IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –

Quantitative Aptitude

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

Directions (01-05): Study the following information carefully and answer the questions.
The given pie chart shows the percentage distribution of total number of students in four different
schools i.e. A, B, C and D.
Total number of students in all four schools=2500

The given pie chart shows the percentage distribution of the number of boys in four different schools.
Number of boys in all four schools=1200

Note:
a) Number of boys in school A is 100 more than the number of girls in the same school.
b) Number of girls in school B is 10.

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

1) Number of boys in schools A and C together 4) The average number of boys in schools B and
is how much more/less than the average C together is what percentage more than the
number of girls in schools C and D together? total number of students in school B?
a) 175 less a) 45%
b) 100 less b) 20%
c) 115 more c) 15%
d) 210 more d) 50%
e) None of these e) None of these

2) Which of the following is true? 5) Find the ratio of the sum of the maximum and
a) Number of girls in school C is more than the minimum number of boys in the school and
number of boys in school A the sum of the first and second-lowest number
b) (Y-X)=Z1+10 of girls in the school?
c) The number of girls in school C is maximum a) 20:7
d) Total number of students in school A is two b) 11:5
times total number of students in school B c) 9:4
e) All of the above d) 8:3
e) None of these
3) Out of the total number of students in school Directions (06-10): Study the following
E, 80% of the students who passed the exam. If information carefully and answer the questions.
the number of boys and girls in school E is 25% The given table chart shows the number of drifts
and 40% more than that of school D and crashes done by four cars namely i.e. P, Q,
respectively, then find the total number of R and S and also the time taken by these cars to
students who have failed the exam in school E. cross 3000 m race.
a) 124
b) 175
c) 138
d) 166
e) None of these

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

8) The speed of the cars R and S together is

what percentage more than the speed of the car
Q?
a) 45%
b) 70%
c) 40%
Note:
d) 25%
1) Drift refers to over-starting intentionally done
e) None of these
by the driver.
2) While calculating the average speed of the
9) If the speed of the car R is decreased by
car, time taken for drifts and crashes are not
25%, then find the time taken by car R to cover
included.
the same distance?
3) Total points=50*drifts-20*crashes
a) 120 sec
6) To gain 120 more points than car R, then how
b) 200 sec
many more drifts should be done by car S if the
c) 150 sec
number of crashes done by car S is 33.33%
d) 180 sec
more than actual crashes and the time taken by
e) None of these
car S is the same.
10) If the number of drifts done by car T is 40%
a) 4
more than that of car P and it still receives 0
b) 3
points at the end, then how many crashes are
c) 2
done by car T?
d) 5
a) 8.5
e) None of these
b) 10.5
c) 17.5
7) Find the difference between the maximum
d) 9.5
points earned by the car and the minimum
e) None of these
points earned by the car at the end of the race.
a) 160
Directions (11-12): Two number series I and II
b) 110
are given below. Where series I is missing
c) 190
number series and series II is wrong number
d) 150
series.
e) None of these
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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

I) 11, P, 181, 350, 639, 1000 14) Car A covers a distance from point P to Q in
II) 242, 251, 255, 280, 329, 450, 619 5 hours and car B covers 3/4th of the distance
11) 45, P, 78, 99, ?. What value should come in from point P to Q in 7.5 hours. If the speed of
the place of (?). car B is increased by 9 km/hr and then the same
a) 124 distance is covered in 6 hours. Find the speed of
b) 123 car A.
c) 126 a) 54 km/hr
d) 129 b) 60 km/hr
e) 122 c) 72 km/hr
d) 45 km/hr
12) What is the value of (2k+1)? e) None of these
Note: K= the correct number which replaces the 15)
wrong number in the given series. I) 9/x2-11/x+2=0
a) 493 II) (y-2)2=2(1/4)
b) 319 a) X > Y
c) 527 b) X ≥ Y
d) 275 c) X = Y (or) relationship can’t be determined
e) 193 d) X< Y
e) X ≤ Y
13) Vessel contains a mixture of milk and water
in the ratio of 4:1. If 20% of the mixture is taken 16) Out of the total number of chairs in a shop,
out and some equal quantity of milk and water 60% of the chairs are sold and the remaining
added into the mixture, then the quantity of milk 290 chairs are unsold. If the total cost of all the
in the final mixture becomes 60 liters more than chairs is Rs.174000, then find the overall profit
that of water. Find the initial quantity of mixture obtained on 60% of the chairs.
in the vessel. Which of the following options is sufficient to find
a) 150 liters the answer.
b) 175 liters a) 20%of the chairs are defective out of the total
c) 100 liters number of chairs in a shop.
d) 125 liters b) The difference between the cost price and the
e) None of these selling price of a chair is Rs.120.

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

c) The marked price of a chair is 50% more than 1) The cost price per share in 2002 is 25% more
the cost price. than that of the previous year and the cost price
d) 40% of the chairs are sold at 25% profit and per share in 2003 is three times the cost price
the remaining chairs are sold at 33.33% profit. per share in 2001.
e) All of the above 2) Total number of shares bought in 2004 is
Directions (17-21): Study the following 32% more than that of 2001 and the ratio of total
information carefully and answer the questions. number of shares bought in 2001 and 2002 is
The given bar graph shows the total number of 5:6.
shares bought in four different years i.e. 2001, 3) Gross value = Market value - (Liability + Other
2003, 2005 and 2007. expense)
4) Market value = The cost price per share *
Total number of shares bought
17) If the total number of shares bought in 2006
is 28% more than that of 2001 and the sum of
the liability and other expenses in 2006 is equal
to the market value in 2001, then find the gross
value in 2006.
a) Rs.546000
b) Rs.702000
The given bar graph shows the cost price per c) Rs.258000
share (in Rs.) in three different years i.e. 2002, d) Rs.675000
2004 and 2006. e) None of these

18) In 2004, 60% of the shares were bought by

old investors and the remaining shares were
bought by new investors. If the ratio of number
of shares bought by old investors to new
investors in 2002 is 8:7 and then find the sum of
number of shares bought by new investors in
2002 and 2004 together?
a) 8160
b) 3240
Note:
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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

c) 7250 c) 50% more

d) 5480 d) 30% less
e) None of these e) None of these

19) In 2003, the ratio of the liability and market Directions (22-26): Study the following
value was 1:5 and the liability value was information carefully and answer the questions.
Rs.12000 more than the other expenses. If the The given table shows the volume and height of
gross value in 2002 is 40% of the gross value in four right circular cylindrical tanks W, X, Y and Z.
2003, then find the sum of the liability and other The given data also depicts time taken to fill or
expenses in 2002? empty the tank by inlet pipe A, B and outlet pipe
a) 68000 C.
b) 75000
c) 54000
d) 87000
e) None of these

20) If the ratio of the cost price per share in 2004

to 2007 is 3:5 and the cost price per share in
2005 is Rs.65 more than that of 2002, then find
the difference between the market value in 2005
and 2007. Note: Ratio between time taken by pipe B and
a) Rs. 595000 that by pipe C is different because pipes were
b) Rs.343000 used by the operator in different ways for
c) Rs.176000 different tanks. Radius of tank Z is 10.5 m.
d) Rs.418000 22) How much volume of initially empty tank W
e) None of these is filled in one hour, when all three pipes were
opened simultaneously (Time taken by pipe C is
21) The average number of shares bought in 30 hours)?
2002 and 2003 is what percentage is more/less a) 4527.6
than the total number of shares bought in 2001? b) 4536.8
a) 20% more c) 4542.4
b) 15% less d) 4524.2

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

e) None of these d) 17863.65

e) 17145.90
23) Pipe B can alone fill the tank X in 36 hours. 26) Find the respective ratio of the curved
When all three pipes were opened for one hour, surface area of tank W and total surface area of
then the volume of tank X filled was tank Y?
approximately 428 cubic meters/hour, what is a) 1:2
the approximate radius of tank x? b) 2:1
a) 12 c) 1:1
b) 14 d) 3:2
c) 21 e) None of these
d) 28
e) 35 Avni and Beena started the business by
investing Rs.P and Rs.1.2P respectively. After x
24) When all three pipes were opened months Avni withdrew her entire amount and
simultaneously, the volume of tank Z filled in one Chetna entered into business. After the end of 9
hour is 3575 cubic meters/hour. Pipe B alone months, Beena increased her initial investment
can fill 25% of the tank in 3.5 hours. In how by 25%. On completion of one year, the share of
much time, can pipe A can fill the 40% of the Avni and Beena in the entire profit is Rs.14200.
tank alone? If beena would have increased her investment
a) 7 hours after x months, then share of Avni and Beena in
b) 3.5 hours entire profit would have been 10:27.
c) 2.8 hours 27) Find the value of x.
d) 2.1 hours a) 6
e) None of these b) 4
c) 3
25) Another tank M has its height is 20% more d) 10
than that of Y and radius is 20% more than that e) 5
of W. What is the sum of total surface area of 28) Find the difference between the profit share
tank W and M together? of Avni and Beena if the ratio of their profit share
a) 17112.48 is 20:51?
b) 17119.53 a) Rs.4800
c) 17845.32 b) Rs.5800

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

c) Rs.6200 c) Rs.3000
d) Rs.6500 d) Rs.3300
e) Rs.7000 e) Rs.3600

29) If the initial investment of Chetna is Rs.7200 32) Teacher distributes ‘N’ chocolates to ‘3x’
and then find the profit share of Chetna at the students. Find the value of x.
end of the year. Statement I: If he distributes 6 chocolates to
a) 2000 each student, then he is left with 24 chocolates.
b) 2700 Statement II: If the number of students were
c) 3600 1/3rd of the original number, then no chocolates
d) 4200 are left with the teacher.
e) Cannot be determined Statement III: Number of the students is more
than 30 and less than 40 and total number of
30) B is 20% more efficient than A. If B is 60% chocolates are more than 200 and less than 300
more efficient than A, then B can complete the a) IF Statement I and II alone are sufficient to
work in 18 days less than the number of days answer the question
taken by A. What fraction of work will be left b) IF statement II and III alone are sufficient to
after 12 days, if A and B work together? answer the question
a) 11/20 c) If All I, II and III are sufficient to answer the
b) 9/20 question
c) 13/20 d) If none of the statement is sufficient to answer
d) 7/20 the question
e) None of these e) None of these
31) A and B started the business with the
investment in the ratio of 2:1. C and D entered 33) A, B and C entered into a partnership. After
into another partnership with the investment of 8 months, B and C left the business. What is
2:1. Total investment of A and B is 25% less their total annual profit at the end of year?
than that of C and D. If the total profit of all four Statement I: Annual profit of B is Rs.400 more
people at the end of year is Rs.10500, then find than that of A and Rs.200 more than that of C.
the profit share of A. Statement II: Amount invested by C is half of
a) Rs.2400 total amount invested by A and B.
b) Rs.2700

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

Statement III: Ratio between shares of C and c) If All I, II and III are sufficient to answer the
that of A and B together is 3:8. question
a) IF Statement I and II alone are sufficient to d) If none of the statement is sufficient to answer
answer the question the question
b) IF statement II and III alone are sufficient to e) None of these
answer the question

Answer With Explanation

Directions (01-05):
Total number of students in school
A=2500*20/100=500
Total number of students in school
D=2500*25/100=625
Number of boys in school B=1200*20/100=240
Number of boys in school C=1200*30/100=360
Number of boys in school A=b 1. Answer: C
Number of boys in schools A and C together
Number of girls in school A=g
b+g=500 =300+360=660

b-g=100 The average number of girls in schools C and

2b=600 D=(765+325)/2=545

b=300 Required difference=660-545=115 more

g=200
Number of boys in school D=1200- 2. Answer: E

(300+240+360)=300 From Option (A)

Number of girls in school B=10 Difference between number of girls in school C

and number of boys in school A=765-300=465
Total number of students in school
B=240+10=250 more

Total number of students in school C=2500- This statement is true.

(500+250+625)=1125 From Option (B)

Number of girls in school C=1125-360=765 45-10=25+10

35=35
Number of girls in school D=625-300=325

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

This statement is true. Total points earned by car P=50*5-20*3=190

From Option (C) Total points earned by car Q=50*9-20*5=350
Number of girls is maximum in school C=765 Total points earned by car R=50*6-20*4=220
This statement is true. Total points earned by car S=50*8-20*6=280
From Option (D) The speed of the car P=3000/180=50/3 m/s
Total number of students in school A=500 The speed of the car Q=3000/120=25 m/s
Total number of students in school B=250 The speed of the car R=3000/150=20 m/s
This statement is true. The speed of the car S=3000/200=15 m/s
All of the above statements are true. 6. Answer: C
Car S gained 120 more points than car
3. Answer: D R=220+120=340
Number of boys in school E=300*125/100=375 The number of crashes done by car S is
Number of girls in school E=325*140/100=455 increased by 33.33%=6*4/3=8
Total number of students in school The number of drifts done by car S=(8+x)
E=375+455=830 50*(8+x)-20*8=340
Total number of students who are failed the 50*(8+x)=500
exam in school E=830*20/100=166 x=10-8
x=2
4. Answer: B
The average number of boys in schools B and 7. Answer: A
C=(240+360)/2=300 Maximum points are earned by the car Q=350
Required average=(300- Minimum points are earned by the car P=190
250)/250*100=50/250*100=20% Required difference=350-190=160

5. Answer: A 8. Answer: C
The sum of the maximum and minimum number The speed of the cars R and S=20+15=35
of boys in the school=360+240=600 Required percentage=(35-25)/25*100=40%
The sum of the first and second lowest number
of girls in the school=200+10=210 9. Answer: B
Required ratio=600:210=20:7 The speed of the car R is decreased by
25%=20*75/100=15 m/s
Directions (06-10): Required time taken=3000/15=200 sec

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

13. Answer: D
10. Answer: C Milk in initial mixture=4x
The number of drifts done by car Water in initial mixture=1x
T=5*140/100=7 Milk and water in initial mixture=5x
The number of crashes done by car T=y 20% of the initial mixture=5x*20/100=x
50*7-y*20=0 The quantity of milk added in the mixture=y
350=20*y The quantity of water added in the mixture=y
y=17.5 (4x-x*4/5+y)-(x-x/5+y)=60
4x-4x/5+y-x+x/5-y=60
11. Answer: B 3x-3x/5=60
12x/5=60
x=25
Milk and water in initial mixture=5*25=125 liters
P=60
14. Answer: C
The distance between point P to Q=4x km
Car B covers a distance =4x*3/4=3x km
3x/6-3x/7.5=9
15x-12x=270
x=90
The distance between point A to B=90*4=360
km
12. Answer: A The speed of the car A=360/5=72 km/hr

15. Answer: C
9/x2-11/x+2=0 --- (1)

P=60 (1)*x2
2x2-11x+9=0
2x2-2x-9x+9=0
2x(x-1)-9(x-1)=0
x=+1, +9/2
Required value=2*246+1=493
x=1, 4.5

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

(y-2)2=2 (¼)
(y-2)2=9/4 Directions (17-21):
y-2= 3/2 The cost price per share in
y=3.5, 0.5 2001=75*100/125=Rs.60
Hence, Relationship can’t be established The cost price per share in 2003=60*3=Rs.180
Total number of shares bought in
16. Answer: D 2002=7500*6/5=9000
The total number of chairs=290*100/40=725 Total number of shares bought in
The number of chairs sold=725*60/100=435 2004=7500*132/100=9900
The cost price of a chair=174000/725=Rs.240
From option (A)
The total number of chairs=725
20% of the defective chairs=725*20/100=145
80% of the non-defective
chairs=725*80/100=580
This is not satisfied with the given condition.
From option (B)
Difference between the selling price and cost 17. Answer: B
price of a chair=120 The market value in 2001=7500*60=Rs.450000
This is not satisfied with the given condition. The sum of liability and other expenses in
From option (C) 2006=Rs.450000
The marked price of a Total number of shares bought in
chair=240*150/100=Rs.360 2006=7500*128/100=9600
This is not satisfied with the given condition. The market value in
From option (D) 2006=9600*120=Rs.1152000
40% of chairs sold=435*40/100=174 The gross value in 2006=1152000-
60% of chairs sold=435*60/100=261 450000=Rs.702000
Required overall
profit=174*240*125/100+261*240*4/3-435*240 18. Answer: A
=135720-435*240 Number of shares bought by old investors in
=Rs.31320 2004=9900*60/100=5940
This satisfies the given condition.

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

Number of shares bought by new investors in

2004=9900-5940=3960 22. Answer: A
Number of shares bought by new investors in Pipe B fill the tank = 30 * 2/3 = 20 hours
2002=9000*7/(8+7)=4200 A + B + C = 1/10 + 1/20 – 1/30
Required sum=3960+4200=8160 = 6 + 3 – 2/60
= 7/60
19. Answer: D Required Volume = 7/60 * 38808 = 4527.6
The market value in
2003=13500*180=Rs.2430000 23. Answer: B
The liability value in C alone empty the tank x = 36 * 2/3 = 24 hours
2003=2430000*1/5=Rs.486000 A + B + C = 1/36 + 1/12 – 1/24 = 2 + 6 – 3/72
The other expenses in 2003=486000- = 5/72
12000=Rs.474000 5/72 * Volume of tank = 428
The gross value in 2003=2430000- 5/72 * 22/7 * r2 * 10 = 428
(486000+474000)=Rs.1470000 r2 = 196
The gross value in r = 14
2002=1470000*40/100=Rs.588000
The market value in 2002=9000*75=Rs.675000 24. Answer: C
The sum of the liability and other expense in Pipe B fill the tank = 3.5 * 100/25 = 14 hours
2002=675000-588000=Rs.87000 Pipe C fill the tank = 14 * 5/2 = 35 hours
A + 1/14 – 1/35 = 3575/19250
20. Answer: A 70A + 5 – 2/70 = 13/70
The cost price per share in 2007=90*5/3=Rs.150 70A = 10
The cost price per share in 2005=75+65=Rs.140 A = 1/7
Required difference=10500*150- A alone fill 40% of the tank = 7 * 40/100 = 2.8
7000*140=Rs.595000 hours

21. Answer: C 25. Answer: A

The average number of shares bought in 2002 22/7 * r * r * 28 = 38808
and 2003=(9000+13500)/2=11250 Radius of the tank W = 21
Required percentage=(11250- Radius of M = 120/100 * 21 = 25.2
7500)/7500*100=3750/75=50% more Height of M = 120/100 * 35 = 42

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

TSA of M = 2 * 22/7 * 25.2 * (42 + 25.2) = Time ratio of A and B = 6:5

10644.48 If B is 60% more efficient than A, then
TSA of W = 2 * 22/7 * 21 * (28 + 21) = 6468 Time ratio of A and B = 6x:6x * 100/160
Required sum = 6468 + 10644.48 = 17112.48 = 6x:15x/4
6x – 15x/4 = 18
26. Answer: B 9x/4 = 18
22/7 * r * r * 28 = 38808 x=8
Radius of the tank W = 21 A and B complete the work in 12 days = 12/(6 *
22/7 * r1*r1 * 35 = 5390 8) + 12/(5 * 8)
Radius of tank Y = 7 = 11/20
Required ratio = (2 * 22/7 * 21 * 28):(2 * 22/7 * 7 Remaining work = 1 – 11/20 = 9/20
* (35 + 7))
= 2:1 31. Answer: C
Investment of A and B together and C and D
27. Answer: A together = 75:100 = 3:4
Profit ratio of Avni and Beena = 10:27 Profit share of A and B = 3/7 * 10500 = 4500
P * x/(1.2P * x + (1.2P * 125/100 * (12-x)) = Profit share of A = 4500 * 2/3 = 3000
10/27
Px/P(1.2x + 18 – 1.5x) = 10/27 32. Answer: C
27x = 180 – 3x From statement I,
x=6 3x * 6 + 24 = N
18x + 24 = N
28. Answer: C So, statement I alone is not sufficient to answer
Required difference = (51 – 20)/(20 + 51) * the question.
14200 From statement II,
= 6200 3x * 1/3 * y = N
N/x= Completely divisible
29. Answer: E So, statement II alone is not sufficient to answer
Since we can’t able to find the value of P the question.
From statement III,
30. Answer: B 30<Number of students <40 and 200 < number
Efficiency of A and B = 100:120 = 5:6 of chocolates < 300.

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 IBPS PO Mains Memory Based Paper 2021-22 Held on 22nd January 2022 –
Quantitative Aptitude

So, statement III alone is not sufficient to answer From statement I,

the question. Investment of A, B and C is not given
From I, II and III, So, Statement I alone is not sufficient to answer
3x * 6 + 24 = N the question.
18x + 24 = N From statement II,
30<3x<40 Investment of A and B together = 2x
180<18x<240 Investment of C = 2x/2 = x
Possible values of x = 11,12, 13 So, Statement II alone is not sufficient to answer
3x * 1/3 * y = N the question.
y = N/x From statement III,
N/x is completely divisible Ratio of the profit share of C and A and B
So the possible value of x is 12 Together = 3:8
N = 18 * 12 + 24 = 240 So, Statement III alone is not sufficient to
So ALL I, II and III together required to answer answer the question.
the question Since, we can't find the answer by combining all
the statements together.
33. Answer: D

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