Ratio of I : E : S = (20 : 19 : 1)×3 = 60 : 57 : 3
Income of A and B = 60 +20 Units = 80
And 80 Units = 40000, 1 unit = 500
So, 20 units = Rupees 10,000
Hence, Correct option is A.

69) Answer: C
As we know that,
37.5% = 3/8
So, Sonu :Monu = 5 : 8
According to the question,
So, required % = (3/5)×100 = 60%
Hence, correct option is C.

70) Answer: A
As we know that, r = 66.66%
Reduction % in consumption =(r/ (100+r)×100)%
So, required % = (66.66/166.66) × 100 = 39.99%
Hence, the correct option is A.

71) Answer: A
As we know that 20% = -1/5 (reduced price),
Price ratio is 5 (old) :4(new)
Now, the quantity ratio is 4 : 5, Difference = 5 – 4 = 1 Unit,
According to the question,
1 Unit = 5,
So, 320/25 = Rupees 12.8.
Hence, the correct option is A.

72) Answer: A
According to the given data and information, we can draw a table and go through it,
The population of a city decreases by 100/17%, 100 /13% and 100/23% respectively in three
years.
And the population of the city decreases by 3680 during 2nd year.
I II III
100/17% = -1/17 100/13% = -1/13 100/23% = -1/23
17:16 13 :12 23 : 22
17×2990 = 50830, 13×3680 =47840 23 Units = 44160
16×2990 = 47840 12×3680 = 44160
As per the above table,
23 Units = 44160
So, 22 Units = 42240.

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Loss in population 50830 - 42240 = 8590.
Hence, the correct option is A.

73) Answer: A
According to the given data and information we can draw a table and go through it,
Spends 100/19% on = -1/19 = 18(Final )/19 (Initial) on food,
And 100/9% of remaining part = -1/9 = 8(Final)/9 (Initial) on medicine,
And 25/3% of remaining part = -1/12 = 11(Final)/12(Initial) on travelling,
And donate Rupees 400/- and savings = Rupees 5500
Food= 19 : 18 Medicine = 9 : 8 Travel = 12 : 11
19×400 = 7600 9×800 = 7200 12×500 = 6000
18×400 = 7200 8×800 = 6400 11×500 = 5500
Now, according to the above table, Difference between expenditure of Travelling and Food =
500 - 400 = Rupees 100.
Hence, the correct option is A.

74) Answer: B
Let the original price be y.
y×(100 + x)×(100 – x)/100×100 = A/100
Or, y×(100 – x2)/100×100 = A/100
Or, y = 100A/(100 - x2).
Hence, the correct option is B.

75) Answer: C
We know that 33.33% = -1/3 = 2/3,
Now,
According to the question,
1200×2/3 × (100 – 5x)/100×(1/2) = 360
Or, 100 – 5x = 90
Or, 5x =10%
Hence, the correct option is C.

76) Answer: A
As we know, that Revenue = Price × Ticket (Visitors)
According to this question,
Price increase by Rupees 70/-
The initial price is Rupees 210/-
Now,
The ratio of the initial and final price = 210 : 280 = 3 : 4
The ratio of the initial and final visitors = 6 : 5
The ratio of the initial and final revenue= 3 × 6 : 4 × 5
= 9 : 10
Revenue increase 1 unit = Rupees 5000/- ( Given)
So, the initial revenue of the theatre
= 9 units = 9×5000 = Rupees 45000/-
Hence, the correct option is A.

77) Answer: A
As we know that, Run=Average run rate × Over
Note: 20% = 1/5
The ratio of over taken by Australia and India to tie the match = 5: 4
Now, Australia: India = 5×4: 4×4;
20 over and 16 Over

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Run = Run Rate (increase) × Over (Decrease)
Run rate = 100/3 % = 1/3,
Ratio of run rate of Inital : Final = 3 : 4,
Ratio of over taken to Inital : Final = 4 : 3,
According to the question,
4 units = 16
1 unit = 4
So, 3 units = 12
India can complete the = (20 – 12) = 8 over before.
Hence, the correct option is A.

78) Answer: C
Let he sold total slot = x
According to the question,
1500 + (1500×20/100 + 20000×20/100)x = 23000
Or, 1500 + (300 + 4000)x = 23000
Or, 4300x = 21500
Or, x= 5
He sold total slot 5 of 20000
5×20000= 100000
And he sold first slot 20000
Then he total sold = 100000 + 20000 = 120000
Hence, the correct option is C.

79) Answer: B
According to the question,
Male = 60% and female = 40%
Ratio of Male to Female = 60 : 40 = 3:2
Let Male = 300 and Female = 200
Out of 300 there are 25% are government employee = 300×25%= 75
Remaining = 300 – 75 = 225
Out of 225 private employee and
= 4 : 5 : ⇒ 4x : 5x = 4×25 : 5×25= 100 : 125
Now,
Female = 200, out of 200 60% are Government Employees = 200×60% = 120
Out of 200 40%= 80; Out of 80, 60% are private employees=80×60%= 48
And 40% are unemployed = 80×40% = 32
So, Unemployed
Or, 125 Units – 32 Units = 6,510
Or, 93 Units = 6,510
1 Unit = 70
So, 195 Units = 195×70 = Rupees 13650
Hence, the correct option is B.

80) Answer: C
According to the given data in the question, draw a table as of the following,
Expenditure Salary Savings
11.76% = 2/17 17 15
20% = 1/5 5 4
5.55% = 1/18 18 17
46.66% = 7/15 15 8
Note: 11.76% = 2/17; 17×5×18×15 = 45 15×4×17×8 = 16
Expenditure=2; Savings=

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15; Salary = 17 and so on.

According to the question,


45×1/9= 5, 5 Units on his friends
Salary = 45 Units and Savings = 16 – 5 = 11 Units
So, 45 Units = 315,00, Therefore 11units = Rupees 7700
Hence, the correct option is C.

81) Answer: C
According to the question,
Sum = 1/5 + 1/8 = 13/40
Subtract = 1 – 13/40 = 27/40 = 0.675
Difference in answer= 0.675 - 0.075 = 0.600
Percentage error = 0.600×100/0.675 = 88.88%
Hence, the correct option is C

82) Answer: B
Let total 5x match is played between England and India.
According to the question,
Match won by England= 80% of 5x = 4x
And, Match won by India= 20%of 5x = x
But, now India won 90 matches in a row and hence India's success rate of percentage increased
to 60%.
Now, Total match = 5x+90
x+90= (5x+90)×60/100
Or, 5x+450= 15x+270
Or, 10x= 180
x= 18
So, total match = 5x+90= 5×18+90= 180.
Hence, the correct option is B.

83) Answer: A
According to the question,
Let his score in the last exam is x,
So,[(74+67+62+60+x)×100]/500 >70
Or, (263+x)/5>70
Or, 263+x>350
Or, x >87
More than 87 marks have to by Amit to meet the desired percentage of marks in all the five
exams to be 70%.
Hence, The correct option is A.

84) Answer: D
According to the question,
In initial alloy,
Gold = 70%of 80= 56 grams and
Zinc = 80-56= 24 grams,
Let x gram of gold is added to the alloy,
56+x/80= 90/100,
Or, 560 + 10x = 720+9x,
Or, x= 16 grams.
Hence, the correct option is D.

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85) Answer: C
According to the question,
Percentage of candidates failed only in,
Math = 52% - 15% = 37%
Only in Hindi = 30% - 15% =15%
Percentage of students who failed in Math or Hindi or both of the subjects
= 37% + 15% + 15% = 67%
So, the percentage of candidates who passed in both subjects = 100% - 67%= 33%
Let the total students be 100% then 33% = 198
So, 100%= 198×100/33= 600
Hence, the correct option is C.

86) Answer: A
We can go through the venn diagram required below by the help of given data in question.
Both Pass : Both fail = y : 3y
As per the question,

3y = 2/5×15x
Or, y/x = 2/1
Or, y = 2x
Now, both pass: both fail = 2x: 6x
Fail in maths= 30x – 9x = 21x,
Now, 21x = 210
Or, x = 210/21 = 10
So, 30x = 10×30 = 300
The total number of students in the class is 300.
Hence, The correct option is A.

87) Answer: A
Let the maximum marks be x
According to the question,
33.45%of x + 23 = 44.45% of x – 32
Or, 44.45% - 33.45% = 32 + 23
Or, 11% of x = 55
Or, x = 55×100/11 = 500
So, passing marks = (33.45×500/100) + 23 = 190.25
Now, passing % = 190.25×100/500 = 38.05%
Hence, the correct option is A.

88) Answer: C
According to the question,
Let Male = 100
Female = 200
By the below venn diagram,

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In the above venn diagram, Number of male only hard drink =50,
Female only like soft drink = 40
Male like both drinks = 10 and Female only like both drink = 40
Number of only hard drink = 60 and Number like only soft drink = 100
20% female like soft drink and hard drink = 200×20/100= 40
Female like only soft and only hard drink = 100×50/100= 50
Male only like soft drink = 50-10= 40
The ratio of female guest who likes an only soft drink and only hard drink = 5:3
8x = 160 ; 5x= 100 ; 3x= 60
Difference between male and female who likes only hard drink = 60Units - 50Units
By the rule of product constant rule,
10 Units×30= 300 Units, So, 100×30 = 3000.
Hence, The correct option is C.

89) Answer: B
According to the question,
P = pressure n = number of molecules
T= temperature, V =Volume
P directly proportional to n × n × T × 1/v
N = Decreases by = 50/3% =- 1/6
T = Increases by = 12.5% = +1/8
V = Decrease by = 8.33%= -1/12
Now,
Initial Pressure Final pressure
n×n = -1/6 36 25
T= +1/8 8 9
V=-1/12( V is inversely 11 12
proportional to pressure)
88 75
Change in pressure = 88 – 75 = 13
Percentage change in pressure
= 13×100/88 = 14.77%
Hence, the correct option is B.

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90) Answer: C
Let, total children = 100x
Out of these 15% twins = 15×2= 30
And 85×1 = 85
Total born = 85 + 30 = 115,
Approximate percentage of the twins out of total children
= 30×100/115 = 26.08%
Hence, the correct option is C.

91) Answer: A
According to the question,
Time= 3 years and Rate = 50/3%
Now,
50/3%= -1/6 (Because the case of depreciation)
Here, Initial = 6 and Final = 5,
Initial = 6×6×6 = 216 and Final = 5×5×5 = 125
216 Units = 108000
1 Unit = 108000/216= 500
Therefore, 125 Units= 500×125 = 62,500.
Hence, the correct option is A.

92) Answer: A
As per the given data in question,
In 15 litres of the first part,
Water = 15×26.66% = 15×4/15 = 4 litres
Note: 26.66% = 4/15
In 8 litres of the second type of liquid,
Water = 8×25/100 = 2 litres
The total amount of water = 4 + 2 = 6 litres
Required % = 6×100/23 = 600/23 %
Hence, the correct option is A.

93) Answer: C
According to the question,
Alcohol = 600×50/100×3 = 100 litres
Let, X litre of alcohol should be added,
Then, (100 + X)/(600 + X) = 36/100 = 9/25
Or, 2500 + 25X = 5400 + 9X
Or, 16X = 2900
Or, X= 2900/16 = 181.25
Hence, the correct option is C.

94) Answer: D
According to the question,
Mass of metal in lead ore = 12000×80% = 9600 Kg.
Mass of Gold in metal = 5×9600/ 6×100 = 80 Kg.
Mass of lead in ore = 9600 - 80 = 9,520 Kg.
Hence, The correct option is D.

95) Answer: D
Let, Income of B is 100x then the income of A is 60x.
Ratio of income of A and B = 60x : 100x = 3x : 5x
And the expenditure of B is 100y then the expenditure of A is 75y.
The ratio of expenditure of A and B = 3y : 4y,

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According to the question,
3x = 4y×80% = 4y×4/5,x : y = 16/15.
As we know that, Savings = Income - Expenditure,
The income of A and B = 3x : 5x;
A = 3×16 = 48 and B = 5×16 = 80,
And the expenditure of A and B = 3y : 4y;
A = 3×15 = 45 and B = 4×15 = 60,
Now,
Savings of A = 48-45 = 3 Units &
Savings of B = 80-60 = 20 Units,
The difference in savings of A and B
= 20 Units - 3 Units = 17 Units,
17 Units = Rupees 5,100 /- 1 Unit = Rupees 3,00/-
So, 20 Units = 300×20 = Rupees 6,000
Hence, The correct option is D.

96) Answer: A
According to the given data in the question, we go through the below table,
Pulp Water
Fresh Fruit 20% = 1×2 80% = 2×4
Dry Fruit 40% = 2×1 60% = 3×1
Because Pulp is constant in both the condition, New Ratio,
Pulp Water
Fresh Fruit 2 8
Dry Fruit 2 3

Now, Fresh Fruits, 10 Units = 30kg., 1Unit = 3Kg. So, 5 Unit = 15 Kg.

97) Answer: C
According to the question,
As we know that 47.1/17% = +8/17,
Price of table = 17+8 = 25 and Price of chair = 17,
Then price of 12 tables = 25×12 = 300/-
And price of 17 tables = 17×15 = 255 /-
Here, price of 17 tables is less than price of 12 tables by 300 – 255 = 45
Required % = (300 – 255)×100/ 300 = 15 % less.
Hence, the correct option is C.

98) Answer: B
According to the question,
Number of successful students in the first year,
= 5x ×70/10 = 3.5x,
Number of successful students in the 2nd year,
= 7x × 85.5/100 = 5.985x,
Number of successful students in the 3rd year,
9x×96.5/100 = 8.685x,
The total number of students who were successful during these three years taken together =
18.17x,
Required % = (18.17x)×100/21x = 86.52%.
Hence, the correct option is B.

99) Answer: C
According to the given data in question, here we go through the below-derived table,

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Initial Army Remaining Army
20% = -1/5; 5 5-1= 4
35% = -7/20; 20 20-7 = 13
50/3% = -1/6 6 6-1= 5
5×20×6/ 60 4×13×5/26
At the Initial = 60 Army and Remaining = 26 Army,
26 Units = 1757600, 1 Unit = 67600
So,
60 Units = 69× 67600 = 4056000.
Hence, the correct option is C.

100) Answer: B
Let the original consumption be 1 Unit, tax on it be 1 Rupee,
So, Revenue = 1×1 = 1 Rupees,
Note; 50/3% = 50/300.
New consumption = (300+50/300)×1 Rupes = 350/300 = 7/6 Unit,
Now, tax on 1 unit = 33.33% = 1/3 less,
New tax = (1-1/3) = 2/3
Tax on 7/6 Unit = (7/6)×(2/3) = 7/9 = 0.7777
Decreased Revenue = 1.00-0.77 = 0.3333
Required % = (3333/1×10000)×100 = 33.33 %
Hence, the correct option is B.

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