ELE 3203
Communication systems
       Lab 9: Frequency Modulation and Demodulation
              Student Name                                  ID Number
                            Faculty Name: Mr. Yacine Adane
                            Lab Instructor: Ms. Rajalakshmi
                            Submission Date: November 21, 2020
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Prepared By: Rajalakshmi S Menon, ADW
Objective
To understand the principle of frequency modulation (FM) and demodulation. Also, to
understand the waveforms of modulated and demodulated signals Moreover, design a
frequency modulator and demodulator using MATLAB “Simulink”.
Apparatus Required
   A. Hardware Tools: Computer system
   B. Software Tool: MATLAB 7.0 and above version.
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Introduction
In a communication system, it is often that one has to send a speech/video signal of lower
frequency content. It is very difficult to transmit the signal at a low frequency through the
medium. Hence the signal is modified to a high-frequency signal so that it can be sent
through the medium. When the signal is modified on the receiver’s end it can be sent through
the medium. As the receiver on receiving the signal applies demodulation techniques to get
the message signal. One such method is frequency modulation. Let the message signal be
m(t).
We define a frequency modulated signal,
                                        x ( t )=cos (2 π f c t+ k ∫ m ( t ) dt) ).
f c is the carrier frequency. K is constant.
Theory
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Prepared By: Rajalakshmi S Menon, ADW
Phase modulation (PM) and frequency modulation (FM) are special cases of angle-modulated
signaling. FM is a process in which the carrier frequency is varied by the amplitude of the
modulating signal (i.e., intelligence signal). Angle modulated signal can be expressed by the
following equation: s ( t ) =A c cos [ 2 π f c t+ θ ( t ) ]
For FM, the phase is proportional to the integral of message signal m(t), therefore
                                      x ( t )=cos (2 π f c t + k ∫ m ( t ) dt) ).
                      Figure 2: Frequency modulation waveform
Frequency demodulator, also called frequency discriminator, is a circuit, which converts
instantaneous frequency variations to linear voltage changes. There are many types of circuits
used in communication systems such as FM to AM conversion, phase-shift discriminators
and phase-locked loop (PLL) frequency demodulator.
Procedure
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Prepared By: Rajalakshmi S Menon, ADW
The following are required to draw the block diagram as shown in the Figure 4.
       1. Message Signal Source
       2. Blocks for viewing the signals – Scope
       3. Trigonometric Function
       4. Summer
       5. Gain
       6. Continuous
       7. Matrix Multiply
       8. Integrator
We can find these blocks in the following locations of Simulink Library:
Carrier, Message, Constant blocks
      Simulink –>DSP System Toolbox –> Sine wave
Integrator
      Simulink –> Continuous–> Integrator
View Block
      Simulink –> Sink –> Scope
Product, summer, Trigonometric and Gain Block
      Simulink –> Math Operations–> Product
      Simulink –> Math Operations–> Summer
      Simulink –> Math Operations–> Gain
      Simulink –> Math Operations–> Trigonometric Function
      Simulink –> Math Operations–> Matrix Multiply
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Prepared By: Rajalakshmi S Menon, ADW
The procedures can be summarized in a three main steps, which are:
   1. Arrange the functional blocks “Simulink Model” for modulated and demodulation
       frequencies.
Frequency Modulations:
Figure 4: Frequency Modulation Simulink Block diagram
   o Parameters:
               Message Signal: frequency = 10, Offset =90, Sample Time= 1/25000
               Gain1= 150, Gain2= 2*pi, Constant= 300
                          1
               Integrator= , Trigonometric Function is “Cos”
                          s
Frequency Demodulations:
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Prepared By: Rajalakshmi S Menon, ADW
Create a Simulink block diagram for the Frequency demodulation with the help of Figure 6.
    o                                                                            Parameters:
                                                                                 Message
                                                                                 Signal: frequ
        e                                                                        ncy   =   10,
                                                                                 Offset =90,
                                                                                 Sample
            Figure 6: Frequency Demodulation Block diagram                       Time=
Figure 5: Frequency Demodulation Simulink Block diagram
        1/25000
                Gain1= 150, Gain2= 2*pi, Constant= 300
                           1
                Integrator= , Trigonometric Function is “Cos”
                           s
                Analog Filter Design “Butter”, Low-pass Filter, filter order 10, Passband edge
        frequency 2*pi*10
RESULTS AND DISCUSSIONS:
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   1. Comment on your results and explain your scope results (modulation and
       demodulation).
      As we can see from figure 7, Frequency modulation as shown in layout 3, is much
      different from Amplitude modulation. The modulated and demodulated signals in FM
      have the same amplitude and it’s the same amplitude as the message signal which is 1.
      The modulated signal in FM is dependent mostly on the message signal.
   2. Upload your Simulink file.
  Figure 7: FM Modulation, and Demodulation
   3. Attach the Simulink Block diagram of FM Demodulation and the scope results
       here.
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Prepared By: Rajalakshmi S Menon, ADW
   Figure 8: FM Demodulation
Figure 9: FM Modulation layout 3, and Demodulation layout 2
      4. Explain your result. (Identify each block function)
              A Message Signal “DSP” source is a message signal, which is a sine wave that carries
               information such as voice, music, and data.
              Gain (150) to increase the message signal’s power and amplitude.
              Summer to add the message signal and the carrier signal also the constant.
              Constant is the modulation index that shows how the carrier wave is being changed by
               the information.
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               After that, the output of the summer stage goes into the Integrator. outputs the value of
                the integral of its input signal with respect to time.
               Gain (2*pi) to increase the power of the modulated frequency signal.
   5. What is the purpose of using a VCO? Explain in detail.
       Voltage-controlled oscillators are used in function generators, phase-locked loops
       including frequency synthesizers used in communication equipment, and the
       production of electronic music, to generate variable tones in synthesizers.
   6. Write the advantages and disadvantages of Frequency Modulation.
       Anything in the world has a pro and cons, this also applied to the frequency
       modulation. To begin with, the advantages of the FM are it has less interface and
       noise. Also, its power consumption is less as compared to AM.
   7. List the applications where the frequency modulation is used.
       -       Frequency modulation can be used for the broadcasting of FM radio. This helps in
               larger signal to noise ratio.
   8. A 100 MHz carrier signal is frequency modulated by a sinusoidal signal of 75
       kHz, such that the frequency deviation is f = 50 kHz. Find the approximate
       bandwidth of the frequency modulated signal.
                   BW=2(B +f) = 2(75K+50K) = 250KHz
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   9. A 100MHz carrier is frequency modulated by 10 KHz wave. For a frequency
       deviation of 50 KHz, calculate the modulation index of the FM signal.
       Given, fc = 100MHz, fm = 10 KHz, Δf = 500 KHz
       Modulation index of FM signal is given by mf = Δf /f m
              50 K
       mf =        =5
              10 K
   10. A sinusoidal modulating waveform of amplitude 5 V and a frequency of 2 KHz is
       applied to FM generator, which has a frequency sensitivity of 40 Hz/volt.
       Calculate the frequency deviation, modulation index, and bandwidth.
       Given:
                Am=5V, fm=2KHz, kf=40Hz/volt
       -   Knowing that the formula for Frequency deviation as Δf=(kf)(Am)
                Δf=40×5=200Hz. Therefore, frequency deviation, Δf is 200Hz
       -   The formula for modulation index is β=Δf/fm
                                           β=200/2×1000=0.1
       Here, the value of modulation index, β is 0.1, which is less than one. Hence, it is
       Narrow Band FM.
CONCLUSION AND OBSERVATION
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To sum up, this experiment was to study the function of frequency modulation and
demodulation. As we know the modulated signal is the encoding of information in a carrier
wave by varying the instantaneous frequency of the wave.
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