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Swimming Pool Design & Pump Specs

The swimming pool has an area of 142.6 m2 and depth of 1.5 m. It requires 3 pumps with a total flow rate of 35.6 m3/hr to circulate the entire 214 m3 volume every 6 hours. The primary pump needs a head of 1.485 bar. There should be 8 water inlet points sized for a flow velocity of 0.32 m/sec. Drain points of 200x200 mm are needed. Maintaining the pool temperature at 20°F above ambient requires 107.8 kW of heating. The circulation pump needs a flow rate of 36.8 gpm and head of 0.53 bar.

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Ibrahim A. Hameed
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189 views4 pages

Swimming Pool Design & Pump Specs

The swimming pool has an area of 142.6 m2 and depth of 1.5 m. It requires 3 pumps with a total flow rate of 35.6 m3/hr to circulate the entire 214 m3 volume every 6 hours. The primary pump needs a head of 1.485 bar. There should be 8 water inlet points sized for a flow velocity of 0.32 m/sec. Drain points of 200x200 mm are needed. Maintaining the pool temperature at 20°F above ambient requires 107.8 kW of heating. The circulation pump needs a flow rate of 36.8 gpm and head of 0.53 bar.

Uploaded by

Ibrahim A. Hameed
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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SWIMMING POOL

DESIGN OF SWIMMING POOL

SWIMMING POOL:
Area = 142.6 m2
Depth = 1.5 m
Volume = 214 m3
1- SWIMMING POOL PUMP SPP-01
FLOW RATE
Take turn over period every 6 hrs
Swimming pool pump capacity = Volume / (Turn over period)
Pump flow rate = Pool volume / 6 hr
= 214 /6 = 35.6 m3/hr
As per selection we use
4 Filter with flow rate = 10 m3/hr
3 Pump with flow rate = 20 m3/hr 2 ON DUTY – 1 STAND BY
Head
Head (H) = H static + H residual + H friction
H static = 3.0 m =0.3 bar
H residual = 0.5 bar
H Drop through sand filter = 5.0 m = 0.5 bar
To get H friction
Pipe length = 50 m
Equivalent length for pipe = 25
Total length = 75
Pipe diameter = 75 mm
Friction loss = 250 pa/m
H friction = 250 x 75 = 18570 pa = 0.185
Head (H) = 0.3 + 0.5 + 0.5 + 0.185 = 1.485 bar

2- water inlet
No of water inlet = pump flow rate /9 m3/hr = 40/9 = 4.44 INLET
USE 8 INLETS
3- Drain point size
Q=AV
Flow rate through drain point (Q) m3/hr
Cross section area of drain point (A) m
Flow velocity through drain point must be
Q = 40 m3/hr
V = 0.32 m/sec
A = 0.0347 m2
Use drain point 200 x 200 mm
4-HEATING OF SWIMMING POOL.

The total required heat to increase and maintain the temperature in an outdoor pool can be expressed
as
H (total) = total heat load (KW)
H (surface) = heat loss from pool through the surface - mainly evaporation of water (KW)
H (heat-up) = heat load required to increase the pool temperature (KW)

Surface Heat Loss due to Temperature Difference


The heat load required replacing the surface heat loss due to the temperature difference between the
pool surface and the ambient air can be expressed as
H (surface) = KS X dtaw x A        
Where
KS = surface heat loss factor – 12 Btu/ft2
∆T = temperature difference between the air and surface water in the pool (c)
A = surface area of the pool (m2)
Ks = 12 Btu/ft2
∆T = 20 F
A = 1535 ft2
H (surface) = 368400 Btu/hr = 107.8 Kw
Take H (total) = 107.8 Kw
5- CIRCULATION PUMP CP-SP

FLOW RATE
H = m X CP X (Tin - Tout)
Wight of water constant at 8.33 lb/gal
Specific heat of water Btu/lb/f (CP) = 1 Btu/lb/f
Temperature difference through boiler loop ∆T = 20 F
H = 368400 Btu/hr = 107.8 Kw
Flow rate (m) = 2211.3 gph = 36.8 gpm = 2.3 l/s
Head
Head (H) = H friction
H drop through electrical heater = 0.5 bar
To get H friction
Pipe length = 10 m
Equivalent length for pipe = 5
Total length = 15
Pipe diameter = 50 mm
Friction loss = 200 pa/m
H friction = 200 x 15 = 3000 pa = .03 bar
Head (H) = 0.5 + .03 = .53 bar

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